Meaning of * operator when used with classes



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








-1















I've been trying to follow a video tutorial on Python and cannot understand one operation the developer performs.



class Polynomial():

def __init__(self, *coeffs):
self.coeffs = coeffs # (3,4,3)

def __repr__(self):
return 'Polynomial(*!r)'.format(self.coeffs)

def __add__(self, other):
print(self.coeffs)
print(other.coeffs)
z = (x + y for x, y in zip(self.coeffs, other.coeffs))
print(z)
return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs)))

p1 = Polynomial(1, 2, 3) # x^2 + 2x + 3
p2 = Polynomial(3, 4, 3) # 3x^2 + 4x + 3
#print(p2) # Polynomial(*(3, 4, 3))
print(p1 + p2) # Polynomial(*(4, 6, 6))


The above example will print



<generator object Polynomial.__add__.<locals>.<genexpr> at 0x030D0390>


as the return value of z, I cannot understand why because I am performing a zip operation of two tuples?



Alongside that problem, I do not understand why removing the * during the return of __add__ causes a problem i.e return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs))) to return Polynomial((x + y for x, y in zip(self.coeffs, other.coeffs)))



What is the * operator doing, and why is z an object of Polynomial?



The _add__ method does not contain a parameter containing a * or ** and is therefore a different situation.










share|improve this question



















  • 2





    Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

    – Norrius
    Nov 15 '18 at 9:19

















-1















I've been trying to follow a video tutorial on Python and cannot understand one operation the developer performs.



class Polynomial():

def __init__(self, *coeffs):
self.coeffs = coeffs # (3,4,3)

def __repr__(self):
return 'Polynomial(*!r)'.format(self.coeffs)

def __add__(self, other):
print(self.coeffs)
print(other.coeffs)
z = (x + y for x, y in zip(self.coeffs, other.coeffs))
print(z)
return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs)))

p1 = Polynomial(1, 2, 3) # x^2 + 2x + 3
p2 = Polynomial(3, 4, 3) # 3x^2 + 4x + 3
#print(p2) # Polynomial(*(3, 4, 3))
print(p1 + p2) # Polynomial(*(4, 6, 6))


The above example will print



<generator object Polynomial.__add__.<locals>.<genexpr> at 0x030D0390>


as the return value of z, I cannot understand why because I am performing a zip operation of two tuples?



Alongside that problem, I do not understand why removing the * during the return of __add__ causes a problem i.e return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs))) to return Polynomial((x + y for x, y in zip(self.coeffs, other.coeffs)))



What is the * operator doing, and why is z an object of Polynomial?



The _add__ method does not contain a parameter containing a * or ** and is therefore a different situation.










share|improve this question



















  • 2





    Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

    – Norrius
    Nov 15 '18 at 9:19













-1












-1








-1








I've been trying to follow a video tutorial on Python and cannot understand one operation the developer performs.



class Polynomial():

def __init__(self, *coeffs):
self.coeffs = coeffs # (3,4,3)

def __repr__(self):
return 'Polynomial(*!r)'.format(self.coeffs)

def __add__(self, other):
print(self.coeffs)
print(other.coeffs)
z = (x + y for x, y in zip(self.coeffs, other.coeffs))
print(z)
return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs)))

p1 = Polynomial(1, 2, 3) # x^2 + 2x + 3
p2 = Polynomial(3, 4, 3) # 3x^2 + 4x + 3
#print(p2) # Polynomial(*(3, 4, 3))
print(p1 + p2) # Polynomial(*(4, 6, 6))


The above example will print



<generator object Polynomial.__add__.<locals>.<genexpr> at 0x030D0390>


as the return value of z, I cannot understand why because I am performing a zip operation of two tuples?



Alongside that problem, I do not understand why removing the * during the return of __add__ causes a problem i.e return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs))) to return Polynomial((x + y for x, y in zip(self.coeffs, other.coeffs)))



What is the * operator doing, and why is z an object of Polynomial?



The _add__ method does not contain a parameter containing a * or ** and is therefore a different situation.










share|improve this question
















I've been trying to follow a video tutorial on Python and cannot understand one operation the developer performs.



class Polynomial():

def __init__(self, *coeffs):
self.coeffs = coeffs # (3,4,3)

def __repr__(self):
return 'Polynomial(*!r)'.format(self.coeffs)

def __add__(self, other):
print(self.coeffs)
print(other.coeffs)
z = (x + y for x, y in zip(self.coeffs, other.coeffs))
print(z)
return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs)))

p1 = Polynomial(1, 2, 3) # x^2 + 2x + 3
p2 = Polynomial(3, 4, 3) # 3x^2 + 4x + 3
#print(p2) # Polynomial(*(3, 4, 3))
print(p1 + p2) # Polynomial(*(4, 6, 6))


The above example will print



<generator object Polynomial.__add__.<locals>.<genexpr> at 0x030D0390>


as the return value of z, I cannot understand why because I am performing a zip operation of two tuples?



Alongside that problem, I do not understand why removing the * during the return of __add__ causes a problem i.e return Polynomial(*(x + y for x, y in zip(self.coeffs, other.coeffs))) to return Polynomial((x + y for x, y in zip(self.coeffs, other.coeffs)))



What is the * operator doing, and why is z an object of Polynomial?



The _add__ method does not contain a parameter containing a * or ** and is therefore a different situation.







python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 9:21







J.doe

















asked Nov 15 '18 at 9:13









J.doeJ.doe

233




233







  • 2





    Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

    – Norrius
    Nov 15 '18 at 9:19












  • 2





    Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

    – Norrius
    Nov 15 '18 at 9:19







2




2





Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

– Norrius
Nov 15 '18 at 9:19





Possible duplicate of What does ** (double star/asterisk) and * (star/asterisk) do for parameters?

– Norrius
Nov 15 '18 at 9:19












3 Answers
3






active

oldest

votes


















1














So first.



Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



Or you can use your generator, so print:



print([el for el in z])


Second, the *.



It will simply pass iterable as separated args, so:



SomeClass(*args)


Will do:



SomeClass(args[0], args[1], args[2], ...)


You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
And here (double asterisk):
https://docs.python.org/3/reference/expressions.html#dictionary-displays






share|improve this answer


















  • 1





    or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

    – buran
    Nov 15 '18 at 9:22



















0














When in a function declaration, * is list of args send.



For exemple:



def my_function(a, *b, **c):
print(a)
print(b)
print(c)

my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


output :



1st args
["other arg", "other arg again", 2]
"arg_type": "kwargs"



And when is not in function declaration, it's for unpack the list.



For exemple:



list_of_arguments = ['a', 'b', 'z']
my_str = "the first letter of alphabet is , the second is and the last is "
print(my_str.format(*list_of_arguments))





or other exemple



 def my_second_func(a, b, c):
print(a)
print(b)

my_list = [1, 2, 3]
my_second_func(a, b, c)


will output:



 1
2





share|improve this answer

























  • but add does not have a parameter with a *

    – J.doe
    Nov 15 '18 at 9:18











  • i edited my post, in your code * is used for unpack the list returned by the zip() function

    – iElden
    Nov 15 '18 at 9:22


















0














Consider this easy example:



a = [1, 2, 3]
b = [4, 5, 6]

gen = (x + y for x, y in zip(a, b))

print(gen) ## this will print <generator object <genexpr> at 0x...>


In this case, the asterisk evaluates the generator expression. So when doing



print(*gen) ## this will print 5 7 9


you evaluate the generator expression.






share|improve this answer























    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53315930%2fmeaning-of-operator-when-used-with-classes%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    So first.



    Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



    Or you can use your generator, so print:



    print([el for el in z])


    Second, the *.



    It will simply pass iterable as separated args, so:



    SomeClass(*args)


    Will do:



    SomeClass(args[0], args[1], args[2], ...)


    You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
    And here (double asterisk):
    https://docs.python.org/3/reference/expressions.html#dictionary-displays






    share|improve this answer


















    • 1





      or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

      – buran
      Nov 15 '18 at 9:22
















    1














    So first.



    Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



    Or you can use your generator, so print:



    print([el for el in z])


    Second, the *.



    It will simply pass iterable as separated args, so:



    SomeClass(*args)


    Will do:



    SomeClass(args[0], args[1], args[2], ...)


    You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
    And here (double asterisk):
    https://docs.python.org/3/reference/expressions.html#dictionary-displays






    share|improve this answer


















    • 1





      or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

      – buran
      Nov 15 '18 at 9:22














    1












    1








    1







    So first.



    Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



    Or you can use your generator, so print:



    print([el for el in z])


    Second, the *.



    It will simply pass iterable as separated args, so:



    SomeClass(*args)


    Will do:



    SomeClass(args[0], args[1], args[2], ...)


    You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
    And here (double asterisk):
    https://docs.python.org/3/reference/expressions.html#dictionary-displays






    share|improve this answer













    So first.



    Your print is ok. You defined a generator using () parentheses. You can change this to and then you should see the elements in list.



    Or you can use your generator, so print:



    print([el for el in z])


    Second, the *.



    It will simply pass iterable as separated args, so:



    SomeClass(*args)


    Will do:



    SomeClass(args[0], args[1], args[2], ...)


    You can read about this in official docs (single asterisk), here: https://docs.python.org/3/reference/expressions.html#expression-lists
    And here (double asterisk):
    https://docs.python.org/3/reference/expressions.html#dictionary-displays







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 15 '18 at 9:21









    opalczynskiopalczynski

    1,045811




    1,045811







    • 1





      or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

      – buran
      Nov 15 '18 at 9:22













    • 1





      or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

      – buran
      Nov 15 '18 at 9:22








    1




    1





    or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

    – buran
    Nov 15 '18 at 9:22






    or just print(list(z)). As to second question - you print the result of p1+p2 - i.e. print(p1 + p2). The add method returns Polynominal object, so when you print it and because you don't have str method, it calls the repr method of Polynominal class

    – buran
    Nov 15 '18 at 9:22














    0














    When in a function declaration, * is list of args send.



    For exemple:



    def my_function(a, *b, **c):
    print(a)
    print(b)
    print(c)

    my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


    output :



    1st args
    ["other arg", "other arg again", 2]
    "arg_type": "kwargs"



    And when is not in function declaration, it's for unpack the list.



    For exemple:



    list_of_arguments = ['a', 'b', 'z']
    my_str = "the first letter of alphabet is , the second is and the last is "
    print(my_str.format(*list_of_arguments))





    or other exemple



     def my_second_func(a, b, c):
    print(a)
    print(b)

    my_list = [1, 2, 3]
    my_second_func(a, b, c)


    will output:



     1
    2





    share|improve this answer

























    • but add does not have a parameter with a *

      – J.doe
      Nov 15 '18 at 9:18











    • i edited my post, in your code * is used for unpack the list returned by the zip() function

      – iElden
      Nov 15 '18 at 9:22















    0














    When in a function declaration, * is list of args send.



    For exemple:



    def my_function(a, *b, **c):
    print(a)
    print(b)
    print(c)

    my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


    output :



    1st args
    ["other arg", "other arg again", 2]
    "arg_type": "kwargs"



    And when is not in function declaration, it's for unpack the list.



    For exemple:



    list_of_arguments = ['a', 'b', 'z']
    my_str = "the first letter of alphabet is , the second is and the last is "
    print(my_str.format(*list_of_arguments))





    or other exemple



     def my_second_func(a, b, c):
    print(a)
    print(b)

    my_list = [1, 2, 3]
    my_second_func(a, b, c)


    will output:



     1
    2





    share|improve this answer

























    • but add does not have a parameter with a *

      – J.doe
      Nov 15 '18 at 9:18











    • i edited my post, in your code * is used for unpack the list returned by the zip() function

      – iElden
      Nov 15 '18 at 9:22













    0












    0








    0







    When in a function declaration, * is list of args send.



    For exemple:



    def my_function(a, *b, **c):
    print(a)
    print(b)
    print(c)

    my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


    output :



    1st args
    ["other arg", "other arg again", 2]
    "arg_type": "kwargs"



    And when is not in function declaration, it's for unpack the list.



    For exemple:



    list_of_arguments = ['a', 'b', 'z']
    my_str = "the first letter of alphabet is , the second is and the last is "
    print(my_str.format(*list_of_arguments))





    or other exemple



     def my_second_func(a, b, c):
    print(a)
    print(b)

    my_list = [1, 2, 3]
    my_second_func(a, b, c)


    will output:



     1
    2





    share|improve this answer















    When in a function declaration, * is list of args send.



    For exemple:



    def my_function(a, *b, **c):
    print(a)
    print(b)
    print(c)

    my_function("1st arg", "other arg", "other arg again", 2, arg_type="kwargs")


    output :



    1st args
    ["other arg", "other arg again", 2]
    "arg_type": "kwargs"



    And when is not in function declaration, it's for unpack the list.



    For exemple:



    list_of_arguments = ['a', 'b', 'z']
    my_str = "the first letter of alphabet is , the second is and the last is "
    print(my_str.format(*list_of_arguments))





    or other exemple



     def my_second_func(a, b, c):
    print(a)
    print(b)

    my_list = [1, 2, 3]
    my_second_func(a, b, c)


    will output:



     1
    2






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 15 '18 at 9:18

























    answered Nov 15 '18 at 9:16









    iEldeniElden

    721618




    721618












    • but add does not have a parameter with a *

      – J.doe
      Nov 15 '18 at 9:18











    • i edited my post, in your code * is used for unpack the list returned by the zip() function

      – iElden
      Nov 15 '18 at 9:22

















    • but add does not have a parameter with a *

      – J.doe
      Nov 15 '18 at 9:18











    • i edited my post, in your code * is used for unpack the list returned by the zip() function

      – iElden
      Nov 15 '18 at 9:22
















    but add does not have a parameter with a *

    – J.doe
    Nov 15 '18 at 9:18





    but add does not have a parameter with a *

    – J.doe
    Nov 15 '18 at 9:18













    i edited my post, in your code * is used for unpack the list returned by the zip() function

    – iElden
    Nov 15 '18 at 9:22





    i edited my post, in your code * is used for unpack the list returned by the zip() function

    – iElden
    Nov 15 '18 at 9:22











    0














    Consider this easy example:



    a = [1, 2, 3]
    b = [4, 5, 6]

    gen = (x + y for x, y in zip(a, b))

    print(gen) ## this will print <generator object <genexpr> at 0x...>


    In this case, the asterisk evaluates the generator expression. So when doing



    print(*gen) ## this will print 5 7 9


    you evaluate the generator expression.






    share|improve this answer



























      0














      Consider this easy example:



      a = [1, 2, 3]
      b = [4, 5, 6]

      gen = (x + y for x, y in zip(a, b))

      print(gen) ## this will print <generator object <genexpr> at 0x...>


      In this case, the asterisk evaluates the generator expression. So when doing



      print(*gen) ## this will print 5 7 9


      you evaluate the generator expression.






      share|improve this answer

























        0












        0








        0







        Consider this easy example:



        a = [1, 2, 3]
        b = [4, 5, 6]

        gen = (x + y for x, y in zip(a, b))

        print(gen) ## this will print <generator object <genexpr> at 0x...>


        In this case, the asterisk evaluates the generator expression. So when doing



        print(*gen) ## this will print 5 7 9


        you evaluate the generator expression.






        share|improve this answer













        Consider this easy example:



        a = [1, 2, 3]
        b = [4, 5, 6]

        gen = (x + y for x, y in zip(a, b))

        print(gen) ## this will print <generator object <genexpr> at 0x...>


        In this case, the asterisk evaluates the generator expression. So when doing



        print(*gen) ## this will print 5 7 9


        you evaluate the generator expression.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 9:27









        DocDrivenDocDriven

        1,2652721




        1,2652721



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53315930%2fmeaning-of-operator-when-used-with-classes%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Use pre created SQLite database for Android project in kotlin

            Darth Vader #20

            Ondo