http error 404 resource not found in spring mvc [duplicate]
-1
This question already has an answer here:
Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?
6 answers
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name> ValidationForm</display-name> <servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping>
</web-app>
index.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action="/wel" method="post">
name:<input type="text" name="name" placeholder="UserName">
<br> password:<input type="password" name="pass" placeholder="Password">
<br>
<input type="submit" value="login">
</form>
</body>
</html>
HomeController.java
package jbr.springmvc.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller public class HomeController
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req,HttpServletResponse res)
String name=req.getParameter("name");
String pass=req.getParameter("pass");
if(name.equals("mohit")&&pass.equals("admin"))
String messege="Welcome"+name;
return new ModelAndView("welcomepage","message",messege);
else
return new ModelAndView("errorpage","message","Authantication Failed");
in this this will show error 404 resource not found i really dont know what happened into this becoz i am in new on spring. please help guys.
thanks in advance.
java xml spring spring-mvc servlets
edited Nov 14 '18 at 8:11
georges van
2,29622438
asked Nov 14 '18 at 7:56
Mohit AggarwalMohit Aggarwal
13
marked as duplicate by Raedwald, BalusC java
Users with the java badge can single-handedly close java questions as duplicates and reopen them as needed.
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Nov 14 '18 at 10:08
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
-1
This question already has an answer here:
Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?
6 answers
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name> ValidationForm</display-name> <servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping>
</web-app>
index.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action="/wel" method="post">
name:<input type="text" name="name" placeholder="UserName">
<br> password:<input type="password" name="pass" placeholder="Password">
<br>
<input type="submit" value="login">
</form>
</body>
</html>
HomeController.java
package jbr.springmvc.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller public class HomeController
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req,HttpServletResponse res)
String name=req.getParameter("name");
String pass=req.getParameter("pass");
if(name.equals("mohit")&&pass.equals("admin"))
String messege="Welcome"+name;
return new ModelAndView("welcomepage","message",messege);
else
return new ModelAndView("errorpage","message","Authantication Failed");
in this this will show error 404 resource not found i really dont know what happened into this becoz i am in new on spring. please help guys.
thanks in advance.
java xml spring spring-mvc servlets
edited Nov 14 '18 at 8:11
georges van
2,29622438
asked Nov 14 '18 at 7:56
Mohit AggarwalMohit Aggarwal
13
marked as duplicate by Raedwald, BalusC java
Users with the java badge can single-handedly close java questions as duplicates and reopen them as needed.
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Nov 14 '18 at 10:08
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
You have to at least format it properly first, and provide project structure
– nguyentaijs
Nov 14 '18 at 8:10
Have you awelcomepage.jsp?
– achAmháin
Nov 14 '18 at 8:25
yeh i have welcomepage and errorpage as well
– Mohit Aggarwal
Nov 14 '18 at 8:55
add a comment |
-1
-1
-1
This question already has an answer here:
Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?
6 answers
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name> ValidationForm</display-name> <servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping>
</web-app>
index.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action="/wel" method="post">
name:<input type="text" name="name" placeholder="UserName">
<br> password:<input type="password" name="pass" placeholder="Password">
<br>
<input type="submit" value="login">
</form>
</body>
</html>
HomeController.java
package jbr.springmvc.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller public class HomeController
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req,HttpServletResponse res)
String name=req.getParameter("name");
String pass=req.getParameter("pass");
if(name.equals("mohit")&&pass.equals("admin"))
String messege="Welcome"+name;
return new ModelAndView("welcomepage","message",messege);
else
return new ModelAndView("errorpage","message","Authantication Failed");
in this this will show error 404 resource not found i really dont know what happened into this becoz i am in new on spring. please help guys.
thanks in advance.
java xml spring spring-mvc servlets
edited Nov 14 '18 at 8:11
georges van
2,29622438
asked Nov 14 '18 at 7:56
Mohit AggarwalMohit Aggarwal
13
This question already has an answer here:
Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?
6 answers
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name> ValidationForm</display-name> <servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping>
</web-app>
index.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action="/wel" method="post">
name:<input type="text" name="name" placeholder="UserName">
<br> password:<input type="password" name="pass" placeholder="Password">
<br>
<input type="submit" value="login">
</form>
</body>
</html>
HomeController.java
package jbr.springmvc.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller public class HomeController
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req,HttpServletResponse res)
String name=req.getParameter("name");
String pass=req.getParameter("pass");
if(name.equals("mohit")&&pass.equals("admin"))
String messege="Welcome"+name;
return new ModelAndView("welcomepage","message",messege);
else
return new ModelAndView("errorpage","message","Authantication Failed");
in this this will show error 404 resource not found i really dont know what happened into this becoz i am in new on spring. please help guys.
thanks in advance.
This question already has an answer here:
Why does Spring MVC respond with a 404 and report “No mapping found for HTTP request with URI […] in DispatcherServlet”?
6 answers
java xml spring spring-mvc servlets
java xml spring spring-mvc servlets
edited Nov 14 '18 at 8:11
georges van
2,29622438
asked Nov 14 '18 at 7:56
Mohit AggarwalMohit Aggarwal
13
edited Nov 14 '18 at 8:11
georges van
2,29622438
asked Nov 14 '18 at 7:56
Mohit AggarwalMohit Aggarwal
13
edited Nov 14 '18 at 8:11
georges van
2,29622438
edited Nov 14 '18 at 8:11
georges van
2,29622438
edited Nov 14 '18 at 8:11
georges van
2,29622438
2,29622438
asked Nov 14 '18 at 7:56
Mohit AggarwalMohit Aggarwal
13
asked Nov 14 '18 at 7:56
Mohit AggarwalMohit Aggarwal
13
asked Nov 14 '18 at 7:56
Mohit AggarwalMohit Aggarwal
13
13
marked as duplicate by Raedwald, BalusC java
Users with the java badge can single-handedly close java questions as duplicates and reopen them as needed.
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This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Raedwald, BalusC java
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Nov 14 '18 at 10:08
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
You have to at least format it properly first, and provide project structure
– nguyentaijs
Nov 14 '18 at 8:10
Have you awelcomepage.jsp?
– achAmháin
Nov 14 '18 at 8:25
yeh i have welcomepage and errorpage as well
– Mohit Aggarwal
Nov 14 '18 at 8:55
add a comment |
You have to at least format it properly first, and provide project structure
– nguyentaijs
Nov 14 '18 at 8:10
Have you awelcomepage.jsp?
– achAmháin
Nov 14 '18 at 8:25
yeh i have welcomepage and errorpage as well
– Mohit Aggarwal
Nov 14 '18 at 8:55
You have to at least format it properly first, and provide project structure
– nguyentaijs
Nov 14 '18 at 8:10
You have to at least format it properly first, and provide project structure
– nguyentaijs
Nov 14 '18 at 8:10
Have you a
welcomepage.jsp?– achAmháin
Nov 14 '18 at 8:25
Have you a
welcomepage.jsp?– achAmháin
Nov 14 '18 at 8:25
yeh i have welcomepage and errorpage as well
– Mohit Aggarwal
Nov 14 '18 at 8:55
yeh i have welcomepage and errorpage as well
– Mohit Aggarwal
Nov 14 '18 at 8:55
add a comment |
2 Answers
2
active
oldest
votes
-1
As i checked this code is working:
Web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Spring-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
HomeController:
package com.demo.spring.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class HomeController
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome()
return new ModelAndView("welcome");
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res)
String name = req.getParameter("name");
String pass = req.getParameter("pass");
if (name.equals("mohit") && pass.equals("admin"))
String messege = "Welcome" + name;
return new ModelAndView("welcome", "message", messege);
else
return new ModelAndView("errorpage", "message", "Authantication Failed");
Try to use it
answered Nov 14 '18 at 9:15
Ravi DeveloperRavi Developer
7819
add a comment |
-1
You need to configure your view resolver.
1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".
answered Nov 14 '18 at 9:20
Dildeep SinghDildeep Singh
447
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
-1
As i checked this code is working:
Web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Spring-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
HomeController:
package com.demo.spring.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class HomeController
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome()
return new ModelAndView("welcome");
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res)
String name = req.getParameter("name");
String pass = req.getParameter("pass");
if (name.equals("mohit") && pass.equals("admin"))
String messege = "Welcome" + name;
return new ModelAndView("welcome", "message", messege);
else
return new ModelAndView("errorpage", "message", "Authantication Failed");
Try to use it
answered Nov 14 '18 at 9:15
Ravi DeveloperRavi Developer
7819
add a comment |
-1
As i checked this code is working:
Web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Spring-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
HomeController:
package com.demo.spring.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class HomeController
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome()
return new ModelAndView("welcome");
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res)
String name = req.getParameter("name");
String pass = req.getParameter("pass");
if (name.equals("mohit") && pass.equals("admin"))
String messege = "Welcome" + name;
return new ModelAndView("welcome", "message", messege);
else
return new ModelAndView("errorpage", "message", "Authantication Failed");
Try to use it
answered Nov 14 '18 at 9:15
Ravi DeveloperRavi Developer
7819
add a comment |
-1
-1
-1
As i checked this code is working:
Web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Spring-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
HomeController:
package com.demo.spring.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class HomeController
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome()
return new ModelAndView("welcome");
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res)
String name = req.getParameter("name");
String pass = req.getParameter("pass");
if (name.equals("mohit") && pass.equals("admin"))
String messege = "Welcome" + name;
return new ModelAndView("welcome", "message", messege);
else
return new ModelAndView("errorpage", "message", "Authantication Failed");
Try to use it
answered Nov 14 '18 at 9:15
Ravi DeveloperRavi Developer
7819
As i checked this code is working:
Web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Spring-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<annotation-driven />
<context:component-scan base-package="com.demo.spring" />
<beans:bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
HomeController:
package com.demo.spring.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class HomeController
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome()
return new ModelAndView("welcome");
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res)
String name = req.getParameter("name");
String pass = req.getParameter("pass");
if (name.equals("mohit") && pass.equals("admin"))
String messege = "Welcome" + name;
return new ModelAndView("welcome", "message", messege);
else
return new ModelAndView("errorpage", "message", "Authantication Failed");
Try to use it
answered Nov 14 '18 at 9:15
Ravi DeveloperRavi Developer
7819
answered Nov 14 '18 at 9:15
Ravi DeveloperRavi Developer
7819
answered Nov 14 '18 at 9:15
Ravi DeveloperRavi Developer
7819
answered Nov 14 '18 at 9:15
Ravi DeveloperRavi Developer
7819
7819
add a comment |
add a comment |
-1
You need to configure your view resolver.
1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".
answered Nov 14 '18 at 9:20
Dildeep SinghDildeep Singh
447
add a comment |
-1
You need to configure your view resolver.
1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".
answered Nov 14 '18 at 9:20
Dildeep SinghDildeep Singh
447
add a comment |
-1
-1
-1
You need to configure your view resolver.
1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".
answered Nov 14 '18 at 9:20
Dildeep SinghDildeep Singh
447
You need to configure your view resolver.
1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".
answered Nov 14 '18 at 9:20
Dildeep SinghDildeep Singh
447
answered Nov 14 '18 at 9:20
Dildeep SinghDildeep Singh
447
answered Nov 14 '18 at 9:20
Dildeep SinghDildeep Singh
447
answered Nov 14 '18 at 9:20
Dildeep SinghDildeep Singh
447
447
add a comment |
add a comment |
You have to at least format it properly first, and provide project structure
– nguyentaijs
Nov 14 '18 at 8:10
Have you a
welcomepage.jsp?– achAmháin
Nov 14 '18 at 8:25
yeh i have welcomepage and errorpage as well
– Mohit Aggarwal
Nov 14 '18 at 8:55