How to create an android app from a python-flask web app created on the desktop?

up vote
1
down vote

favorite

I've created a simple app, rather a basic "HelloWorld" app, just for sake testing the web app and for converting it into an Android app. This is the following code:

 from flask import Flask 

 app = Flask(__name__)

 @app.route('/')
 def hello():
 return 'Hello World'

 if __name__=='__main__':
 app.run()

asked Nov 10 at 6:04

Kerm Lloyd

122

You can use flask as the application backend. Flask doesn't have anything with python mobile app development.
– metmirr
Nov 10 at 9:10

Thanks for the info. Really new to Web app dev, need to learn all the basic factors.
– Kerm Lloyd
Nov 10 at 13:16

add a comment |

up vote
1
down vote

favorite

I've created a simple app, rather a basic "HelloWorld" app, just for sake testing the web app and for converting it into an Android app. This is the following code:

 from flask import Flask 

 app = Flask(__name__)

 @app.route('/')
 def hello():
 return 'Hello World'

 if __name__=='__main__':
 app.run()

asked Nov 10 at 6:04

Kerm Lloyd

122

You can use flask as the application backend. Flask doesn't have anything with python mobile app development.
– metmirr
Nov 10 at 9:10

Thanks for the info. Really new to Web app dev, need to learn all the basic factors.
– Kerm Lloyd
Nov 10 at 13:16

add a comment |

up vote
1
down vote

favorite

I've created a simple app, rather a basic "HelloWorld" app, just for sake testing the web app and for converting it into an Android app. This is the following code:

 from flask import Flask 

 app = Flask(__name__)

 @app.route('/')
 def hello():
 return 'Hello World'

 if __name__=='__main__':
 app.run()

asked Nov 10 at 6:04

Kerm Lloyd

122

I've created a simple app, rather a basic "HelloWorld" app, just for sake testing the web app and for converting it into an Android app. This is the following code:

 from flask import Flask 

 app = Flask(__name__)

 @app.route('/')
 def hello():
 return 'Hello World'

 if __name__=='__main__':
 app.run()

android python-3.x flask

asked Nov 10 at 6:04

Kerm Lloyd

122

asked Nov 10 at 6:04

Kerm Lloyd

122

asked Nov 10 at 6:04

Kerm Lloyd

122

asked Nov 10 at 6:04

Kerm Lloyd

122

asked Nov 10 at 6:04

Kerm Lloyd

122

You can use flask as the application backend. Flask doesn't have anything with python mobile app development.
– metmirr
Nov 10 at 9:10

Thanks for the info. Really new to Web app dev, need to learn all the basic factors.
– Kerm Lloyd
Nov 10 at 13:16

add a comment |

You can use flask as the application backend. Flask doesn't have anything with python mobile app development.
– metmirr
Nov 10 at 9:10

Thanks for the info. Really new to Web app dev, need to learn all the basic factors.
– Kerm Lloyd
Nov 10 at 13:16

You can use flask as the application backend. Flask doesn't have anything with python mobile app development.
– metmirr
Nov 10 at 9:10

Thanks for the info. Really new to Web app dev, need to learn all the basic factors.
– Kerm Lloyd
Nov 10 at 13:16

add a comment |

2 Answers
2

active

oldest

votes

up vote
0
down vote

You can use Kivy. From main page you can read:

Kivy - Open source Python library for rapid development of applications
that make use of innovative user interfaces, such as multi-touch apps.

Kivy runs on Linux, Windows, OS X, Android, iOS, and Raspberry Pi. You can run the same code on all supported platforms.

Afteer learning kivy a little bit, see this answer

answered Nov 10 at 8:33

Dinko Pehar

613324

Thanks for the answer. Will the app run with the same settings as done on flask like: "set FLASK_APP=MyApp" and then "flask run" and on the URL "127.0.0.1:5000/" ?
– Kerm Lloyd
Nov 10 at 13:11

Will Tk help in this situation?
– Kerm Lloyd
Nov 10 at 13:15

I'm getting such output on the terminal, and the app works on "127.0.0.1:5000/" gyazo.com/a5dc31a4dd6df107e179a48c279b39bd
– Kerm Lloyd
Nov 10 at 13:34

Sorry, but I just heard about kivy. I didn't use it before, but in your case, if you want to build Android app, you can always make a web view app, to just 'grab', so to speak, web page and serve it on android. Something like iframe tag does in HTML. But you can learn more about Kivy, since it can export your application written in python, to other platforms, among them android of course.
– Dinko Pehar
Nov 10 at 16:34

add a comment |

up vote
0
down vote

The quickstart for the specific kivy project to use can be found at:

https://python-for-android.readthedocs.io/en/latest/quickstart/

Look at "Build a WebView application"

p4a apk --private $HOME/code/myapp --package=org.example.myapp --name "My WebView Application" --version 0.1 --bootstrap=webview --requirements=flask --port=5000

answered Nov 10 at 12:16

Hewho Seekanswers

Thanks for the answer. Will surely see to it.
– Kerm Lloyd
Nov 10 at 13:18

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
0
down vote

You can use Kivy. From main page you can read:

Kivy - Open source Python library for rapid development of applications
that make use of innovative user interfaces, such as multi-touch apps.

Kivy runs on Linux, Windows, OS X, Android, iOS, and Raspberry Pi. You can run the same code on all supported platforms.

Afteer learning kivy a little bit, see this answer

answered Nov 10 at 8:33

Dinko Pehar

613324

Thanks for the answer. Will the app run with the same settings as done on flask like: "set FLASK_APP=MyApp" and then "flask run" and on the URL "127.0.0.1:5000/" ?
– Kerm Lloyd
Nov 10 at 13:11

Will Tk help in this situation?
– Kerm Lloyd
Nov 10 at 13:15

I'm getting such output on the terminal, and the app works on "127.0.0.1:5000/" gyazo.com/a5dc31a4dd6df107e179a48c279b39bd
– Kerm Lloyd
Nov 10 at 13:34

Sorry, but I just heard about kivy. I didn't use it before, but in your case, if you want to build Android app, you can always make a web view app, to just 'grab', so to speak, web page and serve it on android. Something like iframe tag does in HTML. But you can learn more about Kivy, since it can export your application written in python, to other platforms, among them android of course.
– Dinko Pehar
Nov 10 at 16:34

add a comment |

up vote
0
down vote

You can use Kivy. From main page you can read:

Kivy - Open source Python library for rapid development of applications
that make use of innovative user interfaces, such as multi-touch apps.

Kivy runs on Linux, Windows, OS X, Android, iOS, and Raspberry Pi. You can run the same code on all supported platforms.

Afteer learning kivy a little bit, see this answer

answered Nov 10 at 8:33

Dinko Pehar

613324

Thanks for the answer. Will the app run with the same settings as done on flask like: "set FLASK_APP=MyApp" and then "flask run" and on the URL "127.0.0.1:5000/" ?
– Kerm Lloyd
Nov 10 at 13:11

Will Tk help in this situation?
– Kerm Lloyd
Nov 10 at 13:15

I'm getting such output on the terminal, and the app works on "127.0.0.1:5000/" gyazo.com/a5dc31a4dd6df107e179a48c279b39bd
– Kerm Lloyd
Nov 10 at 13:34

Sorry, but I just heard about kivy. I didn't use it before, but in your case, if you want to build Android app, you can always make a web view app, to just 'grab', so to speak, web page and serve it on android. Something like iframe tag does in HTML. But you can learn more about Kivy, since it can export your application written in python, to other platforms, among them android of course.
– Dinko Pehar
Nov 10 at 16:34

add a comment |

up vote
0
down vote

You can use Kivy. From main page you can read:

Kivy - Open source Python library for rapid development of applications
that make use of innovative user interfaces, such as multi-touch apps.

Kivy runs on Linux, Windows, OS X, Android, iOS, and Raspberry Pi. You can run the same code on all supported platforms.

Afteer learning kivy a little bit, see this answer

answered Nov 10 at 8:33

Dinko Pehar

613324

You can use Kivy. From main page you can read:

Kivy - Open source Python library for rapid development of applications
that make use of innovative user interfaces, such as multi-touch apps.

Kivy runs on Linux, Windows, OS X, Android, iOS, and Raspberry Pi. You can run the same code on all supported platforms.

Afteer learning kivy a little bit, see this answer

answered Nov 10 at 8:33

Dinko Pehar

613324

answered Nov 10 at 8:33

Dinko Pehar

613324

answered Nov 10 at 8:33

Dinko Pehar

613324

answered Nov 10 at 8:33

Dinko Pehar

613324

Thanks for the answer. Will the app run with the same settings as done on flask like: "set FLASK_APP=MyApp" and then "flask run" and on the URL "127.0.0.1:5000/" ?
– Kerm Lloyd
Nov 10 at 13:11

Will Tk help in this situation?
– Kerm Lloyd
Nov 10 at 13:15

I'm getting such output on the terminal, and the app works on "127.0.0.1:5000/" gyazo.com/a5dc31a4dd6df107e179a48c279b39bd
– Kerm Lloyd
Nov 10 at 13:34

Sorry, but I just heard about kivy. I didn't use it before, but in your case, if you want to build Android app, you can always make a web view app, to just 'grab', so to speak, web page and serve it on android. Something like iframe tag does in HTML. But you can learn more about Kivy, since it can export your application written in python, to other platforms, among them android of course.
– Dinko Pehar
Nov 10 at 16:34

add a comment |

Thanks for the answer. Will the app run with the same settings as done on flask like: "set FLASK_APP=MyApp" and then "flask run" and on the URL "127.0.0.1:5000/" ?
– Kerm Lloyd
Nov 10 at 13:11

Will Tk help in this situation?
– Kerm Lloyd
Nov 10 at 13:15

I'm getting such output on the terminal, and the app works on "127.0.0.1:5000/" gyazo.com/a5dc31a4dd6df107e179a48c279b39bd
– Kerm Lloyd
Nov 10 at 13:34

Sorry, but I just heard about kivy. I didn't use it before, but in your case, if you want to build Android app, you can always make a web view app, to just 'grab', so to speak, web page and serve it on android. Something like iframe tag does in HTML. But you can learn more about Kivy, since it can export your application written in python, to other platforms, among them android of course.
– Dinko Pehar
Nov 10 at 16:34

Thanks for the answer. Will the app run with the same settings as done on flask like: "set FLASK_APP=MyApp" and then "flask run" and on the URL "127.0.0.1:5000/" ?
– Kerm Lloyd
Nov 10 at 13:11

Will Tk help in this situation?
– Kerm Lloyd
Nov 10 at 13:15

I'm getting such output on the terminal, and the app works on "127.0.0.1:5000/" gyazo.com/a5dc31a4dd6df107e179a48c279b39bd
– Kerm Lloyd
Nov 10 at 13:34

Sorry, but I just heard about kivy. I didn't use it before, but in your case, if you want to build Android app, you can always make a web view app, to just 'grab', so to speak, web page and serve it on android. Something like iframe tag does in HTML. But you can learn more about Kivy, since it can export your application written in python, to other platforms, among them android of course.
– Dinko Pehar
Nov 10 at 16:34

add a comment |

up vote
0
down vote

The quickstart for the specific kivy project to use can be found at:

https://python-for-android.readthedocs.io/en/latest/quickstart/

Look at "Build a WebView application"

p4a apk --private $HOME/code/myapp --package=org.example.myapp --name "My WebView Application" --version 0.1 --bootstrap=webview --requirements=flask --port=5000

answered Nov 10 at 12:16

Hewho Seekanswers

Thanks for the answer. Will surely see to it.
– Kerm Lloyd
Nov 10 at 13:18

add a comment |

up vote
0
down vote

The quickstart for the specific kivy project to use can be found at:

https://python-for-android.readthedocs.io/en/latest/quickstart/

Look at "Build a WebView application"

p4a apk --private $HOME/code/myapp --package=org.example.myapp --name "My WebView Application" --version 0.1 --bootstrap=webview --requirements=flask --port=5000

answered Nov 10 at 12:16

Hewho Seekanswers

Thanks for the answer. Will surely see to it.
– Kerm Lloyd
Nov 10 at 13:18

add a comment |

up vote
0
down vote

The quickstart for the specific kivy project to use can be found at:

https://python-for-android.readthedocs.io/en/latest/quickstart/

Look at "Build a WebView application"

p4a apk --private $HOME/code/myapp --package=org.example.myapp --name "My WebView Application" --version 0.1 --bootstrap=webview --requirements=flask --port=5000

answered Nov 10 at 12:16

Hewho Seekanswers

The quickstart for the specific kivy project to use can be found at:

https://python-for-android.readthedocs.io/en/latest/quickstart/

Look at "Build a WebView application"

p4a apk --private $HOME/code/myapp --package=org.example.myapp --name "My WebView Application" --version 0.1 --bootstrap=webview --requirements=flask --port=5000

answered Nov 10 at 12:16

Hewho Seekanswers

answered Nov 10 at 12:16

Hewho Seekanswers

answered Nov 10 at 12:16

Hewho Seekanswers

answered Nov 10 at 12:16

Hewho Seekanswers

Thanks for the answer. Will surely see to it.
– Kerm Lloyd
Nov 10 at 13:18

add a comment |

Thanks for the answer. Will surely see to it.
– Kerm Lloyd
Nov 10 at 13:18

Thanks for the answer. Will surely see to it.
– Kerm Lloyd
Nov 10 at 13:18

add a comment |

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