`“apue.h”`is not a global environment PATH , but program can retrieve it









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I am learning from APUE3e



#include "apue.h"
#include <dirent.h>

int main(int argc, char *argv)
{
DIR *dp;
struct dirent *dirp;
....


In the header, import a user-definded module "apue.h". the program run correctly after compiled.



The apue.h is placed in /Library/Developer/CommandLineTools/usr/include,



What confuse me is that /Library/Developer/CommandLineTools/usr/include is not in the $PATH but could be retrieved by the program globally.



$ echo $PATH | grep include
#does not return anything.


How could the program get it done?










share|improve this question

























    up vote
    0
    down vote

    favorite












    I am learning from APUE3e



    #include "apue.h"
    #include <dirent.h>

    int main(int argc, char *argv)
    {
    DIR *dp;
    struct dirent *dirp;
    ....


    In the header, import a user-definded module "apue.h". the program run correctly after compiled.



    The apue.h is placed in /Library/Developer/CommandLineTools/usr/include,



    What confuse me is that /Library/Developer/CommandLineTools/usr/include is not in the $PATH but could be retrieved by the program globally.



    $ echo $PATH | grep include
    #does not return anything.


    How could the program get it done?










    share|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I am learning from APUE3e



      #include "apue.h"
      #include <dirent.h>

      int main(int argc, char *argv)
      {
      DIR *dp;
      struct dirent *dirp;
      ....


      In the header, import a user-definded module "apue.h". the program run correctly after compiled.



      The apue.h is placed in /Library/Developer/CommandLineTools/usr/include,



      What confuse me is that /Library/Developer/CommandLineTools/usr/include is not in the $PATH but could be retrieved by the program globally.



      $ echo $PATH | grep include
      #does not return anything.


      How could the program get it done?










      share|improve this question













      I am learning from APUE3e



      #include "apue.h"
      #include <dirent.h>

      int main(int argc, char *argv)
      {
      DIR *dp;
      struct dirent *dirp;
      ....


      In the header, import a user-definded module "apue.h". the program run correctly after compiled.



      The apue.h is placed in /Library/Developer/CommandLineTools/usr/include,



      What confuse me is that /Library/Developer/CommandLineTools/usr/include is not in the $PATH but could be retrieved by the program globally.



      $ echo $PATH | grep include
      #does not return anything.


      How could the program get it done?







      c






      share|improve this question













      share|improve this question











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      share|improve this question










      asked Nov 10 at 11:03









      avirate

      647113




      647113






















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          $PATH is where the shell looks for executables, not header files. This answer shows how you can get the compiler to show you where it's looking for header files.






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            1 Answer
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            active

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            active

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            up vote
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            $PATH is where the shell looks for executables, not header files. This answer shows how you can get the compiler to show you where it's looking for header files.






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              up vote
              1
              down vote



              accepted










              $PATH is where the shell looks for executables, not header files. This answer shows how you can get the compiler to show you where it's looking for header files.






              share|improve this answer






















                up vote
                1
                down vote



                accepted







                up vote
                1
                down vote



                accepted






                $PATH is where the shell looks for executables, not header files. This answer shows how you can get the compiler to show you where it's looking for header files.






                share|improve this answer












                $PATH is where the shell looks for executables, not header files. This answer shows how you can get the compiler to show you where it's looking for header files.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 10 at 11:05









                Bruce Collie

                4005




                4005



























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