Not able to convert to string










0














I might be using wrong python terminology.

I have an array of 3 integer elements: month, date and year.
However, I am not able to print each individual element when concatenating strings.



import ssl
import OpenSSL
import time
import sys

def get_SSL_Expiry_Date(host, port):
cert = ssl.get_server_certificate((host, 443))
x509 = OpenSSL.crypto.load_certificate(OpenSSL.crypto.FILETYPE_PEM, cert)
raw_date = x509.get_notAfter()
decoded_date = raw_date.decode("utf-8")
dexpires = time.strptime(decoded_date, "%Y%m%d%H%M%Sz")
bes = dexpires.tm_mon,dexpires.tm_mday,dexpires.tm_year
print (bes)
#print(bes[0]+"/"+bes[1]+"/"+bes[2])

domain = sys.argv[1]
port = 443
get_SSL_Expiry_Date(domain, port)


If I uncomment line 14, I get an error:




TypeError: unsupported operand type(s) for +: 'int' and 'str'




I am trying to get the date in this format (all strings): Month/Date/Year.

What am I doing wrong?










share|improve this question




























    0














    I might be using wrong python terminology.

    I have an array of 3 integer elements: month, date and year.
    However, I am not able to print each individual element when concatenating strings.



    import ssl
    import OpenSSL
    import time
    import sys

    def get_SSL_Expiry_Date(host, port):
    cert = ssl.get_server_certificate((host, 443))
    x509 = OpenSSL.crypto.load_certificate(OpenSSL.crypto.FILETYPE_PEM, cert)
    raw_date = x509.get_notAfter()
    decoded_date = raw_date.decode("utf-8")
    dexpires = time.strptime(decoded_date, "%Y%m%d%H%M%Sz")
    bes = dexpires.tm_mon,dexpires.tm_mday,dexpires.tm_year
    print (bes)
    #print(bes[0]+"/"+bes[1]+"/"+bes[2])

    domain = sys.argv[1]
    port = 443
    get_SSL_Expiry_Date(domain, port)


    If I uncomment line 14, I get an error:




    TypeError: unsupported operand type(s) for +: 'int' and 'str'




    I am trying to get the date in this format (all strings): Month/Date/Year.

    What am I doing wrong?










    share|improve this question


























      0












      0








      0







      I might be using wrong python terminology.

      I have an array of 3 integer elements: month, date and year.
      However, I am not able to print each individual element when concatenating strings.



      import ssl
      import OpenSSL
      import time
      import sys

      def get_SSL_Expiry_Date(host, port):
      cert = ssl.get_server_certificate((host, 443))
      x509 = OpenSSL.crypto.load_certificate(OpenSSL.crypto.FILETYPE_PEM, cert)
      raw_date = x509.get_notAfter()
      decoded_date = raw_date.decode("utf-8")
      dexpires = time.strptime(decoded_date, "%Y%m%d%H%M%Sz")
      bes = dexpires.tm_mon,dexpires.tm_mday,dexpires.tm_year
      print (bes)
      #print(bes[0]+"/"+bes[1]+"/"+bes[2])

      domain = sys.argv[1]
      port = 443
      get_SSL_Expiry_Date(domain, port)


      If I uncomment line 14, I get an error:




      TypeError: unsupported operand type(s) for +: 'int' and 'str'




      I am trying to get the date in this format (all strings): Month/Date/Year.

      What am I doing wrong?










      share|improve this question















      I might be using wrong python terminology.

      I have an array of 3 integer elements: month, date and year.
      However, I am not able to print each individual element when concatenating strings.



      import ssl
      import OpenSSL
      import time
      import sys

      def get_SSL_Expiry_Date(host, port):
      cert = ssl.get_server_certificate((host, 443))
      x509 = OpenSSL.crypto.load_certificate(OpenSSL.crypto.FILETYPE_PEM, cert)
      raw_date = x509.get_notAfter()
      decoded_date = raw_date.decode("utf-8")
      dexpires = time.strptime(decoded_date, "%Y%m%d%H%M%Sz")
      bes = dexpires.tm_mon,dexpires.tm_mday,dexpires.tm_year
      print (bes)
      #print(bes[0]+"/"+bes[1]+"/"+bes[2])

      domain = sys.argv[1]
      port = 443
      get_SSL_Expiry_Date(domain, port)


      If I uncomment line 14, I get an error:




      TypeError: unsupported operand type(s) for +: 'int' and 'str'




      I am trying to get the date in this format (all strings): Month/Date/Year.

      What am I doing wrong?







      python python-3.x






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 11 at 9:48









      Black Thunder

      2,2203831




      2,2203831










      asked Nov 9 at 6:55









      Bes

      81




      81






















          3 Answers
          3






          active

          oldest

          votes


















          0














          Simply use:



          print(time.strftime("%m/%d/%y",dexpires))


          See also https://docs.python.org/3/library/time.html



          In general python modules usually contain all kinds of reformatting functions you don't have to reinvent them.



          Example:



          >>> dexpires=time.strptime('20180823131455z','%Y%m%d%H%M%Sz')
          >>> dexpires
          time.struct_time(tm_year=2018, tm_mon=8, tm_mday=23, tm_hour=13, tm_min=14, tm_sec=55, tm_wday=3, tm_yday=235, tm_isdst=-1)
          >>> time.strftime('%m/%d/%y',dexpires)
          '08/23/18'
          >>>





          share|improve this answer






















          • i get this error when i try this solution: AttributeError: 'time.struct_time' object has no attribute 'strftime'
            – Bes
            Nov 11 at 7:25











          • @Bes Sorry, yes, you had to call module function, not the function of the particular time object. Changed the syntax.
            – Gnudiff
            Nov 11 at 9:11


















          1














          You can use Python's format() method to handle it (much cleaner also):



          print("0/1/2".format(bes[0],bes[1],bes[2]))


          ...or further simplified (thanks Anton)



          print("0/1/2".format(*bes))


          ↳ Python String Formatting






          share|improve this answer


















          • 1




            Yeah or .format(*bes)
            – Anton vBR
            Nov 9 at 7:23


















          0














          First you have to convert int values to string than only you are able to concave them.
          You can use str() inbuilt method



          print(str(bes[0])+"/"+ str(bes[1])+"/"+ str(bes[2])) #convert int to str first.





          share|improve this answer






















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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            Simply use:



            print(time.strftime("%m/%d/%y",dexpires))


            See also https://docs.python.org/3/library/time.html



            In general python modules usually contain all kinds of reformatting functions you don't have to reinvent them.



            Example:



            >>> dexpires=time.strptime('20180823131455z','%Y%m%d%H%M%Sz')
            >>> dexpires
            time.struct_time(tm_year=2018, tm_mon=8, tm_mday=23, tm_hour=13, tm_min=14, tm_sec=55, tm_wday=3, tm_yday=235, tm_isdst=-1)
            >>> time.strftime('%m/%d/%y',dexpires)
            '08/23/18'
            >>>





            share|improve this answer






















            • i get this error when i try this solution: AttributeError: 'time.struct_time' object has no attribute 'strftime'
              – Bes
              Nov 11 at 7:25











            • @Bes Sorry, yes, you had to call module function, not the function of the particular time object. Changed the syntax.
              – Gnudiff
              Nov 11 at 9:11















            0














            Simply use:



            print(time.strftime("%m/%d/%y",dexpires))


            See also https://docs.python.org/3/library/time.html



            In general python modules usually contain all kinds of reformatting functions you don't have to reinvent them.



            Example:



            >>> dexpires=time.strptime('20180823131455z','%Y%m%d%H%M%Sz')
            >>> dexpires
            time.struct_time(tm_year=2018, tm_mon=8, tm_mday=23, tm_hour=13, tm_min=14, tm_sec=55, tm_wday=3, tm_yday=235, tm_isdst=-1)
            >>> time.strftime('%m/%d/%y',dexpires)
            '08/23/18'
            >>>





            share|improve this answer






















            • i get this error when i try this solution: AttributeError: 'time.struct_time' object has no attribute 'strftime'
              – Bes
              Nov 11 at 7:25











            • @Bes Sorry, yes, you had to call module function, not the function of the particular time object. Changed the syntax.
              – Gnudiff
              Nov 11 at 9:11













            0












            0








            0






            Simply use:



            print(time.strftime("%m/%d/%y",dexpires))


            See also https://docs.python.org/3/library/time.html



            In general python modules usually contain all kinds of reformatting functions you don't have to reinvent them.



            Example:



            >>> dexpires=time.strptime('20180823131455z','%Y%m%d%H%M%Sz')
            >>> dexpires
            time.struct_time(tm_year=2018, tm_mon=8, tm_mday=23, tm_hour=13, tm_min=14, tm_sec=55, tm_wday=3, tm_yday=235, tm_isdst=-1)
            >>> time.strftime('%m/%d/%y',dexpires)
            '08/23/18'
            >>>





            share|improve this answer














            Simply use:



            print(time.strftime("%m/%d/%y",dexpires))


            See also https://docs.python.org/3/library/time.html



            In general python modules usually contain all kinds of reformatting functions you don't have to reinvent them.



            Example:



            >>> dexpires=time.strptime('20180823131455z','%Y%m%d%H%M%Sz')
            >>> dexpires
            time.struct_time(tm_year=2018, tm_mon=8, tm_mday=23, tm_hour=13, tm_min=14, tm_sec=55, tm_wday=3, tm_yday=235, tm_isdst=-1)
            >>> time.strftime('%m/%d/%y',dexpires)
            '08/23/18'
            >>>






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 11 at 9:11

























            answered Nov 9 at 7:26









            Gnudiff

            3,32111821




            3,32111821











            • i get this error when i try this solution: AttributeError: 'time.struct_time' object has no attribute 'strftime'
              – Bes
              Nov 11 at 7:25











            • @Bes Sorry, yes, you had to call module function, not the function of the particular time object. Changed the syntax.
              – Gnudiff
              Nov 11 at 9:11
















            • i get this error when i try this solution: AttributeError: 'time.struct_time' object has no attribute 'strftime'
              – Bes
              Nov 11 at 7:25











            • @Bes Sorry, yes, you had to call module function, not the function of the particular time object. Changed the syntax.
              – Gnudiff
              Nov 11 at 9:11















            i get this error when i try this solution: AttributeError: 'time.struct_time' object has no attribute 'strftime'
            – Bes
            Nov 11 at 7:25





            i get this error when i try this solution: AttributeError: 'time.struct_time' object has no attribute 'strftime'
            – Bes
            Nov 11 at 7:25













            @Bes Sorry, yes, you had to call module function, not the function of the particular time object. Changed the syntax.
            – Gnudiff
            Nov 11 at 9:11




            @Bes Sorry, yes, you had to call module function, not the function of the particular time object. Changed the syntax.
            – Gnudiff
            Nov 11 at 9:11













            1














            You can use Python's format() method to handle it (much cleaner also):



            print("0/1/2".format(bes[0],bes[1],bes[2]))


            ...or further simplified (thanks Anton)



            print("0/1/2".format(*bes))


            ↳ Python String Formatting






            share|improve this answer


















            • 1




              Yeah or .format(*bes)
              – Anton vBR
              Nov 9 at 7:23















            1














            You can use Python's format() method to handle it (much cleaner also):



            print("0/1/2".format(bes[0],bes[1],bes[2]))


            ...or further simplified (thanks Anton)



            print("0/1/2".format(*bes))


            ↳ Python String Formatting






            share|improve this answer


















            • 1




              Yeah or .format(*bes)
              – Anton vBR
              Nov 9 at 7:23













            1












            1








            1






            You can use Python's format() method to handle it (much cleaner also):



            print("0/1/2".format(bes[0],bes[1],bes[2]))


            ...or further simplified (thanks Anton)



            print("0/1/2".format(*bes))


            ↳ Python String Formatting






            share|improve this answer














            You can use Python's format() method to handle it (much cleaner also):



            print("0/1/2".format(bes[0],bes[1],bes[2]))


            ...or further simplified (thanks Anton)



            print("0/1/2".format(*bes))


            ↳ Python String Formatting







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 11 at 9:48









            Black Thunder

            2,2203831




            2,2203831










            answered Nov 9 at 7:07









            l'L'l

            29.6k54891




            29.6k54891







            • 1




              Yeah or .format(*bes)
              – Anton vBR
              Nov 9 at 7:23












            • 1




              Yeah or .format(*bes)
              – Anton vBR
              Nov 9 at 7:23







            1




            1




            Yeah or .format(*bes)
            – Anton vBR
            Nov 9 at 7:23




            Yeah or .format(*bes)
            – Anton vBR
            Nov 9 at 7:23











            0














            First you have to convert int values to string than only you are able to concave them.
            You can use str() inbuilt method



            print(str(bes[0])+"/"+ str(bes[1])+"/"+ str(bes[2])) #convert int to str first.





            share|improve this answer



























              0














              First you have to convert int values to string than only you are able to concave them.
              You can use str() inbuilt method



              print(str(bes[0])+"/"+ str(bes[1])+"/"+ str(bes[2])) #convert int to str first.





              share|improve this answer

























                0












                0








                0






                First you have to convert int values to string than only you are able to concave them.
                You can use str() inbuilt method



                print(str(bes[0])+"/"+ str(bes[1])+"/"+ str(bes[2])) #convert int to str first.





                share|improve this answer














                First you have to convert int values to string than only you are able to concave them.
                You can use str() inbuilt method



                print(str(bes[0])+"/"+ str(bes[1])+"/"+ str(bes[2])) #convert int to str first.






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 11 at 9:51









                Black Thunder

                2,2203831




                2,2203831










                answered Nov 9 at 6:57









                mukesh kudi

                616417




                616417



























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