How to print 5 random colors from an array of colors










-1














I am trying to print 5 random colors (colors can be repeated as long as they are random) from an array of 10 colors that I created. I know I'm close-ish, but I'm not sure where I'm going wrong.



import java.util.Random;

public class RandomColors

public static void main (String args)

Random r = new Random();

String colors = "red","green","blue","yellow","brown","black","white","indigo","orange","purple";
String solution = new String[5];

for(int i = 0; i < solution.length; i++)

solution[i] = colors[r.nextInt(10)];
System.out.println(i);






I know my problem is that I'm trying to print "i", but I'm not sure what I should be combining to print.










share|improve this question























  • I.ToString()???
    – AndrewE
    Nov 11 '18 at 20:11






  • 2




    Replace System.out.println(i); with System.out.println(solution[i]);
    – apandey846
    Nov 11 '18 at 20:12











  • Thank you @apandey846, that was what I needed.
    – Squanching
    Nov 11 '18 at 20:15






  • 1




    Note that even with the fixes suggested here, you're not going to get different colours.
    – Boris the Spider
    Nov 11 '18 at 20:21










  • How can they be 5 different colours if they can be repeated? I'm not sure I understand the question...
    – Boris the Spider
    Nov 11 '18 at 20:33















-1














I am trying to print 5 random colors (colors can be repeated as long as they are random) from an array of 10 colors that I created. I know I'm close-ish, but I'm not sure where I'm going wrong.



import java.util.Random;

public class RandomColors

public static void main (String args)

Random r = new Random();

String colors = "red","green","blue","yellow","brown","black","white","indigo","orange","purple";
String solution = new String[5];

for(int i = 0; i < solution.length; i++)

solution[i] = colors[r.nextInt(10)];
System.out.println(i);






I know my problem is that I'm trying to print "i", but I'm not sure what I should be combining to print.










share|improve this question























  • I.ToString()???
    – AndrewE
    Nov 11 '18 at 20:11






  • 2




    Replace System.out.println(i); with System.out.println(solution[i]);
    – apandey846
    Nov 11 '18 at 20:12











  • Thank you @apandey846, that was what I needed.
    – Squanching
    Nov 11 '18 at 20:15






  • 1




    Note that even with the fixes suggested here, you're not going to get different colours.
    – Boris the Spider
    Nov 11 '18 at 20:21










  • How can they be 5 different colours if they can be repeated? I'm not sure I understand the question...
    – Boris the Spider
    Nov 11 '18 at 20:33













-1












-1








-1







I am trying to print 5 random colors (colors can be repeated as long as they are random) from an array of 10 colors that I created. I know I'm close-ish, but I'm not sure where I'm going wrong.



import java.util.Random;

public class RandomColors

public static void main (String args)

Random r = new Random();

String colors = "red","green","blue","yellow","brown","black","white","indigo","orange","purple";
String solution = new String[5];

for(int i = 0; i < solution.length; i++)

solution[i] = colors[r.nextInt(10)];
System.out.println(i);






I know my problem is that I'm trying to print "i", but I'm not sure what I should be combining to print.










share|improve this question















I am trying to print 5 random colors (colors can be repeated as long as they are random) from an array of 10 colors that I created. I know I'm close-ish, but I'm not sure where I'm going wrong.



import java.util.Random;

public class RandomColors

public static void main (String args)

Random r = new Random();

String colors = "red","green","blue","yellow","brown","black","white","indigo","orange","purple";
String solution = new String[5];

for(int i = 0; i < solution.length; i++)

solution[i] = colors[r.nextInt(10)];
System.out.println(i);






I know my problem is that I'm trying to print "i", but I'm not sure what I should be combining to print.







java






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 11 '18 at 20:44

























asked Nov 11 '18 at 20:07









Squanching

205




205











  • I.ToString()???
    – AndrewE
    Nov 11 '18 at 20:11






  • 2




    Replace System.out.println(i); with System.out.println(solution[i]);
    – apandey846
    Nov 11 '18 at 20:12











  • Thank you @apandey846, that was what I needed.
    – Squanching
    Nov 11 '18 at 20:15






  • 1




    Note that even with the fixes suggested here, you're not going to get different colours.
    – Boris the Spider
    Nov 11 '18 at 20:21










  • How can they be 5 different colours if they can be repeated? I'm not sure I understand the question...
    – Boris the Spider
    Nov 11 '18 at 20:33
















  • I.ToString()???
    – AndrewE
    Nov 11 '18 at 20:11






  • 2




    Replace System.out.println(i); with System.out.println(solution[i]);
    – apandey846
    Nov 11 '18 at 20:12











  • Thank you @apandey846, that was what I needed.
    – Squanching
    Nov 11 '18 at 20:15






  • 1




    Note that even with the fixes suggested here, you're not going to get different colours.
    – Boris the Spider
    Nov 11 '18 at 20:21










  • How can they be 5 different colours if they can be repeated? I'm not sure I understand the question...
    – Boris the Spider
    Nov 11 '18 at 20:33















I.ToString()???
– AndrewE
Nov 11 '18 at 20:11




I.ToString()???
– AndrewE
Nov 11 '18 at 20:11




2




2




Replace System.out.println(i); with System.out.println(solution[i]);
– apandey846
Nov 11 '18 at 20:12





Replace System.out.println(i); with System.out.println(solution[i]);
– apandey846
Nov 11 '18 at 20:12













Thank you @apandey846, that was what I needed.
– Squanching
Nov 11 '18 at 20:15




Thank you @apandey846, that was what I needed.
– Squanching
Nov 11 '18 at 20:15




1




1




Note that even with the fixes suggested here, you're not going to get different colours.
– Boris the Spider
Nov 11 '18 at 20:21




Note that even with the fixes suggested here, you're not going to get different colours.
– Boris the Spider
Nov 11 '18 at 20:21












How can they be 5 different colours if they can be repeated? I'm not sure I understand the question...
– Boris the Spider
Nov 11 '18 at 20:33




How can they be 5 different colours if they can be repeated? I'm not sure I understand the question...
– Boris the Spider
Nov 11 '18 at 20:33












3 Answers
3






active

oldest

votes


















1














Just Replace




System.out.println(i);




with




System.out.println(solution[i]);







share|improve this answer




























    5














    You have a problem that your algorithm might return the same color several times (r.nextInt(10) can return the same value multiple times).



    A more straightforward solution could be to convert the array to a list, shuffle it (this is the "random" part), and print the first 5 elements:



    List<String> colorsList = Arrays.asList(colors);
    Collections.shuffle(colorsList);
    colorsList.stream().limit(5).forEach(System.out::println);



    Since the question was edited to say that non-unique colors are allowed, they can be printed like this:



    IntStream.generate(() -> r.nextInt(colors.length))
    .limit(5)
    .mapToObj(i -> colors[i])
    .forEach(System.out::println);


    This generates a stream of 5 random integers, and prints the elements by accessing the array.






    share|improve this answer


















    • 1




      This is the only correct answer here.
      – Boris the Spider
      Nov 11 '18 at 20:26










    • It's okay if it returns the same color multiple times, as long as the results are random. I do see what you are saying though. Thank you.
      – Squanching
      Nov 11 '18 at 20:28






    • 3




      Well, your question says "5 different random colors".
      – Magnilex
      Nov 11 '18 at 20:29










    • I realized that after you answered my question. I edited my post. Sorry about that.
      – Squanching
      Nov 11 '18 at 20:30


















    2














    Simply print solution[i] instead of i:



    System.out.println(solution[i]);





    share|improve this answer




















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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      Just Replace




      System.out.println(i);




      with




      System.out.println(solution[i]);







      share|improve this answer

























        1














        Just Replace




        System.out.println(i);




        with




        System.out.println(solution[i]);







        share|improve this answer























          1












          1








          1






          Just Replace




          System.out.println(i);




          with




          System.out.println(solution[i]);







          share|improve this answer












          Just Replace




          System.out.println(i);




          with




          System.out.println(solution[i]);








          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 11 '18 at 20:18









          apandey846

          8441019




          8441019























              5














              You have a problem that your algorithm might return the same color several times (r.nextInt(10) can return the same value multiple times).



              A more straightforward solution could be to convert the array to a list, shuffle it (this is the "random" part), and print the first 5 elements:



              List<String> colorsList = Arrays.asList(colors);
              Collections.shuffle(colorsList);
              colorsList.stream().limit(5).forEach(System.out::println);



              Since the question was edited to say that non-unique colors are allowed, they can be printed like this:



              IntStream.generate(() -> r.nextInt(colors.length))
              .limit(5)
              .mapToObj(i -> colors[i])
              .forEach(System.out::println);


              This generates a stream of 5 random integers, and prints the elements by accessing the array.






              share|improve this answer


















              • 1




                This is the only correct answer here.
                – Boris the Spider
                Nov 11 '18 at 20:26










              • It's okay if it returns the same color multiple times, as long as the results are random. I do see what you are saying though. Thank you.
                – Squanching
                Nov 11 '18 at 20:28






              • 3




                Well, your question says "5 different random colors".
                – Magnilex
                Nov 11 '18 at 20:29










              • I realized that after you answered my question. I edited my post. Sorry about that.
                – Squanching
                Nov 11 '18 at 20:30















              5














              You have a problem that your algorithm might return the same color several times (r.nextInt(10) can return the same value multiple times).



              A more straightforward solution could be to convert the array to a list, shuffle it (this is the "random" part), and print the first 5 elements:



              List<String> colorsList = Arrays.asList(colors);
              Collections.shuffle(colorsList);
              colorsList.stream().limit(5).forEach(System.out::println);



              Since the question was edited to say that non-unique colors are allowed, they can be printed like this:



              IntStream.generate(() -> r.nextInt(colors.length))
              .limit(5)
              .mapToObj(i -> colors[i])
              .forEach(System.out::println);


              This generates a stream of 5 random integers, and prints the elements by accessing the array.






              share|improve this answer


















              • 1




                This is the only correct answer here.
                – Boris the Spider
                Nov 11 '18 at 20:26










              • It's okay if it returns the same color multiple times, as long as the results are random. I do see what you are saying though. Thank you.
                – Squanching
                Nov 11 '18 at 20:28






              • 3




                Well, your question says "5 different random colors".
                – Magnilex
                Nov 11 '18 at 20:29










              • I realized that after you answered my question. I edited my post. Sorry about that.
                – Squanching
                Nov 11 '18 at 20:30













              5












              5








              5






              You have a problem that your algorithm might return the same color several times (r.nextInt(10) can return the same value multiple times).



              A more straightforward solution could be to convert the array to a list, shuffle it (this is the "random" part), and print the first 5 elements:



              List<String> colorsList = Arrays.asList(colors);
              Collections.shuffle(colorsList);
              colorsList.stream().limit(5).forEach(System.out::println);



              Since the question was edited to say that non-unique colors are allowed, they can be printed like this:



              IntStream.generate(() -> r.nextInt(colors.length))
              .limit(5)
              .mapToObj(i -> colors[i])
              .forEach(System.out::println);


              This generates a stream of 5 random integers, and prints the elements by accessing the array.






              share|improve this answer














              You have a problem that your algorithm might return the same color several times (r.nextInt(10) can return the same value multiple times).



              A more straightforward solution could be to convert the array to a list, shuffle it (this is the "random" part), and print the first 5 elements:



              List<String> colorsList = Arrays.asList(colors);
              Collections.shuffle(colorsList);
              colorsList.stream().limit(5).forEach(System.out::println);



              Since the question was edited to say that non-unique colors are allowed, they can be printed like this:



              IntStream.generate(() -> r.nextInt(colors.length))
              .limit(5)
              .mapToObj(i -> colors[i])
              .forEach(System.out::println);


              This generates a stream of 5 random integers, and prints the elements by accessing the array.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 11 '18 at 20:36

























              answered Nov 11 '18 at 20:22









              Magnilex

              7,03763459




              7,03763459







              • 1




                This is the only correct answer here.
                – Boris the Spider
                Nov 11 '18 at 20:26










              • It's okay if it returns the same color multiple times, as long as the results are random. I do see what you are saying though. Thank you.
                – Squanching
                Nov 11 '18 at 20:28






              • 3




                Well, your question says "5 different random colors".
                – Magnilex
                Nov 11 '18 at 20:29










              • I realized that after you answered my question. I edited my post. Sorry about that.
                – Squanching
                Nov 11 '18 at 20:30












              • 1




                This is the only correct answer here.
                – Boris the Spider
                Nov 11 '18 at 20:26










              • It's okay if it returns the same color multiple times, as long as the results are random. I do see what you are saying though. Thank you.
                – Squanching
                Nov 11 '18 at 20:28






              • 3




                Well, your question says "5 different random colors".
                – Magnilex
                Nov 11 '18 at 20:29










              • I realized that after you answered my question. I edited my post. Sorry about that.
                – Squanching
                Nov 11 '18 at 20:30







              1




              1




              This is the only correct answer here.
              – Boris the Spider
              Nov 11 '18 at 20:26




              This is the only correct answer here.
              – Boris the Spider
              Nov 11 '18 at 20:26












              It's okay if it returns the same color multiple times, as long as the results are random. I do see what you are saying though. Thank you.
              – Squanching
              Nov 11 '18 at 20:28




              It's okay if it returns the same color multiple times, as long as the results are random. I do see what you are saying though. Thank you.
              – Squanching
              Nov 11 '18 at 20:28




              3




              3




              Well, your question says "5 different random colors".
              – Magnilex
              Nov 11 '18 at 20:29




              Well, your question says "5 different random colors".
              – Magnilex
              Nov 11 '18 at 20:29












              I realized that after you answered my question. I edited my post. Sorry about that.
              – Squanching
              Nov 11 '18 at 20:30




              I realized that after you answered my question. I edited my post. Sorry about that.
              – Squanching
              Nov 11 '18 at 20:30











              2














              Simply print solution[i] instead of i:



              System.out.println(solution[i]);





              share|improve this answer

























                2














                Simply print solution[i] instead of i:



                System.out.println(solution[i]);





                share|improve this answer























                  2












                  2








                  2






                  Simply print solution[i] instead of i:



                  System.out.println(solution[i]);





                  share|improve this answer












                  Simply print solution[i] instead of i:



                  System.out.println(solution[i]);






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 11 '18 at 20:16









                  Rene Knop

                  1,3463622




                  1,3463622



























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