Checkbox Checked problems in win32 api c++
up vote
0
down vote
favorite
I've this code done in c++ and I want to ask why when I press one CheckBox all of them change status.
Example:
CB1 = Checked
CB2 = UnChecked
CB1 = Press
CB1 = UnChecked
CB2 = Checked
I want just to make work one of them, not the two at the same time.
Here you have the code:
LRESULT CALLBACK WndProc(HWND hwnd, UINT msg, WPARAM wParam, LPARAM lParam)
switch (msg)
case WM_CREATE:
WS_CHILD
case WM_COMMAND:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED); //SetWindowText(hwnd, title or TEXT("algo");
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
//action("chatlim", 150, 0, 0);
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
case WM_DESTROY:
PostQuitMessage(0);
break;
return DefWindowProc(hwnd, msg, wParam, lParam);
c++ api winapi checkbox
asked Apr 1 '16 at 19:17
Onelio
98311
|
show 2 more comments
up vote
0
down vote
favorite
I've this code done in c++ and I want to ask why when I press one CheckBox all of them change status.
Example:
CB1 = Checked
CB2 = UnChecked
CB1 = Press
CB1 = UnChecked
CB2 = Checked
I want just to make work one of them, not the two at the same time.
Here you have the code:
LRESULT CALLBACK WndProc(HWND hwnd, UINT msg, WPARAM wParam, LPARAM lParam)
switch (msg)
case WM_CREATE:
WS_CHILD
case WM_COMMAND:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED); //SetWindowText(hwnd, title or TEXT("algo");
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
//action("chatlim", 150, 0, 0);
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
case WM_DESTROY:
PostQuitMessage(0);
break;
return DefWindowProc(hwnd, msg, wParam, lParam);
c++ api winapi checkbox
asked Apr 1 '16 at 19:17
Onelio
98311
4
You don't distinguish in the WM_OMMAND which one was clicked so when a WM_COMAND is received you change both hwnds.
– Jerry Jeremiah
Apr 1 '16 at 19:36
It's because, everytime you toggle both button states. No matter which one you press
– DimChtz
Apr 1 '16 at 19:36
Create your check box withBS_AUTOCHECKBOXflag (instead ofBS_CHECKBOX) to automatically put the check marks.
– Barmak Shemirani
Apr 1 '16 at 19:38
Jerry, How can I distinguish them?
– Onelio
Apr 1 '16 at 19:56
With BS_AUTOCHECKBOX I get Checked all of them except for the one that I want to check, his state never change(until I check another one)
– Onelio
Apr 1 '16 at 19:59
|
show 2 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I've this code done in c++ and I want to ask why when I press one CheckBox all of them change status.
Example:
CB1 = Checked
CB2 = UnChecked
CB1 = Press
CB1 = UnChecked
CB2 = Checked
I want just to make work one of them, not the two at the same time.
Here you have the code:
LRESULT CALLBACK WndProc(HWND hwnd, UINT msg, WPARAM wParam, LPARAM lParam)
switch (msg)
case WM_CREATE:
WS_CHILD
case WM_COMMAND:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED); //SetWindowText(hwnd, title or TEXT("algo");
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
//action("chatlim", 150, 0, 0);
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
case WM_DESTROY:
PostQuitMessage(0);
break;
return DefWindowProc(hwnd, msg, wParam, lParam);
c++ api winapi checkbox
asked Apr 1 '16 at 19:17
Onelio
98311
I've this code done in c++ and I want to ask why when I press one CheckBox all of them change status.
Example:
CB1 = Checked
CB2 = UnChecked
CB1 = Press
CB1 = UnChecked
CB2 = Checked
I want just to make work one of them, not the two at the same time.
Here you have the code:
LRESULT CALLBACK WndProc(HWND hwnd, UINT msg, WPARAM wParam, LPARAM lParam)
switch (msg)
case WM_CREATE:
WS_CHILD
case WM_COMMAND:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED); //SetWindowText(hwnd, title or TEXT("algo");
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
//action("chatlim", 150, 0, 0);
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
case WM_DESTROY:
PostQuitMessage(0);
break;
return DefWindowProc(hwnd, msg, wParam, lParam);
c++ api winapi checkbox
c++ api winapi checkbox
asked Apr 1 '16 at 19:17
Onelio
98311
asked Apr 1 '16 at 19:17
Onelio
98311
asked Apr 1 '16 at 19:17
Onelio
98311
asked Apr 1 '16 at 19:17
Onelio
98311
asked Apr 1 '16 at 19:17
Onelio
98311
98311
4
You don't distinguish in the WM_OMMAND which one was clicked so when a WM_COMAND is received you change both hwnds.
– Jerry Jeremiah
Apr 1 '16 at 19:36
It's because, everytime you toggle both button states. No matter which one you press
– DimChtz
Apr 1 '16 at 19:36
Create your check box withBS_AUTOCHECKBOXflag (instead ofBS_CHECKBOX) to automatically put the check marks.
– Barmak Shemirani
Apr 1 '16 at 19:38
Jerry, How can I distinguish them?
– Onelio
Apr 1 '16 at 19:56
With BS_AUTOCHECKBOX I get Checked all of them except for the one that I want to check, his state never change(until I check another one)
– Onelio
Apr 1 '16 at 19:59
|
show 2 more comments
4
You don't distinguish in the WM_OMMAND which one was clicked so when a WM_COMAND is received you change both hwnds.
– Jerry Jeremiah
Apr 1 '16 at 19:36
It's because, everytime you toggle both button states. No matter which one you press
– DimChtz
Apr 1 '16 at 19:36
Create your check box withBS_AUTOCHECKBOXflag (instead ofBS_CHECKBOX) to automatically put the check marks.
– Barmak Shemirani
Apr 1 '16 at 19:38
Jerry, How can I distinguish them?
– Onelio
Apr 1 '16 at 19:56
With BS_AUTOCHECKBOX I get Checked all of them except for the one that I want to check, his state never change(until I check another one)
– Onelio
Apr 1 '16 at 19:59
4
4
You don't distinguish in the WM_OMMAND which one was clicked so when a WM_COMAND is received you change both hwnds.
– Jerry Jeremiah
Apr 1 '16 at 19:36
You don't distinguish in the WM_OMMAND which one was clicked so when a WM_COMAND is received you change both hwnds.
– Jerry Jeremiah
Apr 1 '16 at 19:36
It's because, everytime you toggle both button states. No matter which one you press
– DimChtz
Apr 1 '16 at 19:36
It's because, everytime you toggle both button states. No matter which one you press
– DimChtz
Apr 1 '16 at 19:36
Create your check box with
BS_AUTOCHECKBOX flag (instead of BS_CHECKBOX) to automatically put the check marks.– Barmak Shemirani
Apr 1 '16 at 19:38
Create your check box with
BS_AUTOCHECKBOX flag (instead of BS_CHECKBOX) to automatically put the check marks.– Barmak Shemirani
Apr 1 '16 at 19:38
Jerry, How can I distinguish them?
– Onelio
Apr 1 '16 at 19:56
Jerry, How can I distinguish them?
– Onelio
Apr 1 '16 at 19:56
With BS_AUTOCHECKBOX I get Checked all of them except for the one that I want to check, his state never change(until I check another one)
– Onelio
Apr 1 '16 at 19:59
With BS_AUTOCHECKBOX I get Checked all of them except for the one that I want to check, his state never change(until I check another one)
– Onelio
Apr 1 '16 at 19:59
|
show 2 more comments
2 Answers
2
active
oldest
votes
up vote
0
down vote
Fixed, Just need to use switch and case.
answered Apr 1 '16 at 22:30
Onelio
98311
add a comment |
up vote
0
down vote
I will leave this code here just in case if someone will want to know how the author resolved that.
case WM_COMMAND:
switch (LOWORD(wParam))
case 1:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
break;
break;
case 2:
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
break;
answered Nov 11 at 1:25
Ruslan Muhamadiarov
157
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Fixed, Just need to use switch and case.
answered Apr 1 '16 at 22:30
Onelio
98311
add a comment |
up vote
0
down vote
Fixed, Just need to use switch and case.
answered Apr 1 '16 at 22:30
Onelio
98311
add a comment |
up vote
0
down vote
up vote
0
down vote
Fixed, Just need to use switch and case.
answered Apr 1 '16 at 22:30
Onelio
98311
Fixed, Just need to use switch and case.
answered Apr 1 '16 at 22:30
Onelio
98311
answered Apr 1 '16 at 22:30
Onelio
98311
answered Apr 1 '16 at 22:30
Onelio
98311
answered Apr 1 '16 at 22:30
Onelio
98311
98311
add a comment |
add a comment |
up vote
0
down vote
I will leave this code here just in case if someone will want to know how the author resolved that.
case WM_COMMAND:
switch (LOWORD(wParam))
case 1:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
break;
break;
case 2:
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
break;
answered Nov 11 at 1:25
Ruslan Muhamadiarov
157
add a comment |
up vote
0
down vote
I will leave this code here just in case if someone will want to know how the author resolved that.
case WM_COMMAND:
switch (LOWORD(wParam))
case 1:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
break;
break;
case 2:
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
break;
answered Nov 11 at 1:25
Ruslan Muhamadiarov
157
add a comment |
up vote
0
down vote
up vote
0
down vote
I will leave this code here just in case if someone will want to know how the author resolved that.
case WM_COMMAND:
switch (LOWORD(wParam))
case 1:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
break;
break;
case 2:
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
break;
answered Nov 11 at 1:25
Ruslan Muhamadiarov
157
I will leave this code here just in case if someone will want to know how the author resolved that.
case WM_COMMAND:
switch (LOWORD(wParam))
case 1:
BOOL checked = IsDlgButtonChecked(hwnd, 1);
if (checked)
CheckDlgButton(hwnd, 1, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 1, BST_CHECKED);
break;
break;
case 2:
BOOL checked1 = IsDlgButtonChecked(hwnd, 2);
if (checked1)
CheckDlgButton(hwnd, 2, BST_UNCHECKED);
else
CheckDlgButton(hwnd, 2, BST_CHECKED);
break;
break;
answered Nov 11 at 1:25
Ruslan Muhamadiarov
157
answered Nov 11 at 1:25
Ruslan Muhamadiarov
157
answered Nov 11 at 1:25
Ruslan Muhamadiarov
157
answered Nov 11 at 1:25
Ruslan Muhamadiarov
157
157
add a comment |
add a comment |
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4
You don't distinguish in the WM_OMMAND which one was clicked so when a WM_COMAND is received you change both hwnds.
– Jerry Jeremiah
Apr 1 '16 at 19:36
It's because, everytime you toggle both button states. No matter which one you press
– DimChtz
Apr 1 '16 at 19:36
Create your check box with
BS_AUTOCHECKBOXflag (instead ofBS_CHECKBOX) to automatically put the check marks.– Barmak Shemirani
Apr 1 '16 at 19:38
Jerry, How can I distinguish them?
– Onelio
Apr 1 '16 at 19:56
With BS_AUTOCHECKBOX I get Checked all of them except for the one that I want to check, his state never change(until I check another one)
– Onelio
Apr 1 '16 at 19:59