When does JS create an object wrapper for a string?










3















Symbol.iterator in 'retularString' // error right-hand side of in sould be an object



Symbol.iterator in new String() // true



Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?










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    3















    Symbol.iterator in 'retularString' // error right-hand side of in sould be an object



    Symbol.iterator in new String() // true



    Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?










    share|improve this question


























      3












      3








      3


      1






      Symbol.iterator in 'retularString' // error right-hand side of in sould be an object



      Symbol.iterator in new String() // true



      Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?










      share|improve this question
















      Symbol.iterator in 'retularString' // error right-hand side of in sould be an object



      Symbol.iterator in new String() // true



      Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?







      javascript javascript-objects






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      edited Nov 13 '18 at 7:15







      daGo

















      asked Nov 13 '18 at 7:09









      daGodaGo

      553612




      553612






















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          Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?




          Yes.



          When you have a string declared as var foo = 'foo' its type is the primitive string, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String object through a process called implicit coercion.



          See this article for a full explanation of coercion in JavaScript.






          share|improve this answer


















          • 1





            Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948

            – Hero Wanders
            Nov 13 '18 at 7:47











          • I just wanted to be sure that's wrapping does not occur upon any other circumstances.

            – daGo
            Nov 13 '18 at 8:00










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          1 Answer
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          active

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          3















          Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?




          Yes.



          When you have a string declared as var foo = 'foo' its type is the primitive string, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String object through a process called implicit coercion.



          See this article for a full explanation of coercion in JavaScript.






          share|improve this answer


















          • 1





            Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948

            – Hero Wanders
            Nov 13 '18 at 7:47











          • I just wanted to be sure that's wrapping does not occur upon any other circumstances.

            – daGo
            Nov 13 '18 at 8:00















          3















          Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?




          Yes.



          When you have a string declared as var foo = 'foo' its type is the primitive string, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String object through a process called implicit coercion.



          See this article for a full explanation of coercion in JavaScript.






          share|improve this answer


















          • 1





            Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948

            – Hero Wanders
            Nov 13 '18 at 7:47











          • I just wanted to be sure that's wrapping does not occur upon any other circumstances.

            – daGo
            Nov 13 '18 at 8:00













          3












          3








          3








          Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?




          Yes.



          When you have a string declared as var foo = 'foo' its type is the primitive string, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String object through a process called implicit coercion.



          See this article for a full explanation of coercion in JavaScript.






          share|improve this answer














          Does that mean JS creates object wrappers for strings only when it calls methods / or accesses corresponding properties on them like 'string'.toUppercase() / 'string'.length?




          Yes.



          When you have a string declared as var foo = 'foo' its type is the primitive string, having no properties inherently, but when you try and access a property on it, the primitive is wrapped momentarily in the String object through a process called implicit coercion.



          See this article for a full explanation of coercion in JavaScript.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 7:22









          VulcanVulcan

          22.9k94076




          22.9k94076







          • 1





            Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948

            – Hero Wanders
            Nov 13 '18 at 7:47











          • I just wanted to be sure that's wrapping does not occur upon any other circumstances.

            – daGo
            Nov 13 '18 at 8:00












          • 1





            Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948

            – Hero Wanders
            Nov 13 '18 at 7:47











          • I just wanted to be sure that's wrapping does not occur upon any other circumstances.

            – daGo
            Nov 13 '18 at 8:00







          1




          1





          Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948

          – Hero Wanders
          Nov 13 '18 at 7:47





          Perhaps the answers to this question are a good addition: stackoverflow.com/q/17256182/10245948

          – Hero Wanders
          Nov 13 '18 at 7:47













          I just wanted to be sure that's wrapping does not occur upon any other circumstances.

          – daGo
          Nov 13 '18 at 8:00





          I just wanted to be sure that's wrapping does not occur upon any other circumstances.

          – daGo
          Nov 13 '18 at 8:00

















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