How to set Replacement Text to Bullet Format when creating WordDoc from Excel using VBA



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4















Hello and thank you in advance.



I am creating a very complex Word document out of an Excelfile using VBA.
It shall be possible to activate something and a text written in a cell shall be transfered to the word document. I got that already done. But at some parts it must be in a Bullets-Format.
Right now I use tags like "<< replacementPoint1 >>" in the Word Template, find and replace them with the ReplacementText using something as easy as that one-line-code:



With WordDoc.Content.Find
.Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
End With


But how can I set the replacementText to a bullet or a number like this:




  • ReplacementText some more text here......



    1. ReplacementText some more text here.....










share|improve this question






























    4















    Hello and thank you in advance.



    I am creating a very complex Word document out of an Excelfile using VBA.
    It shall be possible to activate something and a text written in a cell shall be transfered to the word document. I got that already done. But at some parts it must be in a Bullets-Format.
    Right now I use tags like "<< replacementPoint1 >>" in the Word Template, find and replace them with the ReplacementText using something as easy as that one-line-code:



    With WordDoc.Content.Find
    .Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
    End With


    But how can I set the replacementText to a bullet or a number like this:




    • ReplacementText some more text here......



      1. ReplacementText some more text here.....










    share|improve this question


























      4












      4








      4








      Hello and thank you in advance.



      I am creating a very complex Word document out of an Excelfile using VBA.
      It shall be possible to activate something and a text written in a cell shall be transfered to the word document. I got that already done. But at some parts it must be in a Bullets-Format.
      Right now I use tags like "<< replacementPoint1 >>" in the Word Template, find and replace them with the ReplacementText using something as easy as that one-line-code:



      With WordDoc.Content.Find
      .Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
      End With


      But how can I set the replacementText to a bullet or a number like this:




      • ReplacementText some more text here......



        1. ReplacementText some more text here.....










      share|improve this question
















      Hello and thank you in advance.



      I am creating a very complex Word document out of an Excelfile using VBA.
      It shall be possible to activate something and a text written in a cell shall be transfered to the word document. I got that already done. But at some parts it must be in a Bullets-Format.
      Right now I use tags like "<< replacementPoint1 >>" in the Word Template, find and replace them with the ReplacementText using something as easy as that one-line-code:



      With WordDoc.Content.Find
      .Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
      End With


      But how can I set the replacementText to a bullet or a number like this:




      • ReplacementText some more text here......



        1. ReplacementText some more text here.....







      excel vba excel-vba ms-word format






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 15 '18 at 8:25









      Pᴇʜ

      25.2k63052




      25.2k63052










      asked Nov 15 '18 at 8:16









      Christian GoldChristian Gold

      1179




      1179






















          1 Answer
          1






          active

          oldest

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          2














          There are a number of possible approaches. One would be to not use wdReplaceAll - instead, the code would do one "find" at a time, apply the required formatting, then loop the find/replace and format again and again until nothing more is found. There are lots of examples of this approach here on Stack Overflow and on the Internet, in general.



          Quicker would be to leverage the fact that Word can apply certain kinds of formatting as part of the Replace functionality. In the Word UI, press Ctrl+H to view the Find & Replace dialog box; click "More" then click "Format" to see the possibilities. Bullets and Numbering is not a selection, here... But Styles are.



          If you're working with a template to generate these documents (highly recommended) then define the bullets / numbering to be used as styles in the template. If no template is used, the code can create the style definition(s) on-the-fly.



          Specify the Style name (case-sensitive!) as part of the Replacement properties defined for the Find and set the Format property to True. Something like:



          Dim rngFind as Word.Range 'Object if late-binding
          Set rngFind = WordDoc.Content
          With rngFind.Find
          .ClearFormatting
          .Replacement.ClearFormatting
          .Replacement.Style = "My style"
          .Format = True
          .Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
          End With





          share|improve this answer























          • Thank you. It worked with this code smoothly. I created a new style in the template and used it at .replacement.Style. Just the font size was not correct afterwards but I set it to the proper value and now it fits my needs.

            – Christian Gold
            Nov 15 '18 at 13:43











          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          There are a number of possible approaches. One would be to not use wdReplaceAll - instead, the code would do one "find" at a time, apply the required formatting, then loop the find/replace and format again and again until nothing more is found. There are lots of examples of this approach here on Stack Overflow and on the Internet, in general.



          Quicker would be to leverage the fact that Word can apply certain kinds of formatting as part of the Replace functionality. In the Word UI, press Ctrl+H to view the Find & Replace dialog box; click "More" then click "Format" to see the possibilities. Bullets and Numbering is not a selection, here... But Styles are.



          If you're working with a template to generate these documents (highly recommended) then define the bullets / numbering to be used as styles in the template. If no template is used, the code can create the style definition(s) on-the-fly.



          Specify the Style name (case-sensitive!) as part of the Replacement properties defined for the Find and set the Format property to True. Something like:



          Dim rngFind as Word.Range 'Object if late-binding
          Set rngFind = WordDoc.Content
          With rngFind.Find
          .ClearFormatting
          .Replacement.ClearFormatting
          .Replacement.Style = "My style"
          .Format = True
          .Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
          End With





          share|improve this answer























          • Thank you. It worked with this code smoothly. I created a new style in the template and used it at .replacement.Style. Just the font size was not correct afterwards but I set it to the proper value and now it fits my needs.

            – Christian Gold
            Nov 15 '18 at 13:43















          2














          There are a number of possible approaches. One would be to not use wdReplaceAll - instead, the code would do one "find" at a time, apply the required formatting, then loop the find/replace and format again and again until nothing more is found. There are lots of examples of this approach here on Stack Overflow and on the Internet, in general.



          Quicker would be to leverage the fact that Word can apply certain kinds of formatting as part of the Replace functionality. In the Word UI, press Ctrl+H to view the Find & Replace dialog box; click "More" then click "Format" to see the possibilities. Bullets and Numbering is not a selection, here... But Styles are.



          If you're working with a template to generate these documents (highly recommended) then define the bullets / numbering to be used as styles in the template. If no template is used, the code can create the style definition(s) on-the-fly.



          Specify the Style name (case-sensitive!) as part of the Replacement properties defined for the Find and set the Format property to True. Something like:



          Dim rngFind as Word.Range 'Object if late-binding
          Set rngFind = WordDoc.Content
          With rngFind.Find
          .ClearFormatting
          .Replacement.ClearFormatting
          .Replacement.Style = "My style"
          .Format = True
          .Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
          End With





          share|improve this answer























          • Thank you. It worked with this code smoothly. I created a new style in the template and used it at .replacement.Style. Just the font size was not correct afterwards but I set it to the proper value and now it fits my needs.

            – Christian Gold
            Nov 15 '18 at 13:43













          2












          2








          2







          There are a number of possible approaches. One would be to not use wdReplaceAll - instead, the code would do one "find" at a time, apply the required formatting, then loop the find/replace and format again and again until nothing more is found. There are lots of examples of this approach here on Stack Overflow and on the Internet, in general.



          Quicker would be to leverage the fact that Word can apply certain kinds of formatting as part of the Replace functionality. In the Word UI, press Ctrl+H to view the Find & Replace dialog box; click "More" then click "Format" to see the possibilities. Bullets and Numbering is not a selection, here... But Styles are.



          If you're working with a template to generate these documents (highly recommended) then define the bullets / numbering to be used as styles in the template. If no template is used, the code can create the style definition(s) on-the-fly.



          Specify the Style name (case-sensitive!) as part of the Replacement properties defined for the Find and set the Format property to True. Something like:



          Dim rngFind as Word.Range 'Object if late-binding
          Set rngFind = WordDoc.Content
          With rngFind.Find
          .ClearFormatting
          .Replacement.ClearFormatting
          .Replacement.Style = "My style"
          .Format = True
          .Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
          End With





          share|improve this answer













          There are a number of possible approaches. One would be to not use wdReplaceAll - instead, the code would do one "find" at a time, apply the required formatting, then loop the find/replace and format again and again until nothing more is found. There are lots of examples of this approach here on Stack Overflow and on the Internet, in general.



          Quicker would be to leverage the fact that Word can apply certain kinds of formatting as part of the Replace functionality. In the Word UI, press Ctrl+H to view the Find & Replace dialog box; click "More" then click "Format" to see the possibilities. Bullets and Numbering is not a selection, here... But Styles are.



          If you're working with a template to generate these documents (highly recommended) then define the bullets / numbering to be used as styles in the template. If no template is used, the code can create the style definition(s) on-the-fly.



          Specify the Style name (case-sensitive!) as part of the Replacement properties defined for the Find and set the Format property to True. Something like:



          Dim rngFind as Word.Range 'Object if late-binding
          Set rngFind = WordDoc.Content
          With rngFind.Find
          .ClearFormatting
          .Replacement.ClearFormatting
          .Replacement.Style = "My style"
          .Format = True
          .Execute FindText:=ReplacementTextF, ReplaceWith:=ReplacementText, Replace:=2
          End With






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 11:48









          Cindy MeisterCindy Meister

          16k102537




          16k102537












          • Thank you. It worked with this code smoothly. I created a new style in the template and used it at .replacement.Style. Just the font size was not correct afterwards but I set it to the proper value and now it fits my needs.

            – Christian Gold
            Nov 15 '18 at 13:43

















          • Thank you. It worked with this code smoothly. I created a new style in the template and used it at .replacement.Style. Just the font size was not correct afterwards but I set it to the proper value and now it fits my needs.

            – Christian Gold
            Nov 15 '18 at 13:43
















          Thank you. It worked with this code smoothly. I created a new style in the template and used it at .replacement.Style. Just the font size was not correct afterwards but I set it to the proper value and now it fits my needs.

          – Christian Gold
          Nov 15 '18 at 13:43





          Thank you. It worked with this code smoothly. I created a new style in the template and used it at .replacement.Style. Just the font size was not correct afterwards but I set it to the proper value and now it fits my needs.

          – Christian Gold
          Nov 15 '18 at 13:43



















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