Pfthb

I want create a web application and use JPA for model layer in MVC for the first time . But I'm having trouble.
The program shows me this error :

Nov 11, 2018 10:56:49 AM org.hibernate.annotations.common.Version <clinit>
INFO: HCANN000001: Hibernate Commons Annotations 4.0.1.Final
Nov 11, 2018 10:56:49 AM org.hibernate.Version logVersion
INFO: HHH000412: Hibernate Core 4.2.0.Final
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment <clinit>
INFO: HHH000205: Loaded properties from resource hibernate.properties: hibernate.connection.driver_class=org.h2.Driver, hibernate.dialect=org.hibernate.dialect.H2Dialect, hibernate.max_fetch_depth=5, hibernate.format_sql=true, hibernate.generate_statistics=true, hibernate.connection.username=sa, hibernate.connection.url=jdbc:h2:mem:db1;DB_CLOSE_DELAY=-1;MVCC=TRUE, hibernate.bytecode.use_reflection_optimizer=false, hibernate.jdbc.batch_versioned_data=true, hibernate.connection.pool_size=5
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment buildBytecodeProvider
INFO: HHH000021: Bytecode provider name : javassist

Exception in thread "main" java.lang.ExceptionInInitializerError
at model.bl.PersonManager.main(PersonManager.java:19)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:144)

Caused by: javax.persistence.PersistenceException: [PersistenceUnit: MyConnection] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:930)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:904)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:72)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47)
at util.JPAProvider.<clinit>(JPAProvider.java:13)
... 6 more

Caused by: org.hibernate.MappingException: Unable to find column with logical name: UID in org.hibernate.mapping.Table(USERS) and its related supertables and secondary tables
at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:552)
at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:257)
at org.hibernate.cfg.annotations.CollectionBinder.bindCollectionSecondPass(CollectionBinder.java:1331)
at org.hibernate.cfg.annotations.CollectionBinder.bindOneToManySecondPass(CollectionBinder.java:791)
at org.hibernate.cfg.annotations.CollectionBinder.bindStarToManySecondPass(CollectionBinder.java:719)
at org.hibernate.cfg.annotations.CollectionBinder$1.secondPass(CollectionBinder.java:668)
at org.hibernate.cfg.CollectionSecondPass.doSecondPass(CollectionSecondPass.java:66)
at org.hibernate.cfg.Configuration.originalSecondPassCompile(Configuration.java:1593)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1350)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1737)
at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:94)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:920)
... 11 more

Person class :

package model.entity;
import model.bl.PersonManager;
import javax.persistence.*;
import java.io.Serializable;
import java.util.List;

//mapping class to table
@Entity (name = "person")
@Table(name = "USERS")
@EntityListeners(value = PersonManager.class)

public class Person implements Serializable


@Id // create id and fill auto by sequence in database
@Column(name="UID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq" , sequenceName = "DB_MYSEQ")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq")
private long uId;


@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
private List<Pictures> picturesList;


@Basic
@Column (name = "USERNAME" , columnDefinition = "NVARCHAR2(30)" , nullable = false , unique = true)
private String username ;

@Basic
@Column (name = "USER_PASSWORD" , columnDefinition = "NVARCHAR2(32)" , nullable = false , unique = true)
private String password ;

@Basic
@Column (name = "EMAIL" , columnDefinition = "NVARCHAR2(40)" , nullable = false)
private String email;


@Basic
@Column (name = "SEX" , columnDefinition = "NVARCHAR2(20)")
private String sex ;

//--------------------------------------------------------

public Person() 

public Person(String username, String password, String email, String sex, String userPic) 
 this.username = username;
 this.password = password;
 this.email = email;
 this.sex = sex;
 this.userPic = userPic;

public Person(String username, String password, String email ,String sex, String userPic,List<Pictures> picturesList ) 
 this.picturesList = picturesList;
 this.sex = sex;
 this.userPic = userPic;
 this.email = email;
 this.password = password;
 this.username = username;


//--------------------------------------------------------

public void setUsername(String username) 
 this.username = username;


public void setPassword(String password) 
 this.password = password;


public void setEmail(String email) 
 this.email = email;


public void setUserPic(String userPic) 
 this.userPic = userPic;


public void setSex(String sex) 
 this.sex = sex;


public void setuId(long uId) this.uId = uId;

//--------------------------------------------------------

public String getUsername() 
 return username;


public String getPassword() 
 return password;


public String getUserPic() 
 return userPic;


public String getEmail() 
 return email;


public String getSex() 
 return sex;


public long getuId() return uId;


}

Pictures class :

package model.entity;

import javax.persistence.*;
import java.io.Serializable;

@Entity(name = "picture")
@Table(name = "PICTURE")

public class Pictures implements Serializable

@Id // create id and fill auto by sequence in database
@Column(name="PID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq2" , sequenceName = "DB_MYSEQ2")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq2")
private long pId;


@Basic
@Column (name = "PICADRESS" , columnDefinition = "NVARCHAR2(50)" , nullable = false)
private String picAdress ;

@Basic
@Column (name = "CAPTION" , columnDefinition = "LONG")
private String caption;

@Basic // user picture for profile
@Column (name = "LIKES" , columnDefinition = "NUMBER")
private int likes;

//--------------------------------------------------------
public Pictures()

public Pictures( String picAdress, String caption, int likes) 
 this.picAdress = picAdress;
 this.caption = caption;
 this.likes = likes;

//--------------------------------------------------------

public void setPid(long pid) 
 this.pId = pid;


public void setLikes(int likes) 
 this.likes = likes;


public void setPicAdress(String picAdress) 
 this.picAdress = picAdress;


public void setCaption(String caption) 
 this.caption = caption;


//--------------------------------------------------------

public int getLikes() 
 return likes;


public String getCaption() 
 return caption;


public String getPicAdress() 
 return picAdress;


public long getPid() 
 return pId;

my JPA Provider is :

public class JPAProvider 

 private static final EntityManagerFactory entityManagerFactory;//instate of session for connect to database
 static
 entityManagerFactory = Persistence.createEntityManagerFactory("MyConnection");
 

 public static EntityManagerFactory getEntityManagerFactory() 
 return entityManagerFactory;
 

PersonManager class is :

public class PersonManager 

 public static void main(String args) 

 EntityManager entityManager = JPAProvider.getEntityManagerFactory().createEntityManager();
 EntityTransaction entityTransaction = entityManager.getTransaction();
 entityTransaction.begin();

 Person person = new Person("midas" , "midas123" , "aaaaa@gmail.com", "female" ,"female-user.png" );
 Pictures pictures = new Pictures("aaa" , "akflkkglhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh" ,2);
 Pictures pictures2 = new Pictures("nnbnbn" , "affddAlllllllllllllllllllllllllllllllllllll" ,5);
 List<Pictures> picturesList =new ArrayList<Pictures>();
 picturesList.add(pictures);
 picturesList.add(pictures2);
 person.setPicturesList(picturesList);

 entityManager.persist(person);
 entityTransaction.commit();
 entityManager.close();
 
 

and persistence.xml :

<persistence-unit name="MyConnection" transaction-type="RESOURCE_LOCAL">
 <provider>org.hibernate.ejb.HibernatePersistence</provider>
 <properties>
 <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
 <property name="hibernate.connection.driver_class" value="oracle.jdbc.driver.OracleDriver"/>
 <property name="hibernate.connection.username" value="midas"/>
 <property name="hibernate.connection.password" value="midas123"/>
 <property name="hibernate.connection.url" value="jdbc:oracle:thin:@localhost:1521:orcl"/>
 <property name="hibernate.hbm2ddl.auto" value="create-drop"/>
 <property name="show_sql" value="true"></property>
 <property name="hibernate.globally_quoted_identifiers" value="true"/>
 </properties>
</persistence-unit>

I used the following libraries :

1)hibernate-enverc-4.2.0.final

2)hibernate-jpa-2.0-api-1.0.1-final.jar

3)tomcat library

my JDK version = 1.8.0-172

my IDE = IntellyJ Idea

I use Oracle 11g .

I tried to solve the problem by solving similar questions, but I could not .
for example I checked the following topics that were more similar to my problem :

[Error creating bean with name 'entityManagerFactory' defined in class path resource : Invocation of init method failed

[Getting Exception in thread "main" java.lang.ExceptionInInitializerError Exception

Additional explanation: No tables have been created in the database so far.

Looks like problem is with @JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
referencedColumnName attribute points to the related column in asociated/referenced entity, i.e. column name of the primary key. By default it is primary key of associated entity. You are not required to fill the referencedColumnName if the referenced entity has single column as PK, because there is no doubt what column it references (i.e. primary key column of associated entity).
change that line to @JoinColumn(name = "FK_PERSON") it should work.

For more info about referencedColumnName refer to "What is referencedColumnName used for in JPA?"