sqlalchemy, select objects that has all tags










2














I have sqlalchemy models:



import sqlalchemy
from sqlalchemy import create_engine
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import Column, Integer, String, ForeignKey, and_
from sqlalchemy.orm import sessionmaker, relationship


engine = create_engine('sqlite:///:memory:')
Session = sessionmaker(bind=engine)
Base = declarative_base()

class TopicToPizzaAssociation(Base):
__tablename__ = 'association'
pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)
topic = relationship("Topic")
pizza = relationship("Pizza")

class Pizza(Base):
__tablename__ = 'pizza'
id = Column(Integer, primary_key=True)
topics = relationship("TopicToPizzaAssociation")

def add_topics(self, topics):
used_topics = t.topic.product for t in self.topics
associations =
for topic in topics:
if topic.product not in used_topics:
associations.append(TopicToPizzaAssociation(pizza=self, topic=topic))
used_topics.add(topic.product)
p1.topics.extend(associations)

class Topic(Base):
__tablename__ = 'topic'
id = Column(Integer, primary_key=True)
product = Column(String(), nullable=False)


I need to select all pizza objects which have the required set of topics:



t1 = Topic(product='t1')
t2 = Topic(product='t2')
t3 = Topic(product='t3')

session = Session()
session.add_all([t1, t2, t3])

p1 = Pizza()
p2 = Pizza()

p1.add_topics([t1, t2, t1])
p2.add_topics([t2, t3])

Base.metadata.create_all(engine)

session.add_all([p1, p2])
session.commit()

values = ['t1', 't2']
topics = session.query(Topic.id).filter(Topic.product.in_(values))
pizza = session.query(Pizza).filter(Pizza.topics.any(TopicToPizzaAssociation.topic_id.in_(
topics
))).all()


This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.



I've found that it is possible to make a query with JOIN and COUNT, but I couldn't build sqlalchemy query. Any possible solution will suit me.










share|improve this question























  • Are you open to changes in the structure of your models, or is the structure set and cannot be changed?
    – SuperShoot
    Nov 11 '18 at 21:55










  • I can change the structure.
    – Iren
    Nov 12 '18 at 5:15










  • By "required set" do you mean that you wan't pizzas with given toppings only, or with given toppings and possibly some others as well.
    – Ilja Everilä
    Nov 12 '18 at 5:46










  • I want pizza with given toppings and possibly some others.
    – Iren
    Nov 12 '18 at 5:53










  • Related: stackoverflow.com/questions/49438529/…, stackoverflow.com/questions/42673699/…
    – Ilja Everilä
    Nov 12 '18 at 12:30















2














I have sqlalchemy models:



import sqlalchemy
from sqlalchemy import create_engine
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import Column, Integer, String, ForeignKey, and_
from sqlalchemy.orm import sessionmaker, relationship


engine = create_engine('sqlite:///:memory:')
Session = sessionmaker(bind=engine)
Base = declarative_base()

class TopicToPizzaAssociation(Base):
__tablename__ = 'association'
pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)
topic = relationship("Topic")
pizza = relationship("Pizza")

class Pizza(Base):
__tablename__ = 'pizza'
id = Column(Integer, primary_key=True)
topics = relationship("TopicToPizzaAssociation")

def add_topics(self, topics):
used_topics = t.topic.product for t in self.topics
associations =
for topic in topics:
if topic.product not in used_topics:
associations.append(TopicToPizzaAssociation(pizza=self, topic=topic))
used_topics.add(topic.product)
p1.topics.extend(associations)

class Topic(Base):
__tablename__ = 'topic'
id = Column(Integer, primary_key=True)
product = Column(String(), nullable=False)


I need to select all pizza objects which have the required set of topics:



t1 = Topic(product='t1')
t2 = Topic(product='t2')
t3 = Topic(product='t3')

session = Session()
session.add_all([t1, t2, t3])

p1 = Pizza()
p2 = Pizza()

p1.add_topics([t1, t2, t1])
p2.add_topics([t2, t3])

Base.metadata.create_all(engine)

session.add_all([p1, p2])
session.commit()

values = ['t1', 't2']
topics = session.query(Topic.id).filter(Topic.product.in_(values))
pizza = session.query(Pizza).filter(Pizza.topics.any(TopicToPizzaAssociation.topic_id.in_(
topics
))).all()


This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.



I've found that it is possible to make a query with JOIN and COUNT, but I couldn't build sqlalchemy query. Any possible solution will suit me.










share|improve this question























  • Are you open to changes in the structure of your models, or is the structure set and cannot be changed?
    – SuperShoot
    Nov 11 '18 at 21:55










  • I can change the structure.
    – Iren
    Nov 12 '18 at 5:15










  • By "required set" do you mean that you wan't pizzas with given toppings only, or with given toppings and possibly some others as well.
    – Ilja Everilä
    Nov 12 '18 at 5:46










  • I want pizza with given toppings and possibly some others.
    – Iren
    Nov 12 '18 at 5:53










  • Related: stackoverflow.com/questions/49438529/…, stackoverflow.com/questions/42673699/…
    – Ilja Everilä
    Nov 12 '18 at 12:30













2












2








2







I have sqlalchemy models:



import sqlalchemy
from sqlalchemy import create_engine
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import Column, Integer, String, ForeignKey, and_
from sqlalchemy.orm import sessionmaker, relationship


engine = create_engine('sqlite:///:memory:')
Session = sessionmaker(bind=engine)
Base = declarative_base()

class TopicToPizzaAssociation(Base):
__tablename__ = 'association'
pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)
topic = relationship("Topic")
pizza = relationship("Pizza")

class Pizza(Base):
__tablename__ = 'pizza'
id = Column(Integer, primary_key=True)
topics = relationship("TopicToPizzaAssociation")

def add_topics(self, topics):
used_topics = t.topic.product for t in self.topics
associations =
for topic in topics:
if topic.product not in used_topics:
associations.append(TopicToPizzaAssociation(pizza=self, topic=topic))
used_topics.add(topic.product)
p1.topics.extend(associations)

class Topic(Base):
__tablename__ = 'topic'
id = Column(Integer, primary_key=True)
product = Column(String(), nullable=False)


I need to select all pizza objects which have the required set of topics:



t1 = Topic(product='t1')
t2 = Topic(product='t2')
t3 = Topic(product='t3')

session = Session()
session.add_all([t1, t2, t3])

p1 = Pizza()
p2 = Pizza()

p1.add_topics([t1, t2, t1])
p2.add_topics([t2, t3])

Base.metadata.create_all(engine)

session.add_all([p1, p2])
session.commit()

values = ['t1', 't2']
topics = session.query(Topic.id).filter(Topic.product.in_(values))
pizza = session.query(Pizza).filter(Pizza.topics.any(TopicToPizzaAssociation.topic_id.in_(
topics
))).all()


This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.



I've found that it is possible to make a query with JOIN and COUNT, but I couldn't build sqlalchemy query. Any possible solution will suit me.










share|improve this question















I have sqlalchemy models:



import sqlalchemy
from sqlalchemy import create_engine
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import Column, Integer, String, ForeignKey, and_
from sqlalchemy.orm import sessionmaker, relationship


engine = create_engine('sqlite:///:memory:')
Session = sessionmaker(bind=engine)
Base = declarative_base()

class TopicToPizzaAssociation(Base):
__tablename__ = 'association'
pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)
topic = relationship("Topic")
pizza = relationship("Pizza")

class Pizza(Base):
__tablename__ = 'pizza'
id = Column(Integer, primary_key=True)
topics = relationship("TopicToPizzaAssociation")

def add_topics(self, topics):
used_topics = t.topic.product for t in self.topics
associations =
for topic in topics:
if topic.product not in used_topics:
associations.append(TopicToPizzaAssociation(pizza=self, topic=topic))
used_topics.add(topic.product)
p1.topics.extend(associations)

class Topic(Base):
__tablename__ = 'topic'
id = Column(Integer, primary_key=True)
product = Column(String(), nullable=False)


I need to select all pizza objects which have the required set of topics:



t1 = Topic(product='t1')
t2 = Topic(product='t2')
t3 = Topic(product='t3')

session = Session()
session.add_all([t1, t2, t3])

p1 = Pizza()
p2 = Pizza()

p1.add_topics([t1, t2, t1])
p2.add_topics([t2, t3])

Base.metadata.create_all(engine)

session.add_all([p1, p2])
session.commit()

values = ['t1', 't2']
topics = session.query(Topic.id).filter(Topic.product.in_(values))
pizza = session.query(Pizza).filter(Pizza.topics.any(TopicToPizzaAssociation.topic_id.in_(
topics
))).all()


This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.



I've found that it is possible to make a query with JOIN and COUNT, but I couldn't build sqlalchemy query. Any possible solution will suit me.







python sqlalchemy many-to-many






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 '18 at 11:46









Ilja Everilä

23.4k33560




23.4k33560










asked Nov 11 '18 at 20:09









Iren

134




134











  • Are you open to changes in the structure of your models, or is the structure set and cannot be changed?
    – SuperShoot
    Nov 11 '18 at 21:55










  • I can change the structure.
    – Iren
    Nov 12 '18 at 5:15










  • By "required set" do you mean that you wan't pizzas with given toppings only, or with given toppings and possibly some others as well.
    – Ilja Everilä
    Nov 12 '18 at 5:46










  • I want pizza with given toppings and possibly some others.
    – Iren
    Nov 12 '18 at 5:53










  • Related: stackoverflow.com/questions/49438529/…, stackoverflow.com/questions/42673699/…
    – Ilja Everilä
    Nov 12 '18 at 12:30
















  • Are you open to changes in the structure of your models, or is the structure set and cannot be changed?
    – SuperShoot
    Nov 11 '18 at 21:55










  • I can change the structure.
    – Iren
    Nov 12 '18 at 5:15










  • By "required set" do you mean that you wan't pizzas with given toppings only, or with given toppings and possibly some others as well.
    – Ilja Everilä
    Nov 12 '18 at 5:46










  • I want pizza with given toppings and possibly some others.
    – Iren
    Nov 12 '18 at 5:53










  • Related: stackoverflow.com/questions/49438529/…, stackoverflow.com/questions/42673699/…
    – Ilja Everilä
    Nov 12 '18 at 12:30















Are you open to changes in the structure of your models, or is the structure set and cannot be changed?
– SuperShoot
Nov 11 '18 at 21:55




Are you open to changes in the structure of your models, or is the structure set and cannot be changed?
– SuperShoot
Nov 11 '18 at 21:55












I can change the structure.
– Iren
Nov 12 '18 at 5:15




I can change the structure.
– Iren
Nov 12 '18 at 5:15












By "required set" do you mean that you wan't pizzas with given toppings only, or with given toppings and possibly some others as well.
– Ilja Everilä
Nov 12 '18 at 5:46




By "required set" do you mean that you wan't pizzas with given toppings only, or with given toppings and possibly some others as well.
– Ilja Everilä
Nov 12 '18 at 5:46












I want pizza with given toppings and possibly some others.
– Iren
Nov 12 '18 at 5:53




I want pizza with given toppings and possibly some others.
– Iren
Nov 12 '18 at 5:53












Related: stackoverflow.com/questions/49438529/…, stackoverflow.com/questions/42673699/…
– Ilja Everilä
Nov 12 '18 at 12:30




Related: stackoverflow.com/questions/49438529/…, stackoverflow.com/questions/42673699/…
– Ilja Everilä
Nov 12 '18 at 12:30












2 Answers
2






active

oldest

votes


















0














Firstly, there is a stack of reading you can do about SQLAlchemy relationships in the docs.



Your code closely matches the Association Object pattern which is (from the docs):




...used when your association table contains additional columns beyond those which are foreign keys to the left and right tables




I.e., if there was something specific about the individual relationship between a Pizza and Topic, you would store that information in line with the relationship between foreign keys in the association table. Here's the example that the docs give:



class Association(Base):
__tablename__ = 'association'
left_id = Column(Integer, ForeignKey('left.id'), primary_key=True)
right_id = Column(Integer, ForeignKey('right.id'), primary_key=True)
extra_data = Column(String(50))
child = relationship("Child", back_populates="parents")
parent = relationship("Parent", back_populates="children")

class Parent(Base):
__tablename__ = 'left'
id = Column(Integer, primary_key=True)
children = relationship("Association", back_populates="parent")

class Child(Base):
__tablename__ = 'right'
id = Column(Integer, primary_key=True)
parents = relationship("Association", back_populates="child")


Note the column extra_data defined on the Association object.



In your example, there is no such need for an extra_data type field in Association so you can simplify expressing the relationship between Pizza and Topic by using the Many to Many Pattern outlined in the docs.



The main benefit that we can get from that pattern is that we can directly relate the Pizza class to the Topic class. The new models look something like this:



class TopicToPizzaAssociation(Base):
__tablename__ = 'association'
pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)


class Pizza(Base):
__tablename__ = 'pizza'
id = Column(Integer, primary_key=True)
topics = relationship("Topic", secondary='association') # relationship is directly to Topic, not to the association table

def __repr__(self):
return f'pizza self.id'


class Topic(Base):
__tablename__ = 'topic'
id = Column(Integer, primary_key=True)
product = Column(String(), nullable=False)

def __repr__(self):
return self.product


The differences to your original code are:



  • No relationships defined on the TopicToPizzaAssociation model. With this pattern we can directly relate Pizza to Topic without having relationships on the association model.

  • Added __repr__() methods to both models so they print nicer.

  • Removed the add_topics method from Pizza (will explain that more later).

  • Added the secondary='association' argument to Pizza.topics relationship. This tells sqlalchemy that the foreign key path needed for the relationship to Topic is through the association table.

Here is the testing code and I've put some comments in there:



t1 = Topic(product='t1')
t2 = Topic(product='t2')
t3 = Topic(product='t3')

session = Session()
session.add_all([t1, t2, t3])

p1 = Pizza()
p2 = Pizza()

p1.topics = [t1, t2] # not adding to the pizzas through a add_topics method
p2.topics = [t2, t3]

Base.metadata.create_all(engine)

session.add_all([p1, p2])
session.commit()

values = [t2, t1] # these aren't strings, but are the actual objects instantiated above

# using Pizza.topics.contains
print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 1]

values = [t2, t3]
print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2]

values = [t2]
print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2, pizza 1]


So this only returns pizzas that have all of the prescribed topics, but not only the prescribed topics.



The reason I left out your add_topics method is that you used that method to check for duplicate Topics added to a given Pizza. That's fine, but the primary key of the association table won't let you add a duplicate topic for a pizza anyway, so I think it's better to let the database layer manage that and just handle the exception that occurs in application code.






share|improve this answer






























    0














    A query to fetch all Pizza with given Topics (and possibly more) can be expressed using a slightly hard to read double negation:



    session.query(Pizza).
    filter(~session.query(Topic).
    filter(Topic.product.in_(values),
    ~session.query(TopicToPizzaAssociation).
    filter(TopicToPizzaAssociation.topic_id == Topic.id,
    TopicToPizzaAssociation.pizza_id == Pizza.id).
    correlate(Pizza, Topic).
    exists()).
    exists())


    In English it reads along the lines of "Fetch pizza where not exists a given topic [sic] that is not in this pizza."




    This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.




    SQL does not have universal quantification and so there is no all() operator for relationships the way that any() maps to EXISTS. But



    FORALL x ( p ( x ) )


    is logically equivalent to



    NOT EXISTS x ( NOT p ( x ) )


    which the above query takes advantage of. It is also described as how to perform relational division in SQL:



    • https://www.red-gate.com/simple-talk/sql/t-sql-programming/divided-we-stand-the-sql-of-relational-division/

    • https://www.jooq.org/doc/3.11/manual/sql-building/table-expressions/relational-division/

    • http://www.inf.usi.ch/faculty/soule/teaching/2016-fall/db/division.pdf





    share|improve this answer






















      Your Answer






      StackExchange.ifUsing("editor", function ()
      StackExchange.using("externalEditor", function ()
      StackExchange.using("snippets", function ()
      StackExchange.snippets.init();
      );
      );
      , "code-snippets");

      StackExchange.ready(function()
      var channelOptions =
      tags: "".split(" "),
      id: "1"
      ;
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function()
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled)
      StackExchange.using("snippets", function()
      createEditor();
      );

      else
      createEditor();

      );

      function createEditor()
      StackExchange.prepareEditor(
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader:
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      ,
      onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      );



      );













      draft saved

      draft discarded


















      StackExchange.ready(
      function ()
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53252749%2fsqlalchemy-select-objects-that-has-all-tags%23new-answer', 'question_page');

      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      Firstly, there is a stack of reading you can do about SQLAlchemy relationships in the docs.



      Your code closely matches the Association Object pattern which is (from the docs):




      ...used when your association table contains additional columns beyond those which are foreign keys to the left and right tables




      I.e., if there was something specific about the individual relationship between a Pizza and Topic, you would store that information in line with the relationship between foreign keys in the association table. Here's the example that the docs give:



      class Association(Base):
      __tablename__ = 'association'
      left_id = Column(Integer, ForeignKey('left.id'), primary_key=True)
      right_id = Column(Integer, ForeignKey('right.id'), primary_key=True)
      extra_data = Column(String(50))
      child = relationship("Child", back_populates="parents")
      parent = relationship("Parent", back_populates="children")

      class Parent(Base):
      __tablename__ = 'left'
      id = Column(Integer, primary_key=True)
      children = relationship("Association", back_populates="parent")

      class Child(Base):
      __tablename__ = 'right'
      id = Column(Integer, primary_key=True)
      parents = relationship("Association", back_populates="child")


      Note the column extra_data defined on the Association object.



      In your example, there is no such need for an extra_data type field in Association so you can simplify expressing the relationship between Pizza and Topic by using the Many to Many Pattern outlined in the docs.



      The main benefit that we can get from that pattern is that we can directly relate the Pizza class to the Topic class. The new models look something like this:



      class TopicToPizzaAssociation(Base):
      __tablename__ = 'association'
      pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
      topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)


      class Pizza(Base):
      __tablename__ = 'pizza'
      id = Column(Integer, primary_key=True)
      topics = relationship("Topic", secondary='association') # relationship is directly to Topic, not to the association table

      def __repr__(self):
      return f'pizza self.id'


      class Topic(Base):
      __tablename__ = 'topic'
      id = Column(Integer, primary_key=True)
      product = Column(String(), nullable=False)

      def __repr__(self):
      return self.product


      The differences to your original code are:



      • No relationships defined on the TopicToPizzaAssociation model. With this pattern we can directly relate Pizza to Topic without having relationships on the association model.

      • Added __repr__() methods to both models so they print nicer.

      • Removed the add_topics method from Pizza (will explain that more later).

      • Added the secondary='association' argument to Pizza.topics relationship. This tells sqlalchemy that the foreign key path needed for the relationship to Topic is through the association table.

      Here is the testing code and I've put some comments in there:



      t1 = Topic(product='t1')
      t2 = Topic(product='t2')
      t3 = Topic(product='t3')

      session = Session()
      session.add_all([t1, t2, t3])

      p1 = Pizza()
      p2 = Pizza()

      p1.topics = [t1, t2] # not adding to the pizzas through a add_topics method
      p2.topics = [t2, t3]

      Base.metadata.create_all(engine)

      session.add_all([p1, p2])
      session.commit()

      values = [t2, t1] # these aren't strings, but are the actual objects instantiated above

      # using Pizza.topics.contains
      print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 1]

      values = [t2, t3]
      print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2]

      values = [t2]
      print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2, pizza 1]


      So this only returns pizzas that have all of the prescribed topics, but not only the prescribed topics.



      The reason I left out your add_topics method is that you used that method to check for duplicate Topics added to a given Pizza. That's fine, but the primary key of the association table won't let you add a duplicate topic for a pizza anyway, so I think it's better to let the database layer manage that and just handle the exception that occurs in application code.






      share|improve this answer



























        0














        Firstly, there is a stack of reading you can do about SQLAlchemy relationships in the docs.



        Your code closely matches the Association Object pattern which is (from the docs):




        ...used when your association table contains additional columns beyond those which are foreign keys to the left and right tables




        I.e., if there was something specific about the individual relationship between a Pizza and Topic, you would store that information in line with the relationship between foreign keys in the association table. Here's the example that the docs give:



        class Association(Base):
        __tablename__ = 'association'
        left_id = Column(Integer, ForeignKey('left.id'), primary_key=True)
        right_id = Column(Integer, ForeignKey('right.id'), primary_key=True)
        extra_data = Column(String(50))
        child = relationship("Child", back_populates="parents")
        parent = relationship("Parent", back_populates="children")

        class Parent(Base):
        __tablename__ = 'left'
        id = Column(Integer, primary_key=True)
        children = relationship("Association", back_populates="parent")

        class Child(Base):
        __tablename__ = 'right'
        id = Column(Integer, primary_key=True)
        parents = relationship("Association", back_populates="child")


        Note the column extra_data defined on the Association object.



        In your example, there is no such need for an extra_data type field in Association so you can simplify expressing the relationship between Pizza and Topic by using the Many to Many Pattern outlined in the docs.



        The main benefit that we can get from that pattern is that we can directly relate the Pizza class to the Topic class. The new models look something like this:



        class TopicToPizzaAssociation(Base):
        __tablename__ = 'association'
        pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
        topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)


        class Pizza(Base):
        __tablename__ = 'pizza'
        id = Column(Integer, primary_key=True)
        topics = relationship("Topic", secondary='association') # relationship is directly to Topic, not to the association table

        def __repr__(self):
        return f'pizza self.id'


        class Topic(Base):
        __tablename__ = 'topic'
        id = Column(Integer, primary_key=True)
        product = Column(String(), nullable=False)

        def __repr__(self):
        return self.product


        The differences to your original code are:



        • No relationships defined on the TopicToPizzaAssociation model. With this pattern we can directly relate Pizza to Topic without having relationships on the association model.

        • Added __repr__() methods to both models so they print nicer.

        • Removed the add_topics method from Pizza (will explain that more later).

        • Added the secondary='association' argument to Pizza.topics relationship. This tells sqlalchemy that the foreign key path needed for the relationship to Topic is through the association table.

        Here is the testing code and I've put some comments in there:



        t1 = Topic(product='t1')
        t2 = Topic(product='t2')
        t3 = Topic(product='t3')

        session = Session()
        session.add_all([t1, t2, t3])

        p1 = Pizza()
        p2 = Pizza()

        p1.topics = [t1, t2] # not adding to the pizzas through a add_topics method
        p2.topics = [t2, t3]

        Base.metadata.create_all(engine)

        session.add_all([p1, p2])
        session.commit()

        values = [t2, t1] # these aren't strings, but are the actual objects instantiated above

        # using Pizza.topics.contains
        print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 1]

        values = [t2, t3]
        print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2]

        values = [t2]
        print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2, pizza 1]


        So this only returns pizzas that have all of the prescribed topics, but not only the prescribed topics.



        The reason I left out your add_topics method is that you used that method to check for duplicate Topics added to a given Pizza. That's fine, but the primary key of the association table won't let you add a duplicate topic for a pizza anyway, so I think it's better to let the database layer manage that and just handle the exception that occurs in application code.






        share|improve this answer

























          0












          0








          0






          Firstly, there is a stack of reading you can do about SQLAlchemy relationships in the docs.



          Your code closely matches the Association Object pattern which is (from the docs):




          ...used when your association table contains additional columns beyond those which are foreign keys to the left and right tables




          I.e., if there was something specific about the individual relationship between a Pizza and Topic, you would store that information in line with the relationship between foreign keys in the association table. Here's the example that the docs give:



          class Association(Base):
          __tablename__ = 'association'
          left_id = Column(Integer, ForeignKey('left.id'), primary_key=True)
          right_id = Column(Integer, ForeignKey('right.id'), primary_key=True)
          extra_data = Column(String(50))
          child = relationship("Child", back_populates="parents")
          parent = relationship("Parent", back_populates="children")

          class Parent(Base):
          __tablename__ = 'left'
          id = Column(Integer, primary_key=True)
          children = relationship("Association", back_populates="parent")

          class Child(Base):
          __tablename__ = 'right'
          id = Column(Integer, primary_key=True)
          parents = relationship("Association", back_populates="child")


          Note the column extra_data defined on the Association object.



          In your example, there is no such need for an extra_data type field in Association so you can simplify expressing the relationship between Pizza and Topic by using the Many to Many Pattern outlined in the docs.



          The main benefit that we can get from that pattern is that we can directly relate the Pizza class to the Topic class. The new models look something like this:



          class TopicToPizzaAssociation(Base):
          __tablename__ = 'association'
          pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
          topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)


          class Pizza(Base):
          __tablename__ = 'pizza'
          id = Column(Integer, primary_key=True)
          topics = relationship("Topic", secondary='association') # relationship is directly to Topic, not to the association table

          def __repr__(self):
          return f'pizza self.id'


          class Topic(Base):
          __tablename__ = 'topic'
          id = Column(Integer, primary_key=True)
          product = Column(String(), nullable=False)

          def __repr__(self):
          return self.product


          The differences to your original code are:



          • No relationships defined on the TopicToPizzaAssociation model. With this pattern we can directly relate Pizza to Topic without having relationships on the association model.

          • Added __repr__() methods to both models so they print nicer.

          • Removed the add_topics method from Pizza (will explain that more later).

          • Added the secondary='association' argument to Pizza.topics relationship. This tells sqlalchemy that the foreign key path needed for the relationship to Topic is through the association table.

          Here is the testing code and I've put some comments in there:



          t1 = Topic(product='t1')
          t2 = Topic(product='t2')
          t3 = Topic(product='t3')

          session = Session()
          session.add_all([t1, t2, t3])

          p1 = Pizza()
          p2 = Pizza()

          p1.topics = [t1, t2] # not adding to the pizzas through a add_topics method
          p2.topics = [t2, t3]

          Base.metadata.create_all(engine)

          session.add_all([p1, p2])
          session.commit()

          values = [t2, t1] # these aren't strings, but are the actual objects instantiated above

          # using Pizza.topics.contains
          print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 1]

          values = [t2, t3]
          print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2]

          values = [t2]
          print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2, pizza 1]


          So this only returns pizzas that have all of the prescribed topics, but not only the prescribed topics.



          The reason I left out your add_topics method is that you used that method to check for duplicate Topics added to a given Pizza. That's fine, but the primary key of the association table won't let you add a duplicate topic for a pizza anyway, so I think it's better to let the database layer manage that and just handle the exception that occurs in application code.






          share|improve this answer














          Firstly, there is a stack of reading you can do about SQLAlchemy relationships in the docs.



          Your code closely matches the Association Object pattern which is (from the docs):




          ...used when your association table contains additional columns beyond those which are foreign keys to the left and right tables




          I.e., if there was something specific about the individual relationship between a Pizza and Topic, you would store that information in line with the relationship between foreign keys in the association table. Here's the example that the docs give:



          class Association(Base):
          __tablename__ = 'association'
          left_id = Column(Integer, ForeignKey('left.id'), primary_key=True)
          right_id = Column(Integer, ForeignKey('right.id'), primary_key=True)
          extra_data = Column(String(50))
          child = relationship("Child", back_populates="parents")
          parent = relationship("Parent", back_populates="children")

          class Parent(Base):
          __tablename__ = 'left'
          id = Column(Integer, primary_key=True)
          children = relationship("Association", back_populates="parent")

          class Child(Base):
          __tablename__ = 'right'
          id = Column(Integer, primary_key=True)
          parents = relationship("Association", back_populates="child")


          Note the column extra_data defined on the Association object.



          In your example, there is no such need for an extra_data type field in Association so you can simplify expressing the relationship between Pizza and Topic by using the Many to Many Pattern outlined in the docs.



          The main benefit that we can get from that pattern is that we can directly relate the Pizza class to the Topic class. The new models look something like this:



          class TopicToPizzaAssociation(Base):
          __tablename__ = 'association'
          pizza_id = Column(Integer, ForeignKey('pizza.id'), primary_key=True)
          topic_id = Column(Integer, ForeignKey('topic.id'), primary_key=True)


          class Pizza(Base):
          __tablename__ = 'pizza'
          id = Column(Integer, primary_key=True)
          topics = relationship("Topic", secondary='association') # relationship is directly to Topic, not to the association table

          def __repr__(self):
          return f'pizza self.id'


          class Topic(Base):
          __tablename__ = 'topic'
          id = Column(Integer, primary_key=True)
          product = Column(String(), nullable=False)

          def __repr__(self):
          return self.product


          The differences to your original code are:



          • No relationships defined on the TopicToPizzaAssociation model. With this pattern we can directly relate Pizza to Topic without having relationships on the association model.

          • Added __repr__() methods to both models so they print nicer.

          • Removed the add_topics method from Pizza (will explain that more later).

          • Added the secondary='association' argument to Pizza.topics relationship. This tells sqlalchemy that the foreign key path needed for the relationship to Topic is through the association table.

          Here is the testing code and I've put some comments in there:



          t1 = Topic(product='t1')
          t2 = Topic(product='t2')
          t3 = Topic(product='t3')

          session = Session()
          session.add_all([t1, t2, t3])

          p1 = Pizza()
          p2 = Pizza()

          p1.topics = [t1, t2] # not adding to the pizzas through a add_topics method
          p2.topics = [t2, t3]

          Base.metadata.create_all(engine)

          session.add_all([p1, p2])
          session.commit()

          values = [t2, t1] # these aren't strings, but are the actual objects instantiated above

          # using Pizza.topics.contains
          print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 1]

          values = [t2, t3]
          print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2]

          values = [t2]
          print(session.query(Pizza).filter(*[Pizza.topics.contains(t) for t in values]).all()) # [pizza 2, pizza 1]


          So this only returns pizzas that have all of the prescribed topics, but not only the prescribed topics.



          The reason I left out your add_topics method is that you used that method to check for duplicate Topics added to a given Pizza. That's fine, but the primary key of the association table won't let you add a duplicate topic for a pizza anyway, so I think it's better to let the database layer manage that and just handle the exception that occurs in application code.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 12 '18 at 6:01

























          answered Nov 12 '18 at 5:55









          SuperShoot

          1,585619




          1,585619























              0














              A query to fetch all Pizza with given Topics (and possibly more) can be expressed using a slightly hard to read double negation:



              session.query(Pizza).
              filter(~session.query(Topic).
              filter(Topic.product.in_(values),
              ~session.query(TopicToPizzaAssociation).
              filter(TopicToPizzaAssociation.topic_id == Topic.id,
              TopicToPizzaAssociation.pizza_id == Pizza.id).
              correlate(Pizza, Topic).
              exists()).
              exists())


              In English it reads along the lines of "Fetch pizza where not exists a given topic [sic] that is not in this pizza."




              This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.




              SQL does not have universal quantification and so there is no all() operator for relationships the way that any() maps to EXISTS. But



              FORALL x ( p ( x ) )


              is logically equivalent to



              NOT EXISTS x ( NOT p ( x ) )


              which the above query takes advantage of. It is also described as how to perform relational division in SQL:



              • https://www.red-gate.com/simple-talk/sql/t-sql-programming/divided-we-stand-the-sql-of-relational-division/

              • https://www.jooq.org/doc/3.11/manual/sql-building/table-expressions/relational-division/

              • http://www.inf.usi.ch/faculty/soule/teaching/2016-fall/db/division.pdf





              share|improve this answer



























                0














                A query to fetch all Pizza with given Topics (and possibly more) can be expressed using a slightly hard to read double negation:



                session.query(Pizza).
                filter(~session.query(Topic).
                filter(Topic.product.in_(values),
                ~session.query(TopicToPizzaAssociation).
                filter(TopicToPizzaAssociation.topic_id == Topic.id,
                TopicToPizzaAssociation.pizza_id == Pizza.id).
                correlate(Pizza, Topic).
                exists()).
                exists())


                In English it reads along the lines of "Fetch pizza where not exists a given topic [sic] that is not in this pizza."




                This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.




                SQL does not have universal quantification and so there is no all() operator for relationships the way that any() maps to EXISTS. But



                FORALL x ( p ( x ) )


                is logically equivalent to



                NOT EXISTS x ( NOT p ( x ) )


                which the above query takes advantage of. It is also described as how to perform relational division in SQL:



                • https://www.red-gate.com/simple-talk/sql/t-sql-programming/divided-we-stand-the-sql-of-relational-division/

                • https://www.jooq.org/doc/3.11/manual/sql-building/table-expressions/relational-division/

                • http://www.inf.usi.ch/faculty/soule/teaching/2016-fall/db/division.pdf





                share|improve this answer

























                  0












                  0








                  0






                  A query to fetch all Pizza with given Topics (and possibly more) can be expressed using a slightly hard to read double negation:



                  session.query(Pizza).
                  filter(~session.query(Topic).
                  filter(Topic.product.in_(values),
                  ~session.query(TopicToPizzaAssociation).
                  filter(TopicToPizzaAssociation.topic_id == Topic.id,
                  TopicToPizzaAssociation.pizza_id == Pizza.id).
                  correlate(Pizza, Topic).
                  exists()).
                  exists())


                  In English it reads along the lines of "Fetch pizza where not exists a given topic [sic] that is not in this pizza."




                  This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.




                  SQL does not have universal quantification and so there is no all() operator for relationships the way that any() maps to EXISTS. But



                  FORALL x ( p ( x ) )


                  is logically equivalent to



                  NOT EXISTS x ( NOT p ( x ) )


                  which the above query takes advantage of. It is also described as how to perform relational division in SQL:



                  • https://www.red-gate.com/simple-talk/sql/t-sql-programming/divided-we-stand-the-sql-of-relational-division/

                  • https://www.jooq.org/doc/3.11/manual/sql-building/table-expressions/relational-division/

                  • http://www.inf.usi.ch/faculty/soule/teaching/2016-fall/db/division.pdf





                  share|improve this answer














                  A query to fetch all Pizza with given Topics (and possibly more) can be expressed using a slightly hard to read double negation:



                  session.query(Pizza).
                  filter(~session.query(Topic).
                  filter(Topic.product.in_(values),
                  ~session.query(TopicToPizzaAssociation).
                  filter(TopicToPizzaAssociation.topic_id == Topic.id,
                  TopicToPizzaAssociation.pizza_id == Pizza.id).
                  correlate(Pizza, Topic).
                  exists()).
                  exists())


                  In English it reads along the lines of "Fetch pizza where not exists a given topic [sic] that is not in this pizza."




                  This returns all pizza that have one of topics. If I try to replace any with all, it doesn't work.




                  SQL does not have universal quantification and so there is no all() operator for relationships the way that any() maps to EXISTS. But



                  FORALL x ( p ( x ) )


                  is logically equivalent to



                  NOT EXISTS x ( NOT p ( x ) )


                  which the above query takes advantage of. It is also described as how to perform relational division in SQL:



                  • https://www.red-gate.com/simple-talk/sql/t-sql-programming/divided-we-stand-the-sql-of-relational-division/

                  • https://www.jooq.org/doc/3.11/manual/sql-building/table-expressions/relational-division/

                  • http://www.inf.usi.ch/faculty/soule/teaching/2016-fall/db/division.pdf






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 12 '18 at 12:38

























                  answered Nov 12 '18 at 12:20









                  Ilja Everilä

                  23.4k33560




                  23.4k33560



























                      draft saved

                      draft discarded
















































                      Thanks for contributing an answer to Stack Overflow!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid


                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.

                      To learn more, see our tips on writing great answers.





                      Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                      Please pay close attention to the following guidance:


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid


                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.

                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function ()
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53252749%2fsqlalchemy-select-objects-that-has-all-tags%23new-answer', 'question_page');

                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Use pre created SQLite database for Android project in kotlin

                      Darth Vader #20

                      Ondo