How To Split Separate Strings in 2 Different Columns in SQL Server










0














I have 2 columns of pipe delimited data that I need to break out into rows but the columns must stay together. Here's what my data looks like:



Plan Name: ABC|DEF|GHI|JKL
Plan Type: HMO|POS|HMO|PPO


I need to end up with 4 rows that look like this:



1 - ABC HMO
2 - DEF POS
3 - GHI HMO
4 - JKL PPO


I know how to separate each column individually using the STUFF function but how do I keep the first value from column 1 with the first value from column 2, etc? Don't know where to start. Appreciate any help!



p.s. - I am not on SQL Server 2016 so can't use STRING_SPLIT










share|improve this question




























    0














    I have 2 columns of pipe delimited data that I need to break out into rows but the columns must stay together. Here's what my data looks like:



    Plan Name: ABC|DEF|GHI|JKL
    Plan Type: HMO|POS|HMO|PPO


    I need to end up with 4 rows that look like this:



    1 - ABC HMO
    2 - DEF POS
    3 - GHI HMO
    4 - JKL PPO


    I know how to separate each column individually using the STUFF function but how do I keep the first value from column 1 with the first value from column 2, etc? Don't know where to start. Appreciate any help!



    p.s. - I am not on SQL Server 2016 so can't use STRING_SPLIT










    share|improve this question


























      0












      0








      0







      I have 2 columns of pipe delimited data that I need to break out into rows but the columns must stay together. Here's what my data looks like:



      Plan Name: ABC|DEF|GHI|JKL
      Plan Type: HMO|POS|HMO|PPO


      I need to end up with 4 rows that look like this:



      1 - ABC HMO
      2 - DEF POS
      3 - GHI HMO
      4 - JKL PPO


      I know how to separate each column individually using the STUFF function but how do I keep the first value from column 1 with the first value from column 2, etc? Don't know where to start. Appreciate any help!



      p.s. - I am not on SQL Server 2016 so can't use STRING_SPLIT










      share|improve this question















      I have 2 columns of pipe delimited data that I need to break out into rows but the columns must stay together. Here's what my data looks like:



      Plan Name: ABC|DEF|GHI|JKL
      Plan Type: HMO|POS|HMO|PPO


      I need to end up with 4 rows that look like this:



      1 - ABC HMO
      2 - DEF POS
      3 - GHI HMO
      4 - JKL PPO


      I know how to separate each column individually using the STUFF function but how do I keep the first value from column 1 with the first value from column 2, etc? Don't know where to start. Appreciate any help!



      p.s. - I am not on SQL Server 2016 so can't use STRING_SPLIT







      sql sql-server






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 11 at 17:48









      Gordon Linoff

      757k35291399




      757k35291399










      asked Nov 11 at 17:40









      shdavis701

      1




      1






















          2 Answers
          2






          active

          oldest

          votes


















          1














          One method is a recursive CTE:



          with t as (
          select *
          from (values ('ABC|DEF|GHI|JKL', 'HMO|POS|HMO|PPO')) v(plannames, plantypes)
          ),
          cte as (
          select convert(varchar(max), left(plannames, charindex('|', plannames + '|') - 1)) as planname,
          convert(varchar(max), left(plantypes, charindex('|', plantypes + '|') - 1)) as plantype,
          convert(varchar(max), stuff(plannames, 1, charindex('|', plannames + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantypes, 1, charindex('|', plantypes + '|'), '')) as plantype_rest,
          1 as lev
          from t
          union all
          select convert(varchar(max), left(planname_rest, charindex('|', planname_rest + '|') - 1)) as planname,
          convert(varchar(max), left(plantype_rest, charindex('|', plantype_rest + '|') - 1)) as plantype,
          convert(varchar(max), stuff(planname_rest, 1, charindex('|', planname_rest + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantype_rest, 1, charindex('|', plantype_rest + '|'), '')) as plantype_rest,
          lev + 1
          from cte
          where planname_rest <> ''
          )
          select *
          from cte;


          Here is a db<>fiddle.






          share|improve this answer






















          • Will this work for rows that have different numbers of plans/types, not just 4?
            – shdavis701
            Nov 11 at 18:00










          • I'm not sure this is returning the expected results in the first place.
            – Larnu
            Nov 11 at 18:12










          • The above worked, and I've used it with my real data now and I think it's working. Lamu why don't you think it's returning the expected results? Just want to make sure I'm not missing something. Thanks.
            – shdavis701
            Nov 11 at 18:17










          • Larnu* (it's rn not m) and the fiddle didn't appear to provide the correct results @shdavis.
            – Larnu
            Nov 11 at 18:23










          • I did have to change plannames in the 4th convert statement to plantypes and it worked fine.
            – shdavis701
            Nov 11 at 23:18


















          0














          Using delimitedsplit8k_lead you could do:



          SELECT CONVERT(varchar(3), itemnumber) + ' - ' + PN.item + ' ' + PT.item
          FROM YourTable YT
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanName,'|') PN
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanType,'|') PT
          WHERE PN.ItemNumber = PT.ItemNumber;


          This assumes PlanName and PlanType have the same number of elements.






          share|improve this answer




















          • They do have the same number of elements in every row.
            – shdavis701
            Nov 11 at 18:17










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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          One method is a recursive CTE:



          with t as (
          select *
          from (values ('ABC|DEF|GHI|JKL', 'HMO|POS|HMO|PPO')) v(plannames, plantypes)
          ),
          cte as (
          select convert(varchar(max), left(plannames, charindex('|', plannames + '|') - 1)) as planname,
          convert(varchar(max), left(plantypes, charindex('|', plantypes + '|') - 1)) as plantype,
          convert(varchar(max), stuff(plannames, 1, charindex('|', plannames + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantypes, 1, charindex('|', plantypes + '|'), '')) as plantype_rest,
          1 as lev
          from t
          union all
          select convert(varchar(max), left(planname_rest, charindex('|', planname_rest + '|') - 1)) as planname,
          convert(varchar(max), left(plantype_rest, charindex('|', plantype_rest + '|') - 1)) as plantype,
          convert(varchar(max), stuff(planname_rest, 1, charindex('|', planname_rest + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantype_rest, 1, charindex('|', plantype_rest + '|'), '')) as plantype_rest,
          lev + 1
          from cte
          where planname_rest <> ''
          )
          select *
          from cte;


          Here is a db<>fiddle.






          share|improve this answer






















          • Will this work for rows that have different numbers of plans/types, not just 4?
            – shdavis701
            Nov 11 at 18:00










          • I'm not sure this is returning the expected results in the first place.
            – Larnu
            Nov 11 at 18:12










          • The above worked, and I've used it with my real data now and I think it's working. Lamu why don't you think it's returning the expected results? Just want to make sure I'm not missing something. Thanks.
            – shdavis701
            Nov 11 at 18:17










          • Larnu* (it's rn not m) and the fiddle didn't appear to provide the correct results @shdavis.
            – Larnu
            Nov 11 at 18:23










          • I did have to change plannames in the 4th convert statement to plantypes and it worked fine.
            – shdavis701
            Nov 11 at 23:18















          1














          One method is a recursive CTE:



          with t as (
          select *
          from (values ('ABC|DEF|GHI|JKL', 'HMO|POS|HMO|PPO')) v(plannames, plantypes)
          ),
          cte as (
          select convert(varchar(max), left(plannames, charindex('|', plannames + '|') - 1)) as planname,
          convert(varchar(max), left(plantypes, charindex('|', plantypes + '|') - 1)) as plantype,
          convert(varchar(max), stuff(plannames, 1, charindex('|', plannames + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantypes, 1, charindex('|', plantypes + '|'), '')) as plantype_rest,
          1 as lev
          from t
          union all
          select convert(varchar(max), left(planname_rest, charindex('|', planname_rest + '|') - 1)) as planname,
          convert(varchar(max), left(plantype_rest, charindex('|', plantype_rest + '|') - 1)) as plantype,
          convert(varchar(max), stuff(planname_rest, 1, charindex('|', planname_rest + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantype_rest, 1, charindex('|', plantype_rest + '|'), '')) as plantype_rest,
          lev + 1
          from cte
          where planname_rest <> ''
          )
          select *
          from cte;


          Here is a db<>fiddle.






          share|improve this answer






















          • Will this work for rows that have different numbers of plans/types, not just 4?
            – shdavis701
            Nov 11 at 18:00










          • I'm not sure this is returning the expected results in the first place.
            – Larnu
            Nov 11 at 18:12










          • The above worked, and I've used it with my real data now and I think it's working. Lamu why don't you think it's returning the expected results? Just want to make sure I'm not missing something. Thanks.
            – shdavis701
            Nov 11 at 18:17










          • Larnu* (it's rn not m) and the fiddle didn't appear to provide the correct results @shdavis.
            – Larnu
            Nov 11 at 18:23










          • I did have to change plannames in the 4th convert statement to plantypes and it worked fine.
            – shdavis701
            Nov 11 at 23:18













          1












          1








          1






          One method is a recursive CTE:



          with t as (
          select *
          from (values ('ABC|DEF|GHI|JKL', 'HMO|POS|HMO|PPO')) v(plannames, plantypes)
          ),
          cte as (
          select convert(varchar(max), left(plannames, charindex('|', plannames + '|') - 1)) as planname,
          convert(varchar(max), left(plantypes, charindex('|', plantypes + '|') - 1)) as plantype,
          convert(varchar(max), stuff(plannames, 1, charindex('|', plannames + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantypes, 1, charindex('|', plantypes + '|'), '')) as plantype_rest,
          1 as lev
          from t
          union all
          select convert(varchar(max), left(planname_rest, charindex('|', planname_rest + '|') - 1)) as planname,
          convert(varchar(max), left(plantype_rest, charindex('|', plantype_rest + '|') - 1)) as plantype,
          convert(varchar(max), stuff(planname_rest, 1, charindex('|', planname_rest + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantype_rest, 1, charindex('|', plantype_rest + '|'), '')) as plantype_rest,
          lev + 1
          from cte
          where planname_rest <> ''
          )
          select *
          from cte;


          Here is a db<>fiddle.






          share|improve this answer














          One method is a recursive CTE:



          with t as (
          select *
          from (values ('ABC|DEF|GHI|JKL', 'HMO|POS|HMO|PPO')) v(plannames, plantypes)
          ),
          cte as (
          select convert(varchar(max), left(plannames, charindex('|', plannames + '|') - 1)) as planname,
          convert(varchar(max), left(plantypes, charindex('|', plantypes + '|') - 1)) as plantype,
          convert(varchar(max), stuff(plannames, 1, charindex('|', plannames + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantypes, 1, charindex('|', plantypes + '|'), '')) as plantype_rest,
          1 as lev
          from t
          union all
          select convert(varchar(max), left(planname_rest, charindex('|', planname_rest + '|') - 1)) as planname,
          convert(varchar(max), left(plantype_rest, charindex('|', plantype_rest + '|') - 1)) as plantype,
          convert(varchar(max), stuff(planname_rest, 1, charindex('|', planname_rest + '|'), '')) as planname_rest,
          convert(varchar(max), stuff(plantype_rest, 1, charindex('|', plantype_rest + '|'), '')) as plantype_rest,
          lev + 1
          from cte
          where planname_rest <> ''
          )
          select *
          from cte;


          Here is a db<>fiddle.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 12 at 2:03

























          answered Nov 11 at 17:54









          Gordon Linoff

          757k35291399




          757k35291399











          • Will this work for rows that have different numbers of plans/types, not just 4?
            – shdavis701
            Nov 11 at 18:00










          • I'm not sure this is returning the expected results in the first place.
            – Larnu
            Nov 11 at 18:12










          • The above worked, and I've used it with my real data now and I think it's working. Lamu why don't you think it's returning the expected results? Just want to make sure I'm not missing something. Thanks.
            – shdavis701
            Nov 11 at 18:17










          • Larnu* (it's rn not m) and the fiddle didn't appear to provide the correct results @shdavis.
            – Larnu
            Nov 11 at 18:23










          • I did have to change plannames in the 4th convert statement to plantypes and it worked fine.
            – shdavis701
            Nov 11 at 23:18
















          • Will this work for rows that have different numbers of plans/types, not just 4?
            – shdavis701
            Nov 11 at 18:00










          • I'm not sure this is returning the expected results in the first place.
            – Larnu
            Nov 11 at 18:12










          • The above worked, and I've used it with my real data now and I think it's working. Lamu why don't you think it's returning the expected results? Just want to make sure I'm not missing something. Thanks.
            – shdavis701
            Nov 11 at 18:17










          • Larnu* (it's rn not m) and the fiddle didn't appear to provide the correct results @shdavis.
            – Larnu
            Nov 11 at 18:23










          • I did have to change plannames in the 4th convert statement to plantypes and it worked fine.
            – shdavis701
            Nov 11 at 23:18















          Will this work for rows that have different numbers of plans/types, not just 4?
          – shdavis701
          Nov 11 at 18:00




          Will this work for rows that have different numbers of plans/types, not just 4?
          – shdavis701
          Nov 11 at 18:00












          I'm not sure this is returning the expected results in the first place.
          – Larnu
          Nov 11 at 18:12




          I'm not sure this is returning the expected results in the first place.
          – Larnu
          Nov 11 at 18:12












          The above worked, and I've used it with my real data now and I think it's working. Lamu why don't you think it's returning the expected results? Just want to make sure I'm not missing something. Thanks.
          – shdavis701
          Nov 11 at 18:17




          The above worked, and I've used it with my real data now and I think it's working. Lamu why don't you think it's returning the expected results? Just want to make sure I'm not missing something. Thanks.
          – shdavis701
          Nov 11 at 18:17












          Larnu* (it's rn not m) and the fiddle didn't appear to provide the correct results @shdavis.
          – Larnu
          Nov 11 at 18:23




          Larnu* (it's rn not m) and the fiddle didn't appear to provide the correct results @shdavis.
          – Larnu
          Nov 11 at 18:23












          I did have to change plannames in the 4th convert statement to plantypes and it worked fine.
          – shdavis701
          Nov 11 at 23:18




          I did have to change plannames in the 4th convert statement to plantypes and it worked fine.
          – shdavis701
          Nov 11 at 23:18













          0














          Using delimitedsplit8k_lead you could do:



          SELECT CONVERT(varchar(3), itemnumber) + ' - ' + PN.item + ' ' + PT.item
          FROM YourTable YT
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanName,'|') PN
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanType,'|') PT
          WHERE PN.ItemNumber = PT.ItemNumber;


          This assumes PlanName and PlanType have the same number of elements.






          share|improve this answer




















          • They do have the same number of elements in every row.
            – shdavis701
            Nov 11 at 18:17















          0














          Using delimitedsplit8k_lead you could do:



          SELECT CONVERT(varchar(3), itemnumber) + ' - ' + PN.item + ' ' + PT.item
          FROM YourTable YT
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanName,'|') PN
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanType,'|') PT
          WHERE PN.ItemNumber = PT.ItemNumber;


          This assumes PlanName and PlanType have the same number of elements.






          share|improve this answer




















          • They do have the same number of elements in every row.
            – shdavis701
            Nov 11 at 18:17













          0












          0








          0






          Using delimitedsplit8k_lead you could do:



          SELECT CONVERT(varchar(3), itemnumber) + ' - ' + PN.item + ' ' + PT.item
          FROM YourTable YT
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanName,'|') PN
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanType,'|') PT
          WHERE PN.ItemNumber = PT.ItemNumber;


          This assumes PlanName and PlanType have the same number of elements.






          share|improve this answer












          Using delimitedsplit8k_lead you could do:



          SELECT CONVERT(varchar(3), itemnumber) + ' - ' + PN.item + ' ' + PT.item
          FROM YourTable YT
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanName,'|') PN
          CROSS APPLY dbo.delimitedsplit8k_lead(YT.PlanType,'|') PT
          WHERE PN.ItemNumber = PT.ItemNumber;


          This assumes PlanName and PlanType have the same number of elements.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 11 at 18:01









          Larnu

          15.3k41630




          15.3k41630











          • They do have the same number of elements in every row.
            – shdavis701
            Nov 11 at 18:17
















          • They do have the same number of elements in every row.
            – shdavis701
            Nov 11 at 18:17















          They do have the same number of elements in every row.
          – shdavis701
          Nov 11 at 18:17




          They do have the same number of elements in every row.
          – shdavis701
          Nov 11 at 18:17

















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