How to map an array to a date?










0















In C#, I would use the following Dictionary



Dictionary << Date, int >>


for having an array bound to a particular date. What would be the simplest way in JS to achieve the same?



I need to be able to alter the values in the integer array.










share|improve this question
























  • you can create something almost the same in JS. : stackoverflow.com/questions/7196212/…

    – Budyn
    Nov 12 '18 at 16:34











  • You can use the JavaScript Map class, but be warned that equality comparison for Map keys is less flexible than in Java (and I would strongly suspect C#).

    – Pointy
    Nov 12 '18 at 16:34






  • 1





    just remember IE 8 < does not support Map function

    – Budyn
    Nov 12 '18 at 16:35















0















In C#, I would use the following Dictionary



Dictionary << Date, int >>


for having an array bound to a particular date. What would be the simplest way in JS to achieve the same?



I need to be able to alter the values in the integer array.










share|improve this question
























  • you can create something almost the same in JS. : stackoverflow.com/questions/7196212/…

    – Budyn
    Nov 12 '18 at 16:34











  • You can use the JavaScript Map class, but be warned that equality comparison for Map keys is less flexible than in Java (and I would strongly suspect C#).

    – Pointy
    Nov 12 '18 at 16:34






  • 1





    just remember IE 8 < does not support Map function

    – Budyn
    Nov 12 '18 at 16:35













0












0








0








In C#, I would use the following Dictionary



Dictionary << Date, int >>


for having an array bound to a particular date. What would be the simplest way in JS to achieve the same?



I need to be able to alter the values in the integer array.










share|improve this question
















In C#, I would use the following Dictionary



Dictionary << Date, int >>


for having an array bound to a particular date. What would be the simplest way in JS to achieve the same?



I need to be able to alter the values in the integer array.







javascript arrays






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 '18 at 16:43







John V

















asked Nov 12 '18 at 16:32









John VJohn V

1,95782546




1,95782546












  • you can create something almost the same in JS. : stackoverflow.com/questions/7196212/…

    – Budyn
    Nov 12 '18 at 16:34











  • You can use the JavaScript Map class, but be warned that equality comparison for Map keys is less flexible than in Java (and I would strongly suspect C#).

    – Pointy
    Nov 12 '18 at 16:34






  • 1





    just remember IE 8 < does not support Map function

    – Budyn
    Nov 12 '18 at 16:35

















  • you can create something almost the same in JS. : stackoverflow.com/questions/7196212/…

    – Budyn
    Nov 12 '18 at 16:34











  • You can use the JavaScript Map class, but be warned that equality comparison for Map keys is less flexible than in Java (and I would strongly suspect C#).

    – Pointy
    Nov 12 '18 at 16:34






  • 1





    just remember IE 8 < does not support Map function

    – Budyn
    Nov 12 '18 at 16:35
















you can create something almost the same in JS. : stackoverflow.com/questions/7196212/…

– Budyn
Nov 12 '18 at 16:34





you can create something almost the same in JS. : stackoverflow.com/questions/7196212/…

– Budyn
Nov 12 '18 at 16:34













You can use the JavaScript Map class, but be warned that equality comparison for Map keys is less flexible than in Java (and I would strongly suspect C#).

– Pointy
Nov 12 '18 at 16:34





You can use the JavaScript Map class, but be warned that equality comparison for Map keys is less flexible than in Java (and I would strongly suspect C#).

– Pointy
Nov 12 '18 at 16:34




1




1





just remember IE 8 < does not support Map function

– Budyn
Nov 12 '18 at 16:35





just remember IE 8 < does not support Map function

– Budyn
Nov 12 '18 at 16:35












3 Answers
3






active

oldest

votes


















1














You can achieve an equal behaviour in Js in various ways.



Dicitionary could be replaced by a Map, or just an object () with dynamic keys, however if you use an object you can only use strings as keys, anything else will be converted to a string. There is also a Date object in JS, however two dates representing the same date in time do not match:



 const a = new Date(0), b = new Date(0);
console.log(a === b); // false


therefore they would not get stored in the same entry in the Map. Instead you could just stringify the Date, as strings are conpared by value. the int would just be an array of numbers in js.



 const date1 = new Date(0);
const date1b = new Date(0);

const obj = ;
const map = new Map;

obj[date1] = [1, 2, 3];
// equals:
obj[date1.toString()] = [1, 2, 3];

map.set(date1, [1, 2, 3]);
map.set(date1.toString(), [3, 4, 5]);

console.log(
obj[date1b], // [1, 2, 3]
map.get(date1b), // undefined
map.get(date1b.toString()), // [3, 4, 5]
);



I only need to group by days




In that case, you'd have to generate a number or string out of the Date that only contains the day:



 (new Date()).toString().split("T")[0] // 2018-12-11


Then use that string as the Maps / objects key.






share|improve this answer

























  • I retrieve dates from the database and using Moment when storing them.

    – John V
    Nov 12 '18 at 16:45











  • @John then i guess the timestamp is already a string (or a number?) in that case just take that.

    – Jonas Wilms
    Nov 12 '18 at 16:47











  • May I ask - I realized the date is also saved with its time component but I only need to group by days, how can I only use the date component? I guess otherwise I will never have two records under the same key as the milliseconds will not match :)

    – John V
    Nov 12 '18 at 16:51












  • @john V ah okay, I'll edit

    – Jonas Wilms
    Nov 12 '18 at 17:03


















2














Use the timestamp of that date as a key for a js object.



For example, let's say you want to map date a to array b:






const a = new Date();
const b = [1, 2, 3];


const c =
[a.getTime()]: b,
;





in this case, c would be an object or hash map from date to array.






share|improve this answer




















  • 1





    In particular with Date instances this is not a bad idea, because the timestamp comparison is reliable and works with different Date instances. That's probably more like what the OP would expect.

    – Pointy
    Nov 12 '18 at 16:36


















1














Since you mentioned you are using momentjs, you could use the moment unix or toDate().getTime() to to get the date in ms and then utilize either an object or Map to get what you need:






let date1 = moment().unix()
let date2 = moment().add(7, 'days').unix()

let dict = // using object

dict[date1] = [1,2,3]
dict[date2] = [4,5,6]

console.log('dict via Object', dict[date1], dict[date2])

let dict2 = new Map() // using Map

dict2.set(date1, [1,2,3])
dict2.set(date2, [4,5,6])

console.log('dict via Map', dict2.get(date1), dict2.get(date2))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>








share|improve this answer




















  • 1





    you have a small typo on getTime

    – rubentd
    Nov 12 '18 at 17:09







  • 1





    Thanks :). Fixed

    – Akrion
    Nov 12 '18 at 17:10










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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














You can achieve an equal behaviour in Js in various ways.



Dicitionary could be replaced by a Map, or just an object () with dynamic keys, however if you use an object you can only use strings as keys, anything else will be converted to a string. There is also a Date object in JS, however two dates representing the same date in time do not match:



 const a = new Date(0), b = new Date(0);
console.log(a === b); // false


therefore they would not get stored in the same entry in the Map. Instead you could just stringify the Date, as strings are conpared by value. the int would just be an array of numbers in js.



 const date1 = new Date(0);
const date1b = new Date(0);

const obj = ;
const map = new Map;

obj[date1] = [1, 2, 3];
// equals:
obj[date1.toString()] = [1, 2, 3];

map.set(date1, [1, 2, 3]);
map.set(date1.toString(), [3, 4, 5]);

console.log(
obj[date1b], // [1, 2, 3]
map.get(date1b), // undefined
map.get(date1b.toString()), // [3, 4, 5]
);



I only need to group by days




In that case, you'd have to generate a number or string out of the Date that only contains the day:



 (new Date()).toString().split("T")[0] // 2018-12-11


Then use that string as the Maps / objects key.






share|improve this answer

























  • I retrieve dates from the database and using Moment when storing them.

    – John V
    Nov 12 '18 at 16:45











  • @John then i guess the timestamp is already a string (or a number?) in that case just take that.

    – Jonas Wilms
    Nov 12 '18 at 16:47











  • May I ask - I realized the date is also saved with its time component but I only need to group by days, how can I only use the date component? I guess otherwise I will never have two records under the same key as the milliseconds will not match :)

    – John V
    Nov 12 '18 at 16:51












  • @john V ah okay, I'll edit

    – Jonas Wilms
    Nov 12 '18 at 17:03















1














You can achieve an equal behaviour in Js in various ways.



Dicitionary could be replaced by a Map, or just an object () with dynamic keys, however if you use an object you can only use strings as keys, anything else will be converted to a string. There is also a Date object in JS, however two dates representing the same date in time do not match:



 const a = new Date(0), b = new Date(0);
console.log(a === b); // false


therefore they would not get stored in the same entry in the Map. Instead you could just stringify the Date, as strings are conpared by value. the int would just be an array of numbers in js.



 const date1 = new Date(0);
const date1b = new Date(0);

const obj = ;
const map = new Map;

obj[date1] = [1, 2, 3];
// equals:
obj[date1.toString()] = [1, 2, 3];

map.set(date1, [1, 2, 3]);
map.set(date1.toString(), [3, 4, 5]);

console.log(
obj[date1b], // [1, 2, 3]
map.get(date1b), // undefined
map.get(date1b.toString()), // [3, 4, 5]
);



I only need to group by days




In that case, you'd have to generate a number or string out of the Date that only contains the day:



 (new Date()).toString().split("T")[0] // 2018-12-11


Then use that string as the Maps / objects key.






share|improve this answer

























  • I retrieve dates from the database and using Moment when storing them.

    – John V
    Nov 12 '18 at 16:45











  • @John then i guess the timestamp is already a string (or a number?) in that case just take that.

    – Jonas Wilms
    Nov 12 '18 at 16:47











  • May I ask - I realized the date is also saved with its time component but I only need to group by days, how can I only use the date component? I guess otherwise I will never have two records under the same key as the milliseconds will not match :)

    – John V
    Nov 12 '18 at 16:51












  • @john V ah okay, I'll edit

    – Jonas Wilms
    Nov 12 '18 at 17:03













1












1








1







You can achieve an equal behaviour in Js in various ways.



Dicitionary could be replaced by a Map, or just an object () with dynamic keys, however if you use an object you can only use strings as keys, anything else will be converted to a string. There is also a Date object in JS, however two dates representing the same date in time do not match:



 const a = new Date(0), b = new Date(0);
console.log(a === b); // false


therefore they would not get stored in the same entry in the Map. Instead you could just stringify the Date, as strings are conpared by value. the int would just be an array of numbers in js.



 const date1 = new Date(0);
const date1b = new Date(0);

const obj = ;
const map = new Map;

obj[date1] = [1, 2, 3];
// equals:
obj[date1.toString()] = [1, 2, 3];

map.set(date1, [1, 2, 3]);
map.set(date1.toString(), [3, 4, 5]);

console.log(
obj[date1b], // [1, 2, 3]
map.get(date1b), // undefined
map.get(date1b.toString()), // [3, 4, 5]
);



I only need to group by days




In that case, you'd have to generate a number or string out of the Date that only contains the day:



 (new Date()).toString().split("T")[0] // 2018-12-11


Then use that string as the Maps / objects key.






share|improve this answer















You can achieve an equal behaviour in Js in various ways.



Dicitionary could be replaced by a Map, or just an object () with dynamic keys, however if you use an object you can only use strings as keys, anything else will be converted to a string. There is also a Date object in JS, however two dates representing the same date in time do not match:



 const a = new Date(0), b = new Date(0);
console.log(a === b); // false


therefore they would not get stored in the same entry in the Map. Instead you could just stringify the Date, as strings are conpared by value. the int would just be an array of numbers in js.



 const date1 = new Date(0);
const date1b = new Date(0);

const obj = ;
const map = new Map;

obj[date1] = [1, 2, 3];
// equals:
obj[date1.toString()] = [1, 2, 3];

map.set(date1, [1, 2, 3]);
map.set(date1.toString(), [3, 4, 5]);

console.log(
obj[date1b], // [1, 2, 3]
map.get(date1b), // undefined
map.get(date1b.toString()), // [3, 4, 5]
);



I only need to group by days




In that case, you'd have to generate a number or string out of the Date that only contains the day:



 (new Date()).toString().split("T")[0] // 2018-12-11


Then use that string as the Maps / objects key.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 12 '18 at 17:05

























answered Nov 12 '18 at 16:43









Jonas WilmsJonas Wilms

56.4k42851




56.4k42851












  • I retrieve dates from the database and using Moment when storing them.

    – John V
    Nov 12 '18 at 16:45











  • @John then i guess the timestamp is already a string (or a number?) in that case just take that.

    – Jonas Wilms
    Nov 12 '18 at 16:47











  • May I ask - I realized the date is also saved with its time component but I only need to group by days, how can I only use the date component? I guess otherwise I will never have two records under the same key as the milliseconds will not match :)

    – John V
    Nov 12 '18 at 16:51












  • @john V ah okay, I'll edit

    – Jonas Wilms
    Nov 12 '18 at 17:03

















  • I retrieve dates from the database and using Moment when storing them.

    – John V
    Nov 12 '18 at 16:45











  • @John then i guess the timestamp is already a string (or a number?) in that case just take that.

    – Jonas Wilms
    Nov 12 '18 at 16:47











  • May I ask - I realized the date is also saved with its time component but I only need to group by days, how can I only use the date component? I guess otherwise I will never have two records under the same key as the milliseconds will not match :)

    – John V
    Nov 12 '18 at 16:51












  • @john V ah okay, I'll edit

    – Jonas Wilms
    Nov 12 '18 at 17:03
















I retrieve dates from the database and using Moment when storing them.

– John V
Nov 12 '18 at 16:45





I retrieve dates from the database and using Moment when storing them.

– John V
Nov 12 '18 at 16:45













@John then i guess the timestamp is already a string (or a number?) in that case just take that.

– Jonas Wilms
Nov 12 '18 at 16:47





@John then i guess the timestamp is already a string (or a number?) in that case just take that.

– Jonas Wilms
Nov 12 '18 at 16:47













May I ask - I realized the date is also saved with its time component but I only need to group by days, how can I only use the date component? I guess otherwise I will never have two records under the same key as the milliseconds will not match :)

– John V
Nov 12 '18 at 16:51






May I ask - I realized the date is also saved with its time component but I only need to group by days, how can I only use the date component? I guess otherwise I will never have two records under the same key as the milliseconds will not match :)

– John V
Nov 12 '18 at 16:51














@john V ah okay, I'll edit

– Jonas Wilms
Nov 12 '18 at 17:03





@john V ah okay, I'll edit

– Jonas Wilms
Nov 12 '18 at 17:03













2














Use the timestamp of that date as a key for a js object.



For example, let's say you want to map date a to array b:






const a = new Date();
const b = [1, 2, 3];


const c =
[a.getTime()]: b,
;





in this case, c would be an object or hash map from date to array.






share|improve this answer




















  • 1





    In particular with Date instances this is not a bad idea, because the timestamp comparison is reliable and works with different Date instances. That's probably more like what the OP would expect.

    – Pointy
    Nov 12 '18 at 16:36















2














Use the timestamp of that date as a key for a js object.



For example, let's say you want to map date a to array b:






const a = new Date();
const b = [1, 2, 3];


const c =
[a.getTime()]: b,
;





in this case, c would be an object or hash map from date to array.






share|improve this answer




















  • 1





    In particular with Date instances this is not a bad idea, because the timestamp comparison is reliable and works with different Date instances. That's probably more like what the OP would expect.

    – Pointy
    Nov 12 '18 at 16:36













2












2








2







Use the timestamp of that date as a key for a js object.



For example, let's say you want to map date a to array b:






const a = new Date();
const b = [1, 2, 3];


const c =
[a.getTime()]: b,
;





in this case, c would be an object or hash map from date to array.






share|improve this answer















Use the timestamp of that date as a key for a js object.



For example, let's say you want to map date a to array b:






const a = new Date();
const b = [1, 2, 3];


const c =
[a.getTime()]: b,
;





in this case, c would be an object or hash map from date to array.






const a = new Date();
const b = [1, 2, 3];


const c =
[a.getTime()]: b,
;





const a = new Date();
const b = [1, 2, 3];


const c =
[a.getTime()]: b,
;






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 12 '18 at 16:37

























answered Nov 12 '18 at 16:35









rubentdrubentd

1,077821




1,077821







  • 1





    In particular with Date instances this is not a bad idea, because the timestamp comparison is reliable and works with different Date instances. That's probably more like what the OP would expect.

    – Pointy
    Nov 12 '18 at 16:36












  • 1





    In particular with Date instances this is not a bad idea, because the timestamp comparison is reliable and works with different Date instances. That's probably more like what the OP would expect.

    – Pointy
    Nov 12 '18 at 16:36







1




1





In particular with Date instances this is not a bad idea, because the timestamp comparison is reliable and works with different Date instances. That's probably more like what the OP would expect.

– Pointy
Nov 12 '18 at 16:36





In particular with Date instances this is not a bad idea, because the timestamp comparison is reliable and works with different Date instances. That's probably more like what the OP would expect.

– Pointy
Nov 12 '18 at 16:36











1














Since you mentioned you are using momentjs, you could use the moment unix or toDate().getTime() to to get the date in ms and then utilize either an object or Map to get what you need:






let date1 = moment().unix()
let date2 = moment().add(7, 'days').unix()

let dict = // using object

dict[date1] = [1,2,3]
dict[date2] = [4,5,6]

console.log('dict via Object', dict[date1], dict[date2])

let dict2 = new Map() // using Map

dict2.set(date1, [1,2,3])
dict2.set(date2, [4,5,6])

console.log('dict via Map', dict2.get(date1), dict2.get(date2))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>








share|improve this answer




















  • 1





    you have a small typo on getTime

    – rubentd
    Nov 12 '18 at 17:09







  • 1





    Thanks :). Fixed

    – Akrion
    Nov 12 '18 at 17:10















1














Since you mentioned you are using momentjs, you could use the moment unix or toDate().getTime() to to get the date in ms and then utilize either an object or Map to get what you need:






let date1 = moment().unix()
let date2 = moment().add(7, 'days').unix()

let dict = // using object

dict[date1] = [1,2,3]
dict[date2] = [4,5,6]

console.log('dict via Object', dict[date1], dict[date2])

let dict2 = new Map() // using Map

dict2.set(date1, [1,2,3])
dict2.set(date2, [4,5,6])

console.log('dict via Map', dict2.get(date1), dict2.get(date2))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>








share|improve this answer




















  • 1





    you have a small typo on getTime

    – rubentd
    Nov 12 '18 at 17:09







  • 1





    Thanks :). Fixed

    – Akrion
    Nov 12 '18 at 17:10













1












1








1







Since you mentioned you are using momentjs, you could use the moment unix or toDate().getTime() to to get the date in ms and then utilize either an object or Map to get what you need:






let date1 = moment().unix()
let date2 = moment().add(7, 'days').unix()

let dict = // using object

dict[date1] = [1,2,3]
dict[date2] = [4,5,6]

console.log('dict via Object', dict[date1], dict[date2])

let dict2 = new Map() // using Map

dict2.set(date1, [1,2,3])
dict2.set(date2, [4,5,6])

console.log('dict via Map', dict2.get(date1), dict2.get(date2))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>








share|improve this answer















Since you mentioned you are using momentjs, you could use the moment unix or toDate().getTime() to to get the date in ms and then utilize either an object or Map to get what you need:






let date1 = moment().unix()
let date2 = moment().add(7, 'days').unix()

let dict = // using object

dict[date1] = [1,2,3]
dict[date2] = [4,5,6]

console.log('dict via Object', dict[date1], dict[date2])

let dict2 = new Map() // using Map

dict2.set(date1, [1,2,3])
dict2.set(date2, [4,5,6])

console.log('dict via Map', dict2.get(date1), dict2.get(date2))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>








let date1 = moment().unix()
let date2 = moment().add(7, 'days').unix()

let dict = // using object

dict[date1] = [1,2,3]
dict[date2] = [4,5,6]

console.log('dict via Object', dict[date1], dict[date2])

let dict2 = new Map() // using Map

dict2.set(date1, [1,2,3])
dict2.set(date2, [4,5,6])

console.log('dict via Map', dict2.get(date1), dict2.get(date2))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>





let date1 = moment().unix()
let date2 = moment().add(7, 'days').unix()

let dict = // using object

dict[date1] = [1,2,3]
dict[date2] = [4,5,6]

console.log('dict via Object', dict[date1], dict[date2])

let dict2 = new Map() // using Map

dict2.set(date1, [1,2,3])
dict2.set(date2, [4,5,6])

console.log('dict via Map', dict2.get(date1), dict2.get(date2))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.min.js"></script>






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edited Nov 12 '18 at 17:10

























answered Nov 12 '18 at 17:03









AkrionAkrion

9,40211224




9,40211224







  • 1





    you have a small typo on getTime

    – rubentd
    Nov 12 '18 at 17:09







  • 1





    Thanks :). Fixed

    – Akrion
    Nov 12 '18 at 17:10












  • 1





    you have a small typo on getTime

    – rubentd
    Nov 12 '18 at 17:09







  • 1





    Thanks :). Fixed

    – Akrion
    Nov 12 '18 at 17:10







1




1





you have a small typo on getTime

– rubentd
Nov 12 '18 at 17:09






you have a small typo on getTime

– rubentd
Nov 12 '18 at 17:09





1




1





Thanks :). Fixed

– Akrion
Nov 12 '18 at 17:10





Thanks :). Fixed

– Akrion
Nov 12 '18 at 17:10

















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