Mixed Integer Quadratic Programming with linear constraints in Matlab calling Gurobi










0















I have some troubles to understand how to implement the following MIQP (Mixed Integer Quadratic Programming) with linear constraints in Matlab calling Gurobi.



Let me explain in a schematic way my setting.




(1) x is the unknown and it is a column vector with size 225x1.




(2) The objective function (which should be minimised wrto x) looks like



enter image description here



which can be rewritten as



enter image description here



I have a Matlab script computing alpha, Q,c (Q,c sparse) when some_known_parameters1 are given:



function [alpha, Q,c]=matrix_objective_function(some_known_parameters1)

%...

end



(3) The constraints are linear in x, include equalities and inequalities, and are written in the form enter image description here



I have a Matlab script computing Aeq,beq,Aineq,bineq (Aeq,Aineq sparse) when some_known_parameters2 is given:



function [Aeq,beq,Aineq,bineq]=constraints(some_known_parameters2)

%...

end



(4) Some components of x are restricted to be in 0,1. I have a Matlab script producing a string of letters B (binary), C (continous) when some_known_parameters3 is given:



function type=binary_continuous(some_known_parameters3)

%...

end



Now, I need to put together (1)-(4) using Gurobi. I am struggling to understand how. I found this example but it looks very cryptic to me. Below I report some lines I have attempted to write, but they are incomplete and I would like your help to complete them.



clear 
rng default

%Define some_known_parameters1,
some_known_parameters2,some_known_parameters3 [...]

%1) generate alpha,Q,c,Aeq,beq,Aineq,bineq,type with Q,c,Aeq, Aineq sparse
[alpha, Q,c]=matrix_objective_function(some_known_parameters1)
[Aeq,beq,Aineq,bineq]=constraints(some_known_parameters2)
type=binary_continuous(some_known_parameters3)



%2) Set up Gurobi
clear model;
model.A=[Aineq; Aeq];
model.rhs=full([bineq(:); beq(:)]);
model.sense=[repmat('<', size(Aineq,1),1); repmat('=', size(Aeq,1),1)];
model.Q=Q; %not sure?
model.alpha=alpha; %not sure?
model.c=c; %not sure?
model.vtype=type;
result=gurobi(model); %how do I get just the objective function here without the minimiser?



Questions:



(1) I'm not sure about



model.Q=Q; 
model.alpha=alpha;
model.c=c;


I'm just trying to set the matrices of the objective function using the letters provided here but it gives me error. The example here seems to me doing



model.Q=Q; 
model.obj=c;


But then how do I set alpha? Is it ignoring it because it does not change the set of solutions?



(2) How do I get as output stored in a matrix just the minimum value of the objective function without the corresponding x?










share|improve this question



















  • 1





    You should not expect to be able to give gurobi some black-box objective. This is something for NLP territory (where some form of differentiation is happening inside; e.g. Ipopt/Bonmin). Gurobi needs this objective in it's own native form. What form that is depends on your lib/wrapper. In low-level form usually something like 0.5 * x'Qx + q'x with Q psd (convex QP; which is probably the only one gurobi supports; ignoring SOCP generalizations). If that's giving you headaches, look for some more high-level wrapper. Gurobi's Python-API for example supports expr = QuadExpr(x*x + y+y).

    – sascha
    Nov 13 '18 at 19:49












  • @sascha thanks: my problem is very basic I guess: (a) I think my objective function can be rewritten as Q+x'Hx (I have added this to my question); (b) I still don't understand how to complete steps 3) and 4) above.

    – user3285148
    Nov 13 '18 at 19:55







  • 1





    This is all explained in the docs for this low-level view. Bring your objective in this form and set obj = some_vec, objcon = some_vec and Q = some_matrix. Then (4) is just a string it seems like BBC (binary, binary, continuous). The bounds are vectors lb and ub.

    – sascha
    Nov 13 '18 at 20:02







  • 1





    vtypes is string. lb ub are vectors. 3 vars between (-1,1), then (1,3) and (2,3) will be lb=[-1,1,2] and ub=[1,3,3].

    – sascha
    Nov 14 '18 at 5:35







  • 1





    That's a modelling thing. I recommend grabbing some integer-programming book. You can use one binary variable and replace all occurences with the term x = 1-2*binVar. x will be in -1,1 then. Yes, this is annoying in low-level form (but there is no way out without wrappers / lib-support). But nobody should do prototyping on this level imho.

    – sascha
    Nov 14 '18 at 8:15
















0















I have some troubles to understand how to implement the following MIQP (Mixed Integer Quadratic Programming) with linear constraints in Matlab calling Gurobi.



Let me explain in a schematic way my setting.




(1) x is the unknown and it is a column vector with size 225x1.




(2) The objective function (which should be minimised wrto x) looks like



enter image description here



which can be rewritten as



enter image description here



I have a Matlab script computing alpha, Q,c (Q,c sparse) when some_known_parameters1 are given:



function [alpha, Q,c]=matrix_objective_function(some_known_parameters1)

%...

end



(3) The constraints are linear in x, include equalities and inequalities, and are written in the form enter image description here



I have a Matlab script computing Aeq,beq,Aineq,bineq (Aeq,Aineq sparse) when some_known_parameters2 is given:



function [Aeq,beq,Aineq,bineq]=constraints(some_known_parameters2)

%...

end



(4) Some components of x are restricted to be in 0,1. I have a Matlab script producing a string of letters B (binary), C (continous) when some_known_parameters3 is given:



function type=binary_continuous(some_known_parameters3)

%...

end



Now, I need to put together (1)-(4) using Gurobi. I am struggling to understand how. I found this example but it looks very cryptic to me. Below I report some lines I have attempted to write, but they are incomplete and I would like your help to complete them.



clear 
rng default

%Define some_known_parameters1,
some_known_parameters2,some_known_parameters3 [...]

%1) generate alpha,Q,c,Aeq,beq,Aineq,bineq,type with Q,c,Aeq, Aineq sparse
[alpha, Q,c]=matrix_objective_function(some_known_parameters1)
[Aeq,beq,Aineq,bineq]=constraints(some_known_parameters2)
type=binary_continuous(some_known_parameters3)



%2) Set up Gurobi
clear model;
model.A=[Aineq; Aeq];
model.rhs=full([bineq(:); beq(:)]);
model.sense=[repmat('<', size(Aineq,1),1); repmat('=', size(Aeq,1),1)];
model.Q=Q; %not sure?
model.alpha=alpha; %not sure?
model.c=c; %not sure?
model.vtype=type;
result=gurobi(model); %how do I get just the objective function here without the minimiser?



Questions:



(1) I'm not sure about



model.Q=Q; 
model.alpha=alpha;
model.c=c;


I'm just trying to set the matrices of the objective function using the letters provided here but it gives me error. The example here seems to me doing



model.Q=Q; 
model.obj=c;


But then how do I set alpha? Is it ignoring it because it does not change the set of solutions?



(2) How do I get as output stored in a matrix just the minimum value of the objective function without the corresponding x?










share|improve this question



















  • 1





    You should not expect to be able to give gurobi some black-box objective. This is something for NLP territory (where some form of differentiation is happening inside; e.g. Ipopt/Bonmin). Gurobi needs this objective in it's own native form. What form that is depends on your lib/wrapper. In low-level form usually something like 0.5 * x'Qx + q'x with Q psd (convex QP; which is probably the only one gurobi supports; ignoring SOCP generalizations). If that's giving you headaches, look for some more high-level wrapper. Gurobi's Python-API for example supports expr = QuadExpr(x*x + y+y).

    – sascha
    Nov 13 '18 at 19:49












  • @sascha thanks: my problem is very basic I guess: (a) I think my objective function can be rewritten as Q+x'Hx (I have added this to my question); (b) I still don't understand how to complete steps 3) and 4) above.

    – user3285148
    Nov 13 '18 at 19:55







  • 1





    This is all explained in the docs for this low-level view. Bring your objective in this form and set obj = some_vec, objcon = some_vec and Q = some_matrix. Then (4) is just a string it seems like BBC (binary, binary, continuous). The bounds are vectors lb and ub.

    – sascha
    Nov 13 '18 at 20:02







  • 1





    vtypes is string. lb ub are vectors. 3 vars between (-1,1), then (1,3) and (2,3) will be lb=[-1,1,2] and ub=[1,3,3].

    – sascha
    Nov 14 '18 at 5:35







  • 1





    That's a modelling thing. I recommend grabbing some integer-programming book. You can use one binary variable and replace all occurences with the term x = 1-2*binVar. x will be in -1,1 then. Yes, this is annoying in low-level form (but there is no way out without wrappers / lib-support). But nobody should do prototyping on this level imho.

    – sascha
    Nov 14 '18 at 8:15














0












0








0


1






I have some troubles to understand how to implement the following MIQP (Mixed Integer Quadratic Programming) with linear constraints in Matlab calling Gurobi.



Let me explain in a schematic way my setting.




(1) x is the unknown and it is a column vector with size 225x1.




(2) The objective function (which should be minimised wrto x) looks like



enter image description here



which can be rewritten as



enter image description here



I have a Matlab script computing alpha, Q,c (Q,c sparse) when some_known_parameters1 are given:



function [alpha, Q,c]=matrix_objective_function(some_known_parameters1)

%...

end



(3) The constraints are linear in x, include equalities and inequalities, and are written in the form enter image description here



I have a Matlab script computing Aeq,beq,Aineq,bineq (Aeq,Aineq sparse) when some_known_parameters2 is given:



function [Aeq,beq,Aineq,bineq]=constraints(some_known_parameters2)

%...

end



(4) Some components of x are restricted to be in 0,1. I have a Matlab script producing a string of letters B (binary), C (continous) when some_known_parameters3 is given:



function type=binary_continuous(some_known_parameters3)

%...

end



Now, I need to put together (1)-(4) using Gurobi. I am struggling to understand how. I found this example but it looks very cryptic to me. Below I report some lines I have attempted to write, but they are incomplete and I would like your help to complete them.



clear 
rng default

%Define some_known_parameters1,
some_known_parameters2,some_known_parameters3 [...]

%1) generate alpha,Q,c,Aeq,beq,Aineq,bineq,type with Q,c,Aeq, Aineq sparse
[alpha, Q,c]=matrix_objective_function(some_known_parameters1)
[Aeq,beq,Aineq,bineq]=constraints(some_known_parameters2)
type=binary_continuous(some_known_parameters3)



%2) Set up Gurobi
clear model;
model.A=[Aineq; Aeq];
model.rhs=full([bineq(:); beq(:)]);
model.sense=[repmat('<', size(Aineq,1),1); repmat('=', size(Aeq,1),1)];
model.Q=Q; %not sure?
model.alpha=alpha; %not sure?
model.c=c; %not sure?
model.vtype=type;
result=gurobi(model); %how do I get just the objective function here without the minimiser?



Questions:



(1) I'm not sure about



model.Q=Q; 
model.alpha=alpha;
model.c=c;


I'm just trying to set the matrices of the objective function using the letters provided here but it gives me error. The example here seems to me doing



model.Q=Q; 
model.obj=c;


But then how do I set alpha? Is it ignoring it because it does not change the set of solutions?



(2) How do I get as output stored in a matrix just the minimum value of the objective function without the corresponding x?










share|improve this question
















I have some troubles to understand how to implement the following MIQP (Mixed Integer Quadratic Programming) with linear constraints in Matlab calling Gurobi.



Let me explain in a schematic way my setting.




(1) x is the unknown and it is a column vector with size 225x1.




(2) The objective function (which should be minimised wrto x) looks like



enter image description here



which can be rewritten as



enter image description here



I have a Matlab script computing alpha, Q,c (Q,c sparse) when some_known_parameters1 are given:



function [alpha, Q,c]=matrix_objective_function(some_known_parameters1)

%...

end



(3) The constraints are linear in x, include equalities and inequalities, and are written in the form enter image description here



I have a Matlab script computing Aeq,beq,Aineq,bineq (Aeq,Aineq sparse) when some_known_parameters2 is given:



function [Aeq,beq,Aineq,bineq]=constraints(some_known_parameters2)

%...

end



(4) Some components of x are restricted to be in 0,1. I have a Matlab script producing a string of letters B (binary), C (continous) when some_known_parameters3 is given:



function type=binary_continuous(some_known_parameters3)

%...

end



Now, I need to put together (1)-(4) using Gurobi. I am struggling to understand how. I found this example but it looks very cryptic to me. Below I report some lines I have attempted to write, but they are incomplete and I would like your help to complete them.



clear 
rng default

%Define some_known_parameters1,
some_known_parameters2,some_known_parameters3 [...]

%1) generate alpha,Q,c,Aeq,beq,Aineq,bineq,type with Q,c,Aeq, Aineq sparse
[alpha, Q,c]=matrix_objective_function(some_known_parameters1)
[Aeq,beq,Aineq,bineq]=constraints(some_known_parameters2)
type=binary_continuous(some_known_parameters3)



%2) Set up Gurobi
clear model;
model.A=[Aineq; Aeq];
model.rhs=full([bineq(:); beq(:)]);
model.sense=[repmat('<', size(Aineq,1),1); repmat('=', size(Aeq,1),1)];
model.Q=Q; %not sure?
model.alpha=alpha; %not sure?
model.c=c; %not sure?
model.vtype=type;
result=gurobi(model); %how do I get just the objective function here without the minimiser?



Questions:



(1) I'm not sure about



model.Q=Q; 
model.alpha=alpha;
model.c=c;


I'm just trying to set the matrices of the objective function using the letters provided here but it gives me error. The example here seems to me doing



model.Q=Q; 
model.obj=c;


But then how do I set alpha? Is it ignoring it because it does not change the set of solutions?



(2) How do I get as output stored in a matrix just the minimum value of the objective function without the corresponding x?







matlab optimization gurobi quadratic-programming mixed-integer-programming






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 13:34







user3285148

















asked Nov 12 '18 at 19:01









user3285148user3285148

623526




623526







  • 1





    You should not expect to be able to give gurobi some black-box objective. This is something for NLP territory (where some form of differentiation is happening inside; e.g. Ipopt/Bonmin). Gurobi needs this objective in it's own native form. What form that is depends on your lib/wrapper. In low-level form usually something like 0.5 * x'Qx + q'x with Q psd (convex QP; which is probably the only one gurobi supports; ignoring SOCP generalizations). If that's giving you headaches, look for some more high-level wrapper. Gurobi's Python-API for example supports expr = QuadExpr(x*x + y+y).

    – sascha
    Nov 13 '18 at 19:49












  • @sascha thanks: my problem is very basic I guess: (a) I think my objective function can be rewritten as Q+x'Hx (I have added this to my question); (b) I still don't understand how to complete steps 3) and 4) above.

    – user3285148
    Nov 13 '18 at 19:55







  • 1





    This is all explained in the docs for this low-level view. Bring your objective in this form and set obj = some_vec, objcon = some_vec and Q = some_matrix. Then (4) is just a string it seems like BBC (binary, binary, continuous). The bounds are vectors lb and ub.

    – sascha
    Nov 13 '18 at 20:02







  • 1





    vtypes is string. lb ub are vectors. 3 vars between (-1,1), then (1,3) and (2,3) will be lb=[-1,1,2] and ub=[1,3,3].

    – sascha
    Nov 14 '18 at 5:35







  • 1





    That's a modelling thing. I recommend grabbing some integer-programming book. You can use one binary variable and replace all occurences with the term x = 1-2*binVar. x will be in -1,1 then. Yes, this is annoying in low-level form (but there is no way out without wrappers / lib-support). But nobody should do prototyping on this level imho.

    – sascha
    Nov 14 '18 at 8:15













  • 1





    You should not expect to be able to give gurobi some black-box objective. This is something for NLP territory (where some form of differentiation is happening inside; e.g. Ipopt/Bonmin). Gurobi needs this objective in it's own native form. What form that is depends on your lib/wrapper. In low-level form usually something like 0.5 * x'Qx + q'x with Q psd (convex QP; which is probably the only one gurobi supports; ignoring SOCP generalizations). If that's giving you headaches, look for some more high-level wrapper. Gurobi's Python-API for example supports expr = QuadExpr(x*x + y+y).

    – sascha
    Nov 13 '18 at 19:49












  • @sascha thanks: my problem is very basic I guess: (a) I think my objective function can be rewritten as Q+x'Hx (I have added this to my question); (b) I still don't understand how to complete steps 3) and 4) above.

    – user3285148
    Nov 13 '18 at 19:55







  • 1





    This is all explained in the docs for this low-level view. Bring your objective in this form and set obj = some_vec, objcon = some_vec and Q = some_matrix. Then (4) is just a string it seems like BBC (binary, binary, continuous). The bounds are vectors lb and ub.

    – sascha
    Nov 13 '18 at 20:02







  • 1





    vtypes is string. lb ub are vectors. 3 vars between (-1,1), then (1,3) and (2,3) will be lb=[-1,1,2] and ub=[1,3,3].

    – sascha
    Nov 14 '18 at 5:35







  • 1





    That's a modelling thing. I recommend grabbing some integer-programming book. You can use one binary variable and replace all occurences with the term x = 1-2*binVar. x will be in -1,1 then. Yes, this is annoying in low-level form (but there is no way out without wrappers / lib-support). But nobody should do prototyping on this level imho.

    – sascha
    Nov 14 '18 at 8:15








1




1





You should not expect to be able to give gurobi some black-box objective. This is something for NLP territory (where some form of differentiation is happening inside; e.g. Ipopt/Bonmin). Gurobi needs this objective in it's own native form. What form that is depends on your lib/wrapper. In low-level form usually something like 0.5 * x'Qx + q'x with Q psd (convex QP; which is probably the only one gurobi supports; ignoring SOCP generalizations). If that's giving you headaches, look for some more high-level wrapper. Gurobi's Python-API for example supports expr = QuadExpr(x*x + y+y).

– sascha
Nov 13 '18 at 19:49






You should not expect to be able to give gurobi some black-box objective. This is something for NLP territory (where some form of differentiation is happening inside; e.g. Ipopt/Bonmin). Gurobi needs this objective in it's own native form. What form that is depends on your lib/wrapper. In low-level form usually something like 0.5 * x'Qx + q'x with Q psd (convex QP; which is probably the only one gurobi supports; ignoring SOCP generalizations). If that's giving you headaches, look for some more high-level wrapper. Gurobi's Python-API for example supports expr = QuadExpr(x*x + y+y).

– sascha
Nov 13 '18 at 19:49














@sascha thanks: my problem is very basic I guess: (a) I think my objective function can be rewritten as Q+x'Hx (I have added this to my question); (b) I still don't understand how to complete steps 3) and 4) above.

– user3285148
Nov 13 '18 at 19:55






@sascha thanks: my problem is very basic I guess: (a) I think my objective function can be rewritten as Q+x'Hx (I have added this to my question); (b) I still don't understand how to complete steps 3) and 4) above.

– user3285148
Nov 13 '18 at 19:55





1




1





This is all explained in the docs for this low-level view. Bring your objective in this form and set obj = some_vec, objcon = some_vec and Q = some_matrix. Then (4) is just a string it seems like BBC (binary, binary, continuous). The bounds are vectors lb and ub.

– sascha
Nov 13 '18 at 20:02






This is all explained in the docs for this low-level view. Bring your objective in this form and set obj = some_vec, objcon = some_vec and Q = some_matrix. Then (4) is just a string it seems like BBC (binary, binary, continuous). The bounds are vectors lb and ub.

– sascha
Nov 13 '18 at 20:02





1




1





vtypes is string. lb ub are vectors. 3 vars between (-1,1), then (1,3) and (2,3) will be lb=[-1,1,2] and ub=[1,3,3].

– sascha
Nov 14 '18 at 5:35






vtypes is string. lb ub are vectors. 3 vars between (-1,1), then (1,3) and (2,3) will be lb=[-1,1,2] and ub=[1,3,3].

– sascha
Nov 14 '18 at 5:35





1




1





That's a modelling thing. I recommend grabbing some integer-programming book. You can use one binary variable and replace all occurences with the term x = 1-2*binVar. x will be in -1,1 then. Yes, this is annoying in low-level form (but there is no way out without wrappers / lib-support). But nobody should do prototyping on this level imho.

– sascha
Nov 14 '18 at 8:15






That's a modelling thing. I recommend grabbing some integer-programming book. You can use one binary variable and replace all occurences with the term x = 1-2*binVar. x will be in -1,1 then. Yes, this is annoying in low-level form (but there is no way out without wrappers / lib-support). But nobody should do prototyping on this level imho.

– sascha
Nov 14 '18 at 8:15













1 Answer
1






active

oldest

votes


















1














(1) You're right, there's no need to pass the constant alpha since it doesn't affect the optimal solution. Gurobi's MATLAB API only accepts sparse matrices. Furthermore model.obj is always the c vector in the problem statement:



model.Q = sparse(Q); 
model.obj = c;


(2) To get the optimal objective value, you first need to pass your model to gurobi and solve it. Then you can access it via the objval attribute:



results = gurobi(model);
val = results.objval + alpha





share|improve this answer






















    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53268494%2fmixed-integer-quadratic-programming-with-linear-constraints-in-matlab-calling-gu%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    (1) You're right, there's no need to pass the constant alpha since it doesn't affect the optimal solution. Gurobi's MATLAB API only accepts sparse matrices. Furthermore model.obj is always the c vector in the problem statement:



    model.Q = sparse(Q); 
    model.obj = c;


    (2) To get the optimal objective value, you first need to pass your model to gurobi and solve it. Then you can access it via the objval attribute:



    results = gurobi(model);
    val = results.objval + alpha





    share|improve this answer



























      1














      (1) You're right, there's no need to pass the constant alpha since it doesn't affect the optimal solution. Gurobi's MATLAB API only accepts sparse matrices. Furthermore model.obj is always the c vector in the problem statement:



      model.Q = sparse(Q); 
      model.obj = c;


      (2) To get the optimal objective value, you first need to pass your model to gurobi and solve it. Then you can access it via the objval attribute:



      results = gurobi(model);
      val = results.objval + alpha





      share|improve this answer

























        1












        1








        1







        (1) You're right, there's no need to pass the constant alpha since it doesn't affect the optimal solution. Gurobi's MATLAB API only accepts sparse matrices. Furthermore model.obj is always the c vector in the problem statement:



        model.Q = sparse(Q); 
        model.obj = c;


        (2) To get the optimal objective value, you first need to pass your model to gurobi and solve it. Then you can access it via the objval attribute:



        results = gurobi(model);
        val = results.objval + alpha





        share|improve this answer













        (1) You're right, there's no need to pass the constant alpha since it doesn't affect the optimal solution. Gurobi's MATLAB API only accepts sparse matrices. Furthermore model.obj is always the c vector in the problem statement:



        model.Q = sparse(Q); 
        model.obj = c;


        (2) To get the optimal objective value, you first need to pass your model to gurobi and solve it. Then you can access it via the objval attribute:



        results = gurobi(model);
        val = results.objval + alpha






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 9:36









        jonijoni

        748157




        748157



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53268494%2fmixed-integer-quadratic-programming-with-linear-constraints-in-matlab-calling-gu%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Use pre created SQLite database for Android project in kotlin

            Darth Vader #20

            Ondo