MYSQL combining, counting and separating instances of rows with same id but different values
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
1
Currently I have a query that looks like
with the query being written as such:
SELECT username, exerciseId, frustrated, bored
FROM affecttutor.selfreportfrustration
order by username;
and I am trying to make it look like this
what would be the possible ways to go about doing it? Thanks for your time!
mysql
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.7k62336
asked Nov 15 '18 at 9:04
John NoJohn No
203
add a comment |
1
Currently I have a query that looks like
with the query being written as such:
SELECT username, exerciseId, frustrated, bored
FROM affecttutor.selfreportfrustration
order by username;
and I am trying to make it look like this
what would be the possible ways to go about doing it? Thanks for your time!
mysql
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.7k62336
asked Nov 15 '18 at 9:04
John NoJohn No
203
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
add a comment |
1
1
1
Currently I have a query that looks like
with the query being written as such:
SELECT username, exerciseId, frustrated, bored
FROM affecttutor.selfreportfrustration
order by username;
and I am trying to make it look like this
what would be the possible ways to go about doing it? Thanks for your time!
mysql
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.7k62336
asked Nov 15 '18 at 9:04
John NoJohn No
203
Currently I have a query that looks like
with the query being written as such:
SELECT username, exerciseId, frustrated, bored
FROM affecttutor.selfreportfrustration
order by username;
and I am trying to make it look like this
what would be the possible ways to go about doing it? Thanks for your time!
mysql
mysql
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.7k62336
asked Nov 15 '18 at 9:04
John NoJohn No
203
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.7k62336
asked Nov 15 '18 at 9:04
John NoJohn No
203
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.7k62336
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.7k62336
edited Nov 15 '18 at 9:09
Madhur Bhaiya
19.7k62336
19.7k62336
asked Nov 15 '18 at 9:04
John NoJohn No
203
asked Nov 15 '18 at 9:04
John NoJohn No
203
asked Nov 15 '18 at 9:04
John NoJohn No
203
203
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
add a comment |
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00
add a comment |
1 Answer
1
active
oldest
votes
1
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.7k62336
answered Nov 15 '18 at 9:08
fa06fa06
19k21019
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53315761%2fmysql-combining-counting-and-separating-instances-of-rows-with-same-id-but-diff%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.7k62336
answered Nov 15 '18 at 9:08
fa06fa06
19k21019
add a comment |
1
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.7k62336
answered Nov 15 '18 at 9:08
fa06fa06
19k21019
add a comment |
1
1
1
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.7k62336
answered Nov 15 '18 at 9:08
fa06fa06
19k21019
You can try using conditional aggregation
select
username,exerciseid,
count(case when frustrated='Y' then 1 end) as frustrated,
count(case when frustrated<>'Y' then 1 end) as notfrustrated,
count(case when bored<>'N' then 1 end) as bored ,
count(case when bored='N' then 1 end) as notbored
from affecttutor.selfreportfrustration
group by username,exerciseid
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.7k62336
answered Nov 15 '18 at 9:08
fa06fa06
19k21019
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.7k62336
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.7k62336
edited Nov 15 '18 at 9:10
Madhur Bhaiya
19.7k62336
19.7k62336
answered Nov 15 '18 at 9:08
fa06fa06
19k21019
answered Nov 15 '18 at 9:08
fa06fa06
19k21019
answered Nov 15 '18 at 9:08
fa06fa06
19k21019
19k21019
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53315761%2fmysql-combining-counting-and-separating-instances-of-rows-with-same-id-but-diff%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
This kind of problem can be symptomatic of poor design. Consider whether there's scope to redesign your schema.
– Strawberry
Nov 15 '18 at 10:00