regex: reject the match
-2
python 3.5 re version 2.2.1
Toy example:
S1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(^.*?Arithm.*$)')
w = [re.findall(p, a) for a in [s1, s2]]
- How can I make sure that I will match only s2 that contains '2019'
- How can I ignore caps / lower case?
regex python-3.x
asked Nov 14 '18 at 21:12
Cy BuCy Bu
5311819
add a comment |
-2
python 3.5 re version 2.2.1
Toy example:
S1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(^.*?Arithm.*$)')
w = [re.findall(p, a) for a in [s1, s2]]
- How can I make sure that I will match only s2 that contains '2019'
- How can I ignore caps / lower case?
regex python-3.x
asked Nov 14 '18 at 21:12
Cy BuCy Bu
5311819
1
Your regex matches any line that hasArithmin it, see ideone.com/tejbbu. What are you trying to achieve?
– Wiktor Stribiżew
Nov 14 '18 at 21:15
What is so specific abouts2that you want to only match that text?
– Wiktor Stribiżew
Nov 14 '18 at 21:16
Is your regex supposed to be "any text that contains Arithm followed by 2019"?
– Patrick Haugh
Nov 14 '18 at 21:17
the year....Essentially I want to match Arithm and NOT 2018. That is I want to reject 2018
– Cy Bu
Nov 14 '18 at 21:17
1
It sounds as if you wanted to useif 'arithm' in s.lower() and '2018' not in s:...
– Wiktor Stribiżew
Nov 14 '18 at 21:18
add a comment |
-2
-2
-2
python 3.5 re version 2.2.1
Toy example:
S1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(^.*?Arithm.*$)')
w = [re.findall(p, a) for a in [s1, s2]]
- How can I make sure that I will match only s2 that contains '2019'
- How can I ignore caps / lower case?
regex python-3.x
asked Nov 14 '18 at 21:12
Cy BuCy Bu
5311819
python 3.5 re version 2.2.1
Toy example:
S1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(^.*?Arithm.*$)')
w = [re.findall(p, a) for a in [s1, s2]]
- How can I make sure that I will match only s2 that contains '2019'
- How can I ignore caps / lower case?
regex python-3.x
regex python-3.x
asked Nov 14 '18 at 21:12
Cy BuCy Bu
5311819
asked Nov 14 '18 at 21:12
Cy BuCy Bu
5311819
edited Nov 14 '18 at 21:15
Cy Bu
asked Nov 14 '18 at 21:12
Cy BuCy Bu
5311819
asked Nov 14 '18 at 21:12
Cy BuCy Bu
5311819
asked Nov 14 '18 at 21:12
Cy BuCy Bu
5311819
5311819
1
Your regex matches any line that hasArithmin it, see ideone.com/tejbbu. What are you trying to achieve?
– Wiktor Stribiżew
Nov 14 '18 at 21:15
What is so specific abouts2that you want to only match that text?
– Wiktor Stribiżew
Nov 14 '18 at 21:16
Is your regex supposed to be "any text that contains Arithm followed by 2019"?
– Patrick Haugh
Nov 14 '18 at 21:17
the year....Essentially I want to match Arithm and NOT 2018. That is I want to reject 2018
– Cy Bu
Nov 14 '18 at 21:17
1
It sounds as if you wanted to useif 'arithm' in s.lower() and '2018' not in s:...
– Wiktor Stribiżew
Nov 14 '18 at 21:18
add a comment |
1
Your regex matches any line that hasArithmin it, see ideone.com/tejbbu. What are you trying to achieve?
– Wiktor Stribiżew
Nov 14 '18 at 21:15
What is so specific abouts2that you want to only match that text?
– Wiktor Stribiżew
Nov 14 '18 at 21:16
Is your regex supposed to be "any text that contains Arithm followed by 2019"?
– Patrick Haugh
Nov 14 '18 at 21:17
the year....Essentially I want to match Arithm and NOT 2018. That is I want to reject 2018
– Cy Bu
Nov 14 '18 at 21:17
1
It sounds as if you wanted to useif 'arithm' in s.lower() and '2018' not in s:...
– Wiktor Stribiżew
Nov 14 '18 at 21:18
1
1
Your regex matches any line that has
Arithm in it, see ideone.com/tejbbu. What are you trying to achieve?– Wiktor Stribiżew
Nov 14 '18 at 21:15
Your regex matches any line that has
Arithm in it, see ideone.com/tejbbu. What are you trying to achieve?– Wiktor Stribiżew
Nov 14 '18 at 21:15
What is so specific about
s2 that you want to only match that text?– Wiktor Stribiżew
Nov 14 '18 at 21:16
What is so specific about
s2 that you want to only match that text?– Wiktor Stribiżew
Nov 14 '18 at 21:16
Is your regex supposed to be "any text that contains Arithm followed by 2019"?
– Patrick Haugh
Nov 14 '18 at 21:17
Is your regex supposed to be "any text that contains Arithm followed by 2019"?
– Patrick Haugh
Nov 14 '18 at 21:17
the year....Essentially I want to match Arithm and NOT 2018. That is I want to reject 2018
– Cy Bu
Nov 14 '18 at 21:17
the year....Essentially I want to match Arithm and NOT 2018. That is I want to reject 2018
– Cy Bu
Nov 14 '18 at 21:17
1
1
It sounds as if you wanted to use
if 'arithm' in s.lower() and '2018' not in s:...– Wiktor Stribiżew
Nov 14 '18 at 21:18
It sounds as if you wanted to use
if 'arithm' in s.lower() and '2018' not in s:...– Wiktor Stribiżew
Nov 14 '18 at 21:18
add a comment |
1 Answer
1
active
oldest
votes
1
You can just add 2019.* to your regex to match a string that contains Arithm (case insensitive through (?i))
followed by 2019 somewhere in the string. Like this: (?i)^.*?Arithm.*2019.*$.
I know it's not javascript but it's handy to see a working example, copied from regex101:
const regex = /^.*?Arithm.*2019.*$/gmi;
const str = `Arithmetic Return 2018 (%)
Arithmetic Return 2019 (%)`;
let m;
while ((m = regex.exec(str)) !== null)
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex)
regex.lastIndex++;
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) =>
console.log(`Found match, group $groupIndex: $match`);
);
Python:
import re
s1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(?i)^.*?Arithm.*2019.*$')
w = [re.findall(p, a) for a in [s1, s2]]
print(w)
answered Nov 14 '18 at 21:18
MarkMark
3,70921126
1
well, python regexes aren't javascript regexes. In particular//gmdon't exist in python
– Jean-François Fabre♦
Nov 14 '18 at 21:19
Anyway, it is not what OP needs. Essentially I want to match Arithm and NOT 2018 Nor does this answer How can I ignore caps / lower case?
– Wiktor Stribiżew
Nov 14 '18 at 21:22
No reason to use compile if you're not going to use the returned object.w = [p.findall(a) for a in [s1, s2]]
– nicholishen
Nov 14 '18 at 21:26
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can just add 2019.* to your regex to match a string that contains Arithm (case insensitive through (?i))
followed by 2019 somewhere in the string. Like this: (?i)^.*?Arithm.*2019.*$.
I know it's not javascript but it's handy to see a working example, copied from regex101:
const regex = /^.*?Arithm.*2019.*$/gmi;
const str = `Arithmetic Return 2018 (%)
Arithmetic Return 2019 (%)`;
let m;
while ((m = regex.exec(str)) !== null)
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex)
regex.lastIndex++;
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) =>
console.log(`Found match, group $groupIndex: $match`);
);
Python:
import re
s1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(?i)^.*?Arithm.*2019.*$')
w = [re.findall(p, a) for a in [s1, s2]]
print(w)
answered Nov 14 '18 at 21:18
MarkMark
3,70921126
1
well, python regexes aren't javascript regexes. In particular//gmdon't exist in python
– Jean-François Fabre♦
Nov 14 '18 at 21:19
Anyway, it is not what OP needs. Essentially I want to match Arithm and NOT 2018 Nor does this answer How can I ignore caps / lower case?
– Wiktor Stribiżew
Nov 14 '18 at 21:22
No reason to use compile if you're not going to use the returned object.w = [p.findall(a) for a in [s1, s2]]
– nicholishen
Nov 14 '18 at 21:26
add a comment |
1
You can just add 2019.* to your regex to match a string that contains Arithm (case insensitive through (?i))
followed by 2019 somewhere in the string. Like this: (?i)^.*?Arithm.*2019.*$.
I know it's not javascript but it's handy to see a working example, copied from regex101:
const regex = /^.*?Arithm.*2019.*$/gmi;
const str = `Arithmetic Return 2018 (%)
Arithmetic Return 2019 (%)`;
let m;
while ((m = regex.exec(str)) !== null)
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex)
regex.lastIndex++;
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) =>
console.log(`Found match, group $groupIndex: $match`);
);
Python:
import re
s1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(?i)^.*?Arithm.*2019.*$')
w = [re.findall(p, a) for a in [s1, s2]]
print(w)
answered Nov 14 '18 at 21:18
MarkMark
3,70921126
1
well, python regexes aren't javascript regexes. In particular//gmdon't exist in python
– Jean-François Fabre♦
Nov 14 '18 at 21:19
Anyway, it is not what OP needs. Essentially I want to match Arithm and NOT 2018 Nor does this answer How can I ignore caps / lower case?
– Wiktor Stribiżew
Nov 14 '18 at 21:22
No reason to use compile if you're not going to use the returned object.w = [p.findall(a) for a in [s1, s2]]
– nicholishen
Nov 14 '18 at 21:26
add a comment |
1
1
1
You can just add 2019.* to your regex to match a string that contains Arithm (case insensitive through (?i))
followed by 2019 somewhere in the string. Like this: (?i)^.*?Arithm.*2019.*$.
I know it's not javascript but it's handy to see a working example, copied from regex101:
const regex = /^.*?Arithm.*2019.*$/gmi;
const str = `Arithmetic Return 2018 (%)
Arithmetic Return 2019 (%)`;
let m;
while ((m = regex.exec(str)) !== null)
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex)
regex.lastIndex++;
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) =>
console.log(`Found match, group $groupIndex: $match`);
);
Python:
import re
s1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(?i)^.*?Arithm.*2019.*$')
w = [re.findall(p, a) for a in [s1, s2]]
print(w)
answered Nov 14 '18 at 21:18
MarkMark
3,70921126
You can just add 2019.* to your regex to match a string that contains Arithm (case insensitive through (?i))
followed by 2019 somewhere in the string. Like this: (?i)^.*?Arithm.*2019.*$.
I know it's not javascript but it's handy to see a working example, copied from regex101:
const regex = /^.*?Arithm.*2019.*$/gmi;
const str = `Arithmetic Return 2018 (%)
Arithmetic Return 2019 (%)`;
let m;
while ((m = regex.exec(str)) !== null)
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex)
regex.lastIndex++;
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) =>
console.log(`Found match, group $groupIndex: $match`);
);
Python:
import re
s1 = 'Arithmetic Return 2018 (%)'
s2 = 'Arithmetic Return 2019 (%)'
p = re.compile(r'(?i)^.*?Arithm.*2019.*$')
w = [re.findall(p, a) for a in [s1, s2]]
print(w)
const regex = /^.*?Arithm.*2019.*$/gmi;
const str = `Arithmetic Return 2018 (%)
Arithmetic Return 2019 (%)`;
let m;
while ((m = regex.exec(str)) !== null)
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex)
regex.lastIndex++;
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) =>
console.log(`Found match, group $groupIndex: $match`);
);
const regex = /^.*?Arithm.*2019.*$/gmi;
const str = `Arithmetic Return 2018 (%)
Arithmetic Return 2019 (%)`;
let m;
while ((m = regex.exec(str)) !== null)
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex)
regex.lastIndex++;
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) =>
console.log(`Found match, group $groupIndex: $match`);
);
answered Nov 14 '18 at 21:18
MarkMark
3,70921126
edited Nov 14 '18 at 21:29
answered Nov 14 '18 at 21:18
MarkMark
3,70921126
answered Nov 14 '18 at 21:18
MarkMark
3,70921126
answered Nov 14 '18 at 21:18
MarkMark
3,70921126
3,70921126
1
well, python regexes aren't javascript regexes. In particular//gmdon't exist in python
– Jean-François Fabre♦
Nov 14 '18 at 21:19
Anyway, it is not what OP needs. Essentially I want to match Arithm and NOT 2018 Nor does this answer How can I ignore caps / lower case?
– Wiktor Stribiżew
Nov 14 '18 at 21:22
No reason to use compile if you're not going to use the returned object.w = [p.findall(a) for a in [s1, s2]]
– nicholishen
Nov 14 '18 at 21:26
add a comment |
1
well, python regexes aren't javascript regexes. In particular//gmdon't exist in python
– Jean-François Fabre♦
Nov 14 '18 at 21:19
Anyway, it is not what OP needs. Essentially I want to match Arithm and NOT 2018 Nor does this answer How can I ignore caps / lower case?
– Wiktor Stribiżew
Nov 14 '18 at 21:22
No reason to use compile if you're not going to use the returned object.w = [p.findall(a) for a in [s1, s2]]
– nicholishen
Nov 14 '18 at 21:26
1
1
well, python regexes aren't javascript regexes. In particular
//gm don't exist in python– Jean-François Fabre♦
Nov 14 '18 at 21:19
well, python regexes aren't javascript regexes. In particular
//gm don't exist in python– Jean-François Fabre♦
Nov 14 '18 at 21:19
Anyway, it is not what OP needs. Essentially I want to match Arithm and NOT 2018 Nor does this answer How can I ignore caps / lower case?
– Wiktor Stribiżew
Nov 14 '18 at 21:22
Anyway, it is not what OP needs. Essentially I want to match Arithm and NOT 2018 Nor does this answer How can I ignore caps / lower case?
– Wiktor Stribiżew
Nov 14 '18 at 21:22
No reason to use compile if you're not going to use the returned object.
w = [p.findall(a) for a in [s1, s2]]– nicholishen
Nov 14 '18 at 21:26
No reason to use compile if you're not going to use the returned object.
w = [p.findall(a) for a in [s1, s2]]– nicholishen
Nov 14 '18 at 21:26
add a comment |
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1
Your regex matches any line that has
Arithmin it, see ideone.com/tejbbu. What are you trying to achieve?– Wiktor Stribiżew
Nov 14 '18 at 21:15
What is so specific about
s2that you want to only match that text?– Wiktor Stribiżew
Nov 14 '18 at 21:16
Is your regex supposed to be "any text that contains Arithm followed by 2019"?
– Patrick Haugh
Nov 14 '18 at 21:17
the year....Essentially I want to match Arithm and NOT 2018. That is I want to reject 2018
– Cy Bu
Nov 14 '18 at 21:17
1
It sounds as if you wanted to use
if 'arithm' in s.lower() and '2018' not in s:...– Wiktor Stribiżew
Nov 14 '18 at 21:18