R, Recursively add text from one row to another by group










2















I want to recursively add text from one row to another using information stored in another column. Below is a sample dataset:



df <- data_frame(person = c(rep("A",4),rep("B",3)),
meal = c(seq(1:4),seq(1:3)),
food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
"Lamb","Salad and meal 1","Beef"),
dependencies = c(NA,NA,2,3,NA,1,NA),
solo_meal = c(1,1,0,1,1,0,1))


Which Gives:



# A tibble: 7 x 5
person meal food dependencies solo_meal
<chr> <int> <chr> <dbl> <dbl>
1 A 1 Chicken NA 1
2 A 2 Beef NA 1
3 A 3 Soup and meal 2 2 0
4 A 4 Lamb and meal 3 3 1
5 B 1 Lamb NA 1
6 B 2 Salad and meal 1 1 0
7 B 3 Beef NA 1


I want to add a column (preferably using tidyverse) that combines the food column to look like this:



 combined_meal 
<chr>
1 Chicken
2 Beef
3 Soup and Beef
4 Lamb and Soup and Beef
5 Lamb
6 Salad and Lamb
7 Beef


I am thinking that this needs to be done recursively, but I don't know how to do that in the tidyverse (or base for that matter).



Thanks for the help!










share|improve this question




























    2















    I want to recursively add text from one row to another using information stored in another column. Below is a sample dataset:



    df <- data_frame(person = c(rep("A",4),rep("B",3)),
    meal = c(seq(1:4),seq(1:3)),
    food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
    "Lamb","Salad and meal 1","Beef"),
    dependencies = c(NA,NA,2,3,NA,1,NA),
    solo_meal = c(1,1,0,1,1,0,1))


    Which Gives:



    # A tibble: 7 x 5
    person meal food dependencies solo_meal
    <chr> <int> <chr> <dbl> <dbl>
    1 A 1 Chicken NA 1
    2 A 2 Beef NA 1
    3 A 3 Soup and meal 2 2 0
    4 A 4 Lamb and meal 3 3 1
    5 B 1 Lamb NA 1
    6 B 2 Salad and meal 1 1 0
    7 B 3 Beef NA 1


    I want to add a column (preferably using tidyverse) that combines the food column to look like this:



     combined_meal 
    <chr>
    1 Chicken
    2 Beef
    3 Soup and Beef
    4 Lamb and Soup and Beef
    5 Lamb
    6 Salad and Lamb
    7 Beef


    I am thinking that this needs to be done recursively, but I don't know how to do that in the tidyverse (or base for that matter).



    Thanks for the help!










    share|improve this question


























      2












      2








      2








      I want to recursively add text from one row to another using information stored in another column. Below is a sample dataset:



      df <- data_frame(person = c(rep("A",4),rep("B",3)),
      meal = c(seq(1:4),seq(1:3)),
      food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
      "Lamb","Salad and meal 1","Beef"),
      dependencies = c(NA,NA,2,3,NA,1,NA),
      solo_meal = c(1,1,0,1,1,0,1))


      Which Gives:



      # A tibble: 7 x 5
      person meal food dependencies solo_meal
      <chr> <int> <chr> <dbl> <dbl>
      1 A 1 Chicken NA 1
      2 A 2 Beef NA 1
      3 A 3 Soup and meal 2 2 0
      4 A 4 Lamb and meal 3 3 1
      5 B 1 Lamb NA 1
      6 B 2 Salad and meal 1 1 0
      7 B 3 Beef NA 1


      I want to add a column (preferably using tidyverse) that combines the food column to look like this:



       combined_meal 
      <chr>
      1 Chicken
      2 Beef
      3 Soup and Beef
      4 Lamb and Soup and Beef
      5 Lamb
      6 Salad and Lamb
      7 Beef


      I am thinking that this needs to be done recursively, but I don't know how to do that in the tidyverse (or base for that matter).



      Thanks for the help!










      share|improve this question
















      I want to recursively add text from one row to another using information stored in another column. Below is a sample dataset:



      df <- data_frame(person = c(rep("A",4),rep("B",3)),
      meal = c(seq(1:4),seq(1:3)),
      food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
      "Lamb","Salad and meal 1","Beef"),
      dependencies = c(NA,NA,2,3,NA,1,NA),
      solo_meal = c(1,1,0,1,1,0,1))


      Which Gives:



      # A tibble: 7 x 5
      person meal food dependencies solo_meal
      <chr> <int> <chr> <dbl> <dbl>
      1 A 1 Chicken NA 1
      2 A 2 Beef NA 1
      3 A 3 Soup and meal 2 2 0
      4 A 4 Lamb and meal 3 3 1
      5 B 1 Lamb NA 1
      6 B 2 Salad and meal 1 1 0
      7 B 3 Beef NA 1


      I want to add a column (preferably using tidyverse) that combines the food column to look like this:



       combined_meal 
      <chr>
      1 Chicken
      2 Beef
      3 Soup and Beef
      4 Lamb and Soup and Beef
      5 Lamb
      6 Salad and Lamb
      7 Beef


      I am thinking that this needs to be done recursively, but I don't know how to do that in the tidyverse (or base for that matter).



      Thanks for the help!







      r parsing tidyverse






      share|improve this question















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      share|improve this question




      share|improve this question








      edited Nov 14 '18 at 23:07







      JoeShmo

















      asked Nov 14 '18 at 16:38









      JoeShmoJoeShmo

      184




      184






















          2 Answers
          2






          active

          oldest

          votes


















          2














          Here is a solution using a while loop.



          library(dplyr)
          library(stringr)
          df <- data_frame(person = c(rep("A",4),rep("B",3)),
          meal = c(seq(1:4),seq(1:3)),
          food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
          "Lamb","Salad and meal 1","Beef"),
          dependencies = c(NA,NA,2,NA,NA,1,NA),
          solo_meal = c(1,1,0,1,1,0,1))

          df2 <- df %>% mutate(combined_meal = food)

          while(any(grepl("meal",df2$combined_meal)))
          df2 <- df2 %>%
          group_by(person) %>%
          mutate(mls = str_extract(combined_meal,"\d"),
          f = combined_meal[strtoi(mls)],
          combined_meal = str_replace(combined_meal,"meal (\d)",f)) %>%
          select(-mls,-f) %>%
          ungroup()

          df2

          #> # A tibble: 7 x 6
          #> person meal food dependencies solo_meal combined_meal
          #> <chr> <int> <chr> <dbl> <dbl> <chr>
          #> 1 A 1 Chicken NA 1 Chicken
          #> 2 A 2 Beef NA 1 Beef
          #> 3 A 3 Soup and meal 2 2 0 Soup and Beef
          #> 4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
          #> 5 B 1 Lamb NA 1 Lamb
          #> 6 B 2 Salad and meal~ 1 0 Salad and Lamb
          #> 7 B 3 Beef NA 1 Beef





          share|improve this answer
































            1














            We can try this with accumulate



            library(tidyverse)
            map_df(split(df, df$person), function(x)
            i = which(grepl('meal', x$food))
            i1 <- i[1] -1
            i2 <- i[length(i)]
            v1 <- x$food[i1:i2]
            v1 <- sub('and\s*$', "",
            sub("meal\s+\d+", "", v1)) %>%
            accumulate(., c) %>%
            map_chr(~ .x %>%
            rev %>%
            paste(., collapse = ' and '))
            x$combined_meal <- x$food
            x$combined_meal[i1:i2] <- v1
            x)
            # A tibble: 7 x 6
            # person meal food dependencies solo_meal combined_meal
            # <chr> <int> <chr> <dbl> <dbl> <chr>
            #1 A 1 Chicken NA 1 Chicken
            #2 A 2 Beef NA 1 Beef
            #3 A 3 Soup and meal 2 2 0 Soup and Beef
            #4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
            #5 B 1 Lamb NA 1 Lamb
            #6 B 2 Salad and meal 1 1 0 Salad and Lamb
            #7 B 3 Beef NA 1 Beef





            share|improve this answer
























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              2 Answers
              2






              active

              oldest

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              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              2














              Here is a solution using a while loop.



              library(dplyr)
              library(stringr)
              df <- data_frame(person = c(rep("A",4),rep("B",3)),
              meal = c(seq(1:4),seq(1:3)),
              food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
              "Lamb","Salad and meal 1","Beef"),
              dependencies = c(NA,NA,2,NA,NA,1,NA),
              solo_meal = c(1,1,0,1,1,0,1))

              df2 <- df %>% mutate(combined_meal = food)

              while(any(grepl("meal",df2$combined_meal)))
              df2 <- df2 %>%
              group_by(person) %>%
              mutate(mls = str_extract(combined_meal,"\d"),
              f = combined_meal[strtoi(mls)],
              combined_meal = str_replace(combined_meal,"meal (\d)",f)) %>%
              select(-mls,-f) %>%
              ungroup()

              df2

              #> # A tibble: 7 x 6
              #> person meal food dependencies solo_meal combined_meal
              #> <chr> <int> <chr> <dbl> <dbl> <chr>
              #> 1 A 1 Chicken NA 1 Chicken
              #> 2 A 2 Beef NA 1 Beef
              #> 3 A 3 Soup and meal 2 2 0 Soup and Beef
              #> 4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
              #> 5 B 1 Lamb NA 1 Lamb
              #> 6 B 2 Salad and meal~ 1 0 Salad and Lamb
              #> 7 B 3 Beef NA 1 Beef





              share|improve this answer





























                2














                Here is a solution using a while loop.



                library(dplyr)
                library(stringr)
                df <- data_frame(person = c(rep("A",4),rep("B",3)),
                meal = c(seq(1:4),seq(1:3)),
                food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
                "Lamb","Salad and meal 1","Beef"),
                dependencies = c(NA,NA,2,NA,NA,1,NA),
                solo_meal = c(1,1,0,1,1,0,1))

                df2 <- df %>% mutate(combined_meal = food)

                while(any(grepl("meal",df2$combined_meal)))
                df2 <- df2 %>%
                group_by(person) %>%
                mutate(mls = str_extract(combined_meal,"\d"),
                f = combined_meal[strtoi(mls)],
                combined_meal = str_replace(combined_meal,"meal (\d)",f)) %>%
                select(-mls,-f) %>%
                ungroup()

                df2

                #> # A tibble: 7 x 6
                #> person meal food dependencies solo_meal combined_meal
                #> <chr> <int> <chr> <dbl> <dbl> <chr>
                #> 1 A 1 Chicken NA 1 Chicken
                #> 2 A 2 Beef NA 1 Beef
                #> 3 A 3 Soup and meal 2 2 0 Soup and Beef
                #> 4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
                #> 5 B 1 Lamb NA 1 Lamb
                #> 6 B 2 Salad and meal~ 1 0 Salad and Lamb
                #> 7 B 3 Beef NA 1 Beef





                share|improve this answer



























                  2












                  2








                  2







                  Here is a solution using a while loop.



                  library(dplyr)
                  library(stringr)
                  df <- data_frame(person = c(rep("A",4),rep("B",3)),
                  meal = c(seq(1:4),seq(1:3)),
                  food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
                  "Lamb","Salad and meal 1","Beef"),
                  dependencies = c(NA,NA,2,NA,NA,1,NA),
                  solo_meal = c(1,1,0,1,1,0,1))

                  df2 <- df %>% mutate(combined_meal = food)

                  while(any(grepl("meal",df2$combined_meal)))
                  df2 <- df2 %>%
                  group_by(person) %>%
                  mutate(mls = str_extract(combined_meal,"\d"),
                  f = combined_meal[strtoi(mls)],
                  combined_meal = str_replace(combined_meal,"meal (\d)",f)) %>%
                  select(-mls,-f) %>%
                  ungroup()

                  df2

                  #> # A tibble: 7 x 6
                  #> person meal food dependencies solo_meal combined_meal
                  #> <chr> <int> <chr> <dbl> <dbl> <chr>
                  #> 1 A 1 Chicken NA 1 Chicken
                  #> 2 A 2 Beef NA 1 Beef
                  #> 3 A 3 Soup and meal 2 2 0 Soup and Beef
                  #> 4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
                  #> 5 B 1 Lamb NA 1 Lamb
                  #> 6 B 2 Salad and meal~ 1 0 Salad and Lamb
                  #> 7 B 3 Beef NA 1 Beef





                  share|improve this answer















                  Here is a solution using a while loop.



                  library(dplyr)
                  library(stringr)
                  df <- data_frame(person = c(rep("A",4),rep("B",3)),
                  meal = c(seq(1:4),seq(1:3)),
                  food = c("Chicken", "Beef", "Soup and meal 2", "Lamb and meal 3",
                  "Lamb","Salad and meal 1","Beef"),
                  dependencies = c(NA,NA,2,NA,NA,1,NA),
                  solo_meal = c(1,1,0,1,1,0,1))

                  df2 <- df %>% mutate(combined_meal = food)

                  while(any(grepl("meal",df2$combined_meal)))
                  df2 <- df2 %>%
                  group_by(person) %>%
                  mutate(mls = str_extract(combined_meal,"\d"),
                  f = combined_meal[strtoi(mls)],
                  combined_meal = str_replace(combined_meal,"meal (\d)",f)) %>%
                  select(-mls,-f) %>%
                  ungroup()

                  df2

                  #> # A tibble: 7 x 6
                  #> person meal food dependencies solo_meal combined_meal
                  #> <chr> <int> <chr> <dbl> <dbl> <chr>
                  #> 1 A 1 Chicken NA 1 Chicken
                  #> 2 A 2 Beef NA 1 Beef
                  #> 3 A 3 Soup and meal 2 2 0 Soup and Beef
                  #> 4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
                  #> 5 B 1 Lamb NA 1 Lamb
                  #> 6 B 2 Salad and meal~ 1 0 Salad and Lamb
                  #> 7 B 3 Beef NA 1 Beef






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 14 '18 at 17:46

























                  answered Nov 14 '18 at 17:37









                  jasbnerjasbner

                  2,026619




                  2,026619























                      1














                      We can try this with accumulate



                      library(tidyverse)
                      map_df(split(df, df$person), function(x)
                      i = which(grepl('meal', x$food))
                      i1 <- i[1] -1
                      i2 <- i[length(i)]
                      v1 <- x$food[i1:i2]
                      v1 <- sub('and\s*$', "",
                      sub("meal\s+\d+", "", v1)) %>%
                      accumulate(., c) %>%
                      map_chr(~ .x %>%
                      rev %>%
                      paste(., collapse = ' and '))
                      x$combined_meal <- x$food
                      x$combined_meal[i1:i2] <- v1
                      x)
                      # A tibble: 7 x 6
                      # person meal food dependencies solo_meal combined_meal
                      # <chr> <int> <chr> <dbl> <dbl> <chr>
                      #1 A 1 Chicken NA 1 Chicken
                      #2 A 2 Beef NA 1 Beef
                      #3 A 3 Soup and meal 2 2 0 Soup and Beef
                      #4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
                      #5 B 1 Lamb NA 1 Lamb
                      #6 B 2 Salad and meal 1 1 0 Salad and Lamb
                      #7 B 3 Beef NA 1 Beef





                      share|improve this answer





























                        1














                        We can try this with accumulate



                        library(tidyverse)
                        map_df(split(df, df$person), function(x)
                        i = which(grepl('meal', x$food))
                        i1 <- i[1] -1
                        i2 <- i[length(i)]
                        v1 <- x$food[i1:i2]
                        v1 <- sub('and\s*$', "",
                        sub("meal\s+\d+", "", v1)) %>%
                        accumulate(., c) %>%
                        map_chr(~ .x %>%
                        rev %>%
                        paste(., collapse = ' and '))
                        x$combined_meal <- x$food
                        x$combined_meal[i1:i2] <- v1
                        x)
                        # A tibble: 7 x 6
                        # person meal food dependencies solo_meal combined_meal
                        # <chr> <int> <chr> <dbl> <dbl> <chr>
                        #1 A 1 Chicken NA 1 Chicken
                        #2 A 2 Beef NA 1 Beef
                        #3 A 3 Soup and meal 2 2 0 Soup and Beef
                        #4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
                        #5 B 1 Lamb NA 1 Lamb
                        #6 B 2 Salad and meal 1 1 0 Salad and Lamb
                        #7 B 3 Beef NA 1 Beef





                        share|improve this answer



























                          1












                          1








                          1







                          We can try this with accumulate



                          library(tidyverse)
                          map_df(split(df, df$person), function(x)
                          i = which(grepl('meal', x$food))
                          i1 <- i[1] -1
                          i2 <- i[length(i)]
                          v1 <- x$food[i1:i2]
                          v1 <- sub('and\s*$', "",
                          sub("meal\s+\d+", "", v1)) %>%
                          accumulate(., c) %>%
                          map_chr(~ .x %>%
                          rev %>%
                          paste(., collapse = ' and '))
                          x$combined_meal <- x$food
                          x$combined_meal[i1:i2] <- v1
                          x)
                          # A tibble: 7 x 6
                          # person meal food dependencies solo_meal combined_meal
                          # <chr> <int> <chr> <dbl> <dbl> <chr>
                          #1 A 1 Chicken NA 1 Chicken
                          #2 A 2 Beef NA 1 Beef
                          #3 A 3 Soup and meal 2 2 0 Soup and Beef
                          #4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
                          #5 B 1 Lamb NA 1 Lamb
                          #6 B 2 Salad and meal 1 1 0 Salad and Lamb
                          #7 B 3 Beef NA 1 Beef





                          share|improve this answer















                          We can try this with accumulate



                          library(tidyverse)
                          map_df(split(df, df$person), function(x)
                          i = which(grepl('meal', x$food))
                          i1 <- i[1] -1
                          i2 <- i[length(i)]
                          v1 <- x$food[i1:i2]
                          v1 <- sub('and\s*$', "",
                          sub("meal\s+\d+", "", v1)) %>%
                          accumulate(., c) %>%
                          map_chr(~ .x %>%
                          rev %>%
                          paste(., collapse = ' and '))
                          x$combined_meal <- x$food
                          x$combined_meal[i1:i2] <- v1
                          x)
                          # A tibble: 7 x 6
                          # person meal food dependencies solo_meal combined_meal
                          # <chr> <int> <chr> <dbl> <dbl> <chr>
                          #1 A 1 Chicken NA 1 Chicken
                          #2 A 2 Beef NA 1 Beef
                          #3 A 3 Soup and meal 2 2 0 Soup and Beef
                          #4 A 4 Lamb and meal 3 NA 1 Lamb and Soup and Beef
                          #5 B 1 Lamb NA 1 Lamb
                          #6 B 2 Salad and meal 1 1 0 Salad and Lamb
                          #7 B 3 Beef NA 1 Beef






                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Nov 14 '18 at 18:17

























                          answered Nov 14 '18 at 17:36









                          akrunakrun

                          414k13202275




                          414k13202275



























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