Asymmetrical [JsonInclude] behaviours for Serialization from Deserialization
I have a class with a field, whose type is List<String>.
I want to ignore empty list when serializaton so the field does not show in my json. But when deserializaton, I want it empty list will be included in my java object.@JsonInclude(Include.NON_EMPTY) will ignore it for both cases. should I write a custom serializDifferenter? What is the best approach for that?
java serialization jackson
asked Nov 14 '18 at 18:29
Carey ShiCarey Shi
33
add a comment |
I have a class with a field, whose type is List<String>.
I want to ignore empty list when serializaton so the field does not show in my json. But when deserializaton, I want it empty list will be included in my java object.@JsonInclude(Include.NON_EMPTY) will ignore it for both cases. should I write a custom serializDifferenter? What is the best approach for that?
java serialization jackson
asked Nov 14 '18 at 18:29
Carey ShiCarey Shi
33
1
i think you should go for custom serializer
– Deadpool
Nov 14 '18 at 18:51
add a comment |
I have a class with a field, whose type is List<String>.
I want to ignore empty list when serializaton so the field does not show in my json. But when deserializaton, I want it empty list will be included in my java object.@JsonInclude(Include.NON_EMPTY) will ignore it for both cases. should I write a custom serializDifferenter? What is the best approach for that?
java serialization jackson
asked Nov 14 '18 at 18:29
Carey ShiCarey Shi
33
I have a class with a field, whose type is List<String>.
I want to ignore empty list when serializaton so the field does not show in my json. But when deserializaton, I want it empty list will be included in my java object.@JsonInclude(Include.NON_EMPTY) will ignore it for both cases. should I write a custom serializDifferenter? What is the best approach for that?
java serialization jackson
java serialization jackson
asked Nov 14 '18 at 18:29
Carey ShiCarey Shi
33
asked Nov 14 '18 at 18:29
Carey ShiCarey Shi
33
edited Nov 14 '18 at 20:26
Carey Shi
asked Nov 14 '18 at 18:29
Carey ShiCarey Shi
33
asked Nov 14 '18 at 18:29
Carey ShiCarey Shi
33
asked Nov 14 '18 at 18:29
Carey ShiCarey Shi
33
33
1
i think you should go for custom serializer
– Deadpool
Nov 14 '18 at 18:51
add a comment |
1
i think you should go for custom serializer
– Deadpool
Nov 14 '18 at 18:51
1
1
i think you should go for custom serializer
– Deadpool
Nov 14 '18 at 18:51
i think you should go for custom serializer
– Deadpool
Nov 14 '18 at 18:51
add a comment |
1 Answer
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Why you don't just initialize the List<String> to an empty ArrayList<String> in the Java object, just this way:
public class JsonTestObject implements Serializable
private String propertyOne = null;
private Integer intProperty = 0;
@JsonInclude(Include.NON_EMPTY)
private List<String> stringList = new ArrayList<String>();
The serialization with an empty List will produce this kind of json:
"propertyOne":"aaaaa","intProperty":1000
And with a sinple deserialization ot this json sample, the List<String> will be initialized to an empty list
answered Nov 16 '18 at 0:13
jlumietujlumietu
3,79131526
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
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active
oldest
votes
Why you don't just initialize the List<String> to an empty ArrayList<String> in the Java object, just this way:
public class JsonTestObject implements Serializable
private String propertyOne = null;
private Integer intProperty = 0;
@JsonInclude(Include.NON_EMPTY)
private List<String> stringList = new ArrayList<String>();
The serialization with an empty List will produce this kind of json:
"propertyOne":"aaaaa","intProperty":1000
And with a sinple deserialization ot this json sample, the List<String> will be initialized to an empty list
answered Nov 16 '18 at 0:13
jlumietujlumietu
3,79131526
add a comment |
Why you don't just initialize the List<String> to an empty ArrayList<String> in the Java object, just this way:
public class JsonTestObject implements Serializable
private String propertyOne = null;
private Integer intProperty = 0;
@JsonInclude(Include.NON_EMPTY)
private List<String> stringList = new ArrayList<String>();
The serialization with an empty List will produce this kind of json:
"propertyOne":"aaaaa","intProperty":1000
And with a sinple deserialization ot this json sample, the List<String> will be initialized to an empty list
answered Nov 16 '18 at 0:13
jlumietujlumietu
3,79131526
add a comment |
Why you don't just initialize the List<String> to an empty ArrayList<String> in the Java object, just this way:
public class JsonTestObject implements Serializable
private String propertyOne = null;
private Integer intProperty = 0;
@JsonInclude(Include.NON_EMPTY)
private List<String> stringList = new ArrayList<String>();
The serialization with an empty List will produce this kind of json:
"propertyOne":"aaaaa","intProperty":1000
And with a sinple deserialization ot this json sample, the List<String> will be initialized to an empty list
answered Nov 16 '18 at 0:13
jlumietujlumietu
3,79131526
Why you don't just initialize the List<String> to an empty ArrayList<String> in the Java object, just this way:
public class JsonTestObject implements Serializable
private String propertyOne = null;
private Integer intProperty = 0;
@JsonInclude(Include.NON_EMPTY)
private List<String> stringList = new ArrayList<String>();
The serialization with an empty List will produce this kind of json:
"propertyOne":"aaaaa","intProperty":1000
And with a sinple deserialization ot this json sample, the List<String> will be initialized to an empty list
answered Nov 16 '18 at 0:13
jlumietujlumietu
3,79131526
answered Nov 16 '18 at 0:13
jlumietujlumietu
3,79131526
answered Nov 16 '18 at 0:13
jlumietujlumietu
3,79131526
answered Nov 16 '18 at 0:13
jlumietujlumietu
3,79131526
3,79131526
add a comment |
add a comment |
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1
i think you should go for custom serializer
– Deadpool
Nov 14 '18 at 18:51