firebase realtime db get non existent child throws exception



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0















my code is like



 var db = admin.database();
var ref = db.ref('referrals')

ref.child("ABCD").once("value").then(
(resp) =>
).catch(err => console.error("error"))


if referrals do not have child node "ABCD" it goes to exception block. How can i check the existence of it and handle rather throwing to catch?










share|improve this question




























    0















    my code is like



     var db = admin.database();
    var ref = db.ref('referrals')

    ref.child("ABCD").once("value").then(
    (resp) =>
    ).catch(err => console.error("error"))


    if referrals do not have child node "ABCD" it goes to exception block. How can i check the existence of it and handle rather throwing to catch?










    share|improve this question
























      0












      0








      0








      my code is like



       var db = admin.database();
      var ref = db.ref('referrals')

      ref.child("ABCD").once("value").then(
      (resp) =>
      ).catch(err => console.error("error"))


      if referrals do not have child node "ABCD" it goes to exception block. How can i check the existence of it and handle rather throwing to catch?










      share|improve this question














      my code is like



       var db = admin.database();
      var ref = db.ref('referrals')

      ref.child("ABCD").once("value").then(
      (resp) =>
      ).catch(err => console.error("error"))


      if referrals do not have child node "ABCD" it goes to exception block. How can i check the existence of it and handle rather throwing to catch?







      firebase firebase-realtime-database google-cloud-functions






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 15 '18 at 7:58









      VikVik

      2,0901346101




      2,0901346101






















          1 Answer
          1






          active

          oldest

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          0














          Try ;



           var db = admin.database();
          var ref = db.ref('referrals')

          ref.child("ABCD").once("value", resp =>
          if (resp.exists())
          // Data exists
          else
          // No data fetched



          )






          share|improve this answer























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            1 Answer
            1






            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            Try ;



             var db = admin.database();
            var ref = db.ref('referrals')

            ref.child("ABCD").once("value", resp =>
            if (resp.exists())
            // Data exists
            else
            // No data fetched



            )






            share|improve this answer



























              0














              Try ;



               var db = admin.database();
              var ref = db.ref('referrals')

              ref.child("ABCD").once("value", resp =>
              if (resp.exists())
              // Data exists
              else
              // No data fetched



              )






              share|improve this answer

























                0












                0








                0







                Try ;



                 var db = admin.database();
                var ref = db.ref('referrals')

                ref.child("ABCD").once("value", resp =>
                if (resp.exists())
                // Data exists
                else
                // No data fetched



                )






                share|improve this answer













                Try ;



                 var db = admin.database();
                var ref = db.ref('referrals')

                ref.child("ABCD").once("value", resp =>
                if (resp.exists())
                // Data exists
                else
                // No data fetched



                )







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 15 '18 at 9:10









                HakanCHakanC

                2,3693814




                2,3693814





























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