Shell program to print the first and last parameter and their sum









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I want to make a shell program which prints out the first and the last parameter, then it prints out their sum. Here is my code, but it gives an error and doesn't work, can anybody help?



echo "How many parameters do you want?"
read param
echo "You entered $param parameters"
first = $param
last = `echo $*|cut –f$# -d" "`
sum = `$first + $last`
echo "The sum of the two parameters are $sum"









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  • What error do you get? Which line?
    – Alex
    Nov 11 at 2:29














up vote
0
down vote

favorite












I want to make a shell program which prints out the first and the last parameter, then it prints out their sum. Here is my code, but it gives an error and doesn't work, can anybody help?



echo "How many parameters do you want?"
read param
echo "You entered $param parameters"
first = $param
last = `echo $*|cut –f$# -d" "`
sum = `$first + $last`
echo "The sum of the two parameters are $sum"









share|improve this question





















  • What error do you get? Which line?
    – Alex
    Nov 11 at 2:29












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I want to make a shell program which prints out the first and the last parameter, then it prints out their sum. Here is my code, but it gives an error and doesn't work, can anybody help?



echo "How many parameters do you want?"
read param
echo "You entered $param parameters"
first = $param
last = `echo $*|cut –f$# -d" "`
sum = `$first + $last`
echo "The sum of the two parameters are $sum"









share|improve this question













I want to make a shell program which prints out the first and the last parameter, then it prints out their sum. Here is my code, but it gives an error and doesn't work, can anybody help?



echo "How many parameters do you want?"
read param
echo "You entered $param parameters"
first = $param
last = `echo $*|cut –f$# -d" "`
sum = `$first + $last`
echo "The sum of the two parameters are $sum"






shell scripting






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asked Nov 11 at 0:01









Tyler Joe

686




686











  • What error do you get? Which line?
    – Alex
    Nov 11 at 2:29
















  • What error do you get? Which line?
    – Alex
    Nov 11 at 2:29















What error do you get? Which line?
– Alex
Nov 11 at 2:29




What error do you get? Which line?
– Alex
Nov 11 at 2:29












1 Answer
1






active

oldest

votes

















up vote
0
down vote



accepted










Here is an approach for you:



first="$1"
last="$@: -1"
echo "first: $first"
echo "last: $last"
sum=$((first + last))
echo "The sum of the two parameters are $sum"


You can run like this:



./program.sh 1 2 3 4 
first: 1
last: 4
The sum of the two parameters are 5





share|improve this answer




















  • Be aware this will only work with integers.
    – kvantour
    Nov 15 at 15:37










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










Here is an approach for you:



first="$1"
last="$@: -1"
echo "first: $first"
echo "last: $last"
sum=$((first + last))
echo "The sum of the two parameters are $sum"


You can run like this:



./program.sh 1 2 3 4 
first: 1
last: 4
The sum of the two parameters are 5





share|improve this answer




















  • Be aware this will only work with integers.
    – kvantour
    Nov 15 at 15:37














up vote
0
down vote



accepted










Here is an approach for you:



first="$1"
last="$@: -1"
echo "first: $first"
echo "last: $last"
sum=$((first + last))
echo "The sum of the two parameters are $sum"


You can run like this:



./program.sh 1 2 3 4 
first: 1
last: 4
The sum of the two parameters are 5





share|improve this answer




















  • Be aware this will only work with integers.
    – kvantour
    Nov 15 at 15:37












up vote
0
down vote



accepted







up vote
0
down vote



accepted






Here is an approach for you:



first="$1"
last="$@: -1"
echo "first: $first"
echo "last: $last"
sum=$((first + last))
echo "The sum of the two parameters are $sum"


You can run like this:



./program.sh 1 2 3 4 
first: 1
last: 4
The sum of the two parameters are 5





share|improve this answer












Here is an approach for you:



first="$1"
last="$@: -1"
echo "first: $first"
echo "last: $last"
sum=$((first + last))
echo "The sum of the two parameters are $sum"


You can run like this:



./program.sh 1 2 3 4 
first: 1
last: 4
The sum of the two parameters are 5






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 11 at 3:32









sirandy

1,51731623




1,51731623











  • Be aware this will only work with integers.
    – kvantour
    Nov 15 at 15:37
















  • Be aware this will only work with integers.
    – kvantour
    Nov 15 at 15:37















Be aware this will only work with integers.
– kvantour
Nov 15 at 15:37




Be aware this will only work with integers.
– kvantour
Nov 15 at 15:37

















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