spring data - Mongodb - findBy Method for nested objects
I have two domain objects,
@Document
public class PracticeQuestion
private int userId;
private List<Question> questions;
// Getters and setters
@Document
public class Question
private int questionID;
private String type;
// Getters and setters
My JSON doc is like this,
"_id" : ObjectId("506d9c0ce4b005cb478c2e97"),
"userId" : 1,
"questions" : [
"questionID" : 1,
"type" : "optional"
,
"questionID" : 3,
"type" : "mandatory"
]
I have to update the "type" based on userId and questionId, so I have written a findBy query method inside the custom Repository interface,
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId,int questionID);
My problem is when I execute this method with userId as 1 and questionID as 3, it returns the entire questions list irrespective of the questionID. Is the query method name valid or how should I write the query for nested objects.
Thanks for any suggestion.
mongodb spring-data findby
add a comment |
I have two domain objects,
@Document
public class PracticeQuestion
private int userId;
private List<Question> questions;
// Getters and setters
@Document
public class Question
private int questionID;
private String type;
// Getters and setters
My JSON doc is like this,
"_id" : ObjectId("506d9c0ce4b005cb478c2e97"),
"userId" : 1,
"questions" : [
"questionID" : 1,
"type" : "optional"
,
"questionID" : 3,
"type" : "mandatory"
]
I have to update the "type" based on userId and questionId, so I have written a findBy query method inside the custom Repository interface,
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId,int questionID);
My problem is when I execute this method with userId as 1 and questionID as 3, it returns the entire questions list irrespective of the questionID. Is the query method name valid or how should I write the query for nested objects.
Thanks for any suggestion.
mongodb spring-data findby
add a comment |
I have two domain objects,
@Document
public class PracticeQuestion
private int userId;
private List<Question> questions;
// Getters and setters
@Document
public class Question
private int questionID;
private String type;
// Getters and setters
My JSON doc is like this,
"_id" : ObjectId("506d9c0ce4b005cb478c2e97"),
"userId" : 1,
"questions" : [
"questionID" : 1,
"type" : "optional"
,
"questionID" : 3,
"type" : "mandatory"
]
I have to update the "type" based on userId and questionId, so I have written a findBy query method inside the custom Repository interface,
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId,int questionID);
My problem is when I execute this method with userId as 1 and questionID as 3, it returns the entire questions list irrespective of the questionID. Is the query method name valid or how should I write the query for nested objects.
Thanks for any suggestion.
mongodb spring-data findby
I have two domain objects,
@Document
public class PracticeQuestion
private int userId;
private List<Question> questions;
// Getters and setters
@Document
public class Question
private int questionID;
private String type;
// Getters and setters
My JSON doc is like this,
"_id" : ObjectId("506d9c0ce4b005cb478c2e97"),
"userId" : 1,
"questions" : [
"questionID" : 1,
"type" : "optional"
,
"questionID" : 3,
"type" : "mandatory"
]
I have to update the "type" based on userId and questionId, so I have written a findBy query method inside the custom Repository interface,
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId,int questionID);
My problem is when I execute this method with userId as 1 and questionID as 3, it returns the entire questions list irrespective of the questionID. Is the query method name valid or how should I write the query for nested objects.
Thanks for any suggestion.
mongodb spring-data findby
mongodb spring-data findby
edited May 8 '17 at 12:20
BiJ
61611029
61611029
asked Oct 4 '12 at 15:11
user1720083user1720083
91113
91113
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Just use the @Query
annotation on that method.
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
@Query(value = " 'userId' : ?0, 'questions.questionID' : ?1 ", fields = " 'questions.questionID' : 1 ")
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId, int questionID);
By adding the fields
part of the @Query
annotation, you are telling Mongo to only return that part of the document. Beware though, it still returns the entire document in the same format - just missing everything you did not specify. So your code will still have to return List<PracticeQuestion>
and you will have to do:
foreach (PracticeQuestion pq : practiceQuestions)
Question q = pq.getQuestions().get(0); // This should be your question.
Thanks for you reply, but again this query returns an array rather than the appropriate element in the array.
– user1720083
Oct 12 '12 at 15:11
1
Oh. I see what you mean. You can only ever return the entire document. The query actually looks for documents that have that questionID. But you always get the entire document returned - never just the question. It isn't a java thing, it is a MongoDB thing. Look at this question/answer for clarification: stackoverflow.com/a/3985982/229178
– sbzoom
Oct 12 '12 at 16:18
1
After some homework I realized you can specify partial objects in thefields
part of your query (projections
). mongodb.org/display/DOCS/Retrieving+a+Subset+of+Fields I will update my answer above to give an example.
– sbzoom
Oct 12 '12 at 16:19
Thanks, meanwhile I will also try that.
– user1720083
Oct 15 '12 at 7:42
add a comment |
Property expressions
Property expressions can refer only to a direct property of the managed entity, as shown in the preceding example. At query creation time you already make sure that the parsed property is a property of the managed domain class. However, you can also define constraints by traversing nested properties. Assume Persons have Addresses with ZipCodes. In that case a method name of
List findByAddressZipCode(ZipCode zipCode);
creates the property traversal x.address.zipCode. The resolution algorithm starts with interpreting the entire part (AddressZipCode) as the property and checks the domain class for a property with that name (uncapitalized). If the algorithm succeeds it uses that property. If not, the algorithm splits up the source at the camel case parts from the right side into a head and a tail and tries to find the corresponding property, in our example, AddressZip and Code. If the algorithm finds a property with that head it takes the tail and continue building the tree down from there, splitting the tail up in the way just described. If the first split does not match, the algorithm move the split point to the left (Address, ZipCode) and continues.
Although this should work for most cases, it is possible for the algorithm to select the wrong property. Suppose the Person class has an addressZip property as well. The algorithm would match in the first split round already and essentially choose the wrong property and finally fail (as the type of addressZip probably has no code property). To resolve this ambiguity you can use _ inside your method name to manually define traversal points. So our method name would end up like so:
UserDataRepository:
List findByAddress_ZipCode(ZipCode zipCode);
UserData findByUserId(String userId);
ProfileRepository:
Profile findByProfileId(String profileId);
UserDataRepositoryImpl:
UserData userData = userDateRepository.findByUserId(userId);
Profile profile = profileRepository.findByProfileId(userData.getProfileId());
userData.setProfile(profile);
Sample Pojo :
public class UserData
private String userId;
private String status;
private Address address;
private String profileId;
//New Property
private Profile profile;
//TODO:setter & getter
public class Profile
private String email;
private String profileId;
For the above Document/POJO in your Repository Class:
UserData findByProfile_Email(String email);
For ref : http://docs.spring.io/spring-data/data-commons/docs/1.6.1.RELEASE/reference/html/repositories.html
1
This is quality post
– ZZ 5
Apr 23 '18 at 13:58
add a comment |
You need to use Mongo Aggregation framework :
1) Create custom method for mongo repository : Add custom method to Repository
UnwindOperation unwind = Aggregation.unwind("questions");
MatchOperation match = Aggregation.match(Criteria.where("userId").is(userId).and("questions.questionId").is(questionID));
Aggregation aggregation = Aggregation.newAggregation(unwind,match);
AggregationResults<PracticeQuestionUnwind> results = mongoOperations.aggregate(aggregation, "PracticeQuestion",
PracticeQuestionUnwind.class);
return results.getMappedResults();
2) You need to cretae a class(Because unwind operation has changed the class structure) like below :
public class PracticeQuestionUnwind {
private String userId;
private Question questions;
This will give you only those result which matches the provide userId
and questionId
Result for userId: 1 and questionId : 111 :
"userId": "1",
"questions":
"questionId": "111",
"type": "optional"
I also tried this but couldn't resolve the problem.
– WGSSAMINTHA
Nov 21 '18 at 9:16
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just use the @Query
annotation on that method.
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
@Query(value = " 'userId' : ?0, 'questions.questionID' : ?1 ", fields = " 'questions.questionID' : 1 ")
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId, int questionID);
By adding the fields
part of the @Query
annotation, you are telling Mongo to only return that part of the document. Beware though, it still returns the entire document in the same format - just missing everything you did not specify. So your code will still have to return List<PracticeQuestion>
and you will have to do:
foreach (PracticeQuestion pq : practiceQuestions)
Question q = pq.getQuestions().get(0); // This should be your question.
Thanks for you reply, but again this query returns an array rather than the appropriate element in the array.
– user1720083
Oct 12 '12 at 15:11
1
Oh. I see what you mean. You can only ever return the entire document. The query actually looks for documents that have that questionID. But you always get the entire document returned - never just the question. It isn't a java thing, it is a MongoDB thing. Look at this question/answer for clarification: stackoverflow.com/a/3985982/229178
– sbzoom
Oct 12 '12 at 16:18
1
After some homework I realized you can specify partial objects in thefields
part of your query (projections
). mongodb.org/display/DOCS/Retrieving+a+Subset+of+Fields I will update my answer above to give an example.
– sbzoom
Oct 12 '12 at 16:19
Thanks, meanwhile I will also try that.
– user1720083
Oct 15 '12 at 7:42
add a comment |
Just use the @Query
annotation on that method.
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
@Query(value = " 'userId' : ?0, 'questions.questionID' : ?1 ", fields = " 'questions.questionID' : 1 ")
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId, int questionID);
By adding the fields
part of the @Query
annotation, you are telling Mongo to only return that part of the document. Beware though, it still returns the entire document in the same format - just missing everything you did not specify. So your code will still have to return List<PracticeQuestion>
and you will have to do:
foreach (PracticeQuestion pq : practiceQuestions)
Question q = pq.getQuestions().get(0); // This should be your question.
Thanks for you reply, but again this query returns an array rather than the appropriate element in the array.
– user1720083
Oct 12 '12 at 15:11
1
Oh. I see what you mean. You can only ever return the entire document. The query actually looks for documents that have that questionID. But you always get the entire document returned - never just the question. It isn't a java thing, it is a MongoDB thing. Look at this question/answer for clarification: stackoverflow.com/a/3985982/229178
– sbzoom
Oct 12 '12 at 16:18
1
After some homework I realized you can specify partial objects in thefields
part of your query (projections
). mongodb.org/display/DOCS/Retrieving+a+Subset+of+Fields I will update my answer above to give an example.
– sbzoom
Oct 12 '12 at 16:19
Thanks, meanwhile I will also try that.
– user1720083
Oct 15 '12 at 7:42
add a comment |
Just use the @Query
annotation on that method.
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
@Query(value = " 'userId' : ?0, 'questions.questionID' : ?1 ", fields = " 'questions.questionID' : 1 ")
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId, int questionID);
By adding the fields
part of the @Query
annotation, you are telling Mongo to only return that part of the document. Beware though, it still returns the entire document in the same format - just missing everything you did not specify. So your code will still have to return List<PracticeQuestion>
and you will have to do:
foreach (PracticeQuestion pq : practiceQuestions)
Question q = pq.getQuestions().get(0); // This should be your question.
Just use the @Query
annotation on that method.
public interface CustomRepository extends MongoRepository<PracticeQuestion, String>
@Query(value = " 'userId' : ?0, 'questions.questionID' : ?1 ", fields = " 'questions.questionID' : 1 ")
List<PracticeQuestion> findByUserIdAndQuestionsQuestionID(int userId, int questionID);
By adding the fields
part of the @Query
annotation, you are telling Mongo to only return that part of the document. Beware though, it still returns the entire document in the same format - just missing everything you did not specify. So your code will still have to return List<PracticeQuestion>
and you will have to do:
foreach (PracticeQuestion pq : practiceQuestions)
Question q = pq.getQuestions().get(0); // This should be your question.
edited Oct 12 '12 at 16:21
answered Oct 10 '12 at 14:04
sbzoomsbzoom
2,31531928
2,31531928
Thanks for you reply, but again this query returns an array rather than the appropriate element in the array.
– user1720083
Oct 12 '12 at 15:11
1
Oh. I see what you mean. You can only ever return the entire document. The query actually looks for documents that have that questionID. But you always get the entire document returned - never just the question. It isn't a java thing, it is a MongoDB thing. Look at this question/answer for clarification: stackoverflow.com/a/3985982/229178
– sbzoom
Oct 12 '12 at 16:18
1
After some homework I realized you can specify partial objects in thefields
part of your query (projections
). mongodb.org/display/DOCS/Retrieving+a+Subset+of+Fields I will update my answer above to give an example.
– sbzoom
Oct 12 '12 at 16:19
Thanks, meanwhile I will also try that.
– user1720083
Oct 15 '12 at 7:42
add a comment |
Thanks for you reply, but again this query returns an array rather than the appropriate element in the array.
– user1720083
Oct 12 '12 at 15:11
1
Oh. I see what you mean. You can only ever return the entire document. The query actually looks for documents that have that questionID. But you always get the entire document returned - never just the question. It isn't a java thing, it is a MongoDB thing. Look at this question/answer for clarification: stackoverflow.com/a/3985982/229178
– sbzoom
Oct 12 '12 at 16:18
1
After some homework I realized you can specify partial objects in thefields
part of your query (projections
). mongodb.org/display/DOCS/Retrieving+a+Subset+of+Fields I will update my answer above to give an example.
– sbzoom
Oct 12 '12 at 16:19
Thanks, meanwhile I will also try that.
– user1720083
Oct 15 '12 at 7:42
Thanks for you reply, but again this query returns an array rather than the appropriate element in the array.
– user1720083
Oct 12 '12 at 15:11
Thanks for you reply, but again this query returns an array rather than the appropriate element in the array.
– user1720083
Oct 12 '12 at 15:11
1
1
Oh. I see what you mean. You can only ever return the entire document. The query actually looks for documents that have that questionID. But you always get the entire document returned - never just the question. It isn't a java thing, it is a MongoDB thing. Look at this question/answer for clarification: stackoverflow.com/a/3985982/229178
– sbzoom
Oct 12 '12 at 16:18
Oh. I see what you mean. You can only ever return the entire document. The query actually looks for documents that have that questionID. But you always get the entire document returned - never just the question. It isn't a java thing, it is a MongoDB thing. Look at this question/answer for clarification: stackoverflow.com/a/3985982/229178
– sbzoom
Oct 12 '12 at 16:18
1
1
After some homework I realized you can specify partial objects in the
fields
part of your query (projections
). mongodb.org/display/DOCS/Retrieving+a+Subset+of+Fields I will update my answer above to give an example.– sbzoom
Oct 12 '12 at 16:19
After some homework I realized you can specify partial objects in the
fields
part of your query (projections
). mongodb.org/display/DOCS/Retrieving+a+Subset+of+Fields I will update my answer above to give an example.– sbzoom
Oct 12 '12 at 16:19
Thanks, meanwhile I will also try that.
– user1720083
Oct 15 '12 at 7:42
Thanks, meanwhile I will also try that.
– user1720083
Oct 15 '12 at 7:42
add a comment |
Property expressions
Property expressions can refer only to a direct property of the managed entity, as shown in the preceding example. At query creation time you already make sure that the parsed property is a property of the managed domain class. However, you can also define constraints by traversing nested properties. Assume Persons have Addresses with ZipCodes. In that case a method name of
List findByAddressZipCode(ZipCode zipCode);
creates the property traversal x.address.zipCode. The resolution algorithm starts with interpreting the entire part (AddressZipCode) as the property and checks the domain class for a property with that name (uncapitalized). If the algorithm succeeds it uses that property. If not, the algorithm splits up the source at the camel case parts from the right side into a head and a tail and tries to find the corresponding property, in our example, AddressZip and Code. If the algorithm finds a property with that head it takes the tail and continue building the tree down from there, splitting the tail up in the way just described. If the first split does not match, the algorithm move the split point to the left (Address, ZipCode) and continues.
Although this should work for most cases, it is possible for the algorithm to select the wrong property. Suppose the Person class has an addressZip property as well. The algorithm would match in the first split round already and essentially choose the wrong property and finally fail (as the type of addressZip probably has no code property). To resolve this ambiguity you can use _ inside your method name to manually define traversal points. So our method name would end up like so:
UserDataRepository:
List findByAddress_ZipCode(ZipCode zipCode);
UserData findByUserId(String userId);
ProfileRepository:
Profile findByProfileId(String profileId);
UserDataRepositoryImpl:
UserData userData = userDateRepository.findByUserId(userId);
Profile profile = profileRepository.findByProfileId(userData.getProfileId());
userData.setProfile(profile);
Sample Pojo :
public class UserData
private String userId;
private String status;
private Address address;
private String profileId;
//New Property
private Profile profile;
//TODO:setter & getter
public class Profile
private String email;
private String profileId;
For the above Document/POJO in your Repository Class:
UserData findByProfile_Email(String email);
For ref : http://docs.spring.io/spring-data/data-commons/docs/1.6.1.RELEASE/reference/html/repositories.html
1
This is quality post
– ZZ 5
Apr 23 '18 at 13:58
add a comment |
Property expressions
Property expressions can refer only to a direct property of the managed entity, as shown in the preceding example. At query creation time you already make sure that the parsed property is a property of the managed domain class. However, you can also define constraints by traversing nested properties. Assume Persons have Addresses with ZipCodes. In that case a method name of
List findByAddressZipCode(ZipCode zipCode);
creates the property traversal x.address.zipCode. The resolution algorithm starts with interpreting the entire part (AddressZipCode) as the property and checks the domain class for a property with that name (uncapitalized). If the algorithm succeeds it uses that property. If not, the algorithm splits up the source at the camel case parts from the right side into a head and a tail and tries to find the corresponding property, in our example, AddressZip and Code. If the algorithm finds a property with that head it takes the tail and continue building the tree down from there, splitting the tail up in the way just described. If the first split does not match, the algorithm move the split point to the left (Address, ZipCode) and continues.
Although this should work for most cases, it is possible for the algorithm to select the wrong property. Suppose the Person class has an addressZip property as well. The algorithm would match in the first split round already and essentially choose the wrong property and finally fail (as the type of addressZip probably has no code property). To resolve this ambiguity you can use _ inside your method name to manually define traversal points. So our method name would end up like so:
UserDataRepository:
List findByAddress_ZipCode(ZipCode zipCode);
UserData findByUserId(String userId);
ProfileRepository:
Profile findByProfileId(String profileId);
UserDataRepositoryImpl:
UserData userData = userDateRepository.findByUserId(userId);
Profile profile = profileRepository.findByProfileId(userData.getProfileId());
userData.setProfile(profile);
Sample Pojo :
public class UserData
private String userId;
private String status;
private Address address;
private String profileId;
//New Property
private Profile profile;
//TODO:setter & getter
public class Profile
private String email;
private String profileId;
For the above Document/POJO in your Repository Class:
UserData findByProfile_Email(String email);
For ref : http://docs.spring.io/spring-data/data-commons/docs/1.6.1.RELEASE/reference/html/repositories.html
1
This is quality post
– ZZ 5
Apr 23 '18 at 13:58
add a comment |
Property expressions
Property expressions can refer only to a direct property of the managed entity, as shown in the preceding example. At query creation time you already make sure that the parsed property is a property of the managed domain class. However, you can also define constraints by traversing nested properties. Assume Persons have Addresses with ZipCodes. In that case a method name of
List findByAddressZipCode(ZipCode zipCode);
creates the property traversal x.address.zipCode. The resolution algorithm starts with interpreting the entire part (AddressZipCode) as the property and checks the domain class for a property with that name (uncapitalized). If the algorithm succeeds it uses that property. If not, the algorithm splits up the source at the camel case parts from the right side into a head and a tail and tries to find the corresponding property, in our example, AddressZip and Code. If the algorithm finds a property with that head it takes the tail and continue building the tree down from there, splitting the tail up in the way just described. If the first split does not match, the algorithm move the split point to the left (Address, ZipCode) and continues.
Although this should work for most cases, it is possible for the algorithm to select the wrong property. Suppose the Person class has an addressZip property as well. The algorithm would match in the first split round already and essentially choose the wrong property and finally fail (as the type of addressZip probably has no code property). To resolve this ambiguity you can use _ inside your method name to manually define traversal points. So our method name would end up like so:
UserDataRepository:
List findByAddress_ZipCode(ZipCode zipCode);
UserData findByUserId(String userId);
ProfileRepository:
Profile findByProfileId(String profileId);
UserDataRepositoryImpl:
UserData userData = userDateRepository.findByUserId(userId);
Profile profile = profileRepository.findByProfileId(userData.getProfileId());
userData.setProfile(profile);
Sample Pojo :
public class UserData
private String userId;
private String status;
private Address address;
private String profileId;
//New Property
private Profile profile;
//TODO:setter & getter
public class Profile
private String email;
private String profileId;
For the above Document/POJO in your Repository Class:
UserData findByProfile_Email(String email);
For ref : http://docs.spring.io/spring-data/data-commons/docs/1.6.1.RELEASE/reference/html/repositories.html
Property expressions
Property expressions can refer only to a direct property of the managed entity, as shown in the preceding example. At query creation time you already make sure that the parsed property is a property of the managed domain class. However, you can also define constraints by traversing nested properties. Assume Persons have Addresses with ZipCodes. In that case a method name of
List findByAddressZipCode(ZipCode zipCode);
creates the property traversal x.address.zipCode. The resolution algorithm starts with interpreting the entire part (AddressZipCode) as the property and checks the domain class for a property with that name (uncapitalized). If the algorithm succeeds it uses that property. If not, the algorithm splits up the source at the camel case parts from the right side into a head and a tail and tries to find the corresponding property, in our example, AddressZip and Code. If the algorithm finds a property with that head it takes the tail and continue building the tree down from there, splitting the tail up in the way just described. If the first split does not match, the algorithm move the split point to the left (Address, ZipCode) and continues.
Although this should work for most cases, it is possible for the algorithm to select the wrong property. Suppose the Person class has an addressZip property as well. The algorithm would match in the first split round already and essentially choose the wrong property and finally fail (as the type of addressZip probably has no code property). To resolve this ambiguity you can use _ inside your method name to manually define traversal points. So our method name would end up like so:
UserDataRepository:
List findByAddress_ZipCode(ZipCode zipCode);
UserData findByUserId(String userId);
ProfileRepository:
Profile findByProfileId(String profileId);
UserDataRepositoryImpl:
UserData userData = userDateRepository.findByUserId(userId);
Profile profile = profileRepository.findByProfileId(userData.getProfileId());
userData.setProfile(profile);
Sample Pojo :
public class UserData
private String userId;
private String status;
private Address address;
private String profileId;
//New Property
private Profile profile;
//TODO:setter & getter
public class Profile
private String email;
private String profileId;
For the above Document/POJO in your Repository Class:
UserData findByProfile_Email(String email);
For ref : http://docs.spring.io/spring-data/data-commons/docs/1.6.1.RELEASE/reference/html/repositories.html
edited Apr 15 '18 at 12:08
Sep GH
555419
555419
answered Jan 19 '15 at 8:51
Govardhana Rao GanjiGovardhana Rao Ganji
34748
34748
1
This is quality post
– ZZ 5
Apr 23 '18 at 13:58
add a comment |
1
This is quality post
– ZZ 5
Apr 23 '18 at 13:58
1
1
This is quality post
– ZZ 5
Apr 23 '18 at 13:58
This is quality post
– ZZ 5
Apr 23 '18 at 13:58
add a comment |
You need to use Mongo Aggregation framework :
1) Create custom method for mongo repository : Add custom method to Repository
UnwindOperation unwind = Aggregation.unwind("questions");
MatchOperation match = Aggregation.match(Criteria.where("userId").is(userId).and("questions.questionId").is(questionID));
Aggregation aggregation = Aggregation.newAggregation(unwind,match);
AggregationResults<PracticeQuestionUnwind> results = mongoOperations.aggregate(aggregation, "PracticeQuestion",
PracticeQuestionUnwind.class);
return results.getMappedResults();
2) You need to cretae a class(Because unwind operation has changed the class structure) like below :
public class PracticeQuestionUnwind {
private String userId;
private Question questions;
This will give you only those result which matches the provide userId
and questionId
Result for userId: 1 and questionId : 111 :
"userId": "1",
"questions":
"questionId": "111",
"type": "optional"
I also tried this but couldn't resolve the problem.
– WGSSAMINTHA
Nov 21 '18 at 9:16
add a comment |
You need to use Mongo Aggregation framework :
1) Create custom method for mongo repository : Add custom method to Repository
UnwindOperation unwind = Aggregation.unwind("questions");
MatchOperation match = Aggregation.match(Criteria.where("userId").is(userId).and("questions.questionId").is(questionID));
Aggregation aggregation = Aggregation.newAggregation(unwind,match);
AggregationResults<PracticeQuestionUnwind> results = mongoOperations.aggregate(aggregation, "PracticeQuestion",
PracticeQuestionUnwind.class);
return results.getMappedResults();
2) You need to cretae a class(Because unwind operation has changed the class structure) like below :
public class PracticeQuestionUnwind {
private String userId;
private Question questions;
This will give you only those result which matches the provide userId
and questionId
Result for userId: 1 and questionId : 111 :
"userId": "1",
"questions":
"questionId": "111",
"type": "optional"
I also tried this but couldn't resolve the problem.
– WGSSAMINTHA
Nov 21 '18 at 9:16
add a comment |
You need to use Mongo Aggregation framework :
1) Create custom method for mongo repository : Add custom method to Repository
UnwindOperation unwind = Aggregation.unwind("questions");
MatchOperation match = Aggregation.match(Criteria.where("userId").is(userId).and("questions.questionId").is(questionID));
Aggregation aggregation = Aggregation.newAggregation(unwind,match);
AggregationResults<PracticeQuestionUnwind> results = mongoOperations.aggregate(aggregation, "PracticeQuestion",
PracticeQuestionUnwind.class);
return results.getMappedResults();
2) You need to cretae a class(Because unwind operation has changed the class structure) like below :
public class PracticeQuestionUnwind {
private String userId;
private Question questions;
This will give you only those result which matches the provide userId
and questionId
Result for userId: 1 and questionId : 111 :
"userId": "1",
"questions":
"questionId": "111",
"type": "optional"
You need to use Mongo Aggregation framework :
1) Create custom method for mongo repository : Add custom method to Repository
UnwindOperation unwind = Aggregation.unwind("questions");
MatchOperation match = Aggregation.match(Criteria.where("userId").is(userId).and("questions.questionId").is(questionID));
Aggregation aggregation = Aggregation.newAggregation(unwind,match);
AggregationResults<PracticeQuestionUnwind> results = mongoOperations.aggregate(aggregation, "PracticeQuestion",
PracticeQuestionUnwind.class);
return results.getMappedResults();
2) You need to cretae a class(Because unwind operation has changed the class structure) like below :
public class PracticeQuestionUnwind {
private String userId;
private Question questions;
This will give you only those result which matches the provide userId
and questionId
Result for userId: 1 and questionId : 111 :
"userId": "1",
"questions":
"questionId": "111",
"type": "optional"
answered Sep 26 '17 at 18:36
Mehraj MalikMehraj Malik
3,82022451
3,82022451
I also tried this but couldn't resolve the problem.
– WGSSAMINTHA
Nov 21 '18 at 9:16
add a comment |
I also tried this but couldn't resolve the problem.
– WGSSAMINTHA
Nov 21 '18 at 9:16
I also tried this but couldn't resolve the problem.
– WGSSAMINTHA
Nov 21 '18 at 9:16
I also tried this but couldn't resolve the problem.
– WGSSAMINTHA
Nov 21 '18 at 9:16
add a comment |
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