Checking a text file line by line and word by word python
-1
I have a list of words Ex: Juice, Water, Lemonade
and a text file
Lemon Lemonade Mango Curd Doggy
Dafne Cord Water Color Lemon
Powder Doggy TV Juice
I need my python program to read each word and compare to "Juice, Water, Lemonade" and per each line print
Line 1: NotAccepted(Lemon) Accepted NotAccepted(Mango) NotAccepted(Curd) NotAccepted(Doggy)
Line 2:NotAccepted(Dafne) NotAccepted(Cord) Accepted NotAccepted(Color) NotAccepted(Lemon)
Line 3:NotAccepted(Powder) NotAccepted(Doggy) NotAccepted(TV) Accepted
My current program is printing
NotAccepted(Lemon)
Accepted
NotAccepted(Mango)
NotAccepted(Curd)
with my current code:
Which
lineas = archivo.readlines()
for linea in lineas:
linea = linea.strip()
lista = linea.split()
for a in lista:
if (a == "Mango"):
print ("Aceptado", end="")
else:
print ("Denegado ("+ a + ")",end="")
python
edited Nov 11 '18 at 20:07
eyllanesc
73.7k103056
asked Nov 11 '18 at 19:39
Nick
35
add a comment |
-1
I have a list of words Ex: Juice, Water, Lemonade
and a text file
Lemon Lemonade Mango Curd Doggy
Dafne Cord Water Color Lemon
Powder Doggy TV Juice
I need my python program to read each word and compare to "Juice, Water, Lemonade" and per each line print
Line 1: NotAccepted(Lemon) Accepted NotAccepted(Mango) NotAccepted(Curd) NotAccepted(Doggy)
Line 2:NotAccepted(Dafne) NotAccepted(Cord) Accepted NotAccepted(Color) NotAccepted(Lemon)
Line 3:NotAccepted(Powder) NotAccepted(Doggy) NotAccepted(TV) Accepted
My current program is printing
NotAccepted(Lemon)
Accepted
NotAccepted(Mango)
NotAccepted(Curd)
with my current code:
Which
lineas = archivo.readlines()
for linea in lineas:
linea = linea.strip()
lista = linea.split()
for a in lista:
if (a == "Mango"):
print ("Aceptado", end="")
else:
print ("Denegado ("+ a + ")",end="")
python
edited Nov 11 '18 at 20:07
eyllanesc
73.7k103056
asked Nov 11 '18 at 19:39
Nick
35
Great list of words. What is your question?
– Willem Van Onsem
Nov 11 '18 at 19:40
add a comment |
-1
-1
-1
I have a list of words Ex: Juice, Water, Lemonade
and a text file
Lemon Lemonade Mango Curd Doggy
Dafne Cord Water Color Lemon
Powder Doggy TV Juice
I need my python program to read each word and compare to "Juice, Water, Lemonade" and per each line print
Line 1: NotAccepted(Lemon) Accepted NotAccepted(Mango) NotAccepted(Curd) NotAccepted(Doggy)
Line 2:NotAccepted(Dafne) NotAccepted(Cord) Accepted NotAccepted(Color) NotAccepted(Lemon)
Line 3:NotAccepted(Powder) NotAccepted(Doggy) NotAccepted(TV) Accepted
My current program is printing
NotAccepted(Lemon)
Accepted
NotAccepted(Mango)
NotAccepted(Curd)
with my current code:
Which
lineas = archivo.readlines()
for linea in lineas:
linea = linea.strip()
lista = linea.split()
for a in lista:
if (a == "Mango"):
print ("Aceptado", end="")
else:
print ("Denegado ("+ a + ")",end="")
python
edited Nov 11 '18 at 20:07
eyllanesc
73.7k103056
asked Nov 11 '18 at 19:39
Nick
35
I have a list of words Ex: Juice, Water, Lemonade
and a text file
Lemon Lemonade Mango Curd Doggy
Dafne Cord Water Color Lemon
Powder Doggy TV Juice
I need my python program to read each word and compare to "Juice, Water, Lemonade" and per each line print
Line 1: NotAccepted(Lemon) Accepted NotAccepted(Mango) NotAccepted(Curd) NotAccepted(Doggy)
Line 2:NotAccepted(Dafne) NotAccepted(Cord) Accepted NotAccepted(Color) NotAccepted(Lemon)
Line 3:NotAccepted(Powder) NotAccepted(Doggy) NotAccepted(TV) Accepted
My current program is printing
NotAccepted(Lemon)
Accepted
NotAccepted(Mango)
NotAccepted(Curd)
with my current code:
Which
lineas = archivo.readlines()
for linea in lineas:
linea = linea.strip()
lista = linea.split()
for a in lista:
if (a == "Mango"):
print ("Aceptado", end="")
else:
print ("Denegado ("+ a + ")",end="")
python
python
edited Nov 11 '18 at 20:07
eyllanesc
73.7k103056
asked Nov 11 '18 at 19:39
Nick
35
edited Nov 11 '18 at 20:07
eyllanesc
73.7k103056
asked Nov 11 '18 at 19:39
Nick
35
edited Nov 11 '18 at 20:07
eyllanesc
73.7k103056
edited Nov 11 '18 at 20:07
eyllanesc
73.7k103056
edited Nov 11 '18 at 20:07
eyllanesc
73.7k103056
73.7k103056
asked Nov 11 '18 at 19:39
Nick
35
asked Nov 11 '18 at 19:39
Nick
35
asked Nov 11 '18 at 19:39
Nick
35
35
Great list of words. What is your question?
– Willem Van Onsem
Nov 11 '18 at 19:40
add a comment |
Great list of words. What is your question?
– Willem Van Onsem
Nov 11 '18 at 19:40
Great list of words. What is your question?
– Willem Van Onsem
Nov 11 '18 at 19:40
Great list of words. What is your question?
– Willem Van Onsem
Nov 11 '18 at 19:40
add a comment |
1 Answer
1
active
oldest
votes
0
If I understand correctly, you want to find out if each word on a line matches with your list of pre-determined words?
for line in text_file:
for j in line.split(' '):
if j=='Juice' or j=='Water' or j=='Lemonade':
print('Accepted')
else:
print('Not accepted('+j+')')
should suffice - it'll break onto new lines every print but that's relatively easily to fix :)
answered Nov 11 '18 at 19:59
Henry
1,204517
How would I make it to print in same line ? like per Line
– Nick
Nov 11 '18 at 20:02
I got it, but if my list of Word is quite big like more than 20? will I have to do "OR" for each word?
– Nick
Nov 11 '18 at 20:09
An easy way would be to have something like a variableword_list=['a','b'....']and then checkif j in word_list. For same line printing, you could - afterfor line in text_file, haveoutput='', and then instead of usingprint, useoutput+=
– Henry
Nov 11 '18 at 20:43
If I want to put that if it starts with an quotation mark, it is correct until the end of the quotation mark Ex: Ramen Cord "Cardomologisticly correct" Rambo NotCorrect(Ramen) NotCorrect(Cord) Correct NotCorrect(Rambo)
– Nick
Nov 11 '18 at 21:13
I dont understand your question
– Henry
Nov 11 '18 at 21:14
|
show 1 more comment
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
If I understand correctly, you want to find out if each word on a line matches with your list of pre-determined words?
for line in text_file:
for j in line.split(' '):
if j=='Juice' or j=='Water' or j=='Lemonade':
print('Accepted')
else:
print('Not accepted('+j+')')
should suffice - it'll break onto new lines every print but that's relatively easily to fix :)
answered Nov 11 '18 at 19:59
Henry
1,204517
How would I make it to print in same line ? like per Line
– Nick
Nov 11 '18 at 20:02
I got it, but if my list of Word is quite big like more than 20? will I have to do "OR" for each word?
– Nick
Nov 11 '18 at 20:09
An easy way would be to have something like a variableword_list=['a','b'....']and then checkif j in word_list. For same line printing, you could - afterfor line in text_file, haveoutput='', and then instead of usingprint, useoutput+=
– Henry
Nov 11 '18 at 20:43
If I want to put that if it starts with an quotation mark, it is correct until the end of the quotation mark Ex: Ramen Cord "Cardomologisticly correct" Rambo NotCorrect(Ramen) NotCorrect(Cord) Correct NotCorrect(Rambo)
– Nick
Nov 11 '18 at 21:13
I dont understand your question
– Henry
Nov 11 '18 at 21:14
|
show 1 more comment
0
If I understand correctly, you want to find out if each word on a line matches with your list of pre-determined words?
for line in text_file:
for j in line.split(' '):
if j=='Juice' or j=='Water' or j=='Lemonade':
print('Accepted')
else:
print('Not accepted('+j+')')
should suffice - it'll break onto new lines every print but that's relatively easily to fix :)
answered Nov 11 '18 at 19:59
Henry
1,204517
How would I make it to print in same line ? like per Line
– Nick
Nov 11 '18 at 20:02
I got it, but if my list of Word is quite big like more than 20? will I have to do "OR" for each word?
– Nick
Nov 11 '18 at 20:09
An easy way would be to have something like a variableword_list=['a','b'....']and then checkif j in word_list. For same line printing, you could - afterfor line in text_file, haveoutput='', and then instead of usingprint, useoutput+=
– Henry
Nov 11 '18 at 20:43
If I want to put that if it starts with an quotation mark, it is correct until the end of the quotation mark Ex: Ramen Cord "Cardomologisticly correct" Rambo NotCorrect(Ramen) NotCorrect(Cord) Correct NotCorrect(Rambo)
– Nick
Nov 11 '18 at 21:13
I dont understand your question
– Henry
Nov 11 '18 at 21:14
|
show 1 more comment
0
0
0
If I understand correctly, you want to find out if each word on a line matches with your list of pre-determined words?
for line in text_file:
for j in line.split(' '):
if j=='Juice' or j=='Water' or j=='Lemonade':
print('Accepted')
else:
print('Not accepted('+j+')')
should suffice - it'll break onto new lines every print but that's relatively easily to fix :)
answered Nov 11 '18 at 19:59
Henry
1,204517
If I understand correctly, you want to find out if each word on a line matches with your list of pre-determined words?
for line in text_file:
for j in line.split(' '):
if j=='Juice' or j=='Water' or j=='Lemonade':
print('Accepted')
else:
print('Not accepted('+j+')')
should suffice - it'll break onto new lines every print but that's relatively easily to fix :)
answered Nov 11 '18 at 19:59
Henry
1,204517
answered Nov 11 '18 at 19:59
Henry
1,204517
answered Nov 11 '18 at 19:59
Henry
1,204517
answered Nov 11 '18 at 19:59
Henry
1,204517
1,204517
How would I make it to print in same line ? like per Line
– Nick
Nov 11 '18 at 20:02
I got it, but if my list of Word is quite big like more than 20? will I have to do "OR" for each word?
– Nick
Nov 11 '18 at 20:09
An easy way would be to have something like a variableword_list=['a','b'....']and then checkif j in word_list. For same line printing, you could - afterfor line in text_file, haveoutput='', and then instead of usingprint, useoutput+=
– Henry
Nov 11 '18 at 20:43
If I want to put that if it starts with an quotation mark, it is correct until the end of the quotation mark Ex: Ramen Cord "Cardomologisticly correct" Rambo NotCorrect(Ramen) NotCorrect(Cord) Correct NotCorrect(Rambo)
– Nick
Nov 11 '18 at 21:13
I dont understand your question
– Henry
Nov 11 '18 at 21:14
|
show 1 more comment
How would I make it to print in same line ? like per Line
– Nick
Nov 11 '18 at 20:02
I got it, but if my list of Word is quite big like more than 20? will I have to do "OR" for each word?
– Nick
Nov 11 '18 at 20:09
An easy way would be to have something like a variableword_list=['a','b'....']and then checkif j in word_list. For same line printing, you could - afterfor line in text_file, haveoutput='', and then instead of usingprint, useoutput+=
– Henry
Nov 11 '18 at 20:43
If I want to put that if it starts with an quotation mark, it is correct until the end of the quotation mark Ex: Ramen Cord "Cardomologisticly correct" Rambo NotCorrect(Ramen) NotCorrect(Cord) Correct NotCorrect(Rambo)
– Nick
Nov 11 '18 at 21:13
I dont understand your question
– Henry
Nov 11 '18 at 21:14
How would I make it to print in same line ? like per Line
– Nick
Nov 11 '18 at 20:02
How would I make it to print in same line ? like per Line
– Nick
Nov 11 '18 at 20:02
I got it, but if my list of Word is quite big like more than 20? will I have to do "OR" for each word?
– Nick
Nov 11 '18 at 20:09
I got it, but if my list of Word is quite big like more than 20? will I have to do "OR" for each word?
– Nick
Nov 11 '18 at 20:09
An easy way would be to have something like a variable
word_list=['a','b'....'] and then check if j in word_list. For same line printing, you could - after for line in text_file, have output='', and then instead of using print, use output+=– Henry
Nov 11 '18 at 20:43
An easy way would be to have something like a variable
word_list=['a','b'....'] and then check if j in word_list. For same line printing, you could - after for line in text_file, have output='', and then instead of using print, use output+=– Henry
Nov 11 '18 at 20:43
If I want to put that if it starts with an quotation mark, it is correct until the end of the quotation mark Ex: Ramen Cord "Cardomologisticly correct" Rambo NotCorrect(Ramen) NotCorrect(Cord) Correct NotCorrect(Rambo)
– Nick
Nov 11 '18 at 21:13
If I want to put that if it starts with an quotation mark, it is correct until the end of the quotation mark Ex: Ramen Cord "Cardomologisticly correct" Rambo NotCorrect(Ramen) NotCorrect(Cord) Correct NotCorrect(Rambo)
– Nick
Nov 11 '18 at 21:13
I dont understand your question
– Henry
Nov 11 '18 at 21:14
I dont understand your question
– Henry
Nov 11 '18 at 21:14
|
show 1 more comment
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Great list of words. What is your question?
– Willem Van Onsem
Nov 11 '18 at 19:40