Fill a new list in R matching columns and rownames
This is my code:
mydatamatrix<-matrix(rnorm(30),nrow=10,ncol=26);colnames(mydatamatrix)<-LETTERS[1:26]
pairs<-matrix(LETTERS[1:20],ncol=2);
mylist <- rep(list(vector(mode = "list", 2)),nrow(pairs))
I would like to fill my mylist list with the collumns values of mydatamatrix matrix but matching with the pairs names.
For example:
mylist[[1]] should have the values of A and K columns of mydatamatrix
And mylist[[1]][1]should be A mylist[[1]][2] should be K.
How can I do this?
And also I would like to name the positions mylist[[k]][j] by the names from mydatamatrix collumns that will fill mylist.
Is it clear?
Any help? Thanks
r
asked Nov 14 '18 at 17:53
LauraLaura
353110
add a comment |
This is my code:
mydatamatrix<-matrix(rnorm(30),nrow=10,ncol=26);colnames(mydatamatrix)<-LETTERS[1:26]
pairs<-matrix(LETTERS[1:20],ncol=2);
mylist <- rep(list(vector(mode = "list", 2)),nrow(pairs))
I would like to fill my mylist list with the collumns values of mydatamatrix matrix but matching with the pairs names.
For example:
mylist[[1]] should have the values of A and K columns of mydatamatrix
And mylist[[1]][1]should be A mylist[[1]][2] should be K.
How can I do this?
And also I would like to name the positions mylist[[k]][j] by the names from mydatamatrix collumns that will fill mylist.
Is it clear?
Any help? Thanks
r
asked Nov 14 '18 at 17:53
LauraLaura
353110
add a comment |
This is my code:
mydatamatrix<-matrix(rnorm(30),nrow=10,ncol=26);colnames(mydatamatrix)<-LETTERS[1:26]
pairs<-matrix(LETTERS[1:20],ncol=2);
mylist <- rep(list(vector(mode = "list", 2)),nrow(pairs))
I would like to fill my mylist list with the collumns values of mydatamatrix matrix but matching with the pairs names.
For example:
mylist[[1]] should have the values of A and K columns of mydatamatrix
And mylist[[1]][1]should be A mylist[[1]][2] should be K.
How can I do this?
And also I would like to name the positions mylist[[k]][j] by the names from mydatamatrix collumns that will fill mylist.
Is it clear?
Any help? Thanks
r
asked Nov 14 '18 at 17:53
LauraLaura
353110
This is my code:
mydatamatrix<-matrix(rnorm(30),nrow=10,ncol=26);colnames(mydatamatrix)<-LETTERS[1:26]
pairs<-matrix(LETTERS[1:20],ncol=2);
mylist <- rep(list(vector(mode = "list", 2)),nrow(pairs))
I would like to fill my mylist list with the collumns values of mydatamatrix matrix but matching with the pairs names.
For example:
mylist[[1]] should have the values of A and K columns of mydatamatrix
And mylist[[1]][1]should be A mylist[[1]][2] should be K.
How can I do this?
And also I would like to name the positions mylist[[k]][j] by the names from mydatamatrix collumns that will fill mylist.
Is it clear?
Any help? Thanks
r
r
asked Nov 14 '18 at 17:53
LauraLaura
353110
asked Nov 14 '18 at 17:53
LauraLaura
353110
asked Nov 14 '18 at 17:53
LauraLaura
353110
asked Nov 14 '18 at 17:53
LauraLaura
353110
asked Nov 14 '18 at 17:53
LauraLaura
353110
353110
add a comment |
add a comment |
1 Answer
1
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oldest
votes
We can split the 'pairs' by row and extract the columns of the dataset in a list
lapply(split(pairs, row(pairs)), function(x)
list(mydatamatrix[, x[1]], mydatamatrix[, x[2]]))
Or assign the already created 'mylist' with the output of extracted values using a for loop
for(i in seq_along(mylist)) mylist[[i]] <- list(mydatamatrix[, pairs[i,][1]],
mydatamatrix[, pairs[i, ][2]])
answered Nov 14 '18 at 18:00
akrunakrun
414k13202276
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
We can split the 'pairs' by row and extract the columns of the dataset in a list
lapply(split(pairs, row(pairs)), function(x)
list(mydatamatrix[, x[1]], mydatamatrix[, x[2]]))
Or assign the already created 'mylist' with the output of extracted values using a for loop
for(i in seq_along(mylist)) mylist[[i]] <- list(mydatamatrix[, pairs[i,][1]],
mydatamatrix[, pairs[i, ][2]])
answered Nov 14 '18 at 18:00
akrunakrun
414k13202276
add a comment |
We can split the 'pairs' by row and extract the columns of the dataset in a list
lapply(split(pairs, row(pairs)), function(x)
list(mydatamatrix[, x[1]], mydatamatrix[, x[2]]))
Or assign the already created 'mylist' with the output of extracted values using a for loop
for(i in seq_along(mylist)) mylist[[i]] <- list(mydatamatrix[, pairs[i,][1]],
mydatamatrix[, pairs[i, ][2]])
answered Nov 14 '18 at 18:00
akrunakrun
414k13202276
add a comment |
We can split the 'pairs' by row and extract the columns of the dataset in a list
lapply(split(pairs, row(pairs)), function(x)
list(mydatamatrix[, x[1]], mydatamatrix[, x[2]]))
Or assign the already created 'mylist' with the output of extracted values using a for loop
for(i in seq_along(mylist)) mylist[[i]] <- list(mydatamatrix[, pairs[i,][1]],
mydatamatrix[, pairs[i, ][2]])
answered Nov 14 '18 at 18:00
akrunakrun
414k13202276
We can split the 'pairs' by row and extract the columns of the dataset in a list
lapply(split(pairs, row(pairs)), function(x)
list(mydatamatrix[, x[1]], mydatamatrix[, x[2]]))
Or assign the already created 'mylist' with the output of extracted values using a for loop
for(i in seq_along(mylist)) mylist[[i]] <- list(mydatamatrix[, pairs[i,][1]],
mydatamatrix[, pairs[i, ][2]])
answered Nov 14 '18 at 18:00
akrunakrun
414k13202276
edited Nov 14 '18 at 18:15
answered Nov 14 '18 at 18:00
akrunakrun
414k13202276
answered Nov 14 '18 at 18:00
akrunakrun
414k13202276
answered Nov 14 '18 at 18:00
akrunakrun
414k13202276
414k13202276
add a comment |
add a comment |
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