Group data and count the frequencies and create new column based on them in R
1
I have data which I want to group based on ID and count the frequencies of occurrences of a column and create new columns based on it. Basically, using table command for each ID.
ID status GPA
1 fail 3.1
1 pass 3.1
1 fail 3.1
1 fail 3.1
2 pass 4
2 pass 4
2 fail 4
3 pass 4.1
result:
ID fail pass GPA
1 3 1 3.1
2 1 2 4
3 0 1 4.1
How can I do it in R?
r group-by
edited Nov 14 '18 at 7:53
Brian Tompsett - 汤莱恩
4,2331338101
asked Nov 14 '18 at 0:11
CinaCina
2,5443922
add a comment |
1
I have data which I want to group based on ID and count the frequencies of occurrences of a column and create new columns based on it. Basically, using table command for each ID.
ID status GPA
1 fail 3.1
1 pass 3.1
1 fail 3.1
1 fail 3.1
2 pass 4
2 pass 4
2 fail 4
3 pass 4.1
result:
ID fail pass GPA
1 3 1 3.1
2 1 2 4
3 0 1 4.1
How can I do it in R?
r group-by
edited Nov 14 '18 at 7:53
Brian Tompsett - 汤莱恩
4,2331338101
asked Nov 14 '18 at 0:11
CinaCina
2,5443922
2
aggregate(x$status, list(x$ID), table)answers the part of your question concerning fail/pass counts. However, it's not entirely clear how aggregate GPA is computed (average? average of successful entries only?)
– 12b345b6b78
Nov 14 '18 at 0:27
thank you. GPA was previously computed and no need for any calculation. just want to keep as extra information for each ID
– Cina
Nov 14 '18 at 0:35
2
To add GPA to 12b...'s solution:aggregate(DF[2], DF[-2], table)assuming that status is a factor column.
– G. Grothendieck
Nov 14 '18 at 1:49
add a comment |
1
1
1
I have data which I want to group based on ID and count the frequencies of occurrences of a column and create new columns based on it. Basically, using table command for each ID.
ID status GPA
1 fail 3.1
1 pass 3.1
1 fail 3.1
1 fail 3.1
2 pass 4
2 pass 4
2 fail 4
3 pass 4.1
result:
ID fail pass GPA
1 3 1 3.1
2 1 2 4
3 0 1 4.1
How can I do it in R?
r group-by
edited Nov 14 '18 at 7:53
Brian Tompsett - 汤莱恩
4,2331338101
asked Nov 14 '18 at 0:11
CinaCina
2,5443922
I have data which I want to group based on ID and count the frequencies of occurrences of a column and create new columns based on it. Basically, using table command for each ID.
ID status GPA
1 fail 3.1
1 pass 3.1
1 fail 3.1
1 fail 3.1
2 pass 4
2 pass 4
2 fail 4
3 pass 4.1
result:
ID fail pass GPA
1 3 1 3.1
2 1 2 4
3 0 1 4.1
How can I do it in R?
r group-by
r group-by
edited Nov 14 '18 at 7:53
Brian Tompsett - 汤莱恩
4,2331338101
asked Nov 14 '18 at 0:11
CinaCina
2,5443922
edited Nov 14 '18 at 7:53
Brian Tompsett - 汤莱恩
4,2331338101
asked Nov 14 '18 at 0:11
CinaCina
2,5443922
edited Nov 14 '18 at 7:53
Brian Tompsett - 汤莱恩
4,2331338101
edited Nov 14 '18 at 7:53
Brian Tompsett - 汤莱恩
4,2331338101
edited Nov 14 '18 at 7:53
Brian Tompsett - 汤莱恩
4,2331338101
4,2331338101
asked Nov 14 '18 at 0:11
CinaCina
2,5443922
asked Nov 14 '18 at 0:11
CinaCina
2,5443922
asked Nov 14 '18 at 0:11
CinaCina
2,5443922
2,5443922
2
aggregate(x$status, list(x$ID), table)answers the part of your question concerning fail/pass counts. However, it's not entirely clear how aggregate GPA is computed (average? average of successful entries only?)
– 12b345b6b78
Nov 14 '18 at 0:27
thank you. GPA was previously computed and no need for any calculation. just want to keep as extra information for each ID
– Cina
Nov 14 '18 at 0:35
2
To add GPA to 12b...'s solution:aggregate(DF[2], DF[-2], table)assuming that status is a factor column.
– G. Grothendieck
Nov 14 '18 at 1:49
add a comment |
2
aggregate(x$status, list(x$ID), table)answers the part of your question concerning fail/pass counts. However, it's not entirely clear how aggregate GPA is computed (average? average of successful entries only?)
– 12b345b6b78
Nov 14 '18 at 0:27
thank you. GPA was previously computed and no need for any calculation. just want to keep as extra information for each ID
– Cina
Nov 14 '18 at 0:35
2
To add GPA to 12b...'s solution:aggregate(DF[2], DF[-2], table)assuming that status is a factor column.
– G. Grothendieck
Nov 14 '18 at 1:49
2
2
aggregate(x$status, list(x$ID), table) answers the part of your question concerning fail/pass counts. However, it's not entirely clear how aggregate GPA is computed (average? average of successful entries only?)– 12b345b6b78
Nov 14 '18 at 0:27
aggregate(x$status, list(x$ID), table) answers the part of your question concerning fail/pass counts. However, it's not entirely clear how aggregate GPA is computed (average? average of successful entries only?)– 12b345b6b78
Nov 14 '18 at 0:27
thank you. GPA was previously computed and no need for any calculation. just want to keep as extra information for each ID
– Cina
Nov 14 '18 at 0:35
thank you. GPA was previously computed and no need for any calculation. just want to keep as extra information for each ID
– Cina
Nov 14 '18 at 0:35
2
2
To add GPA to 12b...'s solution:
aggregate(DF[2], DF[-2], table) assuming that status is a factor column.– G. Grothendieck
Nov 14 '18 at 1:49
To add GPA to 12b...'s solution:
aggregate(DF[2], DF[-2], table) assuming that status is a factor column.– G. Grothendieck
Nov 14 '18 at 1:49
add a comment |
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2
aggregate(x$status, list(x$ID), table)answers the part of your question concerning fail/pass counts. However, it's not entirely clear how aggregate GPA is computed (average? average of successful entries only?)– 12b345b6b78
Nov 14 '18 at 0:27
thank you. GPA was previously computed and no need for any calculation. just want to keep as extra information for each ID
– Cina
Nov 14 '18 at 0:35
2
To add GPA to 12b...'s solution:
aggregate(DF[2], DF[-2], table)assuming that status is a factor column.– G. Grothendieck
Nov 14 '18 at 1:49