Using external abstract class in Typescript without extending it









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I've got one module called utils.tsx so that:



interface IUtils 
toUri: (route: string) => string


export default abstract class Utils implements IUtils
public toUri = (route: string) =>
return route




and another file where I wish to use this utils module:



 import Utils from '../helpers/utils'

class Router
private getBuilder = (search: string) =>
const path = Utils.toUri(search)




When I am trying to use Utils.toUri I am getting TS error:



[ts] Property 'toUri' does not exist on type 'typeof Utils'.



My intention is to call the external abstract class function without extending the Router class nor inheriting from it (as I will have more than one external module in the main file).



Could someone help me to bypass it and understand?



PS: I tried with public abstract toUri() too. Perhaps I mixed up the routines from other programming languages and confusing usage of static with abstract here...










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    up vote
    1
    down vote

    favorite












    I've got one module called utils.tsx so that:



    interface IUtils 
    toUri: (route: string) => string


    export default abstract class Utils implements IUtils
    public toUri = (route: string) =>
    return route




    and another file where I wish to use this utils module:



     import Utils from '../helpers/utils'

    class Router
    private getBuilder = (search: string) =>
    const path = Utils.toUri(search)




    When I am trying to use Utils.toUri I am getting TS error:



    [ts] Property 'toUri' does not exist on type 'typeof Utils'.



    My intention is to call the external abstract class function without extending the Router class nor inheriting from it (as I will have more than one external module in the main file).



    Could someone help me to bypass it and understand?



    PS: I tried with public abstract toUri() too. Perhaps I mixed up the routines from other programming languages and confusing usage of static with abstract here...










    share|improve this question























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I've got one module called utils.tsx so that:



      interface IUtils 
      toUri: (route: string) => string


      export default abstract class Utils implements IUtils
      public toUri = (route: string) =>
      return route




      and another file where I wish to use this utils module:



       import Utils from '../helpers/utils'

      class Router
      private getBuilder = (search: string) =>
      const path = Utils.toUri(search)




      When I am trying to use Utils.toUri I am getting TS error:



      [ts] Property 'toUri' does not exist on type 'typeof Utils'.



      My intention is to call the external abstract class function without extending the Router class nor inheriting from it (as I will have more than one external module in the main file).



      Could someone help me to bypass it and understand?



      PS: I tried with public abstract toUri() too. Perhaps I mixed up the routines from other programming languages and confusing usage of static with abstract here...










      share|improve this question













      I've got one module called utils.tsx so that:



      interface IUtils 
      toUri: (route: string) => string


      export default abstract class Utils implements IUtils
      public toUri = (route: string) =>
      return route




      and another file where I wish to use this utils module:



       import Utils from '../helpers/utils'

      class Router
      private getBuilder = (search: string) =>
      const path = Utils.toUri(search)




      When I am trying to use Utils.toUri I am getting TS error:



      [ts] Property 'toUri' does not exist on type 'typeof Utils'.



      My intention is to call the external abstract class function without extending the Router class nor inheriting from it (as I will have more than one external module in the main file).



      Could someone help me to bypass it and understand?



      PS: I tried with public abstract toUri() too. Perhaps I mixed up the routines from other programming languages and confusing usage of static with abstract here...







      typescript oop typescript-typings






      share|improve this question













      share|improve this question











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      share|improve this question










      asked Nov 9 at 17:15









      Greg Woz

      144111




      144111






















          1 Answer
          1






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          You don't want Utils to implement IUtils, since Utils is the instance type of the class. It looks like you want the Utils constructor (whose type is typeof Utils) to implement IUtils. That is, you want toUri to be a static method of the Utils class. Like this:



          abstract class Utils 
          public static toUri = (route: string) =>
          return route




          There is no way to annotate the class Utils declaration to say that the static side of the class implements IUtils. Luckily, the Utils constructor will automatically be seen as something that implements IUtils without needing to write implements IUtils anywhere. Thanks, structural typing:



          declare function takeIUtils(iUtils: IUtils): void;
          takeIUtils(Utils); // works anyway


          This should allow your Router class to behave as desired.




          Side note, I wonder if you really want Utils to be a class at all. If you never want to see an instance of Utils like class X extends Utils ...; new X(), then you're probably making life unnecessarily hard for yourself. Maybe it should just be a value:



          export const Utils : IUtils = 
          toUri(route: string)
          return route




          Or a namespace:



          export namespace Utils 
          export function toUri(route: string)
          return route




          Or a module, or something.




          Anyway, hope that helps. Good luck!






          share|improve this answer




















          • Yes, definitely namespace is a solution to my problems. Thank you. :)
            – Greg Woz
            Nov 12 at 21:09










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          1 Answer
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          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote



          accepted










          You don't want Utils to implement IUtils, since Utils is the instance type of the class. It looks like you want the Utils constructor (whose type is typeof Utils) to implement IUtils. That is, you want toUri to be a static method of the Utils class. Like this:



          abstract class Utils 
          public static toUri = (route: string) =>
          return route




          There is no way to annotate the class Utils declaration to say that the static side of the class implements IUtils. Luckily, the Utils constructor will automatically be seen as something that implements IUtils without needing to write implements IUtils anywhere. Thanks, structural typing:



          declare function takeIUtils(iUtils: IUtils): void;
          takeIUtils(Utils); // works anyway


          This should allow your Router class to behave as desired.




          Side note, I wonder if you really want Utils to be a class at all. If you never want to see an instance of Utils like class X extends Utils ...; new X(), then you're probably making life unnecessarily hard for yourself. Maybe it should just be a value:



          export const Utils : IUtils = 
          toUri(route: string)
          return route




          Or a namespace:



          export namespace Utils 
          export function toUri(route: string)
          return route




          Or a module, or something.




          Anyway, hope that helps. Good luck!






          share|improve this answer




















          • Yes, definitely namespace is a solution to my problems. Thank you. :)
            – Greg Woz
            Nov 12 at 21:09














          up vote
          1
          down vote



          accepted










          You don't want Utils to implement IUtils, since Utils is the instance type of the class. It looks like you want the Utils constructor (whose type is typeof Utils) to implement IUtils. That is, you want toUri to be a static method of the Utils class. Like this:



          abstract class Utils 
          public static toUri = (route: string) =>
          return route




          There is no way to annotate the class Utils declaration to say that the static side of the class implements IUtils. Luckily, the Utils constructor will automatically be seen as something that implements IUtils without needing to write implements IUtils anywhere. Thanks, structural typing:



          declare function takeIUtils(iUtils: IUtils): void;
          takeIUtils(Utils); // works anyway


          This should allow your Router class to behave as desired.




          Side note, I wonder if you really want Utils to be a class at all. If you never want to see an instance of Utils like class X extends Utils ...; new X(), then you're probably making life unnecessarily hard for yourself. Maybe it should just be a value:



          export const Utils : IUtils = 
          toUri(route: string)
          return route




          Or a namespace:



          export namespace Utils 
          export function toUri(route: string)
          return route




          Or a module, or something.




          Anyway, hope that helps. Good luck!






          share|improve this answer




















          • Yes, definitely namespace is a solution to my problems. Thank you. :)
            – Greg Woz
            Nov 12 at 21:09












          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          You don't want Utils to implement IUtils, since Utils is the instance type of the class. It looks like you want the Utils constructor (whose type is typeof Utils) to implement IUtils. That is, you want toUri to be a static method of the Utils class. Like this:



          abstract class Utils 
          public static toUri = (route: string) =>
          return route




          There is no way to annotate the class Utils declaration to say that the static side of the class implements IUtils. Luckily, the Utils constructor will automatically be seen as something that implements IUtils without needing to write implements IUtils anywhere. Thanks, structural typing:



          declare function takeIUtils(iUtils: IUtils): void;
          takeIUtils(Utils); // works anyway


          This should allow your Router class to behave as desired.




          Side note, I wonder if you really want Utils to be a class at all. If you never want to see an instance of Utils like class X extends Utils ...; new X(), then you're probably making life unnecessarily hard for yourself. Maybe it should just be a value:



          export const Utils : IUtils = 
          toUri(route: string)
          return route




          Or a namespace:



          export namespace Utils 
          export function toUri(route: string)
          return route




          Or a module, or something.




          Anyway, hope that helps. Good luck!






          share|improve this answer












          You don't want Utils to implement IUtils, since Utils is the instance type of the class. It looks like you want the Utils constructor (whose type is typeof Utils) to implement IUtils. That is, you want toUri to be a static method of the Utils class. Like this:



          abstract class Utils 
          public static toUri = (route: string) =>
          return route




          There is no way to annotate the class Utils declaration to say that the static side of the class implements IUtils. Luckily, the Utils constructor will automatically be seen as something that implements IUtils without needing to write implements IUtils anywhere. Thanks, structural typing:



          declare function takeIUtils(iUtils: IUtils): void;
          takeIUtils(Utils); // works anyway


          This should allow your Router class to behave as desired.




          Side note, I wonder if you really want Utils to be a class at all. If you never want to see an instance of Utils like class X extends Utils ...; new X(), then you're probably making life unnecessarily hard for yourself. Maybe it should just be a value:



          export const Utils : IUtils = 
          toUri(route: string)
          return route




          Or a namespace:



          export namespace Utils 
          export function toUri(route: string)
          return route




          Or a module, or something.




          Anyway, hope that helps. Good luck!







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 9 at 17:39









          jcalz

          19.9k21535




          19.9k21535











          • Yes, definitely namespace is a solution to my problems. Thank you. :)
            – Greg Woz
            Nov 12 at 21:09
















          • Yes, definitely namespace is a solution to my problems. Thank you. :)
            – Greg Woz
            Nov 12 at 21:09















          Yes, definitely namespace is a solution to my problems. Thank you. :)
          – Greg Woz
          Nov 12 at 21:09




          Yes, definitely namespace is a solution to my problems. Thank you. :)
          – Greg Woz
          Nov 12 at 21:09

















           

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