How to solve Markov transition rate matrix?
I have some variables to find like x= [1x16 (x1,x2,x3,....x16 variables)] with condition that x1+x2+x3+....x16=1. I have also 16x16 matrix Q= [16x16 (real values)].
I need to solve the equation 'x*Q=x' as shown here. How can I solve it in Matlab or in any other language easily?
matlab matrix markov-chains markov-models
edited Nov 15 '18 at 6:40
Billal Begueradj
6,053132948
asked Nov 15 '18 at 5:36
Abdullah1Abdullah1
114
add a comment |
I have some variables to find like x= [1x16 (x1,x2,x3,....x16 variables)] with condition that x1+x2+x3+....x16=1. I have also 16x16 matrix Q= [16x16 (real values)].
I need to solve the equation 'x*Q=x' as shown here. How can I solve it in Matlab or in any other language easily?
matlab matrix markov-chains markov-models
edited Nov 15 '18 at 6:40
Billal Begueradj
6,053132948
asked Nov 15 '18 at 5:36
Abdullah1Abdullah1
114
add a comment |
I have some variables to find like x= [1x16 (x1,x2,x3,....x16 variables)] with condition that x1+x2+x3+....x16=1. I have also 16x16 matrix Q= [16x16 (real values)].
I need to solve the equation 'x*Q=x' as shown here. How can I solve it in Matlab or in any other language easily?
matlab matrix markov-chains markov-models
edited Nov 15 '18 at 6:40
Billal Begueradj
6,053132948
asked Nov 15 '18 at 5:36
Abdullah1Abdullah1
114
I have some variables to find like x= [1x16 (x1,x2,x3,....x16 variables)] with condition that x1+x2+x3+....x16=1. I have also 16x16 matrix Q= [16x16 (real values)].
I need to solve the equation 'x*Q=x' as shown here. How can I solve it in Matlab or in any other language easily?
matlab matrix markov-chains markov-models
matlab matrix markov-chains markov-models
edited Nov 15 '18 at 6:40
Billal Begueradj
6,053132948
asked Nov 15 '18 at 5:36
Abdullah1Abdullah1
114
edited Nov 15 '18 at 6:40
Billal Begueradj
6,053132948
asked Nov 15 '18 at 5:36
Abdullah1Abdullah1
114
edited Nov 15 '18 at 6:40
Billal Begueradj
6,053132948
edited Nov 15 '18 at 6:40
Billal Begueradj
6,053132948
edited Nov 15 '18 at 6:40
Billal Begueradj
6,053132948
6,053132948
asked Nov 15 '18 at 5:36
Abdullah1Abdullah1
114
asked Nov 15 '18 at 5:36
Abdullah1Abdullah1
114
asked Nov 15 '18 at 5:36
Abdullah1Abdullah1
114
114
add a comment |
add a comment |
1 Answer
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By transposition, your equation is equivalent to Q'y=1y where y:=x' (a column vector) where Q' is the transpose of Q (matlab notation...) which means that y is an eigenvector associated with eigenvalue 1 for matrix Q'. Such an eigenvector always exists for a Markov matrix. Let s be the sum of the entries of column vector y. Two cases can occur :
either s is not 0 ; then it suffices to divide all coordinates of y by s : we obtain a vector that is still an eigenvector, with a coordinate sum equal to 1.
or s=0 and there is no solution to your problem.
Here is a Matlab program that does the work for a 3 x 3 matrix :
M=[.2 .3 .5
.1 .8 .1
.4 .4 .2]
[P,D]=eig(M')
Y=P(:,3)
M'*Y - Y,% should be 0
Z=Y/sum(Y),%the sum of Z's coordinates is 1
M'*Z-Z,% should be 0
answered Nov 15 '18 at 17:02
Jean Marie BeckerJean Marie Becker
1585
add a comment |
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1 Answer
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1 Answer
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active
oldest
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By transposition, your equation is equivalent to Q'y=1y where y:=x' (a column vector) where Q' is the transpose of Q (matlab notation...) which means that y is an eigenvector associated with eigenvalue 1 for matrix Q'. Such an eigenvector always exists for a Markov matrix. Let s be the sum of the entries of column vector y. Two cases can occur :
either s is not 0 ; then it suffices to divide all coordinates of y by s : we obtain a vector that is still an eigenvector, with a coordinate sum equal to 1.
or s=0 and there is no solution to your problem.
Here is a Matlab program that does the work for a 3 x 3 matrix :
M=[.2 .3 .5
.1 .8 .1
.4 .4 .2]
[P,D]=eig(M')
Y=P(:,3)
M'*Y - Y,% should be 0
Z=Y/sum(Y),%the sum of Z's coordinates is 1
M'*Z-Z,% should be 0
answered Nov 15 '18 at 17:02
Jean Marie BeckerJean Marie Becker
1585
add a comment |
By transposition, your equation is equivalent to Q'y=1y where y:=x' (a column vector) where Q' is the transpose of Q (matlab notation...) which means that y is an eigenvector associated with eigenvalue 1 for matrix Q'. Such an eigenvector always exists for a Markov matrix. Let s be the sum of the entries of column vector y. Two cases can occur :
either s is not 0 ; then it suffices to divide all coordinates of y by s : we obtain a vector that is still an eigenvector, with a coordinate sum equal to 1.
or s=0 and there is no solution to your problem.
Here is a Matlab program that does the work for a 3 x 3 matrix :
M=[.2 .3 .5
.1 .8 .1
.4 .4 .2]
[P,D]=eig(M')
Y=P(:,3)
M'*Y - Y,% should be 0
Z=Y/sum(Y),%the sum of Z's coordinates is 1
M'*Z-Z,% should be 0
answered Nov 15 '18 at 17:02
Jean Marie BeckerJean Marie Becker
1585
add a comment |
By transposition, your equation is equivalent to Q'y=1y where y:=x' (a column vector) where Q' is the transpose of Q (matlab notation...) which means that y is an eigenvector associated with eigenvalue 1 for matrix Q'. Such an eigenvector always exists for a Markov matrix. Let s be the sum of the entries of column vector y. Two cases can occur :
either s is not 0 ; then it suffices to divide all coordinates of y by s : we obtain a vector that is still an eigenvector, with a coordinate sum equal to 1.
or s=0 and there is no solution to your problem.
Here is a Matlab program that does the work for a 3 x 3 matrix :
M=[.2 .3 .5
.1 .8 .1
.4 .4 .2]
[P,D]=eig(M')
Y=P(:,3)
M'*Y - Y,% should be 0
Z=Y/sum(Y),%the sum of Z's coordinates is 1
M'*Z-Z,% should be 0
answered Nov 15 '18 at 17:02
Jean Marie BeckerJean Marie Becker
1585
By transposition, your equation is equivalent to Q'y=1y where y:=x' (a column vector) where Q' is the transpose of Q (matlab notation...) which means that y is an eigenvector associated with eigenvalue 1 for matrix Q'. Such an eigenvector always exists for a Markov matrix. Let s be the sum of the entries of column vector y. Two cases can occur :
either s is not 0 ; then it suffices to divide all coordinates of y by s : we obtain a vector that is still an eigenvector, with a coordinate sum equal to 1.
or s=0 and there is no solution to your problem.
Here is a Matlab program that does the work for a 3 x 3 matrix :
M=[.2 .3 .5
.1 .8 .1
.4 .4 .2]
[P,D]=eig(M')
Y=P(:,3)
M'*Y - Y,% should be 0
Z=Y/sum(Y),%the sum of Z's coordinates is 1
M'*Z-Z,% should be 0
answered Nov 15 '18 at 17:02
Jean Marie BeckerJean Marie Becker
1585
edited Nov 15 '18 at 17:15
answered Nov 15 '18 at 17:02
Jean Marie BeckerJean Marie Becker
1585
answered Nov 15 '18 at 17:02
Jean Marie BeckerJean Marie Becker
1585
answered Nov 15 '18 at 17:02
Jean Marie BeckerJean Marie Becker
1585
1585
add a comment |
add a comment |
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