Crystal Report Round










-1















I want to round off the number in crystal report like below,



31.349 to 31.300 range value(0 to 49)



31.350 to 31.400 range value(0 to 99)



how can we implement this on the crystal report?










share|improve this question

















  • 1





    Possible duplicate of Rounding numbers in Crystal report

    – Nekeniehl
    Nov 12 '18 at 14:02















-1















I want to round off the number in crystal report like below,



31.349 to 31.300 range value(0 to 49)



31.350 to 31.400 range value(0 to 99)



how can we implement this on the crystal report?










share|improve this question

















  • 1





    Possible duplicate of Rounding numbers in Crystal report

    – Nekeniehl
    Nov 12 '18 at 14:02













-1












-1








-1








I want to round off the number in crystal report like below,



31.349 to 31.300 range value(0 to 49)



31.350 to 31.400 range value(0 to 99)



how can we implement this on the crystal report?










share|improve this question














I want to round off the number in crystal report like below,



31.349 to 31.300 range value(0 to 49)



31.350 to 31.400 range value(0 to 99)



how can we implement this on the crystal report?







visual-studio crystal-reports report rounding






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 12 '18 at 12:51









Bestin P SebastianBestin P Sebastian

1




1







  • 1





    Possible duplicate of Rounding numbers in Crystal report

    – Nekeniehl
    Nov 12 '18 at 14:02












  • 1





    Possible duplicate of Rounding numbers in Crystal report

    – Nekeniehl
    Nov 12 '18 at 14:02







1




1





Possible duplicate of Rounding numbers in Crystal report

– Nekeniehl
Nov 12 '18 at 14:02





Possible duplicate of Rounding numbers in Crystal report

– Nekeniehl
Nov 12 '18 at 14:02












2 Answers
2






active

oldest

votes


















0














The Round() function in Crystal can accept negative argument for the number of decimals. So simply use: Round(yourNumber, -2) to round to the nearest 100.






share|improve this answer























  • actually, we don't need to round the left part of the decimal point. The second and third figure of decimals(eg: In 3.349 the figure 49, if this value is in between 0 - 49 then desired value is 3.300.If the second and third value considered together and then this value is between 50 - 99 then desired value is 3.400

    – Bestin P Sebastian
    Nov 13 '18 at 5:19


















0














stringvar x := totext(YourFieldValue,3,"");



stringvar array y := split(x,".");



if ubound(y) > 1 then



if remainder (val(y[2]),100)>49 then



val(y[1])+((Truncate (val(y[2])/100)+1)*100)/1000



else
val(y[1])+((Truncate (val(y[2])/100))*100)/1000



I get the solution in this way.






share|improve this answer























  • Thought you were using the dot as a European thousand separator.

    – MilletSoftware
    Nov 13 '18 at 19:55










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














The Round() function in Crystal can accept negative argument for the number of decimals. So simply use: Round(yourNumber, -2) to round to the nearest 100.






share|improve this answer























  • actually, we don't need to round the left part of the decimal point. The second and third figure of decimals(eg: In 3.349 the figure 49, if this value is in between 0 - 49 then desired value is 3.300.If the second and third value considered together and then this value is between 50 - 99 then desired value is 3.400

    – Bestin P Sebastian
    Nov 13 '18 at 5:19















0














The Round() function in Crystal can accept negative argument for the number of decimals. So simply use: Round(yourNumber, -2) to round to the nearest 100.






share|improve this answer























  • actually, we don't need to round the left part of the decimal point. The second and third figure of decimals(eg: In 3.349 the figure 49, if this value is in between 0 - 49 then desired value is 3.300.If the second and third value considered together and then this value is between 50 - 99 then desired value is 3.400

    – Bestin P Sebastian
    Nov 13 '18 at 5:19













0












0








0







The Round() function in Crystal can accept negative argument for the number of decimals. So simply use: Round(yourNumber, -2) to round to the nearest 100.






share|improve this answer













The Round() function in Crystal can accept negative argument for the number of decimals. So simply use: Round(yourNumber, -2) to round to the nearest 100.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 12 '18 at 15:12









MilletSoftwareMilletSoftware

413246




413246












  • actually, we don't need to round the left part of the decimal point. The second and third figure of decimals(eg: In 3.349 the figure 49, if this value is in between 0 - 49 then desired value is 3.300.If the second and third value considered together and then this value is between 50 - 99 then desired value is 3.400

    – Bestin P Sebastian
    Nov 13 '18 at 5:19

















  • actually, we don't need to round the left part of the decimal point. The second and third figure of decimals(eg: In 3.349 the figure 49, if this value is in between 0 - 49 then desired value is 3.300.If the second and third value considered together and then this value is between 50 - 99 then desired value is 3.400

    – Bestin P Sebastian
    Nov 13 '18 at 5:19
















actually, we don't need to round the left part of the decimal point. The second and third figure of decimals(eg: In 3.349 the figure 49, if this value is in between 0 - 49 then desired value is 3.300.If the second and third value considered together and then this value is between 50 - 99 then desired value is 3.400

– Bestin P Sebastian
Nov 13 '18 at 5:19





actually, we don't need to round the left part of the decimal point. The second and third figure of decimals(eg: In 3.349 the figure 49, if this value is in between 0 - 49 then desired value is 3.300.If the second and third value considered together and then this value is between 50 - 99 then desired value is 3.400

– Bestin P Sebastian
Nov 13 '18 at 5:19













0














stringvar x := totext(YourFieldValue,3,"");



stringvar array y := split(x,".");



if ubound(y) > 1 then



if remainder (val(y[2]),100)>49 then



val(y[1])+((Truncate (val(y[2])/100)+1)*100)/1000



else
val(y[1])+((Truncate (val(y[2])/100))*100)/1000



I get the solution in this way.






share|improve this answer























  • Thought you were using the dot as a European thousand separator.

    – MilletSoftware
    Nov 13 '18 at 19:55















0














stringvar x := totext(YourFieldValue,3,"");



stringvar array y := split(x,".");



if ubound(y) > 1 then



if remainder (val(y[2]),100)>49 then



val(y[1])+((Truncate (val(y[2])/100)+1)*100)/1000



else
val(y[1])+((Truncate (val(y[2])/100))*100)/1000



I get the solution in this way.






share|improve this answer























  • Thought you were using the dot as a European thousand separator.

    – MilletSoftware
    Nov 13 '18 at 19:55













0












0








0







stringvar x := totext(YourFieldValue,3,"");



stringvar array y := split(x,".");



if ubound(y) > 1 then



if remainder (val(y[2]),100)>49 then



val(y[1])+((Truncate (val(y[2])/100)+1)*100)/1000



else
val(y[1])+((Truncate (val(y[2])/100))*100)/1000



I get the solution in this way.






share|improve this answer













stringvar x := totext(YourFieldValue,3,"");



stringvar array y := split(x,".");



if ubound(y) > 1 then



if remainder (val(y[2]),100)>49 then



val(y[1])+((Truncate (val(y[2])/100)+1)*100)/1000



else
val(y[1])+((Truncate (val(y[2])/100))*100)/1000



I get the solution in this way.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 13 '18 at 11:40









Bestin P SebastianBestin P Sebastian

1




1












  • Thought you were using the dot as a European thousand separator.

    – MilletSoftware
    Nov 13 '18 at 19:55

















  • Thought you were using the dot as a European thousand separator.

    – MilletSoftware
    Nov 13 '18 at 19:55
















Thought you were using the dot as a European thousand separator.

– MilletSoftware
Nov 13 '18 at 19:55





Thought you were using the dot as a European thousand separator.

– MilletSoftware
Nov 13 '18 at 19:55

















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