why ridge regression with alph=0 is not the same as normal linear regression?









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In theory ridge regression with alpha=0 should have the same coefficients as linear regression but in sklearn python they are slighly different. anyone has idea why this happens? (datasets are normalized)



linear_regressor = linear_model.LinearRegression(fit_intercept=False)
linear_regressor.fit(X_train, Y_train)
y_train_prime = linear_regressor.predict(X_train)
linear_regressor_MSE = metrics.mean_squared_error(y_train_prime,Y_train)


ridge_regressor = linear_model.Ridge(alpha=0, fit_intercept=False)
ridge_regressor.fit(X_train, Y_train)
y_train_prime_ridge = ridge_regressor.predict(X_train)
ridge_regressor_MSEmetrics.mean_squared_error(y_train_prime_ridge,Y_train)









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  • 1




    Please update your question by showing what exactly are the differences; even better, use an openly available dataset and construct a minimal, complete, and verifiable example. As is, there is no much sense at showing us the commands for the MSE etc for some unknown to us dataset without sharing also the actual results...
    – desertnaut
    Nov 9 at 15:25











  • Can be (from here: scikit-learn.org/stable/modules/generated/…): solver, random_state, tol, max_iter Try firstly solver='lsqr'. And also better to add some information on how different are the weights.
    – avchauzov
    Nov 9 at 21:21














up vote
0
down vote

favorite












In theory ridge regression with alpha=0 should have the same coefficients as linear regression but in sklearn python they are slighly different. anyone has idea why this happens? (datasets are normalized)



linear_regressor = linear_model.LinearRegression(fit_intercept=False)
linear_regressor.fit(X_train, Y_train)
y_train_prime = linear_regressor.predict(X_train)
linear_regressor_MSE = metrics.mean_squared_error(y_train_prime,Y_train)


ridge_regressor = linear_model.Ridge(alpha=0, fit_intercept=False)
ridge_regressor.fit(X_train, Y_train)
y_train_prime_ridge = ridge_regressor.predict(X_train)
ridge_regressor_MSEmetrics.mean_squared_error(y_train_prime_ridge,Y_train)









share|improve this question

















  • 1




    Please update your question by showing what exactly are the differences; even better, use an openly available dataset and construct a minimal, complete, and verifiable example. As is, there is no much sense at showing us the commands for the MSE etc for some unknown to us dataset without sharing also the actual results...
    – desertnaut
    Nov 9 at 15:25











  • Can be (from here: scikit-learn.org/stable/modules/generated/…): solver, random_state, tol, max_iter Try firstly solver='lsqr'. And also better to add some information on how different are the weights.
    – avchauzov
    Nov 9 at 21:21












up vote
0
down vote

favorite









up vote
0
down vote

favorite











In theory ridge regression with alpha=0 should have the same coefficients as linear regression but in sklearn python they are slighly different. anyone has idea why this happens? (datasets are normalized)



linear_regressor = linear_model.LinearRegression(fit_intercept=False)
linear_regressor.fit(X_train, Y_train)
y_train_prime = linear_regressor.predict(X_train)
linear_regressor_MSE = metrics.mean_squared_error(y_train_prime,Y_train)


ridge_regressor = linear_model.Ridge(alpha=0, fit_intercept=False)
ridge_regressor.fit(X_train, Y_train)
y_train_prime_ridge = ridge_regressor.predict(X_train)
ridge_regressor_MSEmetrics.mean_squared_error(y_train_prime_ridge,Y_train)









share|improve this question













In theory ridge regression with alpha=0 should have the same coefficients as linear regression but in sklearn python they are slighly different. anyone has idea why this happens? (datasets are normalized)



linear_regressor = linear_model.LinearRegression(fit_intercept=False)
linear_regressor.fit(X_train, Y_train)
y_train_prime = linear_regressor.predict(X_train)
linear_regressor_MSE = metrics.mean_squared_error(y_train_prime,Y_train)


ridge_regressor = linear_model.Ridge(alpha=0, fit_intercept=False)
ridge_regressor.fit(X_train, Y_train)
y_train_prime_ridge = ridge_regressor.predict(X_train)
ridge_regressor_MSEmetrics.mean_squared_error(y_train_prime_ridge,Y_train)






machine-learning scikit-learn






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asked Nov 9 at 15:17









shahriar

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42







  • 1




    Please update your question by showing what exactly are the differences; even better, use an openly available dataset and construct a minimal, complete, and verifiable example. As is, there is no much sense at showing us the commands for the MSE etc for some unknown to us dataset without sharing also the actual results...
    – desertnaut
    Nov 9 at 15:25











  • Can be (from here: scikit-learn.org/stable/modules/generated/…): solver, random_state, tol, max_iter Try firstly solver='lsqr'. And also better to add some information on how different are the weights.
    – avchauzov
    Nov 9 at 21:21












  • 1




    Please update your question by showing what exactly are the differences; even better, use an openly available dataset and construct a minimal, complete, and verifiable example. As is, there is no much sense at showing us the commands for the MSE etc for some unknown to us dataset without sharing also the actual results...
    – desertnaut
    Nov 9 at 15:25











  • Can be (from here: scikit-learn.org/stable/modules/generated/…): solver, random_state, tol, max_iter Try firstly solver='lsqr'. And also better to add some information on how different are the weights.
    – avchauzov
    Nov 9 at 21:21







1




1




Please update your question by showing what exactly are the differences; even better, use an openly available dataset and construct a minimal, complete, and verifiable example. As is, there is no much sense at showing us the commands for the MSE etc for some unknown to us dataset without sharing also the actual results...
– desertnaut
Nov 9 at 15:25





Please update your question by showing what exactly are the differences; even better, use an openly available dataset and construct a minimal, complete, and verifiable example. As is, there is no much sense at showing us the commands for the MSE etc for some unknown to us dataset without sharing also the actual results...
– desertnaut
Nov 9 at 15:25













Can be (from here: scikit-learn.org/stable/modules/generated/…): solver, random_state, tol, max_iter Try firstly solver='lsqr'. And also better to add some information on how different are the weights.
– avchauzov
Nov 9 at 21:21




Can be (from here: scikit-learn.org/stable/modules/generated/…): solver, random_state, tol, max_iter Try firstly solver='lsqr'. And also better to add some information on how different are the weights.
– avchauzov
Nov 9 at 21:21

















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