Matplotlib: Missing channel using imread










0















When I try to load an image that has three channels with matplotlib it only has one channel when I issue the numpy shape command. This shows the following image:



One channel image with matplotlib



Here is the code I used:



import matplotlib.pyplot as plt
import matplotlib.image as mpimg
import numpy as np

img = mpimg.imread('dolphin.png')
plt.imshow(img)
plt.show()

img.shape
(320, 500)


I also followed the matplotlib image tutorial which uses the same commands as above.



Loading the image with opencv the result is an image with three channels, as expected.



import cv2
imgcv = cv2.imread('dolphin.png')
plt.imshow(imgcv)
plt.show()

imgcv.shape
(320, 500, 3)


Three channel image with cv2



I am using Python 3.5.6 with anaconda.



Here is a short output of the conda list command:



...
matplotlib 3.0.0
...
opencv3 3.1.0
...
pillow 5.2.0
...


The original image I used:



Original dolphin image



Am I missing a package or is there another command to load a *.png file? Everything seems to work with *.jpg images










share|improve this question
























  • dolphin.png is a grey scale image with a single channel. Is your question how to duplicate those channels to have a grey RGB image?

    – ImportanceOfBeingErnest
    Nov 14 '18 at 21:16











  • No it has three channels. Please look at the output of imgcv.shape. It is (320, 500, 3)

    – evolved
    Nov 14 '18 at 21:17











  • There seems to be something wrong with the imread command of matplotlib (or how I use it) as it results in an image with only one channel. img.shape yields (320, 500)

    – evolved
    Nov 14 '18 at 21:21











  • So you mean cv2.imread is more trustworthy than plt.imread? I guess we can find out if you provide the original image.

    – ImportanceOfBeingErnest
    Nov 14 '18 at 21:35











  • Yes, thats what I see as a result. However, I expect that plt.imread also results in a numpy array with three channels. Thanks for your help, I provided the original image. I also tested with the png image from the matplotlib tutorial: matplotlib.org/_images/stinkbug.png which is also missing two channels when reading with plt.imread

    – evolved
    Nov 14 '18 at 21:50
















0















When I try to load an image that has three channels with matplotlib it only has one channel when I issue the numpy shape command. This shows the following image:



One channel image with matplotlib



Here is the code I used:



import matplotlib.pyplot as plt
import matplotlib.image as mpimg
import numpy as np

img = mpimg.imread('dolphin.png')
plt.imshow(img)
plt.show()

img.shape
(320, 500)


I also followed the matplotlib image tutorial which uses the same commands as above.



Loading the image with opencv the result is an image with three channels, as expected.



import cv2
imgcv = cv2.imread('dolphin.png')
plt.imshow(imgcv)
plt.show()

imgcv.shape
(320, 500, 3)


Three channel image with cv2



I am using Python 3.5.6 with anaconda.



Here is a short output of the conda list command:



...
matplotlib 3.0.0
...
opencv3 3.1.0
...
pillow 5.2.0
...


The original image I used:



Original dolphin image



Am I missing a package or is there another command to load a *.png file? Everything seems to work with *.jpg images










share|improve this question
























  • dolphin.png is a grey scale image with a single channel. Is your question how to duplicate those channels to have a grey RGB image?

    – ImportanceOfBeingErnest
    Nov 14 '18 at 21:16











  • No it has three channels. Please look at the output of imgcv.shape. It is (320, 500, 3)

    – evolved
    Nov 14 '18 at 21:17











  • There seems to be something wrong with the imread command of matplotlib (or how I use it) as it results in an image with only one channel. img.shape yields (320, 500)

    – evolved
    Nov 14 '18 at 21:21











  • So you mean cv2.imread is more trustworthy than plt.imread? I guess we can find out if you provide the original image.

    – ImportanceOfBeingErnest
    Nov 14 '18 at 21:35











  • Yes, thats what I see as a result. However, I expect that plt.imread also results in a numpy array with three channels. Thanks for your help, I provided the original image. I also tested with the png image from the matplotlib tutorial: matplotlib.org/_images/stinkbug.png which is also missing two channels when reading with plt.imread

    – evolved
    Nov 14 '18 at 21:50














0












0








0








When I try to load an image that has three channels with matplotlib it only has one channel when I issue the numpy shape command. This shows the following image:



One channel image with matplotlib



Here is the code I used:



import matplotlib.pyplot as plt
import matplotlib.image as mpimg
import numpy as np

img = mpimg.imread('dolphin.png')
plt.imshow(img)
plt.show()

img.shape
(320, 500)


I also followed the matplotlib image tutorial which uses the same commands as above.



Loading the image with opencv the result is an image with three channels, as expected.



import cv2
imgcv = cv2.imread('dolphin.png')
plt.imshow(imgcv)
plt.show()

imgcv.shape
(320, 500, 3)


Three channel image with cv2



I am using Python 3.5.6 with anaconda.



Here is a short output of the conda list command:



...
matplotlib 3.0.0
...
opencv3 3.1.0
...
pillow 5.2.0
...


The original image I used:



Original dolphin image



Am I missing a package or is there another command to load a *.png file? Everything seems to work with *.jpg images










share|improve this question
















When I try to load an image that has three channels with matplotlib it only has one channel when I issue the numpy shape command. This shows the following image:



One channel image with matplotlib



Here is the code I used:



import matplotlib.pyplot as plt
import matplotlib.image as mpimg
import numpy as np

img = mpimg.imread('dolphin.png')
plt.imshow(img)
plt.show()

img.shape
(320, 500)


I also followed the matplotlib image tutorial which uses the same commands as above.



Loading the image with opencv the result is an image with three channels, as expected.



import cv2
imgcv = cv2.imread('dolphin.png')
plt.imshow(imgcv)
plt.show()

imgcv.shape
(320, 500, 3)


Three channel image with cv2



I am using Python 3.5.6 with anaconda.



Here is a short output of the conda list command:



...
matplotlib 3.0.0
...
opencv3 3.1.0
...
pillow 5.2.0
...


The original image I used:



Original dolphin image



Am I missing a package or is there another command to load a *.png file? Everything seems to work with *.jpg images







python matplotlib png jpeg imread






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 21:48







evolved

















asked Nov 14 '18 at 21:12









evolvedevolved

397519




397519












  • dolphin.png is a grey scale image with a single channel. Is your question how to duplicate those channels to have a grey RGB image?

    – ImportanceOfBeingErnest
    Nov 14 '18 at 21:16











  • No it has three channels. Please look at the output of imgcv.shape. It is (320, 500, 3)

    – evolved
    Nov 14 '18 at 21:17











  • There seems to be something wrong with the imread command of matplotlib (or how I use it) as it results in an image with only one channel. img.shape yields (320, 500)

    – evolved
    Nov 14 '18 at 21:21











  • So you mean cv2.imread is more trustworthy than plt.imread? I guess we can find out if you provide the original image.

    – ImportanceOfBeingErnest
    Nov 14 '18 at 21:35











  • Yes, thats what I see as a result. However, I expect that plt.imread also results in a numpy array with three channels. Thanks for your help, I provided the original image. I also tested with the png image from the matplotlib tutorial: matplotlib.org/_images/stinkbug.png which is also missing two channels when reading with plt.imread

    – evolved
    Nov 14 '18 at 21:50


















  • dolphin.png is a grey scale image with a single channel. Is your question how to duplicate those channels to have a grey RGB image?

    – ImportanceOfBeingErnest
    Nov 14 '18 at 21:16











  • No it has three channels. Please look at the output of imgcv.shape. It is (320, 500, 3)

    – evolved
    Nov 14 '18 at 21:17











  • There seems to be something wrong with the imread command of matplotlib (or how I use it) as it results in an image with only one channel. img.shape yields (320, 500)

    – evolved
    Nov 14 '18 at 21:21











  • So you mean cv2.imread is more trustworthy than plt.imread? I guess we can find out if you provide the original image.

    – ImportanceOfBeingErnest
    Nov 14 '18 at 21:35











  • Yes, thats what I see as a result. However, I expect that plt.imread also results in a numpy array with three channels. Thanks for your help, I provided the original image. I also tested with the png image from the matplotlib tutorial: matplotlib.org/_images/stinkbug.png which is also missing two channels when reading with plt.imread

    – evolved
    Nov 14 '18 at 21:50

















dolphin.png is a grey scale image with a single channel. Is your question how to duplicate those channels to have a grey RGB image?

– ImportanceOfBeingErnest
Nov 14 '18 at 21:16





dolphin.png is a grey scale image with a single channel. Is your question how to duplicate those channels to have a grey RGB image?

– ImportanceOfBeingErnest
Nov 14 '18 at 21:16













No it has three channels. Please look at the output of imgcv.shape. It is (320, 500, 3)

– evolved
Nov 14 '18 at 21:17





No it has three channels. Please look at the output of imgcv.shape. It is (320, 500, 3)

– evolved
Nov 14 '18 at 21:17













There seems to be something wrong with the imread command of matplotlib (or how I use it) as it results in an image with only one channel. img.shape yields (320, 500)

– evolved
Nov 14 '18 at 21:21





There seems to be something wrong with the imread command of matplotlib (or how I use it) as it results in an image with only one channel. img.shape yields (320, 500)

– evolved
Nov 14 '18 at 21:21













So you mean cv2.imread is more trustworthy than plt.imread? I guess we can find out if you provide the original image.

– ImportanceOfBeingErnest
Nov 14 '18 at 21:35





So you mean cv2.imread is more trustworthy than plt.imread? I guess we can find out if you provide the original image.

– ImportanceOfBeingErnest
Nov 14 '18 at 21:35













Yes, thats what I see as a result. However, I expect that plt.imread also results in a numpy array with three channels. Thanks for your help, I provided the original image. I also tested with the png image from the matplotlib tutorial: matplotlib.org/_images/stinkbug.png which is also missing two channels when reading with plt.imread

– evolved
Nov 14 '18 at 21:50






Yes, thats what I see as a result. However, I expect that plt.imread also results in a numpy array with three channels. Thanks for your help, I provided the original image. I also tested with the png image from the matplotlib tutorial: matplotlib.org/_images/stinkbug.png which is also missing two channels when reading with plt.imread

– evolved
Nov 14 '18 at 21:50













1 Answer
1






active

oldest

votes


















1














As I see it, matplotlib's imread correctly reads in the image. If the image contains only a single channel, the resulting numpy array will be 2D. If the image contains 3 or 4 channels, the numpy array will be 3D.



Taking the dolphin image from the question you get



plt.imread("https://i.stack.imgur.com/cInHj.png").shape
> (320, 500)


Concerning the stinkbug image from the matplotlib documentation there is indeed a little problem. The image you see is a grey scale image as well,



plt.imread("https://matplotlib.org/_images/stinkbug.png").shape
> (375, 500)


However the tutorial claims it to be a 3 channel image. This is correct from the point of view of the tutorial, because it takes the image from the doc on the github repository folder.



plt.imread("https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png").shape
> (375, 500, 3)


The problem is that the documentation is built through sphinx and sphinx-gallery and in addition may use some other libraries. In the course of this, the image is not copied in its raw format to the output folder. This problem has been reported already here, the reason is not yet fully tracked down.



In any case, the remaining open question is then, why does cv2.imread give you a 3D array for a greyscale image?



From the OpenCV imread documentation:




Second argument is a flag which specifies the way image should be read.



  • cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

  • cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

  • cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.




So here you need to specify yourself, which mode you want to use.



Let's verify:



import cv2
import urllib.request as req

dolphinurl ="https://i.stack.imgur.com/cInHj.png"
stinkbugweburl = "https://matplotlib.org/_images/stinkbug.png"
stinkbuggiturl = "https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png"

def printshape(url, **kw):
req.urlretrieve(url, "image_name.png")
im = cv2.imread("image_name.png", **kw)
print(im.shape)

printshape(dolphinurl)
printshape(stinkbugweburl)
printshape(stinkbugweburl)


This prints



(320, 500, 3)
(375, 500, 3)
(375, 500, 3)


while if you specify greyscale,



printshape(dolphinurl,0)
printshape(stinkbugweburl,0)
printshape(stinkbugweburl,0)


it'll print



(320, 500)
(375, 500)
(375, 500)


In that sense it's up to the user to decide how they want to read in the image.






share|improve this answer






















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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    As I see it, matplotlib's imread correctly reads in the image. If the image contains only a single channel, the resulting numpy array will be 2D. If the image contains 3 or 4 channels, the numpy array will be 3D.



    Taking the dolphin image from the question you get



    plt.imread("https://i.stack.imgur.com/cInHj.png").shape
    > (320, 500)


    Concerning the stinkbug image from the matplotlib documentation there is indeed a little problem. The image you see is a grey scale image as well,



    plt.imread("https://matplotlib.org/_images/stinkbug.png").shape
    > (375, 500)


    However the tutorial claims it to be a 3 channel image. This is correct from the point of view of the tutorial, because it takes the image from the doc on the github repository folder.



    plt.imread("https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png").shape
    > (375, 500, 3)


    The problem is that the documentation is built through sphinx and sphinx-gallery and in addition may use some other libraries. In the course of this, the image is not copied in its raw format to the output folder. This problem has been reported already here, the reason is not yet fully tracked down.



    In any case, the remaining open question is then, why does cv2.imread give you a 3D array for a greyscale image?



    From the OpenCV imread documentation:




    Second argument is a flag which specifies the way image should be read.



    • cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

    • cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

    • cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

    Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.




    So here you need to specify yourself, which mode you want to use.



    Let's verify:



    import cv2
    import urllib.request as req

    dolphinurl ="https://i.stack.imgur.com/cInHj.png"
    stinkbugweburl = "https://matplotlib.org/_images/stinkbug.png"
    stinkbuggiturl = "https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png"

    def printshape(url, **kw):
    req.urlretrieve(url, "image_name.png")
    im = cv2.imread("image_name.png", **kw)
    print(im.shape)

    printshape(dolphinurl)
    printshape(stinkbugweburl)
    printshape(stinkbugweburl)


    This prints



    (320, 500, 3)
    (375, 500, 3)
    (375, 500, 3)


    while if you specify greyscale,



    printshape(dolphinurl,0)
    printshape(stinkbugweburl,0)
    printshape(stinkbugweburl,0)


    it'll print



    (320, 500)
    (375, 500)
    (375, 500)


    In that sense it's up to the user to decide how they want to read in the image.






    share|improve this answer



























      1














      As I see it, matplotlib's imread correctly reads in the image. If the image contains only a single channel, the resulting numpy array will be 2D. If the image contains 3 or 4 channels, the numpy array will be 3D.



      Taking the dolphin image from the question you get



      plt.imread("https://i.stack.imgur.com/cInHj.png").shape
      > (320, 500)


      Concerning the stinkbug image from the matplotlib documentation there is indeed a little problem. The image you see is a grey scale image as well,



      plt.imread("https://matplotlib.org/_images/stinkbug.png").shape
      > (375, 500)


      However the tutorial claims it to be a 3 channel image. This is correct from the point of view of the tutorial, because it takes the image from the doc on the github repository folder.



      plt.imread("https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png").shape
      > (375, 500, 3)


      The problem is that the documentation is built through sphinx and sphinx-gallery and in addition may use some other libraries. In the course of this, the image is not copied in its raw format to the output folder. This problem has been reported already here, the reason is not yet fully tracked down.



      In any case, the remaining open question is then, why does cv2.imread give you a 3D array for a greyscale image?



      From the OpenCV imread documentation:




      Second argument is a flag which specifies the way image should be read.



      • cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

      • cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

      • cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

      Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.




      So here you need to specify yourself, which mode you want to use.



      Let's verify:



      import cv2
      import urllib.request as req

      dolphinurl ="https://i.stack.imgur.com/cInHj.png"
      stinkbugweburl = "https://matplotlib.org/_images/stinkbug.png"
      stinkbuggiturl = "https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png"

      def printshape(url, **kw):
      req.urlretrieve(url, "image_name.png")
      im = cv2.imread("image_name.png", **kw)
      print(im.shape)

      printshape(dolphinurl)
      printshape(stinkbugweburl)
      printshape(stinkbugweburl)


      This prints



      (320, 500, 3)
      (375, 500, 3)
      (375, 500, 3)


      while if you specify greyscale,



      printshape(dolphinurl,0)
      printshape(stinkbugweburl,0)
      printshape(stinkbugweburl,0)


      it'll print



      (320, 500)
      (375, 500)
      (375, 500)


      In that sense it's up to the user to decide how they want to read in the image.






      share|improve this answer

























        1












        1








        1







        As I see it, matplotlib's imread correctly reads in the image. If the image contains only a single channel, the resulting numpy array will be 2D. If the image contains 3 or 4 channels, the numpy array will be 3D.



        Taking the dolphin image from the question you get



        plt.imread("https://i.stack.imgur.com/cInHj.png").shape
        > (320, 500)


        Concerning the stinkbug image from the matplotlib documentation there is indeed a little problem. The image you see is a grey scale image as well,



        plt.imread("https://matplotlib.org/_images/stinkbug.png").shape
        > (375, 500)


        However the tutorial claims it to be a 3 channel image. This is correct from the point of view of the tutorial, because it takes the image from the doc on the github repository folder.



        plt.imread("https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png").shape
        > (375, 500, 3)


        The problem is that the documentation is built through sphinx and sphinx-gallery and in addition may use some other libraries. In the course of this, the image is not copied in its raw format to the output folder. This problem has been reported already here, the reason is not yet fully tracked down.



        In any case, the remaining open question is then, why does cv2.imread give you a 3D array for a greyscale image?



        From the OpenCV imread documentation:




        Second argument is a flag which specifies the way image should be read.



        • cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

        • cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

        • cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

        Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.




        So here you need to specify yourself, which mode you want to use.



        Let's verify:



        import cv2
        import urllib.request as req

        dolphinurl ="https://i.stack.imgur.com/cInHj.png"
        stinkbugweburl = "https://matplotlib.org/_images/stinkbug.png"
        stinkbuggiturl = "https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png"

        def printshape(url, **kw):
        req.urlretrieve(url, "image_name.png")
        im = cv2.imread("image_name.png", **kw)
        print(im.shape)

        printshape(dolphinurl)
        printshape(stinkbugweburl)
        printshape(stinkbugweburl)


        This prints



        (320, 500, 3)
        (375, 500, 3)
        (375, 500, 3)


        while if you specify greyscale,



        printshape(dolphinurl,0)
        printshape(stinkbugweburl,0)
        printshape(stinkbugweburl,0)


        it'll print



        (320, 500)
        (375, 500)
        (375, 500)


        In that sense it's up to the user to decide how they want to read in the image.






        share|improve this answer













        As I see it, matplotlib's imread correctly reads in the image. If the image contains only a single channel, the resulting numpy array will be 2D. If the image contains 3 or 4 channels, the numpy array will be 3D.



        Taking the dolphin image from the question you get



        plt.imread("https://i.stack.imgur.com/cInHj.png").shape
        > (320, 500)


        Concerning the stinkbug image from the matplotlib documentation there is indeed a little problem. The image you see is a grey scale image as well,



        plt.imread("https://matplotlib.org/_images/stinkbug.png").shape
        > (375, 500)


        However the tutorial claims it to be a 3 channel image. This is correct from the point of view of the tutorial, because it takes the image from the doc on the github repository folder.



        plt.imread("https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png").shape
        > (375, 500, 3)


        The problem is that the documentation is built through sphinx and sphinx-gallery and in addition may use some other libraries. In the course of this, the image is not copied in its raw format to the output folder. This problem has been reported already here, the reason is not yet fully tracked down.



        In any case, the remaining open question is then, why does cv2.imread give you a 3D array for a greyscale image?



        From the OpenCV imread documentation:




        Second argument is a flag which specifies the way image should be read.



        • cv2.IMREAD_COLOR : Loads a color image. Any transparency of image will be neglected. It is the default flag.

        • cv2.IMREAD_GRAYSCALE : Loads image in grayscale mode

        • cv2.IMREAD_UNCHANGED : Loads image as such including alpha channel

        Note Instead of these three flags, you can simply pass integers 1, 0 or -1 respectively.




        So here you need to specify yourself, which mode you want to use.



        Let's verify:



        import cv2
        import urllib.request as req

        dolphinurl ="https://i.stack.imgur.com/cInHj.png"
        stinkbugweburl = "https://matplotlib.org/_images/stinkbug.png"
        stinkbuggiturl = "https://raw.githubusercontent.com/matplotlib/matplotlib/master/doc/_static/stinkbug.png"

        def printshape(url, **kw):
        req.urlretrieve(url, "image_name.png")
        im = cv2.imread("image_name.png", **kw)
        print(im.shape)

        printshape(dolphinurl)
        printshape(stinkbugweburl)
        printshape(stinkbugweburl)


        This prints



        (320, 500, 3)
        (375, 500, 3)
        (375, 500, 3)


        while if you specify greyscale,



        printshape(dolphinurl,0)
        printshape(stinkbugweburl,0)
        printshape(stinkbugweburl,0)


        it'll print



        (320, 500)
        (375, 500)
        (375, 500)


        In that sense it's up to the user to decide how they want to read in the image.







        share|improve this answer












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        answered Nov 14 '18 at 22:45









        ImportanceOfBeingErnestImportanceOfBeingErnest

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