A bash loop to echo all possible ASCII characters [closed]

up vote
-3
down vote

favorite

I know how to print all letters

a..z and A..Z and 0..9

But is there a way to print all possible ASCII Characters via a bash loop?

asked Nov 10 at 8:44

Gautham Varma Kanumuru

closed as too broad by jww, Madhur Bhaiya, dandan78, rene, Robert Columbia Nov 10 at 12:28

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

2

Define "all possible ASCII Characters". 0-127 or extended ASCII 0-255? What about the non-printable characters?
– Cyrus
Nov 10 at 8:54

1

Try man ascii
– Mark Setchell
Nov 10 at 10:05

1

See also stackoverflow.com/a/48905712/2836621
– Mark Setchell
Nov 10 at 10:08

I meant regular ASCII (0-127)
– Gautham Varma Kanumuru
Nov 11 at 8:11

add a comment |

up vote
-3
down vote

favorite

I know how to print all letters

a..z and A..Z and 0..9

But is there a way to print all possible ASCII Characters via a bash loop?

asked Nov 10 at 8:44

Gautham Varma Kanumuru

closed as too broad by jww, Madhur Bhaiya, dandan78, rene, Robert Columbia Nov 10 at 12:28

2

Define "all possible ASCII Characters". 0-127 or extended ASCII 0-255? What about the non-printable characters?
– Cyrus
Nov 10 at 8:54

1

Try man ascii
– Mark Setchell
Nov 10 at 10:05

1

See also stackoverflow.com/a/48905712/2836621
– Mark Setchell
Nov 10 at 10:08

I meant regular ASCII (0-127)
– Gautham Varma Kanumuru
Nov 11 at 8:11

add a comment |

up vote
-3
down vote

favorite

I know how to print all letters

a..z and A..Z and 0..9

But is there a way to print all possible ASCII Characters via a bash loop?

asked Nov 10 at 8:44

Gautham Varma Kanumuru

I know how to print all letters

a..z and A..Z and 0..9

But is there a way to print all possible ASCII Characters via a bash loop?

linux bash gnome-terminal

asked Nov 10 at 8:44

Gautham Varma Kanumuru

asked Nov 10 at 8:44

Gautham Varma Kanumuru

asked Nov 10 at 8:44

Gautham Varma Kanumuru

asked Nov 10 at 8:44

Gautham Varma Kanumuru

asked Nov 10 at 8:44

Gautham Varma Kanumuru

closed as too broad by jww, Madhur Bhaiya, dandan78, rene, Robert Columbia Nov 10 at 12:28

2

Define "all possible ASCII Characters". 0-127 or extended ASCII 0-255? What about the non-printable characters?
– Cyrus
Nov 10 at 8:54

1

Try man ascii
– Mark Setchell
Nov 10 at 10:05

1

See also stackoverflow.com/a/48905712/2836621
– Mark Setchell
Nov 10 at 10:08

I meant regular ASCII (0-127)
– Gautham Varma Kanumuru
Nov 11 at 8:11

add a comment |

2

Define "all possible ASCII Characters". 0-127 or extended ASCII 0-255? What about the non-printable characters?
– Cyrus
Nov 10 at 8:54

1

Try man ascii
– Mark Setchell
Nov 10 at 10:05

1

See also stackoverflow.com/a/48905712/2836621
– Mark Setchell
Nov 10 at 10:08

I meant regular ASCII (0-127)
– Gautham Varma Kanumuru
Nov 11 at 8:11

Define "all possible ASCII Characters". 0-127 or extended ASCII 0-255? What about the non-printable characters?
– Cyrus
Nov 10 at 8:54

Try man ascii
– Mark Setchell
Nov 10 at 10:05

See also stackoverflow.com/a/48905712/2836621
– Mark Setchell
Nov 10 at 10:08

I meant regular ASCII (0-127)
– Gautham Varma Kanumuru
Nov 11 at 8:11

add a comment |

3 Answers
3

active

oldest

votes

up vote
2
down vote

You don't need a loop

echo -e \x0..70..9,A..F

It prints all chars from 0 to 127.

edited Nov 23 at 6:25

answered Nov 10 at 11:24

oguzismail

2,5642821

add a comment |

up vote
2
down vote

If it is okay to use awk:

awk 'BEGINfor (i=32;i<127;i++) printf("%c", i)'

Or using printf:

for((i=32;i<127;i++)) do printf "x$(printf %x $i)"; done

edited Nov 30 at 9:52

answered Nov 10 at 9:27

ssemilla

2,687423

add a comment |

up vote
1
down vote

use this:

for ((i=32;i<127;i++)) do printf "\$(printf %03o "$i")"; done;printf "n"

answered Nov 10 at 9:10

mahradbt

1389

add a comment |

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
2
down vote

You don't need a loop

echo -e \x0..70..9,A..F

It prints all chars from 0 to 127.

edited Nov 23 at 6:25

answered Nov 10 at 11:24

oguzismail

2,5642821

add a comment |

up vote
2
down vote

You don't need a loop

echo -e \x0..70..9,A..F

It prints all chars from 0 to 127.

edited Nov 23 at 6:25

answered Nov 10 at 11:24

oguzismail

2,5642821

add a comment |

up vote
2
down vote

You don't need a loop

echo -e \x0..70..9,A..F

It prints all chars from 0 to 127.

edited Nov 23 at 6:25

answered Nov 10 at 11:24

oguzismail

2,5642821

You don't need a loop

echo -e \x0..70..9,A..F

It prints all chars from 0 to 127.

edited Nov 23 at 6:25

answered Nov 10 at 11:24

oguzismail

2,5642821

edited Nov 23 at 6:25

answered Nov 10 at 11:24

oguzismail

2,5642821

answered Nov 10 at 11:24

oguzismail

2,5642821

answered Nov 10 at 11:24

oguzismail

2,5642821

add a comment |

up vote
2
down vote

If it is okay to use awk:

awk 'BEGINfor (i=32;i<127;i++) printf("%c", i)'

Or using printf:

for((i=32;i<127;i++)) do printf "x$(printf %x $i)"; done

edited Nov 30 at 9:52

answered Nov 10 at 9:27

ssemilla

2,687423

add a comment |

up vote
2
down vote

If it is okay to use awk:

awk 'BEGINfor (i=32;i<127;i++) printf("%c", i)'

Or using printf:

for((i=32;i<127;i++)) do printf "x$(printf %x $i)"; done

edited Nov 30 at 9:52

answered Nov 10 at 9:27

ssemilla

2,687423

add a comment |

up vote
2
down vote

If it is okay to use awk:

awk 'BEGINfor (i=32;i<127;i++) printf("%c", i)'

Or using printf:

for((i=32;i<127;i++)) do printf "x$(printf %x $i)"; done

edited Nov 30 at 9:52

answered Nov 10 at 9:27

ssemilla

2,687423

If it is okay to use awk:

awk 'BEGINfor (i=32;i<127;i++) printf("%c", i)'

Or using printf:

for((i=32;i<127;i++)) do printf "x$(printf %x $i)"; done

edited Nov 30 at 9:52

answered Nov 10 at 9:27

ssemilla

2,687423

edited Nov 30 at 9:52

answered Nov 10 at 9:27

ssemilla

2,687423

answered Nov 10 at 9:27

ssemilla

2,687423

answered Nov 10 at 9:27

ssemilla

2,687423

add a comment |

up vote
1
down vote

use this:

for ((i=32;i<127;i++)) do printf "\$(printf %03o "$i")"; done;printf "n"

answered Nov 10 at 9:10

mahradbt

1389

add a comment |

up vote
1
down vote

use this:

for ((i=32;i<127;i++)) do printf "\$(printf %03o "$i")"; done;printf "n"

answered Nov 10 at 9:10

mahradbt

1389

add a comment |

up vote
1
down vote

use this:

for ((i=32;i<127;i++)) do printf "\$(printf %03o "$i")"; done;printf "n"

answered Nov 10 at 9:10

mahradbt

1389

use this:

for ((i=32;i<127;i++)) do printf "\$(printf %03o "$i")"; done;printf "n"

answered Nov 10 at 9:10

mahradbt

1389

answered Nov 10 at 9:10

mahradbt

1389

answered Nov 10 at 9:10

mahradbt

1389

answered Nov 10 at 9:10

mahradbt

1389

add a comment |

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Pfthb