Matplotlib 3d: Surface is seen through scattered points despite alpha=1










0















I'm trying to display 3d points and corresponding linear regression plane. But depending on the angle, some points are either seen clearly, or I see surface through them, or I don't see them at all, despite them being at the upper side of the wireframe. Unfortunately, I can't append more images... What can I do to make points completely non-transparent and visible from any angle, where they are closer to the "cam"?



There is some corresponding code:



def display_points(ax:Axes3D, X):

edu, seniority, income = X.T
s = ax.scatter(edu, seniority, income, c='red', alpha=1, depthshade=False)
s.set_edgecolors = s.set_facecolors = lambda *args: None

def display_predictions(ax:Axes3D, xx1, xx2, model):
X_grid = np.column_stack((xx1.ravel(), xx2.ravel()))

zz = model.predict(X_grid).reshape(xx1.shape)
ax.plot_wireframe(xx1, xx2, zz, alpha=1)

def display_perpendiculars(ax:Axes3D, X, y_true, y_pred):
for x_row, y_t, y_p in zip(X, y_true, y_pred):
x1, x2 = x_row
ax.plot(xs=[x1, x1], ys=[x2, x2], zs=[y_t, y_p], color='black', alpha=0.5)


Image










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  • 1





    this FAQ is probably relevant matplotlib.org/mpl_toolkits/mplot3d/…

    – Diziet Asahi
    Nov 12 '18 at 13:30















0















I'm trying to display 3d points and corresponding linear regression plane. But depending on the angle, some points are either seen clearly, or I see surface through them, or I don't see them at all, despite them being at the upper side of the wireframe. Unfortunately, I can't append more images... What can I do to make points completely non-transparent and visible from any angle, where they are closer to the "cam"?



There is some corresponding code:



def display_points(ax:Axes3D, X):

edu, seniority, income = X.T
s = ax.scatter(edu, seniority, income, c='red', alpha=1, depthshade=False)
s.set_edgecolors = s.set_facecolors = lambda *args: None

def display_predictions(ax:Axes3D, xx1, xx2, model):
X_grid = np.column_stack((xx1.ravel(), xx2.ravel()))

zz = model.predict(X_grid).reshape(xx1.shape)
ax.plot_wireframe(xx1, xx2, zz, alpha=1)

def display_perpendiculars(ax:Axes3D, X, y_true, y_pred):
for x_row, y_t, y_p in zip(X, y_true, y_pred):
x1, x2 = x_row
ax.plot(xs=[x1, x1], ys=[x2, x2], zs=[y_t, y_p], color='black', alpha=0.5)


Image










share|improve this question



















  • 1





    this FAQ is probably relevant matplotlib.org/mpl_toolkits/mplot3d/…

    – Diziet Asahi
    Nov 12 '18 at 13:30













0












0








0








I'm trying to display 3d points and corresponding linear regression plane. But depending on the angle, some points are either seen clearly, or I see surface through them, or I don't see them at all, despite them being at the upper side of the wireframe. Unfortunately, I can't append more images... What can I do to make points completely non-transparent and visible from any angle, where they are closer to the "cam"?



There is some corresponding code:



def display_points(ax:Axes3D, X):

edu, seniority, income = X.T
s = ax.scatter(edu, seniority, income, c='red', alpha=1, depthshade=False)
s.set_edgecolors = s.set_facecolors = lambda *args: None

def display_predictions(ax:Axes3D, xx1, xx2, model):
X_grid = np.column_stack((xx1.ravel(), xx2.ravel()))

zz = model.predict(X_grid).reshape(xx1.shape)
ax.plot_wireframe(xx1, xx2, zz, alpha=1)

def display_perpendiculars(ax:Axes3D, X, y_true, y_pred):
for x_row, y_t, y_p in zip(X, y_true, y_pred):
x1, x2 = x_row
ax.plot(xs=[x1, x1], ys=[x2, x2], zs=[y_t, y_p], color='black', alpha=0.5)


Image










share|improve this question
















I'm trying to display 3d points and corresponding linear regression plane. But depending on the angle, some points are either seen clearly, or I see surface through them, or I don't see them at all, despite them being at the upper side of the wireframe. Unfortunately, I can't append more images... What can I do to make points completely non-transparent and visible from any angle, where they are closer to the "cam"?



There is some corresponding code:



def display_points(ax:Axes3D, X):

edu, seniority, income = X.T
s = ax.scatter(edu, seniority, income, c='red', alpha=1, depthshade=False)
s.set_edgecolors = s.set_facecolors = lambda *args: None

def display_predictions(ax:Axes3D, xx1, xx2, model):
X_grid = np.column_stack((xx1.ravel(), xx2.ravel()))

zz = model.predict(X_grid).reshape(xx1.shape)
ax.plot_wireframe(xx1, xx2, zz, alpha=1)

def display_perpendiculars(ax:Axes3D, X, y_true, y_pred):
for x_row, y_t, y_p in zip(X, y_true, y_pred):
x1, x2 = x_row
ax.plot(xs=[x1, x1], ys=[x2, x2], zs=[y_t, y_p], color='black', alpha=0.5)


Image







matplotlib 3d opacity scatter wireframe






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edited Nov 12 '18 at 12:55







Ivan Lazarevsky

















asked Nov 12 '18 at 12:49









Ivan LazarevskyIvan Lazarevsky

111




111







  • 1





    this FAQ is probably relevant matplotlib.org/mpl_toolkits/mplot3d/…

    – Diziet Asahi
    Nov 12 '18 at 13:30












  • 1





    this FAQ is probably relevant matplotlib.org/mpl_toolkits/mplot3d/…

    – Diziet Asahi
    Nov 12 '18 at 13:30







1




1





this FAQ is probably relevant matplotlib.org/mpl_toolkits/mplot3d/…

– Diziet Asahi
Nov 12 '18 at 13:30





this FAQ is probably relevant matplotlib.org/mpl_toolkits/mplot3d/…

– Diziet Asahi
Nov 12 '18 at 13:30












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