When does JS create an object wrapper for a string?
Symbol.iterator in 'retularString' // error right-hand side of in
sould be an object
Symbol.iterator in new String() // true
Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase()
/ 'string'.length
?
javascript javascript-objects
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Symbol.iterator in 'retularString' // error right-hand side of in
sould be an object
Symbol.iterator in new String() // true
Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase()
/ 'string'.length
?
javascript javascript-objects
add a comment |
Symbol.iterator in 'retularString' // error right-hand side of in
sould be an object
Symbol.iterator in new String() // true
Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase()
/ 'string'.length
?
javascript javascript-objects
Symbol.iterator in 'retularString' // error right-hand side of in
sould be an object
Symbol.iterator in new String() // true
Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase()
/ 'string'.length
?
javascript javascript-objects
javascript javascript-objects
edited Nov 13 '18 at 7:15
daGo
asked Nov 13 '18 at 7:09
daGodaGo
553612
553612
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add a comment |
1 Answer
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Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like
'string'.toUppercase()
/'string'.length
?
Yes.
When you have a string declared as var foo = 'foo'
its type is the primitive string
, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String
object through a process called implicit coercion.
See this article for a full explanation of coercion in JavaScript.
1
Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948
– Hero Wanders
Nov 13 '18 at 7:47
I just wanted to be sure that's wrapping does not occur upon any other circumstances.
– daGo
Nov 13 '18 at 8:00
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like
'string'.toUppercase()
/'string'.length
?
Yes.
When you have a string declared as var foo = 'foo'
its type is the primitive string
, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String
object through a process called implicit coercion.
See this article for a full explanation of coercion in JavaScript.
1
Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948
– Hero Wanders
Nov 13 '18 at 7:47
I just wanted to be sure that's wrapping does not occur upon any other circumstances.
– daGo
Nov 13 '18 at 8:00
add a comment |
Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like
'string'.toUppercase()
/'string'.length
?
Yes.
When you have a string declared as var foo = 'foo'
its type is the primitive string
, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String
object through a process called implicit coercion.
See this article for a full explanation of coercion in JavaScript.
1
Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948
– Hero Wanders
Nov 13 '18 at 7:47
I just wanted to be sure that's wrapping does not occur upon any other circumstances.
– daGo
Nov 13 '18 at 8:00
add a comment |
Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like
'string'.toUppercase()
/'string'.length
?
Yes.
When you have a string declared as var foo = 'foo'
its type is the primitive string
, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String
object through a process called implicit coercion.
See this article for a full explanation of coercion in JavaScript.
Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like
'string'.toUppercase()
/'string'.length
?
Yes.
When you have a string declared as var foo = 'foo'
its type is the primitive string
, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String
object through a process called implicit coercion.
See this article for a full explanation of coercion in JavaScript.
answered Nov 13 '18 at 7:22
VulcanVulcan
22.9k94076
22.9k94076
1
Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948
– Hero Wanders
Nov 13 '18 at 7:47
I just wanted to be sure that's wrapping does not occur upon any other circumstances.
– daGo
Nov 13 '18 at 8:00
add a comment |
1
Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948
– Hero Wanders
Nov 13 '18 at 7:47
I just wanted to be sure that's wrapping does not occur upon any other circumstances.
– daGo
Nov 13 '18 at 8:00
1
1
Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948
– Hero Wanders
Nov 13 '18 at 7:47
Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948
– Hero Wanders
Nov 13 '18 at 7:47
I just wanted to be sure that's wrapping does not occur upon any other circumstances.
– daGo
Nov 13 '18 at 8:00
I just wanted to be sure that's wrapping does not occur upon any other circumstances.
– daGo
Nov 13 '18 at 8:00
add a comment |
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