strapi POST file to /upload with relation to a model fails



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0















Doing a POST to http://localhost:1337/upload with the following JSON data and with enough permissions to upload.



The file uploaded is related to an existing entity of model 'product'




"files":"@/path/to/file/image1.png",
"refId":"5bed7b1f7eb8792e4737dc3f",
"ref":"product",
"field":"image"



But fails with the following error in strapi error log:




TypeError: Cannot destructure property refId of 'undefined' or 'null'.




and with 500 "Internal Server Error" response.



Any help?










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    0















    Doing a POST to http://localhost:1337/upload with the following JSON data and with enough permissions to upload.



    The file uploaded is related to an existing entity of model 'product'




    "files":"@/path/to/file/image1.png",
    "refId":"5bed7b1f7eb8792e4737dc3f",
    "ref":"product",
    "field":"image"



    But fails with the following error in strapi error log:




    TypeError: Cannot destructure property refId of 'undefined' or 'null'.




    and with 500 "Internal Server Error" response.



    Any help?










    share|improve this question
























      0












      0








      0


      1






      Doing a POST to http://localhost:1337/upload with the following JSON data and with enough permissions to upload.



      The file uploaded is related to an existing entity of model 'product'




      "files":"@/path/to/file/image1.png",
      "refId":"5bed7b1f7eb8792e4737dc3f",
      "ref":"product",
      "field":"image"



      But fails with the following error in strapi error log:




      TypeError: Cannot destructure property refId of 'undefined' or 'null'.




      and with 500 "Internal Server Error" response.



      Any help?










      share|improve this question














      Doing a POST to http://localhost:1337/upload with the following JSON data and with enough permissions to upload.



      The file uploaded is related to an existing entity of model 'product'




      "files":"@/path/to/file/image1.png",
      "refId":"5bed7b1f7eb8792e4737dc3f",
      "ref":"product",
      "field":"image"



      But fails with the following error in strapi error log:




      TypeError: Cannot destructure property refId of 'undefined' or 'null'.




      and with 500 "Internal Server Error" response.



      Any help?







      strapi






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 15 '18 at 14:14









      rayenrayen

      33




      33






















          1 Answer
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          oldest

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          0














          You have to send a FormData



          The example bellow is to upload a file, you will have to add your ref attributes to make it work with relations.



           <form method="post">
          <input type="file" name="files" id="files">
          <input type="submit" name="" value="Submit">
          </form>

          <script type="text/javascript">
          $('form').on('submit', function (e)
          e.preventDefault();

          var data = new FormData();
          $.each($('#files')[0].files, function(i, file)
          data.append('files', file);
          );

          $.ajax(
          url: '/upload',
          data: data,
          contentType: false,
          processData: false,
          method: 'POST',
          success: function(data)
          alert(data);

          );
          );
          </script>





          share|improve this answer























          • Thanks for your reply @Jim. Posting as a form-data works.

            – rayen
            Dec 12 '18 at 3:09











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          convertImagesToLinks: true,
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          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

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          active

          oldest

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          0














          You have to send a FormData



          The example bellow is to upload a file, you will have to add your ref attributes to make it work with relations.



           <form method="post">
          <input type="file" name="files" id="files">
          <input type="submit" name="" value="Submit">
          </form>

          <script type="text/javascript">
          $('form').on('submit', function (e)
          e.preventDefault();

          var data = new FormData();
          $.each($('#files')[0].files, function(i, file)
          data.append('files', file);
          );

          $.ajax(
          url: '/upload',
          data: data,
          contentType: false,
          processData: false,
          method: 'POST',
          success: function(data)
          alert(data);

          );
          );
          </script>





          share|improve this answer























          • Thanks for your reply @Jim. Posting as a form-data works.

            – rayen
            Dec 12 '18 at 3:09















          0














          You have to send a FormData



          The example bellow is to upload a file, you will have to add your ref attributes to make it work with relations.



           <form method="post">
          <input type="file" name="files" id="files">
          <input type="submit" name="" value="Submit">
          </form>

          <script type="text/javascript">
          $('form').on('submit', function (e)
          e.preventDefault();

          var data = new FormData();
          $.each($('#files')[0].files, function(i, file)
          data.append('files', file);
          );

          $.ajax(
          url: '/upload',
          data: data,
          contentType: false,
          processData: false,
          method: 'POST',
          success: function(data)
          alert(data);

          );
          );
          </script>





          share|improve this answer























          • Thanks for your reply @Jim. Posting as a form-data works.

            – rayen
            Dec 12 '18 at 3:09













          0












          0








          0







          You have to send a FormData



          The example bellow is to upload a file, you will have to add your ref attributes to make it work with relations.



           <form method="post">
          <input type="file" name="files" id="files">
          <input type="submit" name="" value="Submit">
          </form>

          <script type="text/javascript">
          $('form').on('submit', function (e)
          e.preventDefault();

          var data = new FormData();
          $.each($('#files')[0].files, function(i, file)
          data.append('files', file);
          );

          $.ajax(
          url: '/upload',
          data: data,
          contentType: false,
          processData: false,
          method: 'POST',
          success: function(data)
          alert(data);

          );
          );
          </script>





          share|improve this answer













          You have to send a FormData



          The example bellow is to upload a file, you will have to add your ref attributes to make it work with relations.



           <form method="post">
          <input type="file" name="files" id="files">
          <input type="submit" name="" value="Submit">
          </form>

          <script type="text/javascript">
          $('form').on('submit', function (e)
          e.preventDefault();

          var data = new FormData();
          $.each($('#files')[0].files, function(i, file)
          data.append('files', file);
          );

          $.ajax(
          url: '/upload',
          data: data,
          contentType: false,
          processData: false,
          method: 'POST',
          success: function(data)
          alert(data);

          );
          );
          </script>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Dec 10 '18 at 14:18









          Jim LAURIEJim LAURIE

          35615




          35615












          • Thanks for your reply @Jim. Posting as a form-data works.

            – rayen
            Dec 12 '18 at 3:09

















          • Thanks for your reply @Jim. Posting as a form-data works.

            – rayen
            Dec 12 '18 at 3:09
















          Thanks for your reply @Jim. Posting as a form-data works.

          – rayen
          Dec 12 '18 at 3:09





          Thanks for your reply @Jim. Posting as a form-data works.

          – rayen
          Dec 12 '18 at 3:09



















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