How to find the coordinates of the rectangle after turning the javafx shape
I draw a rectangle with coordinates (x = 100, y = 100, width = 200, height = 100). Then I turn the shape of this rectangle around the center.
this.rotation.addListener((obs, old, fresh) ->
Rotate rotate = new Rotate();
rotate.setAngle((double) fresh - (double) old);
rotate.setPivotX(x.getValue().doubleValue() + (width.getValue().doubleValue() / 2));
rotate.setPivotY(y.getValue().doubleValue() + (height.getValue().doubleValue() / 2));
shape.getTransforms().addAll(rotate);
);
How now to find out the coordinates of shape?
java javafx
edited Nov 13 '18 at 12:00
Gayan Mettananda
1,114713
asked Nov 13 '18 at 10:06
A1ex NSA1ex NS
205
add a comment |
I draw a rectangle with coordinates (x = 100, y = 100, width = 200, height = 100). Then I turn the shape of this rectangle around the center.
this.rotation.addListener((obs, old, fresh) ->
Rotate rotate = new Rotate();
rotate.setAngle((double) fresh - (double) old);
rotate.setPivotX(x.getValue().doubleValue() + (width.getValue().doubleValue() / 2));
rotate.setPivotY(y.getValue().doubleValue() + (height.getValue().doubleValue() / 2));
shape.getTransforms().addAll(rotate);
);
How now to find out the coordinates of shape?
java javafx
edited Nov 13 '18 at 12:00
Gayan Mettananda
1,114713
asked Nov 13 '18 at 10:06
A1ex NSA1ex NS
205
add a comment |
I draw a rectangle with coordinates (x = 100, y = 100, width = 200, height = 100). Then I turn the shape of this rectangle around the center.
this.rotation.addListener((obs, old, fresh) ->
Rotate rotate = new Rotate();
rotate.setAngle((double) fresh - (double) old);
rotate.setPivotX(x.getValue().doubleValue() + (width.getValue().doubleValue() / 2));
rotate.setPivotY(y.getValue().doubleValue() + (height.getValue().doubleValue() / 2));
shape.getTransforms().addAll(rotate);
);
How now to find out the coordinates of shape?
java javafx
edited Nov 13 '18 at 12:00
Gayan Mettananda
1,114713
asked Nov 13 '18 at 10:06
A1ex NSA1ex NS
205
I draw a rectangle with coordinates (x = 100, y = 100, width = 200, height = 100). Then I turn the shape of this rectangle around the center.
this.rotation.addListener((obs, old, fresh) ->
Rotate rotate = new Rotate();
rotate.setAngle((double) fresh - (double) old);
rotate.setPivotX(x.getValue().doubleValue() + (width.getValue().doubleValue() / 2));
rotate.setPivotY(y.getValue().doubleValue() + (height.getValue().doubleValue() / 2));
shape.getTransforms().addAll(rotate);
);
How now to find out the coordinates of shape?
java javafx
java javafx
edited Nov 13 '18 at 12:00
Gayan Mettananda
1,114713
asked Nov 13 '18 at 10:06
A1ex NSA1ex NS
205
edited Nov 13 '18 at 12:00
Gayan Mettananda
1,114713
asked Nov 13 '18 at 10:06
A1ex NSA1ex NS
205
edited Nov 13 '18 at 12:00
Gayan Mettananda
1,114713
edited Nov 13 '18 at 12:00
Gayan Mettananda
1,114713
edited Nov 13 '18 at 12:00
Gayan Mettananda
1,114713
1,114713
asked Nov 13 '18 at 10:06
A1ex NSA1ex NS
205
asked Nov 13 '18 at 10:06
A1ex NSA1ex NS
205
asked Nov 13 '18 at 10:06
A1ex NSA1ex NS
205
205
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can use the localToParent method to transform a point from the coordinate system of the Rectangle to the coordinate system of the parent.
Point2D topLeftInParent = shape.localToParent(shape.getX(), shape.getY());
If you simply need the x/y range in the parent where the Rectangle is displayed, you could also use getBoundsInParent:
Bounds parentBounds = shape.getBoundsInParent();
BTW: I do not recommend adding a new transform on every change. Instead I recommend adjusting the existing rotation:
Rotate rotate = new Rotate(0, shape.getX() + shape.getWidth()/2, shape.getX() + shape.getHeight()/2);
shape.getTransforms().add(rotate);
rotate.angleProperty().bind(this.rotation);
answered Nov 13 '18 at 12:52
fabianfabian
51.8k115272
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the localToParent method to transform a point from the coordinate system of the Rectangle to the coordinate system of the parent.
Point2D topLeftInParent = shape.localToParent(shape.getX(), shape.getY());
If you simply need the x/y range in the parent where the Rectangle is displayed, you could also use getBoundsInParent:
Bounds parentBounds = shape.getBoundsInParent();
BTW: I do not recommend adding a new transform on every change. Instead I recommend adjusting the existing rotation:
Rotate rotate = new Rotate(0, shape.getX() + shape.getWidth()/2, shape.getX() + shape.getHeight()/2);
shape.getTransforms().add(rotate);
rotate.angleProperty().bind(this.rotation);
answered Nov 13 '18 at 12:52
fabianfabian
51.8k115272
add a comment |
You can use the localToParent method to transform a point from the coordinate system of the Rectangle to the coordinate system of the parent.
Point2D topLeftInParent = shape.localToParent(shape.getX(), shape.getY());
If you simply need the x/y range in the parent where the Rectangle is displayed, you could also use getBoundsInParent:
Bounds parentBounds = shape.getBoundsInParent();
BTW: I do not recommend adding a new transform on every change. Instead I recommend adjusting the existing rotation:
Rotate rotate = new Rotate(0, shape.getX() + shape.getWidth()/2, shape.getX() + shape.getHeight()/2);
shape.getTransforms().add(rotate);
rotate.angleProperty().bind(this.rotation);
answered Nov 13 '18 at 12:52
fabianfabian
51.8k115272
add a comment |
You can use the localToParent method to transform a point from the coordinate system of the Rectangle to the coordinate system of the parent.
Point2D topLeftInParent = shape.localToParent(shape.getX(), shape.getY());
If you simply need the x/y range in the parent where the Rectangle is displayed, you could also use getBoundsInParent:
Bounds parentBounds = shape.getBoundsInParent();
BTW: I do not recommend adding a new transform on every change. Instead I recommend adjusting the existing rotation:
Rotate rotate = new Rotate(0, shape.getX() + shape.getWidth()/2, shape.getX() + shape.getHeight()/2);
shape.getTransforms().add(rotate);
rotate.angleProperty().bind(this.rotation);
answered Nov 13 '18 at 12:52
fabianfabian
51.8k115272
You can use the localToParent method to transform a point from the coordinate system of the Rectangle to the coordinate system of the parent.
Point2D topLeftInParent = shape.localToParent(shape.getX(), shape.getY());
If you simply need the x/y range in the parent where the Rectangle is displayed, you could also use getBoundsInParent:
Bounds parentBounds = shape.getBoundsInParent();
BTW: I do not recommend adding a new transform on every change. Instead I recommend adjusting the existing rotation:
Rotate rotate = new Rotate(0, shape.getX() + shape.getWidth()/2, shape.getX() + shape.getHeight()/2);
shape.getTransforms().add(rotate);
rotate.angleProperty().bind(this.rotation);
answered Nov 13 '18 at 12:52
fabianfabian
51.8k115272
answered Nov 13 '18 at 12:52
fabianfabian
51.8k115272
answered Nov 13 '18 at 12:52
fabianfabian
51.8k115272
answered Nov 13 '18 at 12:52
fabianfabian
51.8k115272
51.8k115272
add a comment |
add a comment |
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