How can I get the value from a string that has the values inside a square bracket []?

I have a string that comes to me like this: "[value1][value2]"

How can I get the values that are inside the square brackets?
NOTE: if the string is like this "[value2]" the first bracket that has a space must return a "" to me...

I have been trying a lot of regex and split but none workd.

this is the last I tried:

var pattern = /[([^]]*)]/g; 
var res = pattern.exec(datos[0].title);

Another one I tried is:

var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm);

but none do what I need...

I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

edited Nov 14 '18 at 0:19

Jeff

6,34911025

asked Nov 14 '18 at 0:01

Hexxul

8013

What do you know about the values in the brackets? If you know that they won't contain square brackets, you could just use split and then trim off the closing bracket.

– Harry Cutts
Nov 14 '18 at 0:08

Well Jeff, I have seen many regex that helps, but theyreturn the bracket, this is the last I tried: var pattern = /[([^]]*)]/g; var res = pattern.exec(datos[0].title); Another one I tried is: var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm); but none do what I need...

– Hexxul
Nov 14 '18 at 0:11

Put it on the post. Please look at stackoverflow.com/help/how-to-ask

– Abana Clara
Nov 14 '18 at 0:14

2

Possible duplicate of Regular expression to extract text between square brackets

– slider
Nov 14 '18 at 0:16

Abana, I don't know why it is relevant to post code that I've tested and does not do what It is required, but updated my post. I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

– Hexxul
Nov 14 '18 at 0:18

add a comment |

I have a string that comes to me like this: "[value1][value2]"

How can I get the values that are inside the square brackets?
NOTE: if the string is like this "[value2]" the first bracket that has a space must return a "" to me...

I have been trying a lot of regex and split but none workd.

this is the last I tried:

var pattern = /[([^]]*)]/g; 
var res = pattern.exec(datos[0].title);

Another one I tried is:

var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm);

but none do what I need...

I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

edited Nov 14 '18 at 0:19

Jeff

6,34911025

asked Nov 14 '18 at 0:01

Hexxul

8013

What do you know about the values in the brackets? If you know that they won't contain square brackets, you could just use split and then trim off the closing bracket.

– Harry Cutts
Nov 14 '18 at 0:08

Well Jeff, I have seen many regex that helps, but theyreturn the bracket, this is the last I tried: var pattern = /[([^]]*)]/g; var res = pattern.exec(datos[0].title); Another one I tried is: var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm); but none do what I need...

– Hexxul
Nov 14 '18 at 0:11

Put it on the post. Please look at stackoverflow.com/help/how-to-ask

– Abana Clara
Nov 14 '18 at 0:14

2

Possible duplicate of Regular expression to extract text between square brackets

– slider
Nov 14 '18 at 0:16

Abana, I don't know why it is relevant to post code that I've tested and does not do what It is required, but updated my post. I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

– Hexxul
Nov 14 '18 at 0:18

add a comment |

I have a string that comes to me like this: "[value1][value2]"

How can I get the values that are inside the square brackets?
NOTE: if the string is like this "[value2]" the first bracket that has a space must return a "" to me...

I have been trying a lot of regex and split but none workd.

this is the last I tried:

var pattern = /[([^]]*)]/g; 
var res = pattern.exec(datos[0].title);

Another one I tried is:

var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm);

but none do what I need...

I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

edited Nov 14 '18 at 0:19

Jeff

6,34911025

asked Nov 14 '18 at 0:01

Hexxul

8013

I have a string that comes to me like this: "[value1][value2]"

How can I get the values that are inside the square brackets?
NOTE: if the string is like this "[value2]" the first bracket that has a space must return a "" to me...

I have been trying a lot of regex and split but none workd.

this is the last I tried:

var pattern = /[([^]]*)]/g; 
var res = pattern.exec(datos[0].title);

Another one I tried is:

var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm);

but none do what I need...

I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

javascript split

edited Nov 14 '18 at 0:19

Jeff

6,34911025

asked Nov 14 '18 at 0:01

Hexxul

8013

edited Nov 14 '18 at 0:19

Jeff

6,34911025

asked Nov 14 '18 at 0:01

Hexxul

8013

edited Nov 14 '18 at 0:19

Jeff

6,34911025

edited Nov 14 '18 at 0:19

Jeff

6,34911025

edited Nov 14 '18 at 0:19

Jeff

6,34911025

asked Nov 14 '18 at 0:01

Hexxul

8013

asked Nov 14 '18 at 0:01

Hexxul

8013

asked Nov 14 '18 at 0:01

Hexxul

8013

What do you know about the values in the brackets? If you know that they won't contain square brackets, you could just use split and then trim off the closing bracket.

– Harry Cutts
Nov 14 '18 at 0:08

Well Jeff, I have seen many regex that helps, but theyreturn the bracket, this is the last I tried: var pattern = /[([^]]*)]/g; var res = pattern.exec(datos[0].title); Another one I tried is: var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm); but none do what I need...

– Hexxul
Nov 14 '18 at 0:11

Put it on the post. Please look at stackoverflow.com/help/how-to-ask

– Abana Clara
Nov 14 '18 at 0:14

2

Possible duplicate of Regular expression to extract text between square brackets

– slider
Nov 14 '18 at 0:16

Abana, I don't know why it is relevant to post code that I've tested and does not do what It is required, but updated my post. I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

– Hexxul
Nov 14 '18 at 0:18

add a comment |

What do you know about the values in the brackets? If you know that they won't contain square brackets, you could just use split and then trim off the closing bracket.

– Harry Cutts
Nov 14 '18 at 0:08

Well Jeff, I have seen many regex that helps, but theyreturn the bracket, this is the last I tried: var pattern = /[([^]]*)]/g; var res = pattern.exec(datos[0].title); Another one I tried is: var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm); but none do what I need...

– Hexxul
Nov 14 '18 at 0:11

Put it on the post. Please look at stackoverflow.com/help/how-to-ask

– Abana Clara
Nov 14 '18 at 0:14

2

Possible duplicate of Regular expression to extract text between square brackets

– slider
Nov 14 '18 at 0:16

Abana, I don't know why it is relevant to post code that I've tested and does not do what It is required, but updated my post. I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

– Hexxul
Nov 14 '18 at 0:18

What do you know about the values in the brackets? If you know that they won't contain square brackets, you could just use split and then trim off the closing bracket.

– Harry Cutts
Nov 14 '18 at 0:08

Well Jeff, I have seen many regex that helps, but theyreturn the bracket, this is the last I tried: var pattern = /[([^]]*)]/g; var res = pattern.exec(datos[0].title); Another one I tried is: var res = datos[0].title.match(/^.*?[([^]]*)].*?[([^]]*)]/gm); but none do what I need...

– Hexxul
Nov 14 '18 at 0:11

Put it on the post. Please look at stackoverflow.com/help/how-to-ask

– Abana Clara
Nov 14 '18 at 0:14

Possible duplicate of Regular expression to extract text between square brackets

– slider
Nov 14 '18 at 0:16

Abana, I don't know why it is relevant to post code that I've tested and does not do what It is required, but updated my post. I'm trying to find a way "that does it all" a regex that gets anything inside the Square brackets (even white spaces)

– Hexxul
Nov 14 '18 at 0:18

add a comment |

5 Answers
5

active

oldest

votes

As @HarryCutts stated, you don't need regex:

var x = "[value1][value2]";
console.log( x.slice(1,-1).split('][') );

answered Nov 14 '18 at 0:20

cybersam

39.8k43151

add a comment |

You can try this regex and the brute force way to extract the contents.

var regex = /[(.*?)]/g;

var value = "[value1][value2]";

var matches = value.match(regex);

var matchedValues = matches.map(match => 
	return match.replace("[", "").replace("]", "");
).join(" ");

console.log(matchedValues.toString())

answered Nov 14 '18 at 0:20

Sushanth --

49.9k64784

add a comment |

You could just do this:

var str = "['value1']['value2']";
var value1 = str.split("]")[0].split("[")[1];
var value2 = str.split("]")[1].split("[")[1];
console.log(str);
console.log(value1);
console.log(value2);

answered Nov 14 '18 at 0:21

Jack Bashford

9,62131540

add a comment |

You can easily expand it for more values.

const string = "[value1][value2]";

const removeBrackets = (stringWithBrackets) => 
 return stringWithBrackets.split("][").map(s => s = s.replace(/[*]*/g, ""));
;

const [value1, value2] = removeBrackets(string);

console.log(value1, value2);

answered Nov 14 '18 at 0:51

ams

2187

add a comment |

const getItems = (fullItemsString) => 
 let items = fullItemsString.replace(/[/g, "").split("]");
 items.pop()

 return items;

Using:

let items = getItems("[2][34][1]");

result: [ '2', '', '34', '1' ]

answered Nov 14 '18 at 1:01

Fernando Matos

111

add a comment |

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5 Answers
5

active

oldest

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5 Answers
5

active

oldest

votes

As @HarryCutts stated, you don't need regex:

var x = "[value1][value2]";
console.log( x.slice(1,-1).split('][') );

answered Nov 14 '18 at 0:20

cybersam

39.8k43151

add a comment |

As @HarryCutts stated, you don't need regex:

var x = "[value1][value2]";
console.log( x.slice(1,-1).split('][') );

answered Nov 14 '18 at 0:20

cybersam

39.8k43151

add a comment |

As @HarryCutts stated, you don't need regex:

var x = "[value1][value2]";
console.log( x.slice(1,-1).split('][') );

answered Nov 14 '18 at 0:20

cybersam

39.8k43151

As @HarryCutts stated, you don't need regex:

var x = "[value1][value2]";
console.log( x.slice(1,-1).split('][') );

var x = "[value1][value2]";
console.log( x.slice(1,-1).split('][') );

var x = "[value1][value2]";
console.log( x.slice(1,-1).split('][') );

answered Nov 14 '18 at 0:20

cybersam

39.8k43151

answered Nov 14 '18 at 0:20

cybersam

39.8k43151

answered Nov 14 '18 at 0:20

cybersam

39.8k43151

answered Nov 14 '18 at 0:20

cybersam

39.8k43151

add a comment |

You can try this regex and the brute force way to extract the contents.

var regex = /[(.*?)]/g;

var value = "[value1][value2]";

var matches = value.match(regex);

var matchedValues = matches.map(match => 
	return match.replace("[", "").replace("]", "");
).join(" ");

console.log(matchedValues.toString())

answered Nov 14 '18 at 0:20

Sushanth --

49.9k64784

add a comment |

You can try this regex and the brute force way to extract the contents.

var regex = /[(.*?)]/g;

var value = "[value1][value2]";

var matches = value.match(regex);

var matchedValues = matches.map(match => 
	return match.replace("[", "").replace("]", "");
).join(" ");

console.log(matchedValues.toString())

answered Nov 14 '18 at 0:20

Sushanth --

49.9k64784

add a comment |

You can try this regex and the brute force way to extract the contents.

var regex = /[(.*?)]/g;

var value = "[value1][value2]";

var matches = value.match(regex);

var matchedValues = matches.map(match => 
	return match.replace("[", "").replace("]", "");
).join(" ");

console.log(matchedValues.toString())

answered Nov 14 '18 at 0:20

Sushanth --

49.9k64784

You can try this regex and the brute force way to extract the contents.

var regex = /[(.*?)]/g;

var value = "[value1][value2]";

var matches = value.match(regex);

var matchedValues = matches.map(match => 
	return match.replace("[", "").replace("]", "");
).join(" ");

console.log(matchedValues.toString())

var regex = /[(.*?)]/g;

var value = "[value1][value2]";

var matches = value.match(regex);

var matchedValues = matches.map(match => 
	return match.replace("[", "").replace("]", "");
).join(" ");

console.log(matchedValues.toString())

var regex = /[(.*?)]/g;

var value = "[value1][value2]";

var matches = value.match(regex);

var matchedValues = matches.map(match => 
	return match.replace("[", "").replace("]", "");
).join(" ");

console.log(matchedValues.toString())

answered Nov 14 '18 at 0:20

Sushanth --

49.9k64784

answered Nov 14 '18 at 0:20

Sushanth --

49.9k64784

answered Nov 14 '18 at 0:20

Sushanth --

49.9k64784

answered Nov 14 '18 at 0:20

Sushanth --

49.9k64784

add a comment |

You could just do this:

var str = "['value1']['value2']";
var value1 = str.split("]")[0].split("[")[1];
var value2 = str.split("]")[1].split("[")[1];
console.log(str);
console.log(value1);
console.log(value2);

answered Nov 14 '18 at 0:21

Jack Bashford

9,62131540

add a comment |

You could just do this:

var str = "['value1']['value2']";
var value1 = str.split("]")[0].split("[")[1];
var value2 = str.split("]")[1].split("[")[1];
console.log(str);
console.log(value1);
console.log(value2);

answered Nov 14 '18 at 0:21

Jack Bashford

9,62131540

add a comment |

You could just do this:

var str = "['value1']['value2']";
var value1 = str.split("]")[0].split("[")[1];
var value2 = str.split("]")[1].split("[")[1];
console.log(str);
console.log(value1);
console.log(value2);

answered Nov 14 '18 at 0:21

Jack Bashford

9,62131540

You could just do this:

var str = "['value1']['value2']";
var value1 = str.split("]")[0].split("[")[1];
var value2 = str.split("]")[1].split("[")[1];
console.log(str);
console.log(value1);
console.log(value2);

var str = "['value1']['value2']";
var value1 = str.split("]")[0].split("[")[1];
var value2 = str.split("]")[1].split("[")[1];
console.log(str);
console.log(value1);
console.log(value2);

var str = "['value1']['value2']";
var value1 = str.split("]")[0].split("[")[1];
var value2 = str.split("]")[1].split("[")[1];
console.log(str);
console.log(value1);
console.log(value2);

answered Nov 14 '18 at 0:21

Jack Bashford

9,62131540

answered Nov 14 '18 at 0:21

Jack Bashford

9,62131540

answered Nov 14 '18 at 0:21

Jack Bashford

9,62131540

answered Nov 14 '18 at 0:21

Jack Bashford

9,62131540

add a comment |

You can easily expand it for more values.

const string = "[value1][value2]";

const removeBrackets = (stringWithBrackets) => 
 return stringWithBrackets.split("][").map(s => s = s.replace(/[*]*/g, ""));
;

const [value1, value2] = removeBrackets(string);

console.log(value1, value2);

answered Nov 14 '18 at 0:51

ams

2187

add a comment |

You can easily expand it for more values.

const string = "[value1][value2]";

const removeBrackets = (stringWithBrackets) => 
 return stringWithBrackets.split("][").map(s => s = s.replace(/[*]*/g, ""));
;

const [value1, value2] = removeBrackets(string);

console.log(value1, value2);

answered Nov 14 '18 at 0:51

ams

2187

add a comment |

You can easily expand it for more values.

const string = "[value1][value2]";

const removeBrackets = (stringWithBrackets) => 
 return stringWithBrackets.split("][").map(s => s = s.replace(/[*]*/g, ""));
;

const [value1, value2] = removeBrackets(string);

console.log(value1, value2);

answered Nov 14 '18 at 0:51

ams

2187

You can easily expand it for more values.

const string = "[value1][value2]";

const removeBrackets = (stringWithBrackets) => 
 return stringWithBrackets.split("][").map(s => s = s.replace(/[*]*/g, ""));
;

const [value1, value2] = removeBrackets(string);

console.log(value1, value2);

const string = "[value1][value2]";

const removeBrackets = (stringWithBrackets) => 
 return stringWithBrackets.split("][").map(s => s = s.replace(/[*]*/g, ""));
;

const [value1, value2] = removeBrackets(string);

console.log(value1, value2);

const string = "[value1][value2]";

const removeBrackets = (stringWithBrackets) => 
 return stringWithBrackets.split("][").map(s => s = s.replace(/[*]*/g, ""));
;

const [value1, value2] = removeBrackets(string);

console.log(value1, value2);

answered Nov 14 '18 at 0:51

ams

2187

answered Nov 14 '18 at 0:51

ams

2187

answered Nov 14 '18 at 0:51

ams

2187

answered Nov 14 '18 at 0:51

ams

2187

add a comment |

const getItems = (fullItemsString) => 
 let items = fullItemsString.replace(/[/g, "").split("]");
 items.pop()

 return items;

Using:

let items = getItems("[2][34][1]");

result: [ '2', '', '34', '1' ]

answered Nov 14 '18 at 1:01

Fernando Matos

111

add a comment |

const getItems = (fullItemsString) => 
 let items = fullItemsString.replace(/[/g, "").split("]");
 items.pop()

 return items;

Using:

let items = getItems("[2][34][1]");

result: [ '2', '', '34', '1' ]

answered Nov 14 '18 at 1:01

Fernando Matos

111

add a comment |

const getItems = (fullItemsString) => 
 let items = fullItemsString.replace(/[/g, "").split("]");
 items.pop()

 return items;

Using:

let items = getItems("[2][34][1]");

result: [ '2', '', '34', '1' ]

answered Nov 14 '18 at 1:01

Fernando Matos

111

const getItems = (fullItemsString) => 
 let items = fullItemsString.replace(/[/g, "").split("]");
 items.pop()

 return items;

Using:

let items = getItems("[2][34][1]");

result: [ '2', '', '34', '1' ]

answered Nov 14 '18 at 1:01

Fernando Matos

111

answered Nov 14 '18 at 1:01

Fernando Matos

111

answered Nov 14 '18 at 1:01

Fernando Matos

111

answered Nov 14 '18 at 1:01

Fernando Matos

111

add a comment |

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