Javascript Error using cryptico library for decryption
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0
I have a string let's say choice="text to encrypt and decrypt"
I am using a public key I produced with another program to encrypt and it works fine. I get the cipher text and try to decrypt it, but I am getting the following error.
script.js:282 the pub key is : 021e645806ee84055b51------675e75f93d41c407b7826cf1e76c10aaa05dfc8e
script.js:291 the cipher text is: gkEJlPREx/EVPUue3vWlDWImilRrnyUmeNpkvSbY1vVLqf6IYoBqk9H/PBwXXck++Q==?T+kht1n981qDPmJc7H3DrFxqRi2oe6OFu60ASI389Rg=
script.js:303 the priv key is : 2293f6d33--------f37cc02674edec14eae9586c4fab5bd2a89631f10237b13
cryptico.js:3499 Uncaught TypeError: ciphertext.split is not a function
at Object.my.decrypt (cryptico.js:3499)
at Object.success (script.js:306)
at u (jquery.min.js:2)
at Object.fireWith [as resolveWith] (jquery.min.js:2)
at k (jquery.min.js:2)
at XMLHttpRequest.<anonymous> (jquery.min.js:2)
and when I look for the error it stops at the second line of the decrypt function
my.decrypt = function(ciphertext, key)
var cipherblock = ciphertext.split("?");
var aeskey = key.decrypt(my.b64to16(cipherblock[0]));
I understand that the cipher code splits on the "?" but I can see that I have it in my cipher code. What can be wrong?
p.s. I added the dashes to the keys replacing the original values
@UPDATE
I used the example from this page https://github.com/wwwtyro/cryptico and I was getting the same error. So I changed the code as follows
let EncryptionResult = cryptico.encrypt(choice, pub_key);
let DecryptionResult = cryptico.decrypt(EncryptionResult.cipher, priv_key);
Now it passes the original error but I am getting a second error
cryptico.js:3500 Uncaught TypeError: key.decrypt is not a function
at Object.my.decrypt (cryptico.js:3500)
at Object.success (script.js:303)
at u (jquery.min.js:2)
at Object.fireWith [as resolveWith] (jquery.min.js:2)
at k (jquery.min.js:2)
at XMLHttpRequest.<anonymous> (jquery.min.js:2)
enter code here
and it stops at the second line var aeskey = key.decrypt(my.b64to16(cipherblock[0])); . Does this have to do anything with base64?? My keys are hex encoded, I don't know if this helps.
javascript encryption rsa cryptico
asked Nov 15 '18 at 13:47
CheetaraCheetara
338
|
show 4 more comments
0
I have a string let's say choice="text to encrypt and decrypt"
I am using a public key I produced with another program to encrypt and it works fine. I get the cipher text and try to decrypt it, but I am getting the following error.
script.js:282 the pub key is : 021e645806ee84055b51------675e75f93d41c407b7826cf1e76c10aaa05dfc8e
script.js:291 the cipher text is: gkEJlPREx/EVPUue3vWlDWImilRrnyUmeNpkvSbY1vVLqf6IYoBqk9H/PBwXXck++Q==?T+kht1n981qDPmJc7H3DrFxqRi2oe6OFu60ASI389Rg=
script.js:303 the priv key is : 2293f6d33--------f37cc02674edec14eae9586c4fab5bd2a89631f10237b13
cryptico.js:3499 Uncaught TypeError: ciphertext.split is not a function
at Object.my.decrypt (cryptico.js:3499)
at Object.success (script.js:306)
at u (jquery.min.js:2)
at Object.fireWith [as resolveWith] (jquery.min.js:2)
at k (jquery.min.js:2)
at XMLHttpRequest.<anonymous> (jquery.min.js:2)
and when I look for the error it stops at the second line of the decrypt function
my.decrypt = function(ciphertext, key)
var cipherblock = ciphertext.split("?");
var aeskey = key.decrypt(my.b64to16(cipherblock[0]));
I understand that the cipher code splits on the "?" but I can see that I have it in my cipher code. What can be wrong?
p.s. I added the dashes to the keys replacing the original values
@UPDATE
I used the example from this page https://github.com/wwwtyro/cryptico and I was getting the same error. So I changed the code as follows
let EncryptionResult = cryptico.encrypt(choice, pub_key);
let DecryptionResult = cryptico.decrypt(EncryptionResult.cipher, priv_key);
Now it passes the original error but I am getting a second error
cryptico.js:3500 Uncaught TypeError: key.decrypt is not a function
at Object.my.decrypt (cryptico.js:3500)
at Object.success (script.js:303)
at u (jquery.min.js:2)
at Object.fireWith [as resolveWith] (jquery.min.js:2)
at k (jquery.min.js:2)
at XMLHttpRequest.<anonymous> (jquery.min.js:2)
enter code here
and it stops at the second line var aeskey = key.decrypt(my.b64to16(cipherblock[0])); . Does this have to do anything with base64?? My keys are hex encoded, I don't know if this helps.
javascript encryption rsa cryptico
asked Nov 15 '18 at 13:47
CheetaraCheetara
338
1
your error suggests that yourciphertextvariable is not a string, what does showconsole.log(typeof ciphertext);?
– Kaddath
Nov 15 '18 at 13:50
It shows string. But you where right, I was using the variable without the ".cipher" extension. This passed the original problem but no I am getting Uncaught TypeError: key.decrypt is not a function
– Cheetara
Nov 15 '18 at 14:03
The new error suggests that your second parameter given tocryptico.decrypt,priv_keyshouldn't be a string but an object that should have adecryptfunction. Don't have time to check the examples, but i guess this parameter should be constructed with the library?
– Kaddath
Nov 15 '18 at 16:11
1
There's a very strong chance that it doesn't support a key from another library, as it directly runs functions on it without testing their existence. But it's quite normal if the library expects an object instead of something simple like a string (and usual in cryptography). You can try to build a cryptico key object from your existing key object properties if you are forced to use another lib for the keys. If you run into troubles, that's probably subject for a new question with a more precise title instead of editing this one.. (you can still link the new question here for me if the case)
– Kaddath
Nov 16 '18 at 9:24
1
Very helpful information and answers :-) I consider the question as completely answered! You saved my day.
– Cheetara
Nov 16 '18 at 11:03
|
show 4 more comments
0
0
0
I have a string let's say choice="text to encrypt and decrypt"
I am using a public key I produced with another program to encrypt and it works fine. I get the cipher text and try to decrypt it, but I am getting the following error.
script.js:282 the pub key is : 021e645806ee84055b51------675e75f93d41c407b7826cf1e76c10aaa05dfc8e
script.js:291 the cipher text is: gkEJlPREx/EVPUue3vWlDWImilRrnyUmeNpkvSbY1vVLqf6IYoBqk9H/PBwXXck++Q==?T+kht1n981qDPmJc7H3DrFxqRi2oe6OFu60ASI389Rg=
script.js:303 the priv key is : 2293f6d33--------f37cc02674edec14eae9586c4fab5bd2a89631f10237b13
cryptico.js:3499 Uncaught TypeError: ciphertext.split is not a function
at Object.my.decrypt (cryptico.js:3499)
at Object.success (script.js:306)
at u (jquery.min.js:2)
at Object.fireWith [as resolveWith] (jquery.min.js:2)
at k (jquery.min.js:2)
at XMLHttpRequest.<anonymous> (jquery.min.js:2)
and when I look for the error it stops at the second line of the decrypt function
my.decrypt = function(ciphertext, key)
var cipherblock = ciphertext.split("?");
var aeskey = key.decrypt(my.b64to16(cipherblock[0]));
I understand that the cipher code splits on the "?" but I can see that I have it in my cipher code. What can be wrong?
p.s. I added the dashes to the keys replacing the original values
@UPDATE
I used the example from this page https://github.com/wwwtyro/cryptico and I was getting the same error. So I changed the code as follows
let EncryptionResult = cryptico.encrypt(choice, pub_key);
let DecryptionResult = cryptico.decrypt(EncryptionResult.cipher, priv_key);
Now it passes the original error but I am getting a second error
cryptico.js:3500 Uncaught TypeError: key.decrypt is not a function
at Object.my.decrypt (cryptico.js:3500)
at Object.success (script.js:303)
at u (jquery.min.js:2)
at Object.fireWith [as resolveWith] (jquery.min.js:2)
at k (jquery.min.js:2)
at XMLHttpRequest.<anonymous> (jquery.min.js:2)
enter code here
and it stops at the second line var aeskey = key.decrypt(my.b64to16(cipherblock[0])); . Does this have to do anything with base64?? My keys are hex encoded, I don't know if this helps.
javascript encryption rsa cryptico
asked Nov 15 '18 at 13:47
CheetaraCheetara
338
I have a string let's say choice="text to encrypt and decrypt"
I am using a public key I produced with another program to encrypt and it works fine. I get the cipher text and try to decrypt it, but I am getting the following error.
script.js:282 the pub key is : 021e645806ee84055b51------675e75f93d41c407b7826cf1e76c10aaa05dfc8e
script.js:291 the cipher text is: gkEJlPREx/EVPUue3vWlDWImilRrnyUmeNpkvSbY1vVLqf6IYoBqk9H/PBwXXck++Q==?T+kht1n981qDPmJc7H3DrFxqRi2oe6OFu60ASI389Rg=
script.js:303 the priv key is : 2293f6d33--------f37cc02674edec14eae9586c4fab5bd2a89631f10237b13
cryptico.js:3499 Uncaught TypeError: ciphertext.split is not a function
at Object.my.decrypt (cryptico.js:3499)
at Object.success (script.js:306)
at u (jquery.min.js:2)
at Object.fireWith [as resolveWith] (jquery.min.js:2)
at k (jquery.min.js:2)
at XMLHttpRequest.<anonymous> (jquery.min.js:2)
and when I look for the error it stops at the second line of the decrypt function
my.decrypt = function(ciphertext, key)
var cipherblock = ciphertext.split("?");
var aeskey = key.decrypt(my.b64to16(cipherblock[0]));
I understand that the cipher code splits on the "?" but I can see that I have it in my cipher code. What can be wrong?
p.s. I added the dashes to the keys replacing the original values
@UPDATE
I used the example from this page https://github.com/wwwtyro/cryptico and I was getting the same error. So I changed the code as follows
let EncryptionResult = cryptico.encrypt(choice, pub_key);
let DecryptionResult = cryptico.decrypt(EncryptionResult.cipher, priv_key);
Now it passes the original error but I am getting a second error
cryptico.js:3500 Uncaught TypeError: key.decrypt is not a function
at Object.my.decrypt (cryptico.js:3500)
at Object.success (script.js:303)
at u (jquery.min.js:2)
at Object.fireWith [as resolveWith] (jquery.min.js:2)
at k (jquery.min.js:2)
at XMLHttpRequest.<anonymous> (jquery.min.js:2)
enter code here
and it stops at the second line var aeskey = key.decrypt(my.b64to16(cipherblock[0])); . Does this have to do anything with base64?? My keys are hex encoded, I don't know if this helps.
javascript encryption rsa cryptico
javascript encryption rsa cryptico
asked Nov 15 '18 at 13:47
CheetaraCheetara
338
asked Nov 15 '18 at 13:47
CheetaraCheetara
338
edited Nov 15 '18 at 14:12
Cheetara
asked Nov 15 '18 at 13:47
CheetaraCheetara
338
asked Nov 15 '18 at 13:47
CheetaraCheetara
338
asked Nov 15 '18 at 13:47
CheetaraCheetara
338
338
1
your error suggests that yourciphertextvariable is not a string, what does showconsole.log(typeof ciphertext);?
– Kaddath
Nov 15 '18 at 13:50
It shows string. But you where right, I was using the variable without the ".cipher" extension. This passed the original problem but no I am getting Uncaught TypeError: key.decrypt is not a function
– Cheetara
Nov 15 '18 at 14:03
The new error suggests that your second parameter given tocryptico.decrypt,priv_keyshouldn't be a string but an object that should have adecryptfunction. Don't have time to check the examples, but i guess this parameter should be constructed with the library?
– Kaddath
Nov 15 '18 at 16:11
1
There's a very strong chance that it doesn't support a key from another library, as it directly runs functions on it without testing their existence. But it's quite normal if the library expects an object instead of something simple like a string (and usual in cryptography). You can try to build a cryptico key object from your existing key object properties if you are forced to use another lib for the keys. If you run into troubles, that's probably subject for a new question with a more precise title instead of editing this one.. (you can still link the new question here for me if the case)
– Kaddath
Nov 16 '18 at 9:24
1
Very helpful information and answers :-) I consider the question as completely answered! You saved my day.
– Cheetara
Nov 16 '18 at 11:03
|
show 4 more comments
1
your error suggests that yourciphertextvariable is not a string, what does showconsole.log(typeof ciphertext);?
– Kaddath
Nov 15 '18 at 13:50
It shows string. But you where right, I was using the variable without the ".cipher" extension. This passed the original problem but no I am getting Uncaught TypeError: key.decrypt is not a function
– Cheetara
Nov 15 '18 at 14:03
The new error suggests that your second parameter given tocryptico.decrypt,priv_keyshouldn't be a string but an object that should have adecryptfunction. Don't have time to check the examples, but i guess this parameter should be constructed with the library?
– Kaddath
Nov 15 '18 at 16:11
1
There's a very strong chance that it doesn't support a key from another library, as it directly runs functions on it without testing their existence. But it's quite normal if the library expects an object instead of something simple like a string (and usual in cryptography). You can try to build a cryptico key object from your existing key object properties if you are forced to use another lib for the keys. If you run into troubles, that's probably subject for a new question with a more precise title instead of editing this one.. (you can still link the new question here for me if the case)
– Kaddath
Nov 16 '18 at 9:24
1
Very helpful information and answers :-) I consider the question as completely answered! You saved my day.
– Cheetara
Nov 16 '18 at 11:03
1
1
your error suggests that your
ciphertext variable is not a string, what does show console.log(typeof ciphertext);?– Kaddath
Nov 15 '18 at 13:50
your error suggests that your
ciphertext variable is not a string, what does show console.log(typeof ciphertext);?– Kaddath
Nov 15 '18 at 13:50
It shows string. But you where right, I was using the variable without the ".cipher" extension. This passed the original problem but no I am getting Uncaught TypeError: key.decrypt is not a function
– Cheetara
Nov 15 '18 at 14:03
It shows string. But you where right, I was using the variable without the ".cipher" extension. This passed the original problem but no I am getting Uncaught TypeError: key.decrypt is not a function
– Cheetara
Nov 15 '18 at 14:03
The new error suggests that your second parameter given to
cryptico.decrypt, priv_key shouldn't be a string but an object that should have a decrypt function. Don't have time to check the examples, but i guess this parameter should be constructed with the library?– Kaddath
Nov 15 '18 at 16:11
The new error suggests that your second parameter given to
cryptico.decrypt, priv_key shouldn't be a string but an object that should have a decrypt function. Don't have time to check the examples, but i guess this parameter should be constructed with the library?– Kaddath
Nov 15 '18 at 16:11
1
1
There's a very strong chance that it doesn't support a key from another library, as it directly runs functions on it without testing their existence. But it's quite normal if the library expects an object instead of something simple like a string (and usual in cryptography). You can try to build a cryptico key object from your existing key object properties if you are forced to use another lib for the keys. If you run into troubles, that's probably subject for a new question with a more precise title instead of editing this one.. (you can still link the new question here for me if the case)
– Kaddath
Nov 16 '18 at 9:24
There's a very strong chance that it doesn't support a key from another library, as it directly runs functions on it without testing their existence. But it's quite normal if the library expects an object instead of something simple like a string (and usual in cryptography). You can try to build a cryptico key object from your existing key object properties if you are forced to use another lib for the keys. If you run into troubles, that's probably subject for a new question with a more precise title instead of editing this one.. (you can still link the new question here for me if the case)
– Kaddath
Nov 16 '18 at 9:24
1
1
Very helpful information and answers :-) I consider the question as completely answered! You saved my day.
– Cheetara
Nov 16 '18 at 11:03
Very helpful information and answers :-) I consider the question as completely answered! You saved my day.
– Cheetara
Nov 16 '18 at 11:03
|
show 4 more comments
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1
your error suggests that your
ciphertextvariable is not a string, what does showconsole.log(typeof ciphertext);?– Kaddath
Nov 15 '18 at 13:50
It shows string. But you where right, I was using the variable without the ".cipher" extension. This passed the original problem but no I am getting Uncaught TypeError: key.decrypt is not a function
– Cheetara
Nov 15 '18 at 14:03
The new error suggests that your second parameter given to
cryptico.decrypt,priv_keyshouldn't be a string but an object that should have adecryptfunction. Don't have time to check the examples, but i guess this parameter should be constructed with the library?– Kaddath
Nov 15 '18 at 16:11
1
There's a very strong chance that it doesn't support a key from another library, as it directly runs functions on it without testing their existence. But it's quite normal if the library expects an object instead of something simple like a string (and usual in cryptography). You can try to build a cryptico key object from your existing key object properties if you are forced to use another lib for the keys. If you run into troubles, that's probably subject for a new question with a more precise title instead of editing this one.. (you can still link the new question here for me if the case)
– Kaddath
Nov 16 '18 at 9:24
1
Very helpful information and answers :-) I consider the question as completely answered! You saved my day.
– Cheetara
Nov 16 '18 at 11:03