How do I read a “string” as multiple chars if I don't know the length of the char sequence?
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Sorry if the title is a bit confusing, I'll try to explain better here.
So basically I'm trying to write a program where the user inputs a phone number in an alphabetic form and it then gets translated in a numeric form. Like this:
Enter phone number: CALLATT
22555288
Where 2=ABC, 3=DEF, 4=GHI, 5=JKL, 6=MNO, 7=PRS, 8=TUV, 9=WXY
Also if the phone number input contains chars that are not alphabetical they should be left as they are. Which means:
Enter phone number: 1-800-COL-LECT
1-800-265-5328
Now, I know that this could be solved very easily using strings and arrays but I'm not supposed to use them for this exercise. I wrote this code:
#include <stdio.h>
int main()
char two = '2', three = '3', four = '4', five = '5', six = '6',
seven = '7', eight = '8', nine = '9';
char num;
printf("Enter a phone number: ");
do while(getchar() != 'n');
return 0;
Which doesn't obviously work. I mean, it works just fine if the user inputs a single char but not if the input is composed by more than one char. I can't really get my head around this... I know why and where my code is wrong but I can't really find an effective solution to solve the problem without using arrays.
Any help? Thanks a lot :)
c
edited Nov 15 '18 at 11:59
Rai
1,1424823
asked Nov 15 '18 at 11:15
FoxyITFoxyIT
947
add a comment |
Sorry if the title is a bit confusing, I'll try to explain better here.
So basically I'm trying to write a program where the user inputs a phone number in an alphabetic form and it then gets translated in a numeric form. Like this:
Enter phone number: CALLATT
22555288
Where 2=ABC, 3=DEF, 4=GHI, 5=JKL, 6=MNO, 7=PRS, 8=TUV, 9=WXY
Also if the phone number input contains chars that are not alphabetical they should be left as they are. Which means:
Enter phone number: 1-800-COL-LECT
1-800-265-5328
Now, I know that this could be solved very easily using strings and arrays but I'm not supposed to use them for this exercise. I wrote this code:
#include <stdio.h>
int main()
char two = '2', three = '3', four = '4', five = '5', six = '6',
seven = '7', eight = '8', nine = '9';
char num;
printf("Enter a phone number: ");
do while(getchar() != 'n');
return 0;
Which doesn't obviously work. I mean, it works just fine if the user inputs a single char but not if the input is composed by more than one char. I can't really get my head around this... I know why and where my code is wrong but I can't really find an effective solution to solve the problem without using arrays.
Any help? Thanks a lot :)
c
edited Nov 15 '18 at 11:59
Rai
1,1424823
asked Nov 15 '18 at 11:15
FoxyITFoxyIT
947
1
Just a FYI:char num;==>int num;
– pmg
Nov 15 '18 at 11:21
add a comment |
Sorry if the title is a bit confusing, I'll try to explain better here.
So basically I'm trying to write a program where the user inputs a phone number in an alphabetic form and it then gets translated in a numeric form. Like this:
Enter phone number: CALLATT
22555288
Where 2=ABC, 3=DEF, 4=GHI, 5=JKL, 6=MNO, 7=PRS, 8=TUV, 9=WXY
Also if the phone number input contains chars that are not alphabetical they should be left as they are. Which means:
Enter phone number: 1-800-COL-LECT
1-800-265-5328
Now, I know that this could be solved very easily using strings and arrays but I'm not supposed to use them for this exercise. I wrote this code:
#include <stdio.h>
int main()
char two = '2', three = '3', four = '4', five = '5', six = '6',
seven = '7', eight = '8', nine = '9';
char num;
printf("Enter a phone number: ");
do while(getchar() != 'n');
return 0;
Which doesn't obviously work. I mean, it works just fine if the user inputs a single char but not if the input is composed by more than one char. I can't really get my head around this... I know why and where my code is wrong but I can't really find an effective solution to solve the problem without using arrays.
Any help? Thanks a lot :)
c
edited Nov 15 '18 at 11:59
Rai
1,1424823
asked Nov 15 '18 at 11:15
FoxyITFoxyIT
947
Sorry if the title is a bit confusing, I'll try to explain better here.
So basically I'm trying to write a program where the user inputs a phone number in an alphabetic form and it then gets translated in a numeric form. Like this:
Enter phone number: CALLATT
22555288
Where 2=ABC, 3=DEF, 4=GHI, 5=JKL, 6=MNO, 7=PRS, 8=TUV, 9=WXY
Also if the phone number input contains chars that are not alphabetical they should be left as they are. Which means:
Enter phone number: 1-800-COL-LECT
1-800-265-5328
Now, I know that this could be solved very easily using strings and arrays but I'm not supposed to use them for this exercise. I wrote this code:
#include <stdio.h>
int main()
char two = '2', three = '3', four = '4', five = '5', six = '6',
seven = '7', eight = '8', nine = '9';
char num;
printf("Enter a phone number: ");
do while(getchar() != 'n');
return 0;
Which doesn't obviously work. I mean, it works just fine if the user inputs a single char but not if the input is composed by more than one char. I can't really get my head around this... I know why and where my code is wrong but I can't really find an effective solution to solve the problem without using arrays.
Any help? Thanks a lot :)
c
c
edited Nov 15 '18 at 11:59
Rai
1,1424823
asked Nov 15 '18 at 11:15
FoxyITFoxyIT
947
edited Nov 15 '18 at 11:59
Rai
1,1424823
asked Nov 15 '18 at 11:15
FoxyITFoxyIT
947
edited Nov 15 '18 at 11:59
Rai
1,1424823
edited Nov 15 '18 at 11:59
Rai
1,1424823
edited Nov 15 '18 at 11:59
Rai
1,1424823
1,1424823
asked Nov 15 '18 at 11:15
FoxyITFoxyIT
947
asked Nov 15 '18 at 11:15
FoxyITFoxyIT
947
asked Nov 15 '18 at 11:15
FoxyITFoxyIT
947
947
1
Just a FYI:char num;==>int num;
– pmg
Nov 15 '18 at 11:21
add a comment |
1
Just a FYI:char num;==>int num;
– pmg
Nov 15 '18 at 11:21
1
1
Just a FYI:
char num; ==> int num;– pmg
Nov 15 '18 at 11:21
Just a FYI:
char num; ==> int num;– pmg
Nov 15 '18 at 11:21
add a comment |
1 Answer
1
active
oldest
votes
Try
int num = getchar();
do
/* your if / else / if train */
printf("%c", num);
while ((num = getchar()) != 'n'); // assign and compare
answered Nov 15 '18 at 11:24
pmgpmg
84.9k9100172
Thanks that helped. So basically as I wrote it it was listening for 2 chars at once instead of 1, right?
– FoxyIT
Nov 15 '18 at 11:48
2
Basically you were wasting 1 char for every two chars typed.
– pmg
Nov 15 '18 at 11:50
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try
int num = getchar();
do
/* your if / else / if train */
printf("%c", num);
while ((num = getchar()) != 'n'); // assign and compare
answered Nov 15 '18 at 11:24
pmgpmg
84.9k9100172
Thanks that helped. So basically as I wrote it it was listening for 2 chars at once instead of 1, right?
– FoxyIT
Nov 15 '18 at 11:48
2
Basically you were wasting 1 char for every two chars typed.
– pmg
Nov 15 '18 at 11:50
add a comment |
Try
int num = getchar();
do
/* your if / else / if train */
printf("%c", num);
while ((num = getchar()) != 'n'); // assign and compare
answered Nov 15 '18 at 11:24
pmgpmg
84.9k9100172
Thanks that helped. So basically as I wrote it it was listening for 2 chars at once instead of 1, right?
– FoxyIT
Nov 15 '18 at 11:48
2
Basically you were wasting 1 char for every two chars typed.
– pmg
Nov 15 '18 at 11:50
add a comment |
Try
int num = getchar();
do
/* your if / else / if train */
printf("%c", num);
while ((num = getchar()) != 'n'); // assign and compare
answered Nov 15 '18 at 11:24
pmgpmg
84.9k9100172
Try
int num = getchar();
do
/* your if / else / if train */
printf("%c", num);
while ((num = getchar()) != 'n'); // assign and compare
answered Nov 15 '18 at 11:24
pmgpmg
84.9k9100172
answered Nov 15 '18 at 11:24
pmgpmg
84.9k9100172
answered Nov 15 '18 at 11:24
pmgpmg
84.9k9100172
answered Nov 15 '18 at 11:24
pmgpmg
84.9k9100172
84.9k9100172
Thanks that helped. So basically as I wrote it it was listening for 2 chars at once instead of 1, right?
– FoxyIT
Nov 15 '18 at 11:48
2
Basically you were wasting 1 char for every two chars typed.
– pmg
Nov 15 '18 at 11:50
add a comment |
Thanks that helped. So basically as I wrote it it was listening for 2 chars at once instead of 1, right?
– FoxyIT
Nov 15 '18 at 11:48
2
Basically you were wasting 1 char for every two chars typed.
– pmg
Nov 15 '18 at 11:50
Thanks that helped. So basically as I wrote it it was listening for 2 chars at once instead of 1, right?
– FoxyIT
Nov 15 '18 at 11:48
Thanks that helped. So basically as I wrote it it was listening for 2 chars at once instead of 1, right?
– FoxyIT
Nov 15 '18 at 11:48
2
2
Basically you were wasting 1 char for every two chars typed.
– pmg
Nov 15 '18 at 11:50
Basically you were wasting 1 char for every two chars typed.
– pmg
Nov 15 '18 at 11:50
add a comment |
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Just a FYI:
char num;==>int num;– pmg
Nov 15 '18 at 11:21