Replace Nth match of regex with sed
I've got a dataset that looks like:
1099511629352|Nunez|Jorge|female|17/11/2000|2011-04-04T05:54:52.693+0000|201.221.59.59|Opera|Facebook
Column separator in this case is |
-> I want to replace the Nth column ($pos
) given one row's id, using sed.
Here's what I've come up with now:
Find the Nth match of the regex
[$columnsep]*[a-zA-Z0-9./-:+]+
Of a line that starts with the given
$id
- Replace that occurence with
$columnsep$editvalue
So the appropriate sed command would be:
sed "/^$id/[$columnsep]*[a-zA-Z0-9./-:+]+/$columnsep$editvalue/$pos}" $file
I get [a- ...": invalid command code [
although it works with online regex testers like https://regexr.com/
regex sed replace
add a comment |
I've got a dataset that looks like:
1099511629352|Nunez|Jorge|female|17/11/2000|2011-04-04T05:54:52.693+0000|201.221.59.59|Opera|Facebook
Column separator in this case is |
-> I want to replace the Nth column ($pos
) given one row's id, using sed.
Here's what I've come up with now:
Find the Nth match of the regex
[$columnsep]*[a-zA-Z0-9./-:+]+
Of a line that starts with the given
$id
- Replace that occurence with
$columnsep$editvalue
So the appropriate sed command would be:
sed "/^$id/[$columnsep]*[a-zA-Z0-9./-:+]+/$columnsep$editvalue/$pos}" $file
I get [a- ...": invalid command code [
although it works with online regex testers like https://regexr.com/
regex sed replace
2
This is a trivial job forawk
. Why do you needsed
?
– revo
Nov 11 at 13:32
add a comment |
I've got a dataset that looks like:
1099511629352|Nunez|Jorge|female|17/11/2000|2011-04-04T05:54:52.693+0000|201.221.59.59|Opera|Facebook
Column separator in this case is |
-> I want to replace the Nth column ($pos
) given one row's id, using sed.
Here's what I've come up with now:
Find the Nth match of the regex
[$columnsep]*[a-zA-Z0-9./-:+]+
Of a line that starts with the given
$id
- Replace that occurence with
$columnsep$editvalue
So the appropriate sed command would be:
sed "/^$id/[$columnsep]*[a-zA-Z0-9./-:+]+/$columnsep$editvalue/$pos}" $file
I get [a- ...": invalid command code [
although it works with online regex testers like https://regexr.com/
regex sed replace
I've got a dataset that looks like:
1099511629352|Nunez|Jorge|female|17/11/2000|2011-04-04T05:54:52.693+0000|201.221.59.59|Opera|Facebook
Column separator in this case is |
-> I want to replace the Nth column ($pos
) given one row's id, using sed.
Here's what I've come up with now:
Find the Nth match of the regex
[$columnsep]*[a-zA-Z0-9./-:+]+
Of a line that starts with the given
$id
- Replace that occurence with
$columnsep$editvalue
So the appropriate sed command would be:
sed "/^$id/[$columnsep]*[a-zA-Z0-9./-:+]+/$columnsep$editvalue/$pos}" $file
I get [a- ...": invalid command code [
although it works with online regex testers like https://regexr.com/
regex sed replace
regex sed replace
asked Nov 11 at 13:02
Zarkopafilis
3421516
3421516
2
This is a trivial job forawk
. Why do you needsed
?
– revo
Nov 11 at 13:32
add a comment |
2
This is a trivial job forawk
. Why do you needsed
?
– revo
Nov 11 at 13:32
2
2
This is a trivial job for
awk
. Why do you need sed
?– revo
Nov 11 at 13:32
This is a trivial job for
awk
. Why do you need sed
?– revo
Nov 11 at 13:32
add a comment |
1 Answer
1
active
oldest
votes
Something like this will do the job unless $columnsep
is longer than one character.
sed "/^$id/s/[$columnsep]*[^$columnsep]*/$columnsep$editvalue/$pos" "$file"
But, I suggest using awk for tasks like this
awk -F "$columnsep" -v OFS="$columnsep" -v id="$id" -v editvalue="$editvalue" -v pos="$pos" '
($1==id)$pos=editvalue1' "$file"
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Something like this will do the job unless $columnsep
is longer than one character.
sed "/^$id/s/[$columnsep]*[^$columnsep]*/$columnsep$editvalue/$pos" "$file"
But, I suggest using awk for tasks like this
awk -F "$columnsep" -v OFS="$columnsep" -v id="$id" -v editvalue="$editvalue" -v pos="$pos" '
($1==id)$pos=editvalue1' "$file"
add a comment |
Something like this will do the job unless $columnsep
is longer than one character.
sed "/^$id/s/[$columnsep]*[^$columnsep]*/$columnsep$editvalue/$pos" "$file"
But, I suggest using awk for tasks like this
awk -F "$columnsep" -v OFS="$columnsep" -v id="$id" -v editvalue="$editvalue" -v pos="$pos" '
($1==id)$pos=editvalue1' "$file"
add a comment |
Something like this will do the job unless $columnsep
is longer than one character.
sed "/^$id/s/[$columnsep]*[^$columnsep]*/$columnsep$editvalue/$pos" "$file"
But, I suggest using awk for tasks like this
awk -F "$columnsep" -v OFS="$columnsep" -v id="$id" -v editvalue="$editvalue" -v pos="$pos" '
($1==id)$pos=editvalue1' "$file"
Something like this will do the job unless $columnsep
is longer than one character.
sed "/^$id/s/[$columnsep]*[^$columnsep]*/$columnsep$editvalue/$pos" "$file"
But, I suggest using awk for tasks like this
awk -F "$columnsep" -v OFS="$columnsep" -v id="$id" -v editvalue="$editvalue" -v pos="$pos" '
($1==id)$pos=editvalue1' "$file"
edited Nov 11 at 13:34
answered Nov 11 at 13:29
oguzismail
3,24131025
3,24131025
add a comment |
add a comment |
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2
This is a trivial job for
awk
. Why do you needsed
?– revo
Nov 11 at 13:32