Randomly cropping/tiling an image in R









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Is there anybody out there having a smart idea how to create n rectangular tiles from an image, each of different size with no overlapping. The solution given below is limited to n = 4.



randomTiles <- function(w, h, n)

if(sample(c(TRUE, FALSE), 1))
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
bl <- c(0, sample(tl[2]:w-round(w/10), 1), tl[4], h)
tr <- c(tl[2], w, 0, tl[4])
br <- c(bl[2], w, tl[4], h)
else
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
tr <- c(tl[2], w, 0, sample(tl[4]:h-round(h/10), 1))
bl <- c(0, tl[2], tl[4], h)
br <- c(tl[2], w, tr[4], h)

tileFrame <- data.frame(xleft = c(tl[1], bl[1], tr[1], br[1]),
ybottom = c(tl[3], bl[3], tr[3], br[3]),
xright = c(tl[2], bl[2], tr[2], br[2]),
ytop = c(tl[4], bl[4], tr[4], br[4]),
col = rgb(runif(4), runif(4), runif(4)))
return(tileFrame)



h <- 100
w <- 120
n <- 4

op <- par(mfrow = c(2,2))
for(i in 1:4)
plot(h, xlim = c(0, w), ylim = c(h, 0), type = "n", xlab = "WIDTH", ylab = "HIGHT")
tiles <- randomTiles(w = w, h = h, n = n)
rect(tiles[,1], tiles[,2], tiles[,3], tiles[,4], col = tiles[,5])

par(op)


Thanks for any hint...










share|improve this question























  • are rectangular tiles a requirement?
    – hrbrmstr
    Nov 9 at 19:47










  • Actually yes...
    – Robert
    Nov 9 at 19:51














up vote
1
down vote

favorite
1












Is there anybody out there having a smart idea how to create n rectangular tiles from an image, each of different size with no overlapping. The solution given below is limited to n = 4.



randomTiles <- function(w, h, n)

if(sample(c(TRUE, FALSE), 1))
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
bl <- c(0, sample(tl[2]:w-round(w/10), 1), tl[4], h)
tr <- c(tl[2], w, 0, tl[4])
br <- c(bl[2], w, tl[4], h)
else
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
tr <- c(tl[2], w, 0, sample(tl[4]:h-round(h/10), 1))
bl <- c(0, tl[2], tl[4], h)
br <- c(tl[2], w, tr[4], h)

tileFrame <- data.frame(xleft = c(tl[1], bl[1], tr[1], br[1]),
ybottom = c(tl[3], bl[3], tr[3], br[3]),
xright = c(tl[2], bl[2], tr[2], br[2]),
ytop = c(tl[4], bl[4], tr[4], br[4]),
col = rgb(runif(4), runif(4), runif(4)))
return(tileFrame)



h <- 100
w <- 120
n <- 4

op <- par(mfrow = c(2,2))
for(i in 1:4)
plot(h, xlim = c(0, w), ylim = c(h, 0), type = "n", xlab = "WIDTH", ylab = "HIGHT")
tiles <- randomTiles(w = w, h = h, n = n)
rect(tiles[,1], tiles[,2], tiles[,3], tiles[,4], col = tiles[,5])

par(op)


Thanks for any hint...










share|improve this question























  • are rectangular tiles a requirement?
    – hrbrmstr
    Nov 9 at 19:47










  • Actually yes...
    – Robert
    Nov 9 at 19:51












up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





Is there anybody out there having a smart idea how to create n rectangular tiles from an image, each of different size with no overlapping. The solution given below is limited to n = 4.



randomTiles <- function(w, h, n)

if(sample(c(TRUE, FALSE), 1))
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
bl <- c(0, sample(tl[2]:w-round(w/10), 1), tl[4], h)
tr <- c(tl[2], w, 0, tl[4])
br <- c(bl[2], w, tl[4], h)
else
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
tr <- c(tl[2], w, 0, sample(tl[4]:h-round(h/10), 1))
bl <- c(0, tl[2], tl[4], h)
br <- c(tl[2], w, tr[4], h)

tileFrame <- data.frame(xleft = c(tl[1], bl[1], tr[1], br[1]),
ybottom = c(tl[3], bl[3], tr[3], br[3]),
xright = c(tl[2], bl[2], tr[2], br[2]),
ytop = c(tl[4], bl[4], tr[4], br[4]),
col = rgb(runif(4), runif(4), runif(4)))
return(tileFrame)



h <- 100
w <- 120
n <- 4

op <- par(mfrow = c(2,2))
for(i in 1:4)
plot(h, xlim = c(0, w), ylim = c(h, 0), type = "n", xlab = "WIDTH", ylab = "HIGHT")
tiles <- randomTiles(w = w, h = h, n = n)
rect(tiles[,1], tiles[,2], tiles[,3], tiles[,4], col = tiles[,5])

par(op)


Thanks for any hint...










share|improve this question















Is there anybody out there having a smart idea how to create n rectangular tiles from an image, each of different size with no overlapping. The solution given below is limited to n = 4.



randomTiles <- function(w, h, n)

if(sample(c(TRUE, FALSE), 1))
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
bl <- c(0, sample(tl[2]:w-round(w/10), 1), tl[4], h)
tr <- c(tl[2], w, 0, tl[4])
br <- c(bl[2], w, tl[4], h)
else
tl <- c(0, sample(10:w-10, 1), 0, sample(round(h/10):h-round(h/10), 1))
tr <- c(tl[2], w, 0, sample(tl[4]:h-round(h/10), 1))
bl <- c(0, tl[2], tl[4], h)
br <- c(tl[2], w, tr[4], h)

tileFrame <- data.frame(xleft = c(tl[1], bl[1], tr[1], br[1]),
ybottom = c(tl[3], bl[3], tr[3], br[3]),
xright = c(tl[2], bl[2], tr[2], br[2]),
ytop = c(tl[4], bl[4], tr[4], br[4]),
col = rgb(runif(4), runif(4), runif(4)))
return(tileFrame)



h <- 100
w <- 120
n <- 4

op <- par(mfrow = c(2,2))
for(i in 1:4)
plot(h, xlim = c(0, w), ylim = c(h, 0), type = "n", xlab = "WIDTH", ylab = "HIGHT")
tiles <- randomTiles(w = w, h = h, n = n)
rect(tiles[,1], tiles[,2], tiles[,3], tiles[,4], col = tiles[,5])

par(op)


Thanks for any hint...







r image ggplot2 plot tiling






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share|improve this question








edited Nov 9 at 19:52

























asked Nov 9 at 19:40









Robert

688




688











  • are rectangular tiles a requirement?
    – hrbrmstr
    Nov 9 at 19:47










  • Actually yes...
    – Robert
    Nov 9 at 19:51
















  • are rectangular tiles a requirement?
    – hrbrmstr
    Nov 9 at 19:47










  • Actually yes...
    – Robert
    Nov 9 at 19:51















are rectangular tiles a requirement?
– hrbrmstr
Nov 9 at 19:47




are rectangular tiles a requirement?
– hrbrmstr
Nov 9 at 19:47












Actually yes...
– Robert
Nov 9 at 19:51




Actually yes...
– Robert
Nov 9 at 19:51












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.



UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.





library(data.tree)
library(tidyverse)

random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l

nd

split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")

set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x

else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y



get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)

root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)

root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))


set.seed(1)

rect_list <- purrr::rerun(10, random_rects(40, 100, 20))

df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")

ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)




head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6


Created on 2018-11-11 by the reprex package (v0.2.1)






share|improve this answer






















  • Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
    – Robert
    Nov 12 at 11:42










  • Works pretty well, btw...
    – Robert
    Nov 12 at 11:42










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.



UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.





library(data.tree)
library(tidyverse)

random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l

nd

split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")

set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x

else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y



get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)

root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)

root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))


set.seed(1)

rect_list <- purrr::rerun(10, random_rects(40, 100, 20))

df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")

ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)




head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6


Created on 2018-11-11 by the reprex package (v0.2.1)






share|improve this answer






















  • Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
    – Robert
    Nov 12 at 11:42










  • Works pretty well, btw...
    – Robert
    Nov 12 at 11:42














up vote
1
down vote



accepted










I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.



UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.





library(data.tree)
library(tidyverse)

random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l

nd

split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")

set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x

else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y



get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)

root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)

root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))


set.seed(1)

rect_list <- purrr::rerun(10, random_rects(40, 100, 20))

df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")

ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)




head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6


Created on 2018-11-11 by the reprex package (v0.2.1)






share|improve this answer






















  • Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
    – Robert
    Nov 12 at 11:42










  • Works pretty well, btw...
    – Robert
    Nov 12 at 11:42












up vote
1
down vote



accepted







up vote
1
down vote



accepted






I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.



UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.





library(data.tree)
library(tidyverse)

random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l

nd

split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")

set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x

else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y



get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)

root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)

root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))


set.seed(1)

rect_list <- purrr::rerun(10, random_rects(40, 100, 20))

df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")

ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)




head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6


Created on 2018-11-11 by the reprex package (v0.2.1)






share|improve this answer














I was a little bored, so I gave it a go. Works pretty well, but I'm very much not an expert on random generators, so it is very possible that there are some hidden biases in the positions of the rectangles that this code generates.



UPDATE: This really grabbed my attention. I think the first version was in fact biased towards making smaller and smaller rectangles. I updated the code so that this doesn't happen anymore, I think.





library(data.tree)
library(tidyverse)

random_rects <- function (x, y, n)
rand_leaf <- function (nd)
while (data.tree::isNotLeaf(nd))
nd <- if (runif(1) > .5) nd$r else nd$l

nd

split_node <- function (nd)
nd$div <- runif(1)
nd$dir <- ifelse(runif(1) > .5, "h", "v")
nd$AddChild("l")
nd$AddChild("r")

set_dims <- function (nd)
p <- nd$parent
nd$x0 = p$x0
nd$x1 = p$x1
nd$y0 = p$y0
nd$y1 = p$y1
if (p$dir == "h")
new_x <- p$x0 + (p$x1 - p$x0)*p$div
if (nd$name == "l")
nd$x1 <- new_x
else
nd$x0 <- new_x

else
new_y <- p$y0 + (p$y1 - p$y0)*p$div
if (nd$name == "l")
nd$y1 <- new_y
else
nd$y0 <- new_y



get_dims <- function (nd)
tibble::tibble(x0 = nd$x0, x1 = nd$x1, y0 = nd$y0, y1 = nd$y1)

root <- data.tree::Node$new("home")
for (i in seq_len(n - 1))
nd <- rand_leaf(root)
split_node(nd)

root$x0 <- 0
root$x1 <- x
root$y0 <- 0
root$y1 <- y
root$Do(set_dims, traversal = "pre-order", filterFun = data.tree::isNotRoot)
dfs <- purrr::map(data.tree::Traverse(root, filterFun = data.tree::isLeaf), get_dims)
list(tree = root, df = dplyr::bind_rows(dfs))


set.seed(1)

rect_list <- purrr::rerun(10, random_rects(40, 100, 20))

df <- dplyr::bind_rows(purrr::map(rect_list, ~ dplyr::mutate(.x$df, pos = factor(1:n()))), .id = "rep")

ggplot(df, aes(xmin = x0, xmax = x1, ymin = y0, ymax = y1, fill = pos)) +
geom_rect(alpha = .7) +
facet_wrap(~rep)




head(df)
#> # A tibble: 6 x 6
#> rep x0 x1 y0 y1 pos
#> <chr> <dbl> <dbl> <dbl> <dbl> <fct>
#> 1 1 0 15.3 0 3.56 1
#> 2 1 0 15.3 3.56 5.21 2
#> 3 1 0 15.3 5.21 5.47 3
#> 4 1 15.3 40 0 2.70 4
#> 5 1 15.3 25.3 2.70 5.47 5
#> 6 1 25.3 40 2.70 5.47 6


Created on 2018-11-11 by the reprex package (v0.2.1)







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edited Nov 11 at 6:09

























answered Nov 11 at 4:40









seisdrum

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  • Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
    – Robert
    Nov 12 at 11:42










  • Works pretty well, btw...
    – Robert
    Nov 12 at 11:42
















  • Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
    – Robert
    Nov 12 at 11:42










  • Works pretty well, btw...
    – Robert
    Nov 12 at 11:42















Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42




Always good to encounter bored people here on this platform ;-)...thank's a lot @seisdrum
– Robert
Nov 12 at 11:42












Works pretty well, btw...
– Robert
Nov 12 at 11:42




Works pretty well, btw...
– Robert
Nov 12 at 11:42

















 

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