How to edit Flask-plus default swagger-UI text
up vote
2
down vote
favorite
I am developing a simple rest api that only has two Get methods so far. It's working fine etc, and looks pretty great when I navigate to the url thanks to the built in swagger documentation.
However I do not actually see a yaml or json file anywhere. How do I change the title and default values as shown in the screenshot? Hopefully it's possible without making a whole separate yaml or json doc?
I don't actually want to change the design at all. I only want to edit the text a little.
python rest flask swagger flask-restplus
asked Nov 10 at 8:47
sit_on_a_pan_otis
1577
add a comment |
up vote
2
down vote
favorite
I am developing a simple rest api that only has two Get methods so far. It's working fine etc, and looks pretty great when I navigate to the url thanks to the built in swagger documentation.
However I do not actually see a yaml or json file anywhere. How do I change the title and default values as shown in the screenshot? Hopefully it's possible without making a whole separate yaml or json doc?
I don't actually want to change the design at all. I only want to edit the text a little.
python rest flask swagger flask-restplus
asked Nov 10 at 8:47
sit_on_a_pan_otis
1577
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I am developing a simple rest api that only has two Get methods so far. It's working fine etc, and looks pretty great when I navigate to the url thanks to the built in swagger documentation.
However I do not actually see a yaml or json file anywhere. How do I change the title and default values as shown in the screenshot? Hopefully it's possible without making a whole separate yaml or json doc?
I don't actually want to change the design at all. I only want to edit the text a little.
python rest flask swagger flask-restplus
asked Nov 10 at 8:47
sit_on_a_pan_otis
1577
I am developing a simple rest api that only has two Get methods so far. It's working fine etc, and looks pretty great when I navigate to the url thanks to the built in swagger documentation.
However I do not actually see a yaml or json file anywhere. How do I change the title and default values as shown in the screenshot? Hopefully it's possible without making a whole separate yaml or json doc?
I don't actually want to change the design at all. I only want to edit the text a little.
python rest flask swagger flask-restplus
python rest flask swagger flask-restplus
asked Nov 10 at 8:47
sit_on_a_pan_otis
1577
asked Nov 10 at 8:47
sit_on_a_pan_otis
1577
asked Nov 10 at 8:47
sit_on_a_pan_otis
1577
asked Nov 10 at 8:47
sit_on_a_pan_otis
1577
asked Nov 10 at 8:47
sit_on_a_pan_otis
1577
1577
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
You set the title when creating the API:
api = Api(app, version='1.0', title='Your API Name',
description='A more complete description')
You set the namespace to something other than default by creating a namespace:
ns = api.namespace('not-default',
description='Whatever your namespace is')
Then you create your routes in the appropriate namespace:
@ns.route(...)
This is a handy way to group your APIs. See the Full Example for help if needed.
answered Nov 10 at 15:02
dmulter
1,0433717
To add on to that... your answer prompted me to this bug tracker: github.com/noirbizarre/flask-restplus/issues/460 . Thanks for your answer
– sit_on_a_pan_otis
Nov 10 at 17:44
I had to add api.namespaces.clear() before setting the ns variable. Works nicely!
– sit_on_a_pan_otis
Nov 10 at 17:51
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You set the title when creating the API:
api = Api(app, version='1.0', title='Your API Name',
description='A more complete description')
You set the namespace to something other than default by creating a namespace:
ns = api.namespace('not-default',
description='Whatever your namespace is')
Then you create your routes in the appropriate namespace:
@ns.route(...)
This is a handy way to group your APIs. See the Full Example for help if needed.
answered Nov 10 at 15:02
dmulter
1,0433717
To add on to that... your answer prompted me to this bug tracker: github.com/noirbizarre/flask-restplus/issues/460 . Thanks for your answer
– sit_on_a_pan_otis
Nov 10 at 17:44
I had to add api.namespaces.clear() before setting the ns variable. Works nicely!
– sit_on_a_pan_otis
Nov 10 at 17:51
add a comment |
up vote
1
down vote
accepted
You set the title when creating the API:
api = Api(app, version='1.0', title='Your API Name',
description='A more complete description')
You set the namespace to something other than default by creating a namespace:
ns = api.namespace('not-default',
description='Whatever your namespace is')
Then you create your routes in the appropriate namespace:
@ns.route(...)
This is a handy way to group your APIs. See the Full Example for help if needed.
answered Nov 10 at 15:02
dmulter
1,0433717
To add on to that... your answer prompted me to this bug tracker: github.com/noirbizarre/flask-restplus/issues/460 . Thanks for your answer
– sit_on_a_pan_otis
Nov 10 at 17:44
I had to add api.namespaces.clear() before setting the ns variable. Works nicely!
– sit_on_a_pan_otis
Nov 10 at 17:51
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You set the title when creating the API:
api = Api(app, version='1.0', title='Your API Name',
description='A more complete description')
You set the namespace to something other than default by creating a namespace:
ns = api.namespace('not-default',
description='Whatever your namespace is')
Then you create your routes in the appropriate namespace:
@ns.route(...)
This is a handy way to group your APIs. See the Full Example for help if needed.
answered Nov 10 at 15:02
dmulter
1,0433717
You set the title when creating the API:
api = Api(app, version='1.0', title='Your API Name',
description='A more complete description')
You set the namespace to something other than default by creating a namespace:
ns = api.namespace('not-default',
description='Whatever your namespace is')
Then you create your routes in the appropriate namespace:
@ns.route(...)
This is a handy way to group your APIs. See the Full Example for help if needed.
answered Nov 10 at 15:02
dmulter
1,0433717
answered Nov 10 at 15:02
dmulter
1,0433717
answered Nov 10 at 15:02
dmulter
1,0433717
answered Nov 10 at 15:02
dmulter
1,0433717
1,0433717
To add on to that... your answer prompted me to this bug tracker: github.com/noirbizarre/flask-restplus/issues/460 . Thanks for your answer
– sit_on_a_pan_otis
Nov 10 at 17:44
I had to add api.namespaces.clear() before setting the ns variable. Works nicely!
– sit_on_a_pan_otis
Nov 10 at 17:51
add a comment |
To add on to that... your answer prompted me to this bug tracker: github.com/noirbizarre/flask-restplus/issues/460 . Thanks for your answer
– sit_on_a_pan_otis
Nov 10 at 17:44
I had to add api.namespaces.clear() before setting the ns variable. Works nicely!
– sit_on_a_pan_otis
Nov 10 at 17:51
To add on to that... your answer prompted me to this bug tracker: github.com/noirbizarre/flask-restplus/issues/460 . Thanks for your answer
– sit_on_a_pan_otis
Nov 10 at 17:44
To add on to that... your answer prompted me to this bug tracker: github.com/noirbizarre/flask-restplus/issues/460 . Thanks for your answer
– sit_on_a_pan_otis
Nov 10 at 17:44
I had to add api.namespaces.clear() before setting the ns variable. Works nicely!
– sit_on_a_pan_otis
Nov 10 at 17:51
I had to add api.namespaces.clear() before setting the ns variable. Works nicely!
– sit_on_a_pan_otis
Nov 10 at 17:51
add a comment |
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