How to find Time complexity of Graph coloring using backtracking?









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I have to find out the time complexity of graph coloring problem using backtracking. I have found somewhere it is O(n*m^n) where n=no vertex and m= number of color.



Suppose my code is given below how to find time complexity?



bool isSafe (int v, bool graph[V][V], int color, int c)

for (int i = 0; i < V; i++)
if (graph[v][i] && c == color[i])
return false;
return true;


bool graphColoringUtil(bool graph[V][V], int m, int color, int v)

if (v == V)
return true;

for (int c = 1; c <= m; c++)

if (isSafe(v, graph, color, c))

color[v] = c;

if (graphColoringUtil (graph, m, color, v+1) == true)
return true;

color[v] = 0;



return false;

bool graphColoring(bool graph[V][V], int m)

int *color = new int[V];
for (int i = 0; i < V; i++)
color[i] = 0;

if (graphColoringUtil(graph, m, color, 0) == false)

printf("Solution does not existn");
return false;


printSolution(color);
return true;

void printSolution(int color)

printf("Solution Exists:"
" Following are the assigned colors n");
for (int i = 0; i < V; i++)
printf(" %d ", color[i]);
printf("n");










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    up vote
    1
    down vote

    favorite












    I have to find out the time complexity of graph coloring problem using backtracking. I have found somewhere it is O(n*m^n) where n=no vertex and m= number of color.



    Suppose my code is given below how to find time complexity?



    bool isSafe (int v, bool graph[V][V], int color, int c)

    for (int i = 0; i < V; i++)
    if (graph[v][i] && c == color[i])
    return false;
    return true;


    bool graphColoringUtil(bool graph[V][V], int m, int color, int v)

    if (v == V)
    return true;

    for (int c = 1; c <= m; c++)

    if (isSafe(v, graph, color, c))

    color[v] = c;

    if (graphColoringUtil (graph, m, color, v+1) == true)
    return true;

    color[v] = 0;



    return false;

    bool graphColoring(bool graph[V][V], int m)

    int *color = new int[V];
    for (int i = 0; i < V; i++)
    color[i] = 0;

    if (graphColoringUtil(graph, m, color, 0) == false)

    printf("Solution does not existn");
    return false;


    printSolution(color);
    return true;

    void printSolution(int color)

    printf("Solution Exists:"
    " Following are the assigned colors n");
    for (int i = 0; i < V; i++)
    printf(" %d ", color[i]);
    printf("n");










    share|improve this question























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I have to find out the time complexity of graph coloring problem using backtracking. I have found somewhere it is O(n*m^n) where n=no vertex and m= number of color.



      Suppose my code is given below how to find time complexity?



      bool isSafe (int v, bool graph[V][V], int color, int c)

      for (int i = 0; i < V; i++)
      if (graph[v][i] && c == color[i])
      return false;
      return true;


      bool graphColoringUtil(bool graph[V][V], int m, int color, int v)

      if (v == V)
      return true;

      for (int c = 1; c <= m; c++)

      if (isSafe(v, graph, color, c))

      color[v] = c;

      if (graphColoringUtil (graph, m, color, v+1) == true)
      return true;

      color[v] = 0;



      return false;

      bool graphColoring(bool graph[V][V], int m)

      int *color = new int[V];
      for (int i = 0; i < V; i++)
      color[i] = 0;

      if (graphColoringUtil(graph, m, color, 0) == false)

      printf("Solution does not existn");
      return false;


      printSolution(color);
      return true;

      void printSolution(int color)

      printf("Solution Exists:"
      " Following are the assigned colors n");
      for (int i = 0; i < V; i++)
      printf(" %d ", color[i]);
      printf("n");










      share|improve this question













      I have to find out the time complexity of graph coloring problem using backtracking. I have found somewhere it is O(n*m^n) where n=no vertex and m= number of color.



      Suppose my code is given below how to find time complexity?



      bool isSafe (int v, bool graph[V][V], int color, int c)

      for (int i = 0; i < V; i++)
      if (graph[v][i] && c == color[i])
      return false;
      return true;


      bool graphColoringUtil(bool graph[V][V], int m, int color, int v)

      if (v == V)
      return true;

      for (int c = 1; c <= m; c++)

      if (isSafe(v, graph, color, c))

      color[v] = c;

      if (graphColoringUtil (graph, m, color, v+1) == true)
      return true;

      color[v] = 0;



      return false;

      bool graphColoring(bool graph[V][V], int m)

      int *color = new int[V];
      for (int i = 0; i < V; i++)
      color[i] = 0;

      if (graphColoringUtil(graph, m, color, 0) == false)

      printf("Solution does not existn");
      return false;


      printSolution(color);
      return true;

      void printSolution(int color)

      printf("Solution Exists:"
      " Following are the assigned colors n");
      for (int i = 0; i < V; i++)
      printf(" %d ", color[i]);
      printf("n");







      algorithm graph colors backtracking






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      asked Apr 17 at 20:55









      Rahul Krishna

      136




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