why i get this error jq: error Cannot index array with string from json file?
i'm trying to build script that takes specific attribute value and store it in the array , this is the following JSON file:
[
"id": 1,
"name": "myna",
"description": "Simple Question",
"speaker": "USER",
,
"all_Id's": [
"11111"
],
"user": "me",
,
"id": 2,
"name": "mry",
"description": "Simple",
"speaker": "aaa",
]
as you see object in json file don't have the same attributes so i'm looking only on object has "name " attribute,the following script reads the Json file and return the values of attribute name only ,but i build something wrond as theERROR always on the "{" of the last object in file I don't know why , what i am i doing wrong?
the expected output is : [myna, mry]
#!/bin/bash
declare -a OB_I=()
declare counter1=0
jq -r '.name' file.json ; while read -r val ; do
if [[ ! $val ]]
then
OB_I[$counter]=$val ;
counter=$((counter+1));
fi
done;
$ printf '%sn' "$OB_I[@]"
bash shell jq
asked Nov 11 '18 at 20:14
reeena11
407
add a comment |
i'm trying to build script that takes specific attribute value and store it in the array , this is the following JSON file:
[
"id": 1,
"name": "myna",
"description": "Simple Question",
"speaker": "USER",
,
"all_Id's": [
"11111"
],
"user": "me",
,
"id": 2,
"name": "mry",
"description": "Simple",
"speaker": "aaa",
]
as you see object in json file don't have the same attributes so i'm looking only on object has "name " attribute,the following script reads the Json file and return the values of attribute name only ,but i build something wrond as theERROR always on the "{" of the last object in file I don't know why , what i am i doing wrong?
the expected output is : [myna, mry]
#!/bin/bash
declare -a OB_I=()
declare counter1=0
jq -r '.name' file.json ; while read -r val ; do
if [[ ! $val ]]
then
OB_I[$counter]=$val ;
counter=$((counter+1));
fi
done;
$ printf '%sn' "$OB_I[@]"
bash shell jq
asked Nov 11 '18 at 20:14
reeena11
407
1
If thewhileloop is supposed to consume the output ofjq, you want a pipe (|), not a semicolon (;) before thewhilekeyword.
– chepner
Nov 11 '18 at 20:20
The putative "JSON file" does not contain valid JSON. You could either fix it manually, or use a converter such as hjson to rectify it.
– peak
Nov 11 '18 at 23:21
See https://stackoverflow.com/help/someone-answers . You asked 23 questions, not a single one is accepted.
– c0der
Dec 16 '18 at 12:41
add a comment |
i'm trying to build script that takes specific attribute value and store it in the array , this is the following JSON file:
[
"id": 1,
"name": "myna",
"description": "Simple Question",
"speaker": "USER",
,
"all_Id's": [
"11111"
],
"user": "me",
,
"id": 2,
"name": "mry",
"description": "Simple",
"speaker": "aaa",
]
as you see object in json file don't have the same attributes so i'm looking only on object has "name " attribute,the following script reads the Json file and return the values of attribute name only ,but i build something wrond as theERROR always on the "{" of the last object in file I don't know why , what i am i doing wrong?
the expected output is : [myna, mry]
#!/bin/bash
declare -a OB_I=()
declare counter1=0
jq -r '.name' file.json ; while read -r val ; do
if [[ ! $val ]]
then
OB_I[$counter]=$val ;
counter=$((counter+1));
fi
done;
$ printf '%sn' "$OB_I[@]"
bash shell jq
asked Nov 11 '18 at 20:14
reeena11
407
i'm trying to build script that takes specific attribute value and store it in the array , this is the following JSON file:
[
"id": 1,
"name": "myna",
"description": "Simple Question",
"speaker": "USER",
,
"all_Id's": [
"11111"
],
"user": "me",
,
"id": 2,
"name": "mry",
"description": "Simple",
"speaker": "aaa",
]
as you see object in json file don't have the same attributes so i'm looking only on object has "name " attribute,the following script reads the Json file and return the values of attribute name only ,but i build something wrond as theERROR always on the "{" of the last object in file I don't know why , what i am i doing wrong?
the expected output is : [myna, mry]
#!/bin/bash
declare -a OB_I=()
declare counter1=0
jq -r '.name' file.json ; while read -r val ; do
if [[ ! $val ]]
then
OB_I[$counter]=$val ;
counter=$((counter+1));
fi
done;
$ printf '%sn' "$OB_I[@]"
bash shell jq
bash shell jq
asked Nov 11 '18 at 20:14
reeena11
407
asked Nov 11 '18 at 20:14
reeena11
407
asked Nov 11 '18 at 20:14
reeena11
407
asked Nov 11 '18 at 20:14
reeena11
407
asked Nov 11 '18 at 20:14
reeena11
407
407
1
If thewhileloop is supposed to consume the output ofjq, you want a pipe (|), not a semicolon (;) before thewhilekeyword.
– chepner
Nov 11 '18 at 20:20
The putative "JSON file" does not contain valid JSON. You could either fix it manually, or use a converter such as hjson to rectify it.
– peak
Nov 11 '18 at 23:21
See https://stackoverflow.com/help/someone-answers . You asked 23 questions, not a single one is accepted.
– c0der
Dec 16 '18 at 12:41
add a comment |
1
If thewhileloop is supposed to consume the output ofjq, you want a pipe (|), not a semicolon (;) before thewhilekeyword.
– chepner
Nov 11 '18 at 20:20
The putative "JSON file" does not contain valid JSON. You could either fix it manually, or use a converter such as hjson to rectify it.
– peak
Nov 11 '18 at 23:21
See https://stackoverflow.com/help/someone-answers . You asked 23 questions, not a single one is accepted.
– c0der
Dec 16 '18 at 12:41
1
1
If the
while loop is supposed to consume the output of jq, you want a pipe (|), not a semicolon (;) before the while keyword.– chepner
Nov 11 '18 at 20:20
If the
while loop is supposed to consume the output of jq, you want a pipe (|), not a semicolon (;) before the while keyword.– chepner
Nov 11 '18 at 20:20
The putative "JSON file" does not contain valid JSON. You could either fix it manually, or use a converter such as hjson to rectify it.
– peak
Nov 11 '18 at 23:21
The putative "JSON file" does not contain valid JSON. You could either fix it manually, or use a converter such as hjson to rectify it.
– peak
Nov 11 '18 at 23:21
See https://stackoverflow.com/help/someone-answers . You asked 23 questions, not a single one is accepted.
– c0der
Dec 16 '18 at 12:41
See https://stackoverflow.com/help/someone-answers . You asked 23 questions, not a single one is accepted.
– c0der
Dec 16 '18 at 12:41
add a comment |
1 Answer
1
active
oldest
votes
The input of jq is a list, which doesn't have any keys, let alone one named name. You want
jq -r '..name'
instead.
Unrelated, you don't need the variable counter. You can simply append to your array with OB_I+=("$val").
answered Nov 11 '18 at 20:22
chepner
244k31231323
hi , thank you for the first part of the solution , as for the second part ,i've used this method before and simply it doesn't add the value at all to the array i don't know why
– reeena11
Nov 11 '18 at 21:42
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The input of jq is a list, which doesn't have any keys, let alone one named name. You want
jq -r '..name'
instead.
Unrelated, you don't need the variable counter. You can simply append to your array with OB_I+=("$val").
answered Nov 11 '18 at 20:22
chepner
244k31231323
hi , thank you for the first part of the solution , as for the second part ,i've used this method before and simply it doesn't add the value at all to the array i don't know why
– reeena11
Nov 11 '18 at 21:42
add a comment |
The input of jq is a list, which doesn't have any keys, let alone one named name. You want
jq -r '..name'
instead.
Unrelated, you don't need the variable counter. You can simply append to your array with OB_I+=("$val").
answered Nov 11 '18 at 20:22
chepner
244k31231323
hi , thank you for the first part of the solution , as for the second part ,i've used this method before and simply it doesn't add the value at all to the array i don't know why
– reeena11
Nov 11 '18 at 21:42
add a comment |
The input of jq is a list, which doesn't have any keys, let alone one named name. You want
jq -r '..name'
instead.
Unrelated, you don't need the variable counter. You can simply append to your array with OB_I+=("$val").
answered Nov 11 '18 at 20:22
chepner
244k31231323
The input of jq is a list, which doesn't have any keys, let alone one named name. You want
jq -r '..name'
instead.
Unrelated, you don't need the variable counter. You can simply append to your array with OB_I+=("$val").
answered Nov 11 '18 at 20:22
chepner
244k31231323
answered Nov 11 '18 at 20:22
chepner
244k31231323
answered Nov 11 '18 at 20:22
chepner
244k31231323
answered Nov 11 '18 at 20:22
chepner
244k31231323
244k31231323
hi , thank you for the first part of the solution , as for the second part ,i've used this method before and simply it doesn't add the value at all to the array i don't know why
– reeena11
Nov 11 '18 at 21:42
add a comment |
hi , thank you for the first part of the solution , as for the second part ,i've used this method before and simply it doesn't add the value at all to the array i don't know why
– reeena11
Nov 11 '18 at 21:42
hi , thank you for the first part of the solution , as for the second part ,i've used this method before and simply it doesn't add the value at all to the array i don't know why
– reeena11
Nov 11 '18 at 21:42
hi , thank you for the first part of the solution , as for the second part ,i've used this method before and simply it doesn't add the value at all to the array i don't know why
– reeena11
Nov 11 '18 at 21:42
add a comment |
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1
If the
whileloop is supposed to consume the output ofjq, you want a pipe (|), not a semicolon (;) before thewhilekeyword.– chepner
Nov 11 '18 at 20:20
The putative "JSON file" does not contain valid JSON. You could either fix it manually, or use a converter such as hjson to rectify it.
– peak
Nov 11 '18 at 23:21
See https://stackoverflow.com/help/someone-answers . You asked 23 questions, not a single one is accepted.
– c0der
Dec 16 '18 at 12:41