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Let's say I have a project called my-project/ that lives in it's own directory and has the following file structure.

.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
└── project.config.js

Now let's say I have a new project called my-new-project that also lives in it's own directory and has the same file structure as my-project but it contains an additional file called my-files-to-copy.txt

.
├── src
│ ├── index.html
│ ├── main.js
│ ├── normalize.js
│ ├── routes
│ │ ├── index.js
│ │ └── Home
│ │ ├── index.js
│ │ └── assets
│ ├── static
│ ├── store
│ │ ├── createStore.js
│ │ └── reducers.js
│ └── styles
├── project.config.js
└── my-files-to-copy.txt # new file added to tree

my-new-project/ has the same file structure but different file contents than my-project/

Now let's say my-files-to-copy.txt contains a list of files I want to copy from my-project/ and write to the same path in my-new-project/ to overwrite the existing files in my-new-project/ at those locations.

src/main.js
src/routes/index.js
src/store/reducers.js
project.config.js

How can I accomplish this with a terminal/bash/shell command or script?

edit:

I think I might be able to do:

cp my-project/src/main.js my-new-project/src/main.js
cp my-project/src/routes/index.js my-new-project/src/routes/index.js
cp my-project/src/store/reducers.js my-new-project/src/store/reducers.js
cp my-project/project.config.js my-new-project/project.config.js

But as the number of files scales, this method will become less efficient. I was looking for a more efficient solution that would allow me to leverage the file that contains the list of files (or at least a script) without having to write a separate command for each one.

Assuming my-project and my-new-project are on the same directory:

xargs -i -a my-new-project/my-files-to-copy.txt cp my-project/ my-new-project/