phpBB and login query









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I want to change my auth method from giving the username/password to giving the user ID/password.



I checked the auth.php file ( in /phpbb/auth/auth.php ) which includes the login() function. I've found a query :



$sql = 'SELECT user_id, username, user_password, user_passchg, user_pass_convert, user_email, user_type, user_login_attempts
FROM ' . USERS_TABLE . "
WHERE username_clean = '" . $this->db->sql_escape($username_clean) . "'";


I've changed it into :



$sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
FROM ' . USERS_TABLE . "
WHERE user_id == ' . $user_id . '";


But I'm not able to log with my ID/password.










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    up vote
    -1
    down vote

    favorite












    I want to change my auth method from giving the username/password to giving the user ID/password.



    I checked the auth.php file ( in /phpbb/auth/auth.php ) which includes the login() function. I've found a query :



    $sql = 'SELECT user_id, username, user_password, user_passchg, user_pass_convert, user_email, user_type, user_login_attempts
    FROM ' . USERS_TABLE . "
    WHERE username_clean = '" . $this->db->sql_escape($username_clean) . "'";


    I've changed it into :



    $sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
    FROM ' . USERS_TABLE . "
    WHERE user_id == ' . $user_id . '";


    But I'm not able to log with my ID/password.










    share|improve this question

























      up vote
      -1
      down vote

      favorite









      up vote
      -1
      down vote

      favorite











      I want to change my auth method from giving the username/password to giving the user ID/password.



      I checked the auth.php file ( in /phpbb/auth/auth.php ) which includes the login() function. I've found a query :



      $sql = 'SELECT user_id, username, user_password, user_passchg, user_pass_convert, user_email, user_type, user_login_attempts
      FROM ' . USERS_TABLE . "
      WHERE username_clean = '" . $this->db->sql_escape($username_clean) . "'";


      I've changed it into :



      $sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
      FROM ' . USERS_TABLE . "
      WHERE user_id == ' . $user_id . '";


      But I'm not able to log with my ID/password.










      share|improve this question















      I want to change my auth method from giving the username/password to giving the user ID/password.



      I checked the auth.php file ( in /phpbb/auth/auth.php ) which includes the login() function. I've found a query :



      $sql = 'SELECT user_id, username, user_password, user_passchg, user_pass_convert, user_email, user_type, user_login_attempts
      FROM ' . USERS_TABLE . "
      WHERE username_clean = '" . $this->db->sql_escape($username_clean) . "'";


      I've changed it into :



      $sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
      FROM ' . USERS_TABLE . "
      WHERE user_id == ' . $user_id . '";


      But I'm not able to log with my ID/password.







      php sql phpbb






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      share|improve this question




      share|improve this question








      edited Nov 10 at 12:49









      AS Mackay

      1,7853816




      1,7853816










      asked Nov 10 at 9:50









      Germain P

      93




      93






















          1 Answer
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          You are mixing up your ' and " signs which is inevitably breaking your query. Instead of $user_id variable value being inserted into the query, it is literally inserting $user_id.



          $sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
          FROM ' . USERS_TABLE . ' WHERE user_id == ' . $user_id . ';


          That would fix that issue. Even still I think you are only supposed to have a single '=' and there appears to be some more issues.



          Also I assume $user_id is an integer, but if it's a user-inputted string, then please sanitize it to prevent SQL Injection.






          share|improve this answer




















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            1 Answer
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            1 Answer
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            active

            oldest

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            active

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            up vote
            0
            down vote













            You are mixing up your ' and " signs which is inevitably breaking your query. Instead of $user_id variable value being inserted into the query, it is literally inserting $user_id.



            $sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
            FROM ' . USERS_TABLE . ' WHERE user_id == ' . $user_id . ';


            That would fix that issue. Even still I think you are only supposed to have a single '=' and there appears to be some more issues.



            Also I assume $user_id is an integer, but if it's a user-inputted string, then please sanitize it to prevent SQL Injection.






            share|improve this answer
























              up vote
              0
              down vote













              You are mixing up your ' and " signs which is inevitably breaking your query. Instead of $user_id variable value being inserted into the query, it is literally inserting $user_id.



              $sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
              FROM ' . USERS_TABLE . ' WHERE user_id == ' . $user_id . ';


              That would fix that issue. Even still I think you are only supposed to have a single '=' and there appears to be some more issues.



              Also I assume $user_id is an integer, but if it's a user-inputted string, then please sanitize it to prevent SQL Injection.






              share|improve this answer






















                up vote
                0
                down vote










                up vote
                0
                down vote









                You are mixing up your ' and " signs which is inevitably breaking your query. Instead of $user_id variable value being inserted into the query, it is literally inserting $user_id.



                $sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
                FROM ' . USERS_TABLE . ' WHERE user_id == ' . $user_id . ';


                That would fix that issue. Even still I think you are only supposed to have a single '=' and there appears to be some more issues.



                Also I assume $user_id is an integer, but if it's a user-inputted string, then please sanitize it to prevent SQL Injection.






                share|improve this answer












                You are mixing up your ' and " signs which is inevitably breaking your query. Instead of $user_id variable value being inserted into the query, it is literally inserting $user_id.



                $sql = 'SELECT user_id, username, user_password, user_passchg, user_email, user_type
                FROM ' . USERS_TABLE . ' WHERE user_id == ' . $user_id . ';


                That would fix that issue. Even still I think you are only supposed to have a single '=' and there appears to be some more issues.



                Also I assume $user_id is an integer, but if it's a user-inputted string, then please sanitize it to prevent SQL Injection.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 10 at 12:57









                Cillian Collins

                6477




                6477



























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