how to insert elements into xml with xmlstarlet?










1















I want to insert additional elements into some variants of XML input. This script tries to demonstrate the input, and my attempt to insert code into the existing XML. As it can be seen, modifying a.xml gives the expected output. But in b.xml and c.xml, the result is bogus. In b.xml, the existing <c/> is changed and another block of <b/> is created. In c.xml, the result is that d="" is assigned twice.



There should be only a single <a><b>, with several <c>.



Any idea how to achieve that?



#!/bin/bash
# insert <a><b><c d="2"/>
set -e
td=`mktemp --directory --tmpdir=/dev/shm XXX`
trap "rm -rf '$td'" EXIT
xmlstarlet --version
pushd "$td"
cat > a.xml <<_EOX_
<a>
</a>
_EOX_
cat > b.xml <<_EOX_
<a>
<b>
<c/>
</b>
</a>
_EOX_
cat > c.xml <<_EOX_
<a>
<b>
<c d="1"/>
</b>
</a>
_EOX_

for i in *.xml
do
echo "$i"
cat "$i" |
xmlstarlet ed -O
-s 'a' -t elem -n b
-s 'a/b' -t elem -n c
-i 'a/b/c' -t attr -n d -v '2' |
xmlstarlet fo -o || echo "$?"
done


This produces the following output:



1.6.1
compiled against libxml2 2.9.7, linked with 20907
compiled against libxslt 1.1.32, linked with 10132
/dev/shm/tpX ~/work
a.xml
<a>
<b>
<c d="2"/>
</b>
</a>
37
b.xml
<a>
<b>
<c d="2"/>
<c d="2"/>
</b>
<b>
<c d="2"/>
</b>
</a>
80
c.xml
-:3.19: Attribute d redefined
<c d="1" d="2"/>
^
2









share|improve this question
























  • could you please inform us how the output should look like for the 3 cases?

    – kvantour
    Nov 16 '18 at 9:37











  • @kvantour There should be only a single <a><b>, with several <c>.

    – olh
    Nov 16 '18 at 13:50











  • updated the answer

    – kvantour
    Nov 16 '18 at 13:58
















1















I want to insert additional elements into some variants of XML input. This script tries to demonstrate the input, and my attempt to insert code into the existing XML. As it can be seen, modifying a.xml gives the expected output. But in b.xml and c.xml, the result is bogus. In b.xml, the existing <c/> is changed and another block of <b/> is created. In c.xml, the result is that d="" is assigned twice.



There should be only a single <a><b>, with several <c>.



Any idea how to achieve that?



#!/bin/bash
# insert <a><b><c d="2"/>
set -e
td=`mktemp --directory --tmpdir=/dev/shm XXX`
trap "rm -rf '$td'" EXIT
xmlstarlet --version
pushd "$td"
cat > a.xml <<_EOX_
<a>
</a>
_EOX_
cat > b.xml <<_EOX_
<a>
<b>
<c/>
</b>
</a>
_EOX_
cat > c.xml <<_EOX_
<a>
<b>
<c d="1"/>
</b>
</a>
_EOX_

for i in *.xml
do
echo "$i"
cat "$i" |
xmlstarlet ed -O
-s 'a' -t elem -n b
-s 'a/b' -t elem -n c
-i 'a/b/c' -t attr -n d -v '2' |
xmlstarlet fo -o || echo "$?"
done


This produces the following output:



1.6.1
compiled against libxml2 2.9.7, linked with 20907
compiled against libxslt 1.1.32, linked with 10132
/dev/shm/tpX ~/work
a.xml
<a>
<b>
<c d="2"/>
</b>
</a>
37
b.xml
<a>
<b>
<c d="2"/>
<c d="2"/>
</b>
<b>
<c d="2"/>
</b>
</a>
80
c.xml
-:3.19: Attribute d redefined
<c d="1" d="2"/>
^
2









share|improve this question
























  • could you please inform us how the output should look like for the 3 cases?

    – kvantour
    Nov 16 '18 at 9:37











  • @kvantour There should be only a single <a><b>, with several <c>.

    – olh
    Nov 16 '18 at 13:50











  • updated the answer

    – kvantour
    Nov 16 '18 at 13:58














1












1








1


1






I want to insert additional elements into some variants of XML input. This script tries to demonstrate the input, and my attempt to insert code into the existing XML. As it can be seen, modifying a.xml gives the expected output. But in b.xml and c.xml, the result is bogus. In b.xml, the existing <c/> is changed and another block of <b/> is created. In c.xml, the result is that d="" is assigned twice.



There should be only a single <a><b>, with several <c>.



Any idea how to achieve that?



#!/bin/bash
# insert <a><b><c d="2"/>
set -e
td=`mktemp --directory --tmpdir=/dev/shm XXX`
trap "rm -rf '$td'" EXIT
xmlstarlet --version
pushd "$td"
cat > a.xml <<_EOX_
<a>
</a>
_EOX_
cat > b.xml <<_EOX_
<a>
<b>
<c/>
</b>
</a>
_EOX_
cat > c.xml <<_EOX_
<a>
<b>
<c d="1"/>
</b>
</a>
_EOX_

for i in *.xml
do
echo "$i"
cat "$i" |
xmlstarlet ed -O
-s 'a' -t elem -n b
-s 'a/b' -t elem -n c
-i 'a/b/c' -t attr -n d -v '2' |
xmlstarlet fo -o || echo "$?"
done


This produces the following output:



1.6.1
compiled against libxml2 2.9.7, linked with 20907
compiled against libxslt 1.1.32, linked with 10132
/dev/shm/tpX ~/work
a.xml
<a>
<b>
<c d="2"/>
</b>
</a>
37
b.xml
<a>
<b>
<c d="2"/>
<c d="2"/>
</b>
<b>
<c d="2"/>
</b>
</a>
80
c.xml
-:3.19: Attribute d redefined
<c d="1" d="2"/>
^
2









share|improve this question
















I want to insert additional elements into some variants of XML input. This script tries to demonstrate the input, and my attempt to insert code into the existing XML. As it can be seen, modifying a.xml gives the expected output. But in b.xml and c.xml, the result is bogus. In b.xml, the existing <c/> is changed and another block of <b/> is created. In c.xml, the result is that d="" is assigned twice.



There should be only a single <a><b>, with several <c>.



Any idea how to achieve that?



#!/bin/bash
# insert <a><b><c d="2"/>
set -e
td=`mktemp --directory --tmpdir=/dev/shm XXX`
trap "rm -rf '$td'" EXIT
xmlstarlet --version
pushd "$td"
cat > a.xml <<_EOX_
<a>
</a>
_EOX_
cat > b.xml <<_EOX_
<a>
<b>
<c/>
</b>
</a>
_EOX_
cat > c.xml <<_EOX_
<a>
<b>
<c d="1"/>
</b>
</a>
_EOX_

for i in *.xml
do
echo "$i"
cat "$i" |
xmlstarlet ed -O
-s 'a' -t elem -n b
-s 'a/b' -t elem -n c
-i 'a/b/c' -t attr -n d -v '2' |
xmlstarlet fo -o || echo "$?"
done


This produces the following output:



1.6.1
compiled against libxml2 2.9.7, linked with 20907
compiled against libxslt 1.1.32, linked with 10132
/dev/shm/tpX ~/work
a.xml
<a>
<b>
<c d="2"/>
</b>
</a>
37
b.xml
<a>
<b>
<c d="2"/>
<c d="2"/>
</b>
<b>
<c d="2"/>
</b>
</a>
80
c.xml
-:3.19: Attribute d redefined
<c d="1" d="2"/>
^
2






xml shell xpath xmlstarlet






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 16:50









kvantour

9,44431731




9,44431731










asked Nov 14 '18 at 15:38









olholh

333




333












  • could you please inform us how the output should look like for the 3 cases?

    – kvantour
    Nov 16 '18 at 9:37











  • @kvantour There should be only a single <a><b>, with several <c>.

    – olh
    Nov 16 '18 at 13:50











  • updated the answer

    – kvantour
    Nov 16 '18 at 13:58


















  • could you please inform us how the output should look like for the 3 cases?

    – kvantour
    Nov 16 '18 at 9:37











  • @kvantour There should be only a single <a><b>, with several <c>.

    – olh
    Nov 16 '18 at 13:50











  • updated the answer

    – kvantour
    Nov 16 '18 at 13:58

















could you please inform us how the output should look like for the 3 cases?

– kvantour
Nov 16 '18 at 9:37





could you please inform us how the output should look like for the 3 cases?

– kvantour
Nov 16 '18 at 9:37













@kvantour There should be only a single <a><b>, with several <c>.

– olh
Nov 16 '18 at 13:50





@kvantour There should be only a single <a><b>, with several <c>.

– olh
Nov 16 '18 at 13:50













updated the answer

– kvantour
Nov 16 '18 at 13:58






updated the answer

– kvantour
Nov 16 '18 at 13:58













1 Answer
1






active

oldest

votes


















0














The problem is that you need to tell which node you want to change.




  1. Add child b only if b does not exist in a:



    -s "/a[not(b)]" -t elem -n "b"



  2. Add a new child c in a/b:



    -s "/a/b[not(c)]" -t elem -n "c"



  3. Add attribute d to the newly added node c which is in the last place:



    -s "/a/b/c[last()]" -t attr -n "d" -v "2"


So the complete commands reads now:



xmlstarlet ed -O 
-s "/a[not(b)]" -t elem -n "b"
-s "/a/b" -t elem -n "c"
-s "/a/b/c[last()]" -t attr -n "d" -v "2"


Here we made use of the not() function to indicate that we just want to select the nodes that do not contain that particular item.



Useful links:



  • A very handy XPath tutorial

  • XPath 1.0 specification





share|improve this answer

























  • Thanks. But the last one gives just a single <c/> inside <b/>. I was expecting two of them,

    – olh
    Nov 14 '18 at 21:45











  • @olh I thought this was your question. All XML inputs should give the same result.

    – kvantour
    Nov 14 '18 at 22:36











  • Thanks so much.

    – olh
    Nov 16 '18 at 20:03










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














The problem is that you need to tell which node you want to change.




  1. Add child b only if b does not exist in a:



    -s "/a[not(b)]" -t elem -n "b"



  2. Add a new child c in a/b:



    -s "/a/b[not(c)]" -t elem -n "c"



  3. Add attribute d to the newly added node c which is in the last place:



    -s "/a/b/c[last()]" -t attr -n "d" -v "2"


So the complete commands reads now:



xmlstarlet ed -O 
-s "/a[not(b)]" -t elem -n "b"
-s "/a/b" -t elem -n "c"
-s "/a/b/c[last()]" -t attr -n "d" -v "2"


Here we made use of the not() function to indicate that we just want to select the nodes that do not contain that particular item.



Useful links:



  • A very handy XPath tutorial

  • XPath 1.0 specification





share|improve this answer

























  • Thanks. But the last one gives just a single <c/> inside <b/>. I was expecting two of them,

    – olh
    Nov 14 '18 at 21:45











  • @olh I thought this was your question. All XML inputs should give the same result.

    – kvantour
    Nov 14 '18 at 22:36











  • Thanks so much.

    – olh
    Nov 16 '18 at 20:03















0














The problem is that you need to tell which node you want to change.




  1. Add child b only if b does not exist in a:



    -s "/a[not(b)]" -t elem -n "b"



  2. Add a new child c in a/b:



    -s "/a/b[not(c)]" -t elem -n "c"



  3. Add attribute d to the newly added node c which is in the last place:



    -s "/a/b/c[last()]" -t attr -n "d" -v "2"


So the complete commands reads now:



xmlstarlet ed -O 
-s "/a[not(b)]" -t elem -n "b"
-s "/a/b" -t elem -n "c"
-s "/a/b/c[last()]" -t attr -n "d" -v "2"


Here we made use of the not() function to indicate that we just want to select the nodes that do not contain that particular item.



Useful links:



  • A very handy XPath tutorial

  • XPath 1.0 specification





share|improve this answer

























  • Thanks. But the last one gives just a single <c/> inside <b/>. I was expecting two of them,

    – olh
    Nov 14 '18 at 21:45











  • @olh I thought this was your question. All XML inputs should give the same result.

    – kvantour
    Nov 14 '18 at 22:36











  • Thanks so much.

    – olh
    Nov 16 '18 at 20:03













0












0








0







The problem is that you need to tell which node you want to change.




  1. Add child b only if b does not exist in a:



    -s "/a[not(b)]" -t elem -n "b"



  2. Add a new child c in a/b:



    -s "/a/b[not(c)]" -t elem -n "c"



  3. Add attribute d to the newly added node c which is in the last place:



    -s "/a/b/c[last()]" -t attr -n "d" -v "2"


So the complete commands reads now:



xmlstarlet ed -O 
-s "/a[not(b)]" -t elem -n "b"
-s "/a/b" -t elem -n "c"
-s "/a/b/c[last()]" -t attr -n "d" -v "2"


Here we made use of the not() function to indicate that we just want to select the nodes that do not contain that particular item.



Useful links:



  • A very handy XPath tutorial

  • XPath 1.0 specification





share|improve this answer















The problem is that you need to tell which node you want to change.




  1. Add child b only if b does not exist in a:



    -s "/a[not(b)]" -t elem -n "b"



  2. Add a new child c in a/b:



    -s "/a/b[not(c)]" -t elem -n "c"



  3. Add attribute d to the newly added node c which is in the last place:



    -s "/a/b/c[last()]" -t attr -n "d" -v "2"


So the complete commands reads now:



xmlstarlet ed -O 
-s "/a[not(b)]" -t elem -n "b"
-s "/a/b" -t elem -n "c"
-s "/a/b/c[last()]" -t attr -n "d" -v "2"


Here we made use of the not() function to indicate that we just want to select the nodes that do not contain that particular item.



Useful links:



  • A very handy XPath tutorial

  • XPath 1.0 specification






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 16 '18 at 13:58

























answered Nov 14 '18 at 16:28









kvantourkvantour

9,44431731




9,44431731












  • Thanks. But the last one gives just a single <c/> inside <b/>. I was expecting two of them,

    – olh
    Nov 14 '18 at 21:45











  • @olh I thought this was your question. All XML inputs should give the same result.

    – kvantour
    Nov 14 '18 at 22:36











  • Thanks so much.

    – olh
    Nov 16 '18 at 20:03

















  • Thanks. But the last one gives just a single <c/> inside <b/>. I was expecting two of them,

    – olh
    Nov 14 '18 at 21:45











  • @olh I thought this was your question. All XML inputs should give the same result.

    – kvantour
    Nov 14 '18 at 22:36











  • Thanks so much.

    – olh
    Nov 16 '18 at 20:03
















Thanks. But the last one gives just a single <c/> inside <b/>. I was expecting two of them,

– olh
Nov 14 '18 at 21:45





Thanks. But the last one gives just a single <c/> inside <b/>. I was expecting two of them,

– olh
Nov 14 '18 at 21:45













@olh I thought this was your question. All XML inputs should give the same result.

– kvantour
Nov 14 '18 at 22:36





@olh I thought this was your question. All XML inputs should give the same result.

– kvantour
Nov 14 '18 at 22:36













Thanks so much.

– olh
Nov 16 '18 at 20:03





Thanks so much.

– olh
Nov 16 '18 at 20:03



















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