Pass the list of checked values to controller by Bean object?
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Trying to pass the list of selected subjects to Controller, but the bean is not receiving the list of subjects.
Here's the code that I'm trying:
$("#submitCreateStudent").click(function() {
var selSubjectIds = new Array();
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
if (selSubjectIds.length < 1)
selSubjectIds.push($(this).attr('data-record-key') + '$');
else
selSubjectIds += $(this).attr('data-record-key') + '$';
);
if (validateCreateStudentForm())
var data = new FormData();
data.append('firstName', $("#firstNameInCreateStudent").val());
data.append('lastName', $("#lastNameInCreateStudent").val());
data.append('address', $("#studentAddressInCreateStudent").val());
data.append('collegeName', $("#studentCollegeNameInCreateStudent").val());
data.append('phoneNumber', $("#phoneNumberInCreateStudent").val());
data.append('email', $("#emailInCreateStudent").val());
data.append('studentDepartment', $("#departmentInCreateStudent").val());
data.append('studentBranch', $("#branchInCreateStudent").val());
data.append('DateOfBirth', $("#dobInCreateStudent").val());
data.append('DateOfReport', $("#dorInCreateStudent").val());
data.append('loginUserName', $("#studentUserNameInCreateStudent").val());
data.append('loginPassword', $("#passwordInCreateStudent").val());
data.append('studentSubjects', selSubjectIds);
// data.append('skipInitialTraining', skipInitialTraining);
$("#maskingId").mask("Saving...");
$.ajax(
url: "AddStudent.do",
data: data,
//
//Remaining code goes here.
);
);
All the details are coming to controller class except for the list of subjects which are selected check boxes.
javascript jquery spring-mvc jquery-ui
|
show 1 more comment
Trying to pass the list of selected subjects to Controller, but the bean is not receiving the list of subjects.
Here's the code that I'm trying:
$("#submitCreateStudent").click(function() {
var selSubjectIds = new Array();
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
if (selSubjectIds.length < 1)
selSubjectIds.push($(this).attr('data-record-key') + '$');
else
selSubjectIds += $(this).attr('data-record-key') + '$';
);
if (validateCreateStudentForm())
var data = new FormData();
data.append('firstName', $("#firstNameInCreateStudent").val());
data.append('lastName', $("#lastNameInCreateStudent").val());
data.append('address', $("#studentAddressInCreateStudent").val());
data.append('collegeName', $("#studentCollegeNameInCreateStudent").val());
data.append('phoneNumber', $("#phoneNumberInCreateStudent").val());
data.append('email', $("#emailInCreateStudent").val());
data.append('studentDepartment', $("#departmentInCreateStudent").val());
data.append('studentBranch', $("#branchInCreateStudent").val());
data.append('DateOfBirth', $("#dobInCreateStudent").val());
data.append('DateOfReport', $("#dorInCreateStudent").val());
data.append('loginUserName', $("#studentUserNameInCreateStudent").val());
data.append('loginPassword', $("#passwordInCreateStudent").val());
data.append('studentSubjects', selSubjectIds);
// data.append('skipInitialTraining', skipInitialTraining);
$("#maskingId").mask("Saving...");
$.ajax(
url: "AddStudent.do",
data: data,
//
//Remaining code goes here.
);
);
All the details are coming to controller class except for the list of subjects which are selected check boxes.
javascript jquery spring-mvc jquery-ui
To shorten how about using$("form").on("submit")
and$(this).serialize()
– mplungjan
Nov 15 '18 at 7:46
understood. but will that solve problem?
– Shaik Bajivali
Nov 15 '18 at 7:50
Simplification is always good. Any errors in console or app log?
– mplungjan
Nov 15 '18 at 8:00
No error messages in console
– Shaik Bajivali
Nov 15 '18 at 8:32
it just need to store the elements in the jtable in to array and append it to the data field.
– Shaik Bajivali
Nov 15 '18 at 8:33
|
show 1 more comment
Trying to pass the list of selected subjects to Controller, but the bean is not receiving the list of subjects.
Here's the code that I'm trying:
$("#submitCreateStudent").click(function() {
var selSubjectIds = new Array();
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
if (selSubjectIds.length < 1)
selSubjectIds.push($(this).attr('data-record-key') + '$');
else
selSubjectIds += $(this).attr('data-record-key') + '$';
);
if (validateCreateStudentForm())
var data = new FormData();
data.append('firstName', $("#firstNameInCreateStudent").val());
data.append('lastName', $("#lastNameInCreateStudent").val());
data.append('address', $("#studentAddressInCreateStudent").val());
data.append('collegeName', $("#studentCollegeNameInCreateStudent").val());
data.append('phoneNumber', $("#phoneNumberInCreateStudent").val());
data.append('email', $("#emailInCreateStudent").val());
data.append('studentDepartment', $("#departmentInCreateStudent").val());
data.append('studentBranch', $("#branchInCreateStudent").val());
data.append('DateOfBirth', $("#dobInCreateStudent").val());
data.append('DateOfReport', $("#dorInCreateStudent").val());
data.append('loginUserName', $("#studentUserNameInCreateStudent").val());
data.append('loginPassword', $("#passwordInCreateStudent").val());
data.append('studentSubjects', selSubjectIds);
// data.append('skipInitialTraining', skipInitialTraining);
$("#maskingId").mask("Saving...");
$.ajax(
url: "AddStudent.do",
data: data,
//
//Remaining code goes here.
);
);
All the details are coming to controller class except for the list of subjects which are selected check boxes.
javascript jquery spring-mvc jquery-ui
Trying to pass the list of selected subjects to Controller, but the bean is not receiving the list of subjects.
Here's the code that I'm trying:
$("#submitCreateStudent").click(function() {
var selSubjectIds = new Array();
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
if (selSubjectIds.length < 1)
selSubjectIds.push($(this).attr('data-record-key') + '$');
else
selSubjectIds += $(this).attr('data-record-key') + '$';
);
if (validateCreateStudentForm())
var data = new FormData();
data.append('firstName', $("#firstNameInCreateStudent").val());
data.append('lastName', $("#lastNameInCreateStudent").val());
data.append('address', $("#studentAddressInCreateStudent").val());
data.append('collegeName', $("#studentCollegeNameInCreateStudent").val());
data.append('phoneNumber', $("#phoneNumberInCreateStudent").val());
data.append('email', $("#emailInCreateStudent").val());
data.append('studentDepartment', $("#departmentInCreateStudent").val());
data.append('studentBranch', $("#branchInCreateStudent").val());
data.append('DateOfBirth', $("#dobInCreateStudent").val());
data.append('DateOfReport', $("#dorInCreateStudent").val());
data.append('loginUserName', $("#studentUserNameInCreateStudent").val());
data.append('loginPassword', $("#passwordInCreateStudent").val());
data.append('studentSubjects', selSubjectIds);
// data.append('skipInitialTraining', skipInitialTraining);
$("#maskingId").mask("Saving...");
$.ajax(
url: "AddStudent.do",
data: data,
//
//Remaining code goes here.
);
);
All the details are coming to controller class except for the list of subjects which are selected check boxes.
javascript jquery spring-mvc jquery-ui
javascript jquery spring-mvc jquery-ui
edited Nov 15 '18 at 7:45
mplungjan
90.1k22127184
90.1k22127184
asked Nov 15 '18 at 7:30
Shaik BajivaliShaik Bajivali
368
368
To shorten how about using$("form").on("submit")
and$(this).serialize()
– mplungjan
Nov 15 '18 at 7:46
understood. but will that solve problem?
– Shaik Bajivali
Nov 15 '18 at 7:50
Simplification is always good. Any errors in console or app log?
– mplungjan
Nov 15 '18 at 8:00
No error messages in console
– Shaik Bajivali
Nov 15 '18 at 8:32
it just need to store the elements in the jtable in to array and append it to the data field.
– Shaik Bajivali
Nov 15 '18 at 8:33
|
show 1 more comment
To shorten how about using$("form").on("submit")
and$(this).serialize()
– mplungjan
Nov 15 '18 at 7:46
understood. but will that solve problem?
– Shaik Bajivali
Nov 15 '18 at 7:50
Simplification is always good. Any errors in console or app log?
– mplungjan
Nov 15 '18 at 8:00
No error messages in console
– Shaik Bajivali
Nov 15 '18 at 8:32
it just need to store the elements in the jtable in to array and append it to the data field.
– Shaik Bajivali
Nov 15 '18 at 8:33
To shorten how about using
$("form").on("submit")
and $(this).serialize()
– mplungjan
Nov 15 '18 at 7:46
To shorten how about using
$("form").on("submit")
and $(this).serialize()
– mplungjan
Nov 15 '18 at 7:46
understood. but will that solve problem?
– Shaik Bajivali
Nov 15 '18 at 7:50
understood. but will that solve problem?
– Shaik Bajivali
Nov 15 '18 at 7:50
Simplification is always good. Any errors in console or app log?
– mplungjan
Nov 15 '18 at 8:00
Simplification is always good. Any errors in console or app log?
– mplungjan
Nov 15 '18 at 8:00
No error messages in console
– Shaik Bajivali
Nov 15 '18 at 8:32
No error messages in console
– Shaik Bajivali
Nov 15 '18 at 8:32
it just need to store the elements in the jtable in to array and append it to the data field.
– Shaik Bajivali
Nov 15 '18 at 8:33
it just need to store the elements in the jtable in to array and append it to the data field.
– Shaik Bajivali
Nov 15 '18 at 8:33
|
show 1 more comment
2 Answers
2
active
oldest
votes
By default, jQuery supports json format submissions
data :‘selSubjectIds’:selSubjectIds
or $(this).serialize();
thanks for the answer. Can you be more specific like where should i put this and which lines has to be replaced?
– Shaik Bajivali
Nov 15 '18 at 9:59
var data = 'firstName':$("#firstNameInCreateStudent").val()), ......... 'studentSubjects': selSubjectIds data :data
– Z KK
Nov 16 '18 at 9:55
that was helpful. thanks
– Shaik Bajivali
Nov 20 '18 at 11:29
add a comment |
Thanks to Everyone for your efforts.I found my self a way to solve
this as Follows
var arr = "";
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
var record = $(this).data('record');
arr += record.subjectId + seperatorForGridCells;
);
Here the arr variable stores every ID as a String by concating with
Some seperator "seperatorForGridCells". Then i used StringTokenizer to
seperate each id and parsed each id from string type to int.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
By default, jQuery supports json format submissions
data :‘selSubjectIds’:selSubjectIds
or $(this).serialize();
thanks for the answer. Can you be more specific like where should i put this and which lines has to be replaced?
– Shaik Bajivali
Nov 15 '18 at 9:59
var data = 'firstName':$("#firstNameInCreateStudent").val()), ......... 'studentSubjects': selSubjectIds data :data
– Z KK
Nov 16 '18 at 9:55
that was helpful. thanks
– Shaik Bajivali
Nov 20 '18 at 11:29
add a comment |
By default, jQuery supports json format submissions
data :‘selSubjectIds’:selSubjectIds
or $(this).serialize();
thanks for the answer. Can you be more specific like where should i put this and which lines has to be replaced?
– Shaik Bajivali
Nov 15 '18 at 9:59
var data = 'firstName':$("#firstNameInCreateStudent").val()), ......... 'studentSubjects': selSubjectIds data :data
– Z KK
Nov 16 '18 at 9:55
that was helpful. thanks
– Shaik Bajivali
Nov 20 '18 at 11:29
add a comment |
By default, jQuery supports json format submissions
data :‘selSubjectIds’:selSubjectIds
or $(this).serialize();
By default, jQuery supports json format submissions
data :‘selSubjectIds’:selSubjectIds
or $(this).serialize();
edited Nov 15 '18 at 10:24
Saeed Zhiany
1,60141825
1,60141825
answered Nov 15 '18 at 9:51
Z KKZ KK
111
111
thanks for the answer. Can you be more specific like where should i put this and which lines has to be replaced?
– Shaik Bajivali
Nov 15 '18 at 9:59
var data = 'firstName':$("#firstNameInCreateStudent").val()), ......... 'studentSubjects': selSubjectIds data :data
– Z KK
Nov 16 '18 at 9:55
that was helpful. thanks
– Shaik Bajivali
Nov 20 '18 at 11:29
add a comment |
thanks for the answer. Can you be more specific like where should i put this and which lines has to be replaced?
– Shaik Bajivali
Nov 15 '18 at 9:59
var data = 'firstName':$("#firstNameInCreateStudent").val()), ......... 'studentSubjects': selSubjectIds data :data
– Z KK
Nov 16 '18 at 9:55
that was helpful. thanks
– Shaik Bajivali
Nov 20 '18 at 11:29
thanks for the answer. Can you be more specific like where should i put this and which lines has to be replaced?
– Shaik Bajivali
Nov 15 '18 at 9:59
thanks for the answer. Can you be more specific like where should i put this and which lines has to be replaced?
– Shaik Bajivali
Nov 15 '18 at 9:59
var data = 'firstName':$("#firstNameInCreateStudent").val()), ......... 'studentSubjects': selSubjectIds data :data
– Z KK
Nov 16 '18 at 9:55
var data = 'firstName':$("#firstNameInCreateStudent").val()), ......... 'studentSubjects': selSubjectIds data :data
– Z KK
Nov 16 '18 at 9:55
that was helpful. thanks
– Shaik Bajivali
Nov 20 '18 at 11:29
that was helpful. thanks
– Shaik Bajivali
Nov 20 '18 at 11:29
add a comment |
Thanks to Everyone for your efforts.I found my self a way to solve
this as Follows
var arr = "";
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
var record = $(this).data('record');
arr += record.subjectId + seperatorForGridCells;
);
Here the arr variable stores every ID as a String by concating with
Some seperator "seperatorForGridCells". Then i used StringTokenizer to
seperate each id and parsed each id from string type to int.
add a comment |
Thanks to Everyone for your efforts.I found my self a way to solve
this as Follows
var arr = "";
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
var record = $(this).data('record');
arr += record.subjectId + seperatorForGridCells;
);
Here the arr variable stores every ID as a String by concating with
Some seperator "seperatorForGridCells". Then i used StringTokenizer to
seperate each id and parsed each id from string type to int.
add a comment |
Thanks to Everyone for your efforts.I found my self a way to solve
this as Follows
var arr = "";
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
var record = $(this).data('record');
arr += record.subjectId + seperatorForGridCells;
);
Here the arr variable stores every ID as a String by concating with
Some seperator "seperatorForGridCells". Then i used StringTokenizer to
seperate each id and parsed each id from string type to int.
Thanks to Everyone for your efforts.I found my self a way to solve
this as Follows
var arr = "";
$('#subjectsTableInCreateStudent').find('.jtable-data-row').each(function()
var record = $(this).data('record');
arr += record.subjectId + seperatorForGridCells;
);
Here the arr variable stores every ID as a String by concating with
Some seperator "seperatorForGridCells". Then i used StringTokenizer to
seperate each id and parsed each id from string type to int.
answered Nov 16 '18 at 10:20
Shaik BajivaliShaik Bajivali
368
368
add a comment |
add a comment |
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To shorten how about using
$("form").on("submit")
and$(this).serialize()
– mplungjan
Nov 15 '18 at 7:46
understood. but will that solve problem?
– Shaik Bajivali
Nov 15 '18 at 7:50
Simplification is always good. Any errors in console or app log?
– mplungjan
Nov 15 '18 at 8:00
No error messages in console
– Shaik Bajivali
Nov 15 '18 at 8:32
it just need to store the elements in the jtable in to array and append it to the data field.
– Shaik Bajivali
Nov 15 '18 at 8:33