JSCalc for loop statement









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Javascript beginner



Trying to create a compound calculator, but then it only displays one row (year, investment value). How do I get the calculator to display table of investment values from year 1 to year n?






'use strict';
var ir=inputs.interestRate/100;
var yr=inputs.years;

return
returnz:[
'years' : yr,
'returnValue': inputs.value*(Math.pow((1+ir),yr))

]
;





The webpage:
https://jscalc.io/calc/OaVdNdV6sRENdT66



Thank you!










share|improve this question









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    up vote
    -1
    down vote

    favorite












    Javascript beginner



    Trying to create a compound calculator, but then it only displays one row (year, investment value). How do I get the calculator to display table of investment values from year 1 to year n?






    'use strict';
    var ir=inputs.interestRate/100;
    var yr=inputs.years;

    return
    returnz:[
    'years' : yr,
    'returnValue': inputs.value*(Math.pow((1+ir),yr))

    ]
    ;





    The webpage:
    https://jscalc.io/calc/OaVdNdV6sRENdT66



    Thank you!










    share|improve this question









    New contributor




    okay_picture is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





















      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      Javascript beginner



      Trying to create a compound calculator, but then it only displays one row (year, investment value). How do I get the calculator to display table of investment values from year 1 to year n?






      'use strict';
      var ir=inputs.interestRate/100;
      var yr=inputs.years;

      return
      returnz:[
      'years' : yr,
      'returnValue': inputs.value*(Math.pow((1+ir),yr))

      ]
      ;





      The webpage:
      https://jscalc.io/calc/OaVdNdV6sRENdT66



      Thank you!










      share|improve this question









      New contributor




      okay_picture is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Javascript beginner



      Trying to create a compound calculator, but then it only displays one row (year, investment value). How do I get the calculator to display table of investment values from year 1 to year n?






      'use strict';
      var ir=inputs.interestRate/100;
      var yr=inputs.years;

      return
      returnz:[
      'years' : yr,
      'returnValue': inputs.value*(Math.pow((1+ir),yr))

      ]
      ;





      The webpage:
      https://jscalc.io/calc/OaVdNdV6sRENdT66



      Thank you!






      'use strict';
      var ir=inputs.interestRate/100;
      var yr=inputs.years;

      return
      returnz:[
      'years' : yr,
      'returnValue': inputs.value*(Math.pow((1+ir),yr))

      ]
      ;





      'use strict';
      var ir=inputs.interestRate/100;
      var yr=inputs.years;

      return
      returnz:[
      'years' : yr,
      'returnValue': inputs.value*(Math.pow((1+ir),yr))

      ]
      ;






      javascript






      share|improve this question









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      share|improve this question









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      edited Nov 9 at 15:20





















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      asked Nov 9 at 15:11









      okay_picture

      11




      11




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          1 Answer
          1






          active

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          up vote
          0
          down vote













          The value that you're returning in returnz is a list that has only one element, containing the last year and its associated interest rate.



          You need to initialize an empty list and add each year with a for loop:



          'use strict';
          var ir=inputs.interestRate/100;
          var yr=inputs.years;

          var years = ;
          for(var year = 1; year <= yr; year++)
          years.push(
          'years' : year,
          'returnValue': inputs.value*(Math.pow((1+ir), year))
          );


          return
          returnz: years
          ;





          share|improve this answer




















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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            0
            down vote













            The value that you're returning in returnz is a list that has only one element, containing the last year and its associated interest rate.



            You need to initialize an empty list and add each year with a for loop:



            'use strict';
            var ir=inputs.interestRate/100;
            var yr=inputs.years;

            var years = ;
            for(var year = 1; year <= yr; year++)
            years.push(
            'years' : year,
            'returnValue': inputs.value*(Math.pow((1+ir), year))
            );


            return
            returnz: years
            ;





            share|improve this answer
























              up vote
              0
              down vote













              The value that you're returning in returnz is a list that has only one element, containing the last year and its associated interest rate.



              You need to initialize an empty list and add each year with a for loop:



              'use strict';
              var ir=inputs.interestRate/100;
              var yr=inputs.years;

              var years = ;
              for(var year = 1; year <= yr; year++)
              years.push(
              'years' : year,
              'returnValue': inputs.value*(Math.pow((1+ir), year))
              );


              return
              returnz: years
              ;





              share|improve this answer






















                up vote
                0
                down vote










                up vote
                0
                down vote









                The value that you're returning in returnz is a list that has only one element, containing the last year and its associated interest rate.



                You need to initialize an empty list and add each year with a for loop:



                'use strict';
                var ir=inputs.interestRate/100;
                var yr=inputs.years;

                var years = ;
                for(var year = 1; year <= yr; year++)
                years.push(
                'years' : year,
                'returnValue': inputs.value*(Math.pow((1+ir), year))
                );


                return
                returnz: years
                ;





                share|improve this answer












                The value that you're returning in returnz is a list that has only one element, containing the last year and its associated interest rate.



                You need to initialize an empty list and add each year with a for loop:



                'use strict';
                var ir=inputs.interestRate/100;
                var yr=inputs.years;

                var years = ;
                for(var year = 1; year <= yr; year++)
                years.push(
                'years' : year,
                'returnValue': inputs.value*(Math.pow((1+ir), year))
                );


                return
                returnz: years
                ;






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 9 at 15:23









                Locoluis

                54337




                54337




















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