SQL Query not returning desired result with NOT LIKE










0















I am running a simple query where comparing a TEXT column using NOT LIKE but the results are not coming correct. Tried a lot but no luck. Here is the query :



SELECT *
FROM `restaurant_session_log`
WHERE `restId` = '176'
OR branchId = '203'
OR `multi_vendorId` LIKE '%,176%'
OR `multi_vendorId` LIKE '%,176,%'
OR `multi_vendorId` LIKE '%176,%'
OR `multi_vendorId` LIKE '%[176]%'
AND (`excluded_branch_id` NOT LIKE '%,203%' OR `excluded_branch_id` NOT LIKE '%,203,%' OR `excluded_branch_id` NOT LIKE '%203,%' OR `excluded_branch_id` NOT LIKE '%[203]%' )


And here is the result:
screenshot



Now the correct result would only include 2nd row, with id = 27707 because I have mentioned in the query to bring result where excluded_branch_id != %203% but I don't understand why it's giving the row with 203 in excluded_branch_id column.



Please help!










share|improve this question






















  • Try with not like [203]

    – Himanshu Ahuja
    Nov 12 '18 at 18:52












  • the main reason is restid is same for both so it is meeting the condition as restid=176 and (since inside it is OR so if any of them mets ) then it will result

    – Himanshu Ahuja
    Nov 12 '18 at 18:56











  • What is with [203]? If there is a single value then you store it wrapped inside ?

    – Salman A
    Nov 12 '18 at 19:23











  • That's supposed to also have multiple values e.g. [203,176,345] ... We have wrapped in square brackets just for ease when retrieving in PHP in form of Array. I understand now its not a good practice but that's how the existing system has been running and handed over to me

    – hyd00
    Nov 12 '18 at 19:27















0















I am running a simple query where comparing a TEXT column using NOT LIKE but the results are not coming correct. Tried a lot but no luck. Here is the query :



SELECT *
FROM `restaurant_session_log`
WHERE `restId` = '176'
OR branchId = '203'
OR `multi_vendorId` LIKE '%,176%'
OR `multi_vendorId` LIKE '%,176,%'
OR `multi_vendorId` LIKE '%176,%'
OR `multi_vendorId` LIKE '%[176]%'
AND (`excluded_branch_id` NOT LIKE '%,203%' OR `excluded_branch_id` NOT LIKE '%,203,%' OR `excluded_branch_id` NOT LIKE '%203,%' OR `excluded_branch_id` NOT LIKE '%[203]%' )


And here is the result:
screenshot



Now the correct result would only include 2nd row, with id = 27707 because I have mentioned in the query to bring result where excluded_branch_id != %203% but I don't understand why it's giving the row with 203 in excluded_branch_id column.



Please help!










share|improve this question






















  • Try with not like [203]

    – Himanshu Ahuja
    Nov 12 '18 at 18:52












  • the main reason is restid is same for both so it is meeting the condition as restid=176 and (since inside it is OR so if any of them mets ) then it will result

    – Himanshu Ahuja
    Nov 12 '18 at 18:56











  • What is with [203]? If there is a single value then you store it wrapped inside ?

    – Salman A
    Nov 12 '18 at 19:23











  • That's supposed to also have multiple values e.g. [203,176,345] ... We have wrapped in square brackets just for ease when retrieving in PHP in form of Array. I understand now its not a good practice but that's how the existing system has been running and handed over to me

    – hyd00
    Nov 12 '18 at 19:27













0












0








0








I am running a simple query where comparing a TEXT column using NOT LIKE but the results are not coming correct. Tried a lot but no luck. Here is the query :



SELECT *
FROM `restaurant_session_log`
WHERE `restId` = '176'
OR branchId = '203'
OR `multi_vendorId` LIKE '%,176%'
OR `multi_vendorId` LIKE '%,176,%'
OR `multi_vendorId` LIKE '%176,%'
OR `multi_vendorId` LIKE '%[176]%'
AND (`excluded_branch_id` NOT LIKE '%,203%' OR `excluded_branch_id` NOT LIKE '%,203,%' OR `excluded_branch_id` NOT LIKE '%203,%' OR `excluded_branch_id` NOT LIKE '%[203]%' )


And here is the result:
screenshot



Now the correct result would only include 2nd row, with id = 27707 because I have mentioned in the query to bring result where excluded_branch_id != %203% but I don't understand why it's giving the row with 203 in excluded_branch_id column.



Please help!










share|improve this question














I am running a simple query where comparing a TEXT column using NOT LIKE but the results are not coming correct. Tried a lot but no luck. Here is the query :



SELECT *
FROM `restaurant_session_log`
WHERE `restId` = '176'
OR branchId = '203'
OR `multi_vendorId` LIKE '%,176%'
OR `multi_vendorId` LIKE '%,176,%'
OR `multi_vendorId` LIKE '%176,%'
OR `multi_vendorId` LIKE '%[176]%'
AND (`excluded_branch_id` NOT LIKE '%,203%' OR `excluded_branch_id` NOT LIKE '%,203,%' OR `excluded_branch_id` NOT LIKE '%203,%' OR `excluded_branch_id` NOT LIKE '%[203]%' )


And here is the result:
screenshot



Now the correct result would only include 2nd row, with id = 27707 because I have mentioned in the query to bring result where excluded_branch_id != %203% but I don't understand why it's giving the row with 203 in excluded_branch_id column.



Please help!







mysql sql






share|improve this question













share|improve this question











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share|improve this question










asked Nov 12 '18 at 18:42









hyd00hyd00

62221029




62221029












  • Try with not like [203]

    – Himanshu Ahuja
    Nov 12 '18 at 18:52












  • the main reason is restid is same for both so it is meeting the condition as restid=176 and (since inside it is OR so if any of them mets ) then it will result

    – Himanshu Ahuja
    Nov 12 '18 at 18:56











  • What is with [203]? If there is a single value then you store it wrapped inside ?

    – Salman A
    Nov 12 '18 at 19:23











  • That's supposed to also have multiple values e.g. [203,176,345] ... We have wrapped in square brackets just for ease when retrieving in PHP in form of Array. I understand now its not a good practice but that's how the existing system has been running and handed over to me

    – hyd00
    Nov 12 '18 at 19:27

















  • Try with not like [203]

    – Himanshu Ahuja
    Nov 12 '18 at 18:52












  • the main reason is restid is same for both so it is meeting the condition as restid=176 and (since inside it is OR so if any of them mets ) then it will result

    – Himanshu Ahuja
    Nov 12 '18 at 18:56











  • What is with [203]? If there is a single value then you store it wrapped inside ?

    – Salman A
    Nov 12 '18 at 19:23











  • That's supposed to also have multiple values e.g. [203,176,345] ... We have wrapped in square brackets just for ease when retrieving in PHP in form of Array. I understand now its not a good practice but that's how the existing system has been running and handed over to me

    – hyd00
    Nov 12 '18 at 19:27
















Try with not like [203]

– Himanshu Ahuja
Nov 12 '18 at 18:52






Try with not like [203]

– Himanshu Ahuja
Nov 12 '18 at 18:52














the main reason is restid is same for both so it is meeting the condition as restid=176 and (since inside it is OR so if any of them mets ) then it will result

– Himanshu Ahuja
Nov 12 '18 at 18:56





the main reason is restid is same for both so it is meeting the condition as restid=176 and (since inside it is OR so if any of them mets ) then it will result

– Himanshu Ahuja
Nov 12 '18 at 18:56













What is with [203]? If there is a single value then you store it wrapped inside ?

– Salman A
Nov 12 '18 at 19:23





What is with [203]? If there is a single value then you store it wrapped inside ?

– Salman A
Nov 12 '18 at 19:23













That's supposed to also have multiple values e.g. [203,176,345] ... We have wrapped in square brackets just for ease when retrieving in PHP in form of Array. I understand now its not a good practice but that's how the existing system has been running and handed over to me

– hyd00
Nov 12 '18 at 19:27





That's supposed to also have multiple values e.g. [203,176,345] ... We have wrapped in square brackets just for ease when retrieving in PHP in form of Array. I understand now its not a good practice but that's how the existing system has been running and handed over to me

– hyd00
Nov 12 '18 at 19:27












3 Answers
3






active

oldest

votes


















1














You can use REGEXP to simplify the matching. The following matches 203 if it has word boundaries on both sides of it:



(excluded_branch_id IS NULL OR excluded_branch_id NOT REGEXP '[[:<:]]203[[:>:]]')


E.g:



SELECT
'203,111' REGEXP '[[:<:]]203[[:>:]]', -- 1
'111,203' REGEXP '[[:<:]]203[[:>:]]', -- 1
'1,203,1' REGEXP '[[:<:]]203[[:>:]]', -- 1
'1120311' REGEXP '[[:<:]]203[[:>:]]' -- 0





share|improve this answer

























  • Works like a charm! Thanks a lot Salman for reminding me of REGEXP

    – hyd00
    Nov 12 '18 at 19:31


















1














Don't store multiple values in a single string! Don't put numeric values in a string! This is the root cause of your problems.



Sometimes, you cannot change someone's really, really, really bad data modeling decision. Your obvious problem is parentheses.



But, the logic would be simplified if you used find_in_set(). I think you intend:



WHERE (`restId` = '176' OR branchId = '203' OR
find_in_set(176, `multi_vendorId`)
) AND
(find_in_set(203, `excluded_branch_id`)





share|improve this answer

























  • Thanks for the suggestion! So I should go after breaking it up and normalising right? Nothing can be done using the current structure to get desired result? Anyway using a subquery or any other trick?

    – hyd00
    Nov 12 '18 at 18:59












  • @hyd00 . .. I answered your question.

    – Gordon Linoff
    Nov 12 '18 at 19:04


















0














$query = "SELECT * FROM movies WHERE year_released NOT LIKE '200_';"



$result = db_query($query, array(':movies' => $value));






share|improve this answer






















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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    You can use REGEXP to simplify the matching. The following matches 203 if it has word boundaries on both sides of it:



    (excluded_branch_id IS NULL OR excluded_branch_id NOT REGEXP '[[:<:]]203[[:>:]]')


    E.g:



    SELECT
    '203,111' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '111,203' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '1,203,1' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '1120311' REGEXP '[[:<:]]203[[:>:]]' -- 0





    share|improve this answer

























    • Works like a charm! Thanks a lot Salman for reminding me of REGEXP

      – hyd00
      Nov 12 '18 at 19:31















    1














    You can use REGEXP to simplify the matching. The following matches 203 if it has word boundaries on both sides of it:



    (excluded_branch_id IS NULL OR excluded_branch_id NOT REGEXP '[[:<:]]203[[:>:]]')


    E.g:



    SELECT
    '203,111' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '111,203' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '1,203,1' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '1120311' REGEXP '[[:<:]]203[[:>:]]' -- 0





    share|improve this answer

























    • Works like a charm! Thanks a lot Salman for reminding me of REGEXP

      – hyd00
      Nov 12 '18 at 19:31













    1












    1








    1







    You can use REGEXP to simplify the matching. The following matches 203 if it has word boundaries on both sides of it:



    (excluded_branch_id IS NULL OR excluded_branch_id NOT REGEXP '[[:<:]]203[[:>:]]')


    E.g:



    SELECT
    '203,111' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '111,203' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '1,203,1' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '1120311' REGEXP '[[:<:]]203[[:>:]]' -- 0





    share|improve this answer















    You can use REGEXP to simplify the matching. The following matches 203 if it has word boundaries on both sides of it:



    (excluded_branch_id IS NULL OR excluded_branch_id NOT REGEXP '[[:<:]]203[[:>:]]')


    E.g:



    SELECT
    '203,111' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '111,203' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '1,203,1' REGEXP '[[:<:]]203[[:>:]]', -- 1
    '1120311' REGEXP '[[:<:]]203[[:>:]]' -- 0






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 13 '18 at 5:57

























    answered Nov 12 '18 at 19:11









    Salman ASalman A

    179k66338430




    179k66338430












    • Works like a charm! Thanks a lot Salman for reminding me of REGEXP

      – hyd00
      Nov 12 '18 at 19:31

















    • Works like a charm! Thanks a lot Salman for reminding me of REGEXP

      – hyd00
      Nov 12 '18 at 19:31
















    Works like a charm! Thanks a lot Salman for reminding me of REGEXP

    – hyd00
    Nov 12 '18 at 19:31





    Works like a charm! Thanks a lot Salman for reminding me of REGEXP

    – hyd00
    Nov 12 '18 at 19:31













    1














    Don't store multiple values in a single string! Don't put numeric values in a string! This is the root cause of your problems.



    Sometimes, you cannot change someone's really, really, really bad data modeling decision. Your obvious problem is parentheses.



    But, the logic would be simplified if you used find_in_set(). I think you intend:



    WHERE (`restId` = '176' OR branchId = '203' OR
    find_in_set(176, `multi_vendorId`)
    ) AND
    (find_in_set(203, `excluded_branch_id`)





    share|improve this answer

























    • Thanks for the suggestion! So I should go after breaking it up and normalising right? Nothing can be done using the current structure to get desired result? Anyway using a subquery or any other trick?

      – hyd00
      Nov 12 '18 at 18:59












    • @hyd00 . .. I answered your question.

      – Gordon Linoff
      Nov 12 '18 at 19:04















    1














    Don't store multiple values in a single string! Don't put numeric values in a string! This is the root cause of your problems.



    Sometimes, you cannot change someone's really, really, really bad data modeling decision. Your obvious problem is parentheses.



    But, the logic would be simplified if you used find_in_set(). I think you intend:



    WHERE (`restId` = '176' OR branchId = '203' OR
    find_in_set(176, `multi_vendorId`)
    ) AND
    (find_in_set(203, `excluded_branch_id`)





    share|improve this answer

























    • Thanks for the suggestion! So I should go after breaking it up and normalising right? Nothing can be done using the current structure to get desired result? Anyway using a subquery or any other trick?

      – hyd00
      Nov 12 '18 at 18:59












    • @hyd00 . .. I answered your question.

      – Gordon Linoff
      Nov 12 '18 at 19:04













    1












    1








    1







    Don't store multiple values in a single string! Don't put numeric values in a string! This is the root cause of your problems.



    Sometimes, you cannot change someone's really, really, really bad data modeling decision. Your obvious problem is parentheses.



    But, the logic would be simplified if you used find_in_set(). I think you intend:



    WHERE (`restId` = '176' OR branchId = '203' OR
    find_in_set(176, `multi_vendorId`)
    ) AND
    (find_in_set(203, `excluded_branch_id`)





    share|improve this answer















    Don't store multiple values in a single string! Don't put numeric values in a string! This is the root cause of your problems.



    Sometimes, you cannot change someone's really, really, really bad data modeling decision. Your obvious problem is parentheses.



    But, the logic would be simplified if you used find_in_set(). I think you intend:



    WHERE (`restId` = '176' OR branchId = '203' OR
    find_in_set(176, `multi_vendorId`)
    ) AND
    (find_in_set(203, `excluded_branch_id`)






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 12 '18 at 19:04

























    answered Nov 12 '18 at 18:49









    Gordon LinoffGordon Linoff

    770k35303404




    770k35303404












    • Thanks for the suggestion! So I should go after breaking it up and normalising right? Nothing can be done using the current structure to get desired result? Anyway using a subquery or any other trick?

      – hyd00
      Nov 12 '18 at 18:59












    • @hyd00 . .. I answered your question.

      – Gordon Linoff
      Nov 12 '18 at 19:04

















    • Thanks for the suggestion! So I should go after breaking it up and normalising right? Nothing can be done using the current structure to get desired result? Anyway using a subquery or any other trick?

      – hyd00
      Nov 12 '18 at 18:59












    • @hyd00 . .. I answered your question.

      – Gordon Linoff
      Nov 12 '18 at 19:04
















    Thanks for the suggestion! So I should go after breaking it up and normalising right? Nothing can be done using the current structure to get desired result? Anyway using a subquery or any other trick?

    – hyd00
    Nov 12 '18 at 18:59






    Thanks for the suggestion! So I should go after breaking it up and normalising right? Nothing can be done using the current structure to get desired result? Anyway using a subquery or any other trick?

    – hyd00
    Nov 12 '18 at 18:59














    @hyd00 . .. I answered your question.

    – Gordon Linoff
    Nov 12 '18 at 19:04





    @hyd00 . .. I answered your question.

    – Gordon Linoff
    Nov 12 '18 at 19:04











    0














    $query = "SELECT * FROM movies WHERE year_released NOT LIKE '200_';"



    $result = db_query($query, array(':movies' => $value));






    share|improve this answer



























      0














      $query = "SELECT * FROM movies WHERE year_released NOT LIKE '200_';"



      $result = db_query($query, array(':movies' => $value));






      share|improve this answer

























        0












        0








        0







        $query = "SELECT * FROM movies WHERE year_released NOT LIKE '200_';"



        $result = db_query($query, array(':movies' => $value));






        share|improve this answer













        $query = "SELECT * FROM movies WHERE year_released NOT LIKE '200_';"



        $result = db_query($query, array(':movies' => $value));







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 '18 at 19:13









        Ammar IqbalAmmar Iqbal

        314




        314



























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