Output data in a single line to a csv file



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0















How can I output data from the database in a single line to a csv file? Now it looks like this:



ID
SN
CLASS_ID


and I need as:



ID SN CLASS_ID


My code so far:



path = "C:IBSODOKexercise_1.csv"
try:
connection = cx_Oracle.connect("admin", "123", "localhost")
except cx_Oracle.DatabaseError as err:
print("Error auth", err)
cursor = connection.cursor()
cursor.execute("""
SELECT * FROM Z#PRODUCT
WHERE ROWNUM <=10
""")
with open(path, 'w', newline='') as csvfile:
writer = csv.writer(csvfile, delimiter=' ')
for column in cursor.description:
writer.writerow(''.join(column[0]))









share|improve this question



















  • 1





    Where are you fetching the output of cur.execute? I can't seem to find cur.fetchall() in your code.

    – Mayank Porwal
    Nov 15 '18 at 10:06












  • Firstly I want output column name

    – Straider
    Nov 15 '18 at 10:32

















0















How can I output data from the database in a single line to a csv file? Now it looks like this:



ID
SN
CLASS_ID


and I need as:



ID SN CLASS_ID


My code so far:



path = "C:IBSODOKexercise_1.csv"
try:
connection = cx_Oracle.connect("admin", "123", "localhost")
except cx_Oracle.DatabaseError as err:
print("Error auth", err)
cursor = connection.cursor()
cursor.execute("""
SELECT * FROM Z#PRODUCT
WHERE ROWNUM <=10
""")
with open(path, 'w', newline='') as csvfile:
writer = csv.writer(csvfile, delimiter=' ')
for column in cursor.description:
writer.writerow(''.join(column[0]))









share|improve this question



















  • 1





    Where are you fetching the output of cur.execute? I can't seem to find cur.fetchall() in your code.

    – Mayank Porwal
    Nov 15 '18 at 10:06












  • Firstly I want output column name

    – Straider
    Nov 15 '18 at 10:32













0












0








0








How can I output data from the database in a single line to a csv file? Now it looks like this:



ID
SN
CLASS_ID


and I need as:



ID SN CLASS_ID


My code so far:



path = "C:IBSODOKexercise_1.csv"
try:
connection = cx_Oracle.connect("admin", "123", "localhost")
except cx_Oracle.DatabaseError as err:
print("Error auth", err)
cursor = connection.cursor()
cursor.execute("""
SELECT * FROM Z#PRODUCT
WHERE ROWNUM <=10
""")
with open(path, 'w', newline='') as csvfile:
writer = csv.writer(csvfile, delimiter=' ')
for column in cursor.description:
writer.writerow(''.join(column[0]))









share|improve this question
















How can I output data from the database in a single line to a csv file? Now it looks like this:



ID
SN
CLASS_ID


and I need as:



ID SN CLASS_ID


My code so far:



path = "C:IBSODOKexercise_1.csv"
try:
connection = cx_Oracle.connect("admin", "123", "localhost")
except cx_Oracle.DatabaseError as err:
print("Error auth", err)
cursor = connection.cursor()
cursor.execute("""
SELECT * FROM Z#PRODUCT
WHERE ROWNUM <=10
""")
with open(path, 'w', newline='') as csvfile:
writer = csv.writer(csvfile, delimiter=' ')
for column in cursor.description:
writer.writerow(''.join(column[0]))






python-3.x cx-oracle






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share|improve this question













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edited Nov 15 '18 at 10:37









usr2564301

17.9k73373




17.9k73373










asked Nov 15 '18 at 10:00









StraiderStraider

13




13







  • 1





    Where are you fetching the output of cur.execute? I can't seem to find cur.fetchall() in your code.

    – Mayank Porwal
    Nov 15 '18 at 10:06












  • Firstly I want output column name

    – Straider
    Nov 15 '18 at 10:32












  • 1





    Where are you fetching the output of cur.execute? I can't seem to find cur.fetchall() in your code.

    – Mayank Porwal
    Nov 15 '18 at 10:06












  • Firstly I want output column name

    – Straider
    Nov 15 '18 at 10:32







1




1





Where are you fetching the output of cur.execute? I can't seem to find cur.fetchall() in your code.

– Mayank Porwal
Nov 15 '18 at 10:06






Where are you fetching the output of cur.execute? I can't seem to find cur.fetchall() in your code.

– Mayank Porwal
Nov 15 '18 at 10:06














Firstly I want output column name

– Straider
Nov 15 '18 at 10:32





Firstly I want output column name

– Straider
Nov 15 '18 at 10:32












2 Answers
2






active

oldest

votes


















0














You can usepandas.read_sql(conn, query) to read your SQL into a pandas.DataFrame and then save to file using pandas.to_csv(path)



so the code would be something like:



import pandas as pd 
path = "C:IBSODOKexercise_1.csv"
try:
connection = cx_Oracle.connect("admin", "123", "localhost")
except cx_Oracle.DatabaseError as err:
print("Error auth", err)
query = """
SELECT * FROM Z#PRODUCT
WHERE ROWNUM <=10
"""
df = pd.read_sql(connection, query)
df.to_csv(path, index= False)


Theoretically, you could likely one-line it into: pd.read_sql(connection, query).to_csv(path, index= False) but I have not tested that.






share|improve this answer






























    0














    The problem lies in



    for column in cursor.description:
    writer.writerow(''.join(column[0]))


    I assume that each column is a string, so for each column you write the results of joining, with the null string, the individual characters in the column name, e.g.:



    In [58]: ''.join('asdfe') 
    Out[58]: 'asdfe'


    and using writerow then you put a single column name on an individual row.



    What you want to do is to leave the work to writerow that is designed to put in the CSV the values contained in a, losely speaking, list:



    with open(path, 'w', newline='') as csvfile:
    writer = csv.writer(csvfile, delimiter=' ')

    writer.writerow(cursor.description)
    # other code where you process and output the query results





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      You can usepandas.read_sql(conn, query) to read your SQL into a pandas.DataFrame and then save to file using pandas.to_csv(path)



      so the code would be something like:



      import pandas as pd 
      path = "C:IBSODOKexercise_1.csv"
      try:
      connection = cx_Oracle.connect("admin", "123", "localhost")
      except cx_Oracle.DatabaseError as err:
      print("Error auth", err)
      query = """
      SELECT * FROM Z#PRODUCT
      WHERE ROWNUM <=10
      """
      df = pd.read_sql(connection, query)
      df.to_csv(path, index= False)


      Theoretically, you could likely one-line it into: pd.read_sql(connection, query).to_csv(path, index= False) but I have not tested that.






      share|improve this answer



























        0














        You can usepandas.read_sql(conn, query) to read your SQL into a pandas.DataFrame and then save to file using pandas.to_csv(path)



        so the code would be something like:



        import pandas as pd 
        path = "C:IBSODOKexercise_1.csv"
        try:
        connection = cx_Oracle.connect("admin", "123", "localhost")
        except cx_Oracle.DatabaseError as err:
        print("Error auth", err)
        query = """
        SELECT * FROM Z#PRODUCT
        WHERE ROWNUM <=10
        """
        df = pd.read_sql(connection, query)
        df.to_csv(path, index= False)


        Theoretically, you could likely one-line it into: pd.read_sql(connection, query).to_csv(path, index= False) but I have not tested that.






        share|improve this answer

























          0












          0








          0







          You can usepandas.read_sql(conn, query) to read your SQL into a pandas.DataFrame and then save to file using pandas.to_csv(path)



          so the code would be something like:



          import pandas as pd 
          path = "C:IBSODOKexercise_1.csv"
          try:
          connection = cx_Oracle.connect("admin", "123", "localhost")
          except cx_Oracle.DatabaseError as err:
          print("Error auth", err)
          query = """
          SELECT * FROM Z#PRODUCT
          WHERE ROWNUM <=10
          """
          df = pd.read_sql(connection, query)
          df.to_csv(path, index= False)


          Theoretically, you could likely one-line it into: pd.read_sql(connection, query).to_csv(path, index= False) but I have not tested that.






          share|improve this answer













          You can usepandas.read_sql(conn, query) to read your SQL into a pandas.DataFrame and then save to file using pandas.to_csv(path)



          so the code would be something like:



          import pandas as pd 
          path = "C:IBSODOKexercise_1.csv"
          try:
          connection = cx_Oracle.connect("admin", "123", "localhost")
          except cx_Oracle.DatabaseError as err:
          print("Error auth", err)
          query = """
          SELECT * FROM Z#PRODUCT
          WHERE ROWNUM <=10
          """
          df = pd.read_sql(connection, query)
          df.to_csv(path, index= False)


          Theoretically, you could likely one-line it into: pd.read_sql(connection, query).to_csv(path, index= False) but I have not tested that.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 10:10









          dozyaustindozyaustin

          14911




          14911























              0














              The problem lies in



              for column in cursor.description:
              writer.writerow(''.join(column[0]))


              I assume that each column is a string, so for each column you write the results of joining, with the null string, the individual characters in the column name, e.g.:



              In [58]: ''.join('asdfe') 
              Out[58]: 'asdfe'


              and using writerow then you put a single column name on an individual row.



              What you want to do is to leave the work to writerow that is designed to put in the CSV the values contained in a, losely speaking, list:



              with open(path, 'w', newline='') as csvfile:
              writer = csv.writer(csvfile, delimiter=' ')

              writer.writerow(cursor.description)
              # other code where you process and output the query results





              share|improve this answer



























                0














                The problem lies in



                for column in cursor.description:
                writer.writerow(''.join(column[0]))


                I assume that each column is a string, so for each column you write the results of joining, with the null string, the individual characters in the column name, e.g.:



                In [58]: ''.join('asdfe') 
                Out[58]: 'asdfe'


                and using writerow then you put a single column name on an individual row.



                What you want to do is to leave the work to writerow that is designed to put in the CSV the values contained in a, losely speaking, list:



                with open(path, 'w', newline='') as csvfile:
                writer = csv.writer(csvfile, delimiter=' ')

                writer.writerow(cursor.description)
                # other code where you process and output the query results





                share|improve this answer

























                  0












                  0








                  0







                  The problem lies in



                  for column in cursor.description:
                  writer.writerow(''.join(column[0]))


                  I assume that each column is a string, so for each column you write the results of joining, with the null string, the individual characters in the column name, e.g.:



                  In [58]: ''.join('asdfe') 
                  Out[58]: 'asdfe'


                  and using writerow then you put a single column name on an individual row.



                  What you want to do is to leave the work to writerow that is designed to put in the CSV the values contained in a, losely speaking, list:



                  with open(path, 'w', newline='') as csvfile:
                  writer = csv.writer(csvfile, delimiter=' ')

                  writer.writerow(cursor.description)
                  # other code where you process and output the query results





                  share|improve this answer













                  The problem lies in



                  for column in cursor.description:
                  writer.writerow(''.join(column[0]))


                  I assume that each column is a string, so for each column you write the results of joining, with the null string, the individual characters in the column name, e.g.:



                  In [58]: ''.join('asdfe') 
                  Out[58]: 'asdfe'


                  and using writerow then you put a single column name on an individual row.



                  What you want to do is to leave the work to writerow that is designed to put in the CSV the values contained in a, losely speaking, list:



                  with open(path, 'w', newline='') as csvfile:
                  writer = csv.writer(csvfile, delimiter=' ')

                  writer.writerow(cursor.description)
                  # other code where you process and output the query results






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 15 '18 at 10:31









                  gboffigboffi

                  9,33822558




                  9,33822558



























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