Randomly cropping/tiling an image in R
up vote
1
down vote
favorite
Is there anybody out there having a smart idea how to create n rectangular tiles from an image, each of different size with no overlapping. The solution given below is limited to n = 4.
randomTiles <- function(w, h, n)
if(sample(c(TRUE, FALSE), 1))
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
bl <- c(0, sample(tl[2]:w-round(w/10), 1), tl[4], h)
tr <- c(tl[2], w, 0, tl[4])
br <- c(bl[2], w, tl[4], h)
else
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
tr <- c(tl[2], w, 0, sample(tl[4]:h-round(h/10), 1))
bl <- c(0, tl[2], tl[4], h)
br <- c(tl[2], w, tr[4], h)
tileFrame <- data.frame(xleft = c(tl[1], bl[1], tr[1], br[1]),
ybottom = c(tl[3], bl[3], tr[3], br[3]),
xright = c(tl[2], bl[2], tr[2], br[2]),
ytop = c(tl[4], bl[4], tr[4], br[4]),
col = rgb(runif(4), runif(4), runif(4)))
return(tileFrame)
h <- 100
w <- 120
n <- 4
op <- par(mfrow = c(2,2))
for(i in 1:4)
plot(h, xlim = c(0, w), ylim = c(h, 0), type = "n", xlab = "WIDTH", ylab = "HIGHT")
tiles <- randomTiles(w = w, h = h, n = n)
rect(tiles[,1], tiles[,2], tiles[,3], tiles[,4], col = tiles[,5])
par(op)
Thanks for any hint...
r image ggplot2 plot tiling
add a comment |
up vote
1
down vote
favorite
Is there anybody out there having a smart idea how to create n rectangular tiles from an image, each of different size with no overlapping. The solution given below is limited to n = 4.
randomTiles <- function(w, h, n)
if(sample(c(TRUE, FALSE), 1))
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
bl <- c(0, sample(tl[2]:w-round(w/10), 1), tl[4], h)
tr <- c(tl[2], w, 0, tl[4])
br <- c(bl[2], w, tl[4], h)
else
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
tr <- c(tl[2], w, 0, sample(tl[4]:h-round(h/10), 1))
bl <- c(0, tl[2], tl[4], h)
br <- c(tl[2], w, tr[4], h)
tileFrame <- data.frame(xleft = c(tl[1], bl[1], tr[1], br[1]),
ybottom = c(tl[3], bl[3], tr[3], br[3]),
xright = c(tl[2], bl[2], tr[2], br[2]),
ytop = c(tl[4], bl[4], tr[4], br[4]),
col = rgb(runif(4), runif(4), runif(4)))
return(tileFrame)
h <- 100
w <- 120
n <- 4
op <- par(mfrow = c(2,2))
for(i in 1:4)
plot(h, xlim = c(0, w), ylim = c(h, 0), type = "n", xlab = "WIDTH", ylab = "HIGHT")
tiles <- randomTiles(w = w, h = h, n = n)
rect(tiles[,1], tiles[,2], tiles[,3], tiles[,4], col = tiles[,5])
par(op)
Thanks for any hint...
r image ggplot2 plot tiling
are rectangular tiles a requirement?
– hrbrmstr
Nov 9 at 19:47
Actually yes...
– Robert
Nov 9 at 19:51
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Is there anybody out there having a smart idea how to create n rectangular tiles from an image, each of different size with no overlapping. The solution given below is limited to n = 4.
randomTiles <- function(w, h, n)
if(sample(c(TRUE, FALSE), 1))
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
bl <- c(0, sample(tl[2]:w-round(w/10), 1), tl[4], h)
tr <- c(tl[2], w, 0, tl[4])
br <- c(bl[2], w, tl[4], h)
else
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
tr <- c(tl[2], w, 0, sample(tl[4]:h-round(h/10), 1))
bl <- c(0, tl[2], tl[4], h)
br <- c(tl[2], w, tr[4], h)
tileFrame <- data.frame(xleft = c(tl[1], bl[1], tr[1], br[1]),
ybottom = c(tl[3], bl[3], tr[3], br[3]),
xright = c(tl[2], bl[2], tr[2], br[2]),
ytop = c(tl[4], bl[4], tr[4], br[4]),
col = rgb(runif(4), runif(4), runif(4)))
return(tileFrame)
h <- 100
w <- 120
n <- 4
op <- par(mfrow = c(2,2))
for(i in 1:4)
plot(h, xlim = c(0, w), ylim = c(h, 0), type = "n", xlab = "WIDTH", ylab = "HIGHT")
tiles <- randomTiles(w = w, h = h, n = n)
rect(tiles[,1], tiles[,2], tiles[,3], tiles[,4], col = tiles[,5])
par(op)
Thanks for any hint...
r image ggplot2 plot tiling
Is there anybody out there having a smart idea how to create n rectangular tiles from an image, each of different size with no overlapping. The solution given below is limited to n = 4.
randomTiles <- function(w, h, n)
if(sample(c(TRUE, FALSE), 1))
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
bl <- c(0, sample(tl[2]:w-round(w/10), 1), tl[4], h)
tr <- c(tl[2], w, 0, tl[4])
br <- c(bl[2], w, tl[4], h)
else
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
tr <- c(tl[2], w, 0, sample(tl[4]:h-round(h/10), 1))
bl <- c(0, tl[2], tl[4], h)
br <- c(tl[2], w, tr[4], h)
tileFrame <- data.frame(xleft = c(tl[1], bl[1], tr[1], br[1]),
ybottom = c(tl[3], bl[3], tr[3], br[3]),
xright = c(tl[2], bl[2], tr[2], br[2]),
ytop = c(tl[4], bl[4], tr[4], br[4]),
col = rgb(runif(4), runif(4), runif(4)))
return(tileFrame)
h <- 100
w <- 120
n <- 4
op <- par(mfrow = c(2,2))
for(i in 1:4)
plot(h, xlim = c(0, w), ylim = c(h, 0), type = "n", xlab = "WIDTH", ylab = "HIGHT")
tiles <- randomTiles(w = w, h = h, n = n)
rect(tiles[,1], tiles[,2], tiles[,3], tiles[,4], col = tiles[,5])
par(op)
Thanks for any hint...
r image ggplot2 plot tiling
r image ggplot2 plot tiling
edited Nov 9 at 19:52
asked Nov 9 at 19:40
Robert
688
688
are rectangular tiles a requirement?
– hrbrmstr
Nov 9 at 19:47
Actually yes...
– Robert
Nov 9 at 19:51
add a comment |
are rectangular tiles a requirement?
– hrbrmstr
Nov 9 at 19:47
Actually yes...
– Robert
Nov 9 at 19:51
are rectangular tiles a requirement?
– hrbrmstr
Nov 9 at 19:47
are rectangular tiles a requirement?
– hrbrmstr
Nov 9 at 19:47
Actually yes...
– Robert
Nov 9 at 19:51
Actually yes...
– Robert
Nov 9 at 19:51
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.
UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.
library(data.tree)
library(tidyverse)
random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l
nd
split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")
set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x
else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y
get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)
root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)
root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))
set.seed(1)
rect_list <- purrr::rerun(10, random_rects(40, 100, 20))
df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")
ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)
head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6
Created on 2018-11-11 by the reprex package (v0.2.1)
Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42
Works pretty well, btw...
– Robert
Nov 12 at 11:42
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.
UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.
library(data.tree)
library(tidyverse)
random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l
nd
split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")
set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x
else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y
get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)
root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)
root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))
set.seed(1)
rect_list <- purrr::rerun(10, random_rects(40, 100, 20))
df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")
ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)
head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6
Created on 2018-11-11 by the reprex package (v0.2.1)
Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42
Works pretty well, btw...
– Robert
Nov 12 at 11:42
add a comment |
up vote
1
down vote
accepted
I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.
UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.
library(data.tree)
library(tidyverse)
random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l
nd
split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")
set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x
else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y
get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)
root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)
root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))
set.seed(1)
rect_list <- purrr::rerun(10, random_rects(40, 100, 20))
df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")
ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)
head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6
Created on 2018-11-11 by the reprex package (v0.2.1)
Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42
Works pretty well, btw...
– Robert
Nov 12 at 11:42
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.
UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.
library(data.tree)
library(tidyverse)
random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l
nd
split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")
set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x
else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y
get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)
root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)
root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))
set.seed(1)
rect_list <- purrr::rerun(10, random_rects(40, 100, 20))
df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")
ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)
head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6
Created on 2018-11-11 by the reprex package (v0.2.1)
I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.
UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.
library(data.tree)
library(tidyverse)
random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l
nd
split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")
set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x
else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y
get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)
root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)
root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))
set.seed(1)
rect_list <- purrr::rerun(10, random_rects(40, 100, 20))
df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")
ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)
head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6
Created on 2018-11-11 by the reprex package (v0.2.1)
edited Nov 11 at 6:09
answered Nov 11 at 4:40
seisdrum
1765
1765
Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42
Works pretty well, btw...
– Robert
Nov 12 at 11:42
add a comment |
Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42
Works pretty well, btw...
– Robert
Nov 12 at 11:42
Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42
Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42
Works pretty well, btw...
– Robert
Nov 12 at 11:42
Works pretty well, btw...
– Robert
Nov 12 at 11:42
add a comment |
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are rectangular tiles a requirement?
– hrbrmstr
Nov 9 at 19:47
Actually yes...
– Robert
Nov 9 at 19:51