How to determine the ranges when fitting piecewise equation?
I am currently giving a fitting equation in matlab for a scatter plot like this:
It seems that we'd better make it a piecewise equation
But how should I determine the ranges of those segmented funtions? Is there an api in matlab for this?
matlab curve-fitting data-fitting
add a comment |
I am currently giving a fitting equation in matlab for a scatter plot like this:
It seems that we'd better make it a piecewise equation
But how should I determine the ranges of those segmented funtions? Is there an api in matlab for this?
matlab curve-fitting data-fitting
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 '18 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 '18 at 12:05
add a comment |
I am currently giving a fitting equation in matlab for a scatter plot like this:
It seems that we'd better make it a piecewise equation
But how should I determine the ranges of those segmented funtions? Is there an api in matlab for this?
matlab curve-fitting data-fitting
I am currently giving a fitting equation in matlab for a scatter plot like this:
It seems that we'd better make it a piecewise equation
But how should I determine the ranges of those segmented funtions? Is there an api in matlab for this?
matlab curve-fitting data-fitting
matlab curve-fitting data-fitting
asked Nov 12 '18 at 6:56
Noah ZuoNoah Zuo
589
589
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 '18 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 '18 at 12:05
add a comment |
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 '18 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 '18 at 12:05
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 '18 at 7:25
Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 '18 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 '18 at 12:05
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 '18 at 12:05
add a comment |
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Don't know about matlab, but if possible I'd fit x(y) rather than y(x), on that data Otherwise you could place the split point as parameter in a least square. In this particular case, however it wouldn't help very much either---at least in y(x)---as points belonging to the middle part are left of where the first graph ends. Here an EMA may help.
– mikuszefski
Nov 12 '18 at 7:25
It looks to me as if there are two different "Y" values at X = 5.5 on the scatterplot red lines. If you post a link to the data, I will run it through my zunzun.com web site's "function finder" and try to find a single equation.
– James Phillips
Nov 12 '18 at 12:05