Auto-update Ubuntu IP address in python script
I am using python3 , flask server on ubuntu virtual machine. The server is working fine. It uploads a browsed video and print **found file when the browsed video file is in appropriate extension.
The problem is, every time when I restart my ubuntu virtual machine the IP address is changed and I have to update it manually in python script app.run(host= '192.168.1.101', debug=True).
Please tell me how to automatically update it.
Any help would be appreciated.
Thanks in advance.
Here is the code.
import os
from flask import Flask, request, redirect, url_for, send_from_directory, jsonify
from werkzeug import secure_filename
UPLOAD_FOLDER = 'uploads'
ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'mp4'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
# this has changed from the original example because the original did not work for me
return filename[-3:].lower() in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET', 'POST'])
def upload_file():
print("Printing the request ".format(request.headers))
print("Printing the request ".format(request))
print("Printing the request ".format(request.data))
print("Printing the request ".format(request.form))
if request.method == 'POST':
file = request.files['file']
if file and allowed_file(file.filename):
print('**found file', file.filename)
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
# for browser, add 'redirect' function on top of 'url_for'
return jsonify("success" : url_for('uploaded_file',
filename=filename))
return '''
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file name=file>
<input type=submit value=Upload>
</form>
'''
@app.route('/uploads/<filename>')
def uploaded_file(filename):
return send_from_directory(app.config['UPLOAD_FOLDER'],
filename)
if __name__ == '__main__':
app.run(host= '192.168.1.101', debug=True)
python-3.x flask ubuntu-14.04
asked Nov 12 '18 at 15:52
Afshan AnwaraliAfshan Anwarali
206
add a comment |
I am using python3 , flask server on ubuntu virtual machine. The server is working fine. It uploads a browsed video and print **found file when the browsed video file is in appropriate extension.
The problem is, every time when I restart my ubuntu virtual machine the IP address is changed and I have to update it manually in python script app.run(host= '192.168.1.101', debug=True).
Please tell me how to automatically update it.
Any help would be appreciated.
Thanks in advance.
Here is the code.
import os
from flask import Flask, request, redirect, url_for, send_from_directory, jsonify
from werkzeug import secure_filename
UPLOAD_FOLDER = 'uploads'
ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'mp4'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
# this has changed from the original example because the original did not work for me
return filename[-3:].lower() in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET', 'POST'])
def upload_file():
print("Printing the request ".format(request.headers))
print("Printing the request ".format(request))
print("Printing the request ".format(request.data))
print("Printing the request ".format(request.form))
if request.method == 'POST':
file = request.files['file']
if file and allowed_file(file.filename):
print('**found file', file.filename)
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
# for browser, add 'redirect' function on top of 'url_for'
return jsonify("success" : url_for('uploaded_file',
filename=filename))
return '''
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file name=file>
<input type=submit value=Upload>
</form>
'''
@app.route('/uploads/<filename>')
def uploaded_file(filename):
return send_from_directory(app.config['UPLOAD_FOLDER'],
filename)
if __name__ == '__main__':
app.run(host= '192.168.1.101', debug=True)
python-3.x flask ubuntu-14.04
asked Nov 12 '18 at 15:52
Afshan AnwaraliAfshan Anwarali
206
add a comment |
I am using python3 , flask server on ubuntu virtual machine. The server is working fine. It uploads a browsed video and print **found file when the browsed video file is in appropriate extension.
The problem is, every time when I restart my ubuntu virtual machine the IP address is changed and I have to update it manually in python script app.run(host= '192.168.1.101', debug=True).
Please tell me how to automatically update it.
Any help would be appreciated.
Thanks in advance.
Here is the code.
import os
from flask import Flask, request, redirect, url_for, send_from_directory, jsonify
from werkzeug import secure_filename
UPLOAD_FOLDER = 'uploads'
ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'mp4'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
# this has changed from the original example because the original did not work for me
return filename[-3:].lower() in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET', 'POST'])
def upload_file():
print("Printing the request ".format(request.headers))
print("Printing the request ".format(request))
print("Printing the request ".format(request.data))
print("Printing the request ".format(request.form))
if request.method == 'POST':
file = request.files['file']
if file and allowed_file(file.filename):
print('**found file', file.filename)
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
# for browser, add 'redirect' function on top of 'url_for'
return jsonify("success" : url_for('uploaded_file',
filename=filename))
return '''
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file name=file>
<input type=submit value=Upload>
</form>
'''
@app.route('/uploads/<filename>')
def uploaded_file(filename):
return send_from_directory(app.config['UPLOAD_FOLDER'],
filename)
if __name__ == '__main__':
app.run(host= '192.168.1.101', debug=True)
python-3.x flask ubuntu-14.04
asked Nov 12 '18 at 15:52
Afshan AnwaraliAfshan Anwarali
206
I am using python3 , flask server on ubuntu virtual machine. The server is working fine. It uploads a browsed video and print **found file when the browsed video file is in appropriate extension.
The problem is, every time when I restart my ubuntu virtual machine the IP address is changed and I have to update it manually in python script app.run(host= '192.168.1.101', debug=True).
Please tell me how to automatically update it.
Any help would be appreciated.
Thanks in advance.
Here is the code.
import os
from flask import Flask, request, redirect, url_for, send_from_directory, jsonify
from werkzeug import secure_filename
UPLOAD_FOLDER = 'uploads'
ALLOWED_EXTENSIONS = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'mp4'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
# this has changed from the original example because the original did not work for me
return filename[-3:].lower() in ALLOWED_EXTENSIONS
@app.route('/', methods=['GET', 'POST'])
def upload_file():
print("Printing the request ".format(request.headers))
print("Printing the request ".format(request))
print("Printing the request ".format(request.data))
print("Printing the request ".format(request.form))
if request.method == 'POST':
file = request.files['file']
if file and allowed_file(file.filename):
print('**found file', file.filename)
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
# for browser, add 'redirect' function on top of 'url_for'
return jsonify("success" : url_for('uploaded_file',
filename=filename))
return '''
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file name=file>
<input type=submit value=Upload>
</form>
'''
@app.route('/uploads/<filename>')
def uploaded_file(filename):
return send_from_directory(app.config['UPLOAD_FOLDER'],
filename)
if __name__ == '__main__':
app.run(host= '192.168.1.101', debug=True)
python-3.x flask ubuntu-14.04
python-3.x flask ubuntu-14.04
asked Nov 12 '18 at 15:52
Afshan AnwaraliAfshan Anwarali
206
asked Nov 12 '18 at 15:52
Afshan AnwaraliAfshan Anwarali
206
asked Nov 12 '18 at 15:52
Afshan AnwaraliAfshan Anwarali
206
asked Nov 12 '18 at 15:52
Afshan AnwaraliAfshan Anwarali
206
asked Nov 12 '18 at 15:52
Afshan AnwaraliAfshan Anwarali
206
206
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
you will have to either parse the "ip address" or "ifconfig" command, or use
import socket
socket.gethostbyname(socket.gethostname())
cfr. Finding local IP addresses using Python's stdlib
answered Nov 12 '18 at 16:01
TohmaxxxTohmaxxx
1766
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
you will have to either parse the "ip address" or "ifconfig" command, or use
import socket
socket.gethostbyname(socket.gethostname())
cfr. Finding local IP addresses using Python's stdlib
answered Nov 12 '18 at 16:01
TohmaxxxTohmaxxx
1766
add a comment |
you will have to either parse the "ip address" or "ifconfig" command, or use
import socket
socket.gethostbyname(socket.gethostname())
cfr. Finding local IP addresses using Python's stdlib
answered Nov 12 '18 at 16:01
TohmaxxxTohmaxxx
1766
add a comment |
you will have to either parse the "ip address" or "ifconfig" command, or use
import socket
socket.gethostbyname(socket.gethostname())
cfr. Finding local IP addresses using Python's stdlib
answered Nov 12 '18 at 16:01
TohmaxxxTohmaxxx
1766
you will have to either parse the "ip address" or "ifconfig" command, or use
import socket
socket.gethostbyname(socket.gethostname())
cfr. Finding local IP addresses using Python's stdlib
answered Nov 12 '18 at 16:01
TohmaxxxTohmaxxx
1766
answered Nov 12 '18 at 16:01
TohmaxxxTohmaxxx
1766
answered Nov 12 '18 at 16:01
TohmaxxxTohmaxxx
1766
answered Nov 12 '18 at 16:01
TohmaxxxTohmaxxx
1766
1766
add a comment |
add a comment |
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